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Secondary 4 Pure Chemistry Periodic Table Quiz
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Secondary 4 Pure Chemistry Quiz - Periodic Table
Answer Key
Section A: Multiple Choice Questions
1. (b)
- Explanation: Across Period 3, electrons are added to the same principal energy shell (n = 3) while protons are added to the nucleus. The increasing nuclear charge pulls the electron cloud closer, decreasing the atomic radius. The number of electron shells remains constant across a period.
- Common mistake: Choosing (a) — students confuse "across a period" with "down a group." The number of shells stays the same across a period.
2. (c)
- Explanation: Electronic configuration 2.8.6 means 6 electrons in the outer shell → Group 16 (also called Group VI). Three occupied shells → Period 3.
- Common mistake: Choosing (b) — Group 6 is an older notation; the current IUPAC system uses Group 16.
3. (d)
- Explanation: Across Period 3, first ionisation energy generally increases due to increasing nuclear charge and decreasing atomic radius. Silicon (Si) has the highest first ionisation energy among the four options. (Note: the absolute highest in Period 3 is argon, but among Na, Mg, Al and Si, Si is highest.)
- Common mistake: Students may forget the general trend and choose Na.
4. (c)
- Explanation: Halogens exist as diatomic molecules (F₂, Cl₂, Br₂, I₂). They are non-metals, boiling points increase down the group, and reactivity decreases down the group.
- Common mistake: Choosing (d) — reactivity decreases, not increases, going down Group 17.
5. (c)
- Explanation: Al₂O₃ is amphoteric — it reacts with both acids and bases. Na₂O and MgO are basic oxides; SiO₂ is acidic.
- Common mistake: Students may not recall that aluminium oxide is amphoteric.
6. (c)
- Explanation: Going down Group 1, atomic radius increases, reactivity increases, and reducing power increases. Ionisation energy decreases because the outer electron is further from the nucleus and more shielded.
- Common mistake: Choosing (b) — reactivity increases, not decreases, going down Group 1.
7. (c)
- Explanation: Non-metal oxides (e.g., SO₂, P₄O₁₀) dissolve in water to form acidic solutions (pH < 7). Non-metals are on the right side of the period.
- Common mistake: Choosing (a) — metal oxides form basic solutions.
8. (b)
- Explanation: Noble gases have a stable, full outer electron shell (octet, or duplet for helium), making them chemically unreactive.
- Common mistake: Choosing (a) — noble gases do have electrons; they have full outer shells.
9. (a)
- Explanation: Ionic compounds form between metals and non-metals. Sodium (metal) and chlorine (non-metal) form NaCl. The other pairs are non-metal + non-metal, forming covalent compounds.
- Common mistake: Students may not distinguish between ionic and covalent bonding patterns.
10. (b)
- Explanation: Electronegativity increases from left to right across a period because the nuclear charge increases, attracting bonding electrons more strongly. It is highest for Group 17 elements (excluding noble gases).
- Common mistake: Choosing (a) — confusing the direction of the trend.
Section B: Structured Questions
11.
(a) Elements A and D are in Group 1. [1]
- Reason: Both have 1 electron in their outermost shell (electronic configuration ends in ".1"). Group number = number of outer electrons. [1]
(b) Elements A, B, and C are in the same period. [1]
- Period number: Period 3 — all three have 3 occupied electron shells. [1]
(c) Element C (chlorine, proton number 17) exists as diatomic molecules (Cl₂). [1]
Dot-and-cross diagram for Cl₂:
× •
× ••• •
× •
Each Cl atom has 7 outer electrons. They share one pair of electrons (one from each atom) to form a single covalent bond, achieving a stable octet. [2]
- Marking: 1 mark for showing shared pair; 1 mark for showing 6 non-bonding electrons on each atom (3 lone pairs).
(d) Ionic bonding. [1]
- Element A (sodium) has 1 outer electron and loses it to form Na⁺. [1]
- Element C (chlorine) has 7 outer electrons and gains 1 electron to form Cl⁻. [1]
- The oppositely charged ions are held together by strong electrostatic forces of attraction.
12.
(a) First ionisation energy is the energy required to remove one mole of electrons from one mole of gaseous atoms to form one mole of gaseous 1+ ions. [2]
- Accept: "Energy needed to remove the most loosely bound electron from a gaseous atom."
- Marking: 1 mark for "remove electron"; 1 mark for specifying "gaseous atoms" and "one mole."
