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Secondary 4 Pure Chemistry Atomic Structure Bonding Quiz
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Questions
Secondary 4 Pure Chemistry Quiz - Atomic Structure Bonding
Name: ________________________
Class: ________________________
Date: ________________________
Score: _____ / 40
Duration: 45 minutes
Total Marks: 40
Instructions:
- Answer all questions in the spaces provided.
- The number of marks is given in brackets [ ] at the end of each question or part question.
- For calculations, show all working clearly.
- Use the Periodic Table provided where necessary.
- Write chemical equations with state symbols where appropriate.
Section A: Multiple Choice Questions [10 marks]
Answer all questions. Choose the correct option (A, B, C, or D) and write your answer in the box provided.
-
Which of the following statements about the structure of an atom is correct? [1]
- A. The nucleus contains protons and electrons.
- B. The mass of an electron is approximately 1/1840 the mass of a proton.
- C. Neutrons have a positive charge.
- D. The atomic number equals the number of neutrons.
Answer: □
-
An ion X³⁻ has 10 electrons and 8 neutrons. What is the mass number of element X? [1]
- A. 15
- B. 17
- C. 18
- D. 25
Answer: □
-
Which diagram correctly represents the electronic structure of a magnesium ion, Mg²⁺? [1]
- A. 2,8,2
- B. 2,8
- C. 2,8,8
- D. 2,6
Answer: □
-
Element Y is in Group 16 and Period 3 of the Periodic Table. How many valence electrons does an atom of Y have? [1]
- A. 3
- B. 6
- C. 8
- D. 16
Answer: □
-
Which of the following substances contains both ionic and covalent bonds? [1]
- A. Sodium chloride, NaCl
- B. Carbon dioxide, CO₂
- C. Ammonium chloride, NH₄Cl
- D. Hydrogen gas, H₂
Answer: □
-
The melting points of four substances are given below. Which substance is most likely a giant covalent structure? [1]
- A. Substance W: -114 °C
- B. Substance X: 801 °C
- C. Substance Y: 1650 °C
- D. Substance Z: -188 °C
Answer: □
-
Which statement about metallic bonding is correct? [1]
- A. Metal atoms share electrons in fixed pairs between specific atoms.
- B. Metal atoms lose electrons to form a lattice of positive ions in a 'sea of electrons'.
- C. Metallic bonds are directional and form between specific pairs of atoms.
- D. Metals have low electrical conductivity because electrons are tightly held.
Answer: □
-
Diamond and graphite are allotropes of carbon. Which property is the same for both? [1]
- A. Electrical conductivity
- B. Hardness
- C. Melting point
- D. Density
Answer: □
-
A molecule of phosphorus(V) chloride, PCl₅, has which shape? [1]
- A. Tetrahedral
- B. Trigonal pyramidal
- C. Trigonal bipyramidal
- D. Octahedral
Answer: □
-
Which of the following dots-and-crosses diagrams correctly shows the bonding in a water molecule, H₂O? [1]
- A. O with 2 lone pairs, each H sharing 1 electron with O
- B. O with 1 lone pair, each H sharing 2 electrons with O
- C. O with 3 lone pairs, each H sharing 1 electron with O
- D. O with no lone pairs, each H sharing 1 electron with O
Answer: □
Section B: Structured Questions [18 marks]
Answer all questions in the spaces provided.
- The table below shows information about three particles, A, B, and C.
| Particle | Number of protons | Number of neutrons | Number of electrons |
|---|---|---|---|
| A | 11 | 12 | 11 |
| B | 17 | 18 | 18 |
| C | 19 | 20 | 18 |
(a) Identify which particle is a neutral atom. Explain your answer. [2]
(b) Identify which particle is a negative ion. Write its chemical symbol with charge. [2]
(c) Particles B and C have the same number of electrons. What term describes such particles? [1]
- Sodium reacts with chlorine to form sodium chloride.
(a) Draw a 'dots-and-crosses' diagram to show the electron transfer and the electronic structures of the ions formed. Show only outer shell electrons. [3]
<image_placeholder> id: Q12a-fig1 type: diagram linked_question: Q12 description: Dots-and-crosses diagram for NaCl formation showing electron transfer from Na to Cl. Two separate diagrams: (1) Na atom (2,8,1) and Cl atom (2,8,7) before transfer; (2) Na⁺ ion (2,8) with empty outer shell shown as [ ]²⁺ and Cl⁻ ion (2,8,8) with 8 crosses/dots. Use dots for Na electrons, crosses for Cl electrons. labels: Na atom, Cl atom, Na⁺ ion, Cl⁻ ion, electron transfer arrow values: Na: 2,8,1; Cl: 2,8,7; Na⁺: 2,8; Cl⁻: 2,8,8 must_show: Outer shell electrons only, electron transfer arrow, charges on ions, square brackets for ions </image_placeholder>
(b) Explain why sodium chloride has a high melting point. [2]
(c) Solid sodium chloride does not conduct electricity, but molten sodium chloride does. Explain this difference. [2]
- Covalent bonding involves the sharing of electrons.
(a) Draw a 'dots-and-crosses' diagram for a molecule of carbon dioxide, CO₂. Show only outer shell electrons. [2]
<image_placeholder> id: Q13a-fig1 type: diagram linked_question: Q13 description: Dots-and-crosses diagram for CO₂ molecule. Central C atom double bonded to two O atoms. C has 4 valence electrons (dots), each O has 6 valence electrons (crosses). Show 2 shared pairs (4 electrons) in each C=O double bond. No lone pairs on C, two lone pairs on each O. labels: C atom, O atoms, shared electron pairs, lone pairs on O values: C: 4 valence electrons; O: 6 valence electrons each; double bonds must_show: Double bonds, lone pairs on oxygen atoms, correct electron count </image_placeholder>
(b) Carbon dioxide is a gas at room temperature. Explain this in terms of its structure and bonding. [2]
- The diagram below shows the structure of graphite.
<image_placeholder> id: Q14-fig1 type: diagram linked_question: Q14 description: Layered structure of graphite showing hexagonal arrangement of carbon atoms in layers. Each C atom bonded to 3 others in plane. Weak van der Waals forces between layers. Delocalised electrons shown between layers. labels: Carbon atoms, covalent bonds within layer, weak forces between layers, delocalised electrons values: C-C bond length ~1.42 Å, interlayer spacing ~3.35 Å must_show: Hexagonal rings in layers, 3 bonds per carbon, delocalised electrons between layers, interlayer spacing </image_placeholder>
(a) Each carbon atom in graphite is bonded to three other carbon atoms. What type of hybridisation does this suggest for the carbon atoms? [1]
(b) Explain why graphite can conduct electricity. [2]
(c) Graphite is used as a lubricant. Explain this property in terms of its structure. [2]
- Magnesium reacts with oxygen to form magnesium oxide, MgO.
(a) Write a balanced chemical equation, including state symbols, for this reaction. [2]
(b) Magnesium oxide has a giant ionic lattice structure. Draw a diagram to show the arrangement of ions in a small portion of the magnesium oxide lattice. [2]
<image_placeholder> id: Q15b-fig1 type: diagram linked_question: Q15 description: 2D representation of MgO ionic lattice showing alternating Mg²⁺ and O²⁻ ions in a square grid pattern (face-centred cubic projected). Show at least 3×3 ions with correct charges. labels: Mg²⁺ ions, O²⁻ ions values: 1:1 ratio, alternating charges must_show: Alternating positive and negative ions, correct charges, regular lattice arrangement </image_placeholder>
(c) Predict whether magnesium oxide would conduct electricity when solid and when molten. Explain your prediction. [2]
Section C: Free Response / Data-Based Questions [12 marks]
Answer all questions in the spaces provided.
- A student investigates the properties of four unknown substances, W, X, Y, and Z. The results are shown in the table below.
| Substance | Melting point / °C | Electrical conductivity (solid) | Electrical conductivity (molten) | Solubility in water |
|---|---|---|---|---|
| W | 801 | Does not conduct | Conducts | Soluble |
| X | 1650 | Does not conduct | Does not conduct | Insoluble |
| Y | -114 | Does not conduct | Does not conduct | Soluble |
| Z | 1085 | Conducts | Conducts | Insoluble |
(a) Identify the type of structure and bonding for each substance W, X, Y, and Z. [4]
| Substance | Structure and Bonding |
|---|---|
| W | |
| X | |
| Y | |
| Z |
(b) Substance W is sodium chloride. Explain why it conducts electricity when molten but not when solid. [2]
(c) Substance X is silicon dioxide. Draw a diagram to show the arrangement of atoms in a small portion of the silicon dioxide structure. [2]
<image_placeholder> id: Q16c-fig1 type: diagram linked_question: Q16 description: 3D tetrahedral network structure of SiO₂ showing each Si atom bonded to 4 O atoms in tetrahedral arrangement, each O atom bridging 2 Si atoms. Show at least 4 Si atoms and bridging O atoms. labels: Si atoms, O atoms, Si-O-Si bridges, tetrahedral geometry values: Si-O bond length ~1.61 Å, O-Si-O angle ~109.5° must_show: Tetrahedral coordination around Si, bridging oxygen atoms, extended network </image_placeholder>
(d) Substance Z is copper. Explain why copper is malleable and ductile in terms of its metallic bonding. [2]
- The table below shows the electronic configurations of five elements, P, Q, R, S, and T, represented by letters (not their chemical symbols).