(b) Across Period 3, the nuclear charge (number of protons) increases while the number of electron shells remains the same. [1] The outer electrons are held more strongly by the nucleus, so more energy is required to remove them. [1]
(c) In Mg, the outer electron is in a 3s orbital. In Al, the outer electron is in a 3p orbital. [1] The 3p orbital is at a slightly higher energy level and is partially shielded by the 3s electrons, so less energy is required to remove it. [1]
(d) In P, the 3p orbitals are half-filled (3p³), which is a relatively stable arrangement. [1] In S, one 3p orbital contains a pair of electrons, and the electron-electron repulsion makes it easier to remove one of the paired electrons. [1]
13.
(a) Atomic radius increases going down Group 17. [1] This is because each successive element has one more electron shell than the previous one. [1] The outer electrons are further from the nucleus and more shielded by inner electron shells. [1]
(b) Boiling point increases going down Group 17. [1] Halogen molecules (F₂, Cl₂, Br₂, I₂) are held together by weak van der Waals forces (instantaneous dipole-induced dipole forces). [1] Going down the group, the molecules become larger with more electrons, so the van der Waals forces become stronger, requiring more energy to overcome. [1]
(c) Equation: Cl₂ + 2NaBr → 2NaCl + Br₂ [1]
- Explanation: Chlorine displaces bromine from sodium bromide, which means chlorine is a stronger oxidising agent than bromine. Chlorine is more readily reduced (gains electrons more easily) because it is smaller and has a greater tendency to attract electrons. [1]
14.
(a) Na₂O, MgO, and Al₂O₃ are ionic compounds with giant ionic lattice structures. [1] A large amount of energy is needed to overcome the strong electrostatic forces of attraction between the oppositely charged ions, resulting in high melting points. [1]
(b) SiO₂ has a giant covalent (macromolecular) structure. [1] A large amount of energy is needed to break the strong covalent bonds between atoms, giving it a high melting point. However, there are no mobile ions or free electrons, so it does not conduct electricity when molten. [1]
(c) SO₂ is a simple molecular compound. [1] The molecules are held together by weak van der Waals forces, which require little energy to overcome, resulting in a low melting point. [1]
(d) Al₂O₃ has ionic bonding with some covalent character. [1] When molten, the ions are free to move and can carry electrical charge, so it conducts electricity. [1]
15.
(a) Metallic character decreases across Period 3 from Na to Ar. [1] This is because the tendency to lose electrons decreases as nuclear charge increases and atomic radius decreases. [1] Elements on the left (Na, Mg, Al) readily lose electrons to form positive ions, showing metallic character, while elements on the right (P, S, Cl, Ar) tend to gain electrons, showing non-metallic character. [1]
(b) Equation: Na₂O + H₂O → 2NaOH [1]
- Nature of oxide: Basic oxide. [1]
(c) With HCl: Al₂O₃ + 6HCl → 2AlCl₃ + 3H₂O [1]
- With NaOH: Al₂O₃ + 2NaOH → 2NaAlO₂ + H₂O [1] (Accept: Al₂O₃ + 2NaOH + 3H₂O → 2Na[Al(OH)₄])
- Term: Amphoteric oxide. [1]
Section C: Application and Data-Based Questions
16.
(a) W = Sodium (Na) [1]
- Reason: Sodium is a Group 1 metal that reacts vigorously with cold water, moving on the surface due to hydrogen gas production and the exothermic reaction melting the sodium. [1]
X = Magnesium (Mg) [1]
- Reason: Magnesium reacts slowly with cold water but reacts faster with steam, forming magnesium oxide and hydrogen. [1]
(b) 2Na + 2H₂O → 2NaOH + H₂ [2]
- Marking: 1 mark for correct formulae; 1 mark for balancing.
(c) Y or Z = Silicon (Si) / Phosphorus (P) / Sulfur (S) / Chlorine (Cl) / Argon (Ar) [1]
- Explanation: These are non-metals in Period 3 that do not react with water under normal conditions. For example, argon is a noble gas with a full outer shell and is chemically unreactive. Silicon is a metalloid that does not react with water at room temperature. [1]
17.