| Element | Electronic Configuration |
|---|---|
| P | 2,1 |
| Q | 2,7 |
| R | 2,8,1 |
| S | 2,8,7 |
| T | 2,8,8 |
(a) Which element is a noble gas? [1]
(b) Which two elements would react together to form an ionic compound with formula MX? [1]
(c) Element Q reacts with element R to form a compound. Predict the formula of this compound and draw its 'dots-and-crosses' diagram. Show only outer shell electrons. [3]
Formula: _______________________
<image_placeholder> id: Q17c-fig1 type: diagram linked_question: Q17 description: Dots-and-crosses diagram for ionic compound between Q (2,7) and R (2,8,1). R loses 1 electron to Q. R⁺ ion (2,8) and Q⁻ ion (2,8,8). Use dots for R electrons, crosses for Q electrons. labels: R atom, Q atom, R⁺ ion, Q⁻ ion, electron transfer values: R: 2,8,1; Q: 2,8,7; R⁺: 2,8; Q⁻: 2,8,8 must_show: Electron transfer, correct ion charges, square brackets for ions, outer shell electrons only </image_placeholder>
(d) Elements P and R are in the same group of the Periodic Table. Explain why they have similar chemical properties. [2]
- Ammonium sulfate, (NH₄)₂SO₄, is an ionic compound containing the ammonium ion, NH₄⁺, and the sulfate ion, SO₄²⁻.
(a) The ammonium ion is formed when ammonia (NH₃) reacts with a hydrogen ion (H⁺). Name the type of bond formed between NH₃ and H⁺. [1]
(b) Draw a 'dots-and-crosses' diagram for the ammonium ion, NH₄⁺. Show only outer shell electrons and indicate the coordinate bond. [3]
<image_placeholder> id: Q18b-fig1 type: diagram linked_question: Q18 description: Dots-and-crosses diagram for NH₄⁺ ion. Central N atom with 4 H atoms in tetrahedral arrangement. N has 5 valence electrons (dots), each H has 1 electron (crosses). One N-H bond is a coordinate bond (both electrons from N shown as dots). Overall +1 charge shown. labels: N atom, H atoms, coordinate bond (arrow or both dots), +1 charge values: N: 5 valence electrons; H: 1 electron each; 4 bonding pairs; tetrahedral must_show: 4 N-H bonds, one coordinate bond indicated, tetrahedral arrangement, +1 charge </image_placeholder>
(c) The sulfate ion, SO₄²⁻, has a tetrahedral shape. Draw a 'dots-and-crosses' diagram for the sulfate ion. Show only outer shell electrons. [3]
<image_placeholder> id: Q18c-fig1 type: diagram linked_question: Q18 description: Dots-and-crosses diagram for SO₄²⁻ ion. Central S atom with 4 O atoms in tetrahedral arrangement. S has 6 valence electrons (dots), each O has 6 valence electrons (crosses). Two S=O double bonds and two S-O single bonds with negative charges on the single-bonded O atoms. Overall -2 charge. labels: S atom, O atoms, double bonds, single bonds with negative charges, -2 charge values: S: 6 valence electrons; O: 6 valence electrons each; 2 double bonds, 2 single bonds; formal charges must_show: Tetrahedral arrangement, 2 double bonds, 2 single bonds with negative charges, -2 overall charge </image_placeholder>
(d) Ammonium sulfate dissolves in water to form a solution. Write an equation, with state symbols, to represent this process. [1]
- The diagram below shows the structure of a simple molecular substance, iodine (I₂).
<image_placeholder> id: Q19-fig1 type: diagram linked_question: Q19 description: I₂ molecule showing two iodine atoms joined by a single covalent bond. Each I atom has 3 lone pairs. Weak van der Waals forces between molecules shown as dashed lines in a crystal lattice arrangement. labels: I atoms, covalent bond, lone pairs, van der Waals forces between molecules values: I-I bond length ~2.66 Å, van der Waals distance ~4.3 Å must_show: Single covalent bond, 3 lone pairs per I atom, intermolecular forces between molecules </image_placeholder>
(a) Iodine has a low melting point (114 °C). Explain this in terms of its structure and bonding. [2]
(b) When iodine crystals are heated gently, they sublime. Explain what happens to the particles during sublimation. [2]
(c) Iodine dissolves in organic solvents like hexane but is only slightly soluble in water. Explain this observation. [2]
- The following question is about the Periodic Table and bonding trends.
(a) Describe the trend in bonding type of the oxides of elements across Period 3 (Na to Cl). [3]
(b) Aluminium oxide, Al₂O₃, is amphoteric. Write balanced