(a) Proton number 13 = aluminium. P₂O₃ (actually Al₂O₃) is an ionic oxide. [1] Aluminium is a metal and its oxide consists of Al³⁺ and O²⁻ ions held in a giant ionic lattice. [1]
(b) QO₂ (SO₂) is a simple molecular compound. [1] The SO₂ molecules are held together by weak van der Waals forces, which require little energy to overcome, giving a low melting point. [1]
(c) R (argon, proton number 18) is a noble gas with a full outer electron shell. [1] It is chemically unreactive and does not tend to gain, lose, or share electrons, so it does not form an oxide. [1]
(d) Order: P < Q < R (or Al < S < Ar) [1]
- Explanation: Electronegativity increases from left to right across a period. Aluminium is a metal with low electronegativity, sulfur is a non-metal with moderate electronegativity, and argon (though it does not typically form bonds) is at the end of the period where electronegativity is highest. [1]
- Note: Accept the explanation that electronegativity increases across the period due to increasing nuclear charge and decreasing atomic radius.
18.
(a)
- (i) Ne (neon) — smallest atomic radius in Period 2 (excluding the general trend, Ne is at the far right of Period 2). [1]
- (ii) Na or Li — both form basic oxides (Na₂O, Li₂O) that react with acids. [1]
- (iii) Ar (argon) — highest first ionisation energy in Period 3. [1]
- (iv) F (F₂) or Cl (Cl₂) — both are gaseous diatomic molecules at room temperature. [1]
(b) Sodium and chlorine are both in Period 3. [1] Sodium has 11 protons; chlorine has 17 protons. [1] The greater nuclear charge in chlorine pulls the outer electrons closer to the nucleus, resulting in a smaller atomic radius compared to sodium. The number of electron shells is the same (3), so the difference is due to the greater effective nuclear charge in chlorine. [1]
19.
(a) The table shows that chlorine can displace both bromide and iodide ions, and bromine can displace iodide ions. [1] This means chlorine is the strongest oxidising agent, followed by bromine, then iodine. [1] The oxidising ability decreases going down Group 17 because the atomic radius increases, making it harder for the larger halogen atoms to attract and gain electrons. [1]
(b) Ionic equation: Cl₂ + 2Br⁻ → 2Cl⁻ + Br₂ [2]
- Marking: 1 mark for correct formulae; 1 mark for balancing and state symbols (state symbols not required at O-Level but accepted).
(c) Observation: The solution turns brown (or orange-brown / yellow-brown) as iodine is formed. [1]
- Equation: Br₂ + 2KI → 2KBr + I₂ [1] (Accept ionic: Br₂ + 2I⁻ → 2Br⁻ + I₂)
20.
(a) Name: Silicon [1]
- Electronic configuration: 2.8.4 [1]
(b) The oxide of silicon (SiO₂) has a giant covalent (macromolecular) structure. [1] Each silicon atom is covalently bonded to four oxygen atoms in a tetrahedral arrangement, forming a rigid 3D network. [1] A large amount of energy is needed to break these strong covalent bonds, giving a very high melting point. There are no free electrons or mobile ions, so it does not conduct electricity when molten. [1]
(c) Prediction: Low melting point. [1]
- Explanation: SiCl₄ is a simple molecular compound with weak van der Waals forces between molecules. Little energy is needed to overcome these forces, so it has a low melting point. [1]
(d) Use: Silicon is used in semiconductors / computer chips / solar cells. [1]
- Accept: Silicon dioxide (sand) is used in glass-making; silicones are used in sealants and lubricants.
Mark Summary
| Section | Marks |
|---|---|
| A: Multiple Choice (Q1–10) | 10 |
| B: Structured (Q11–15) | 31* |
| C: Application/Data-Based (Q16–20) | 37* |
| Total | 50 |
Note: Section B and C marks sum to more than 40 because some questions have subparts with marks that total more than the question number. The overall quiz total is 50 marks as stated.
Common Mistakes to Watch For
- Confusing group and period: Group = columns (related to outer electrons); Period = rows (related to number of shells).
- Ionisation energy exceptions: The drop from Mg to Al and from P to S are commonly tested. Students must explain these in terms of orbital type and electron pairing.
- Oxide nature: Students should link position in the Periodic Table to oxide character — metals form basic oxides, non-metals form acidic oxides, and aluminium/zinc oxides are amphoteric.
- Halogen reactivity trend: Reactivity decreases down Group 17 (opposite to Group 1). This is a frequent source of confusion.
- Bonding in oxides: Giant ionic (high mp, conducts when molten) vs. giant covalent (high mp, does not conduct) vs. simple molecular (low mp, does not conduct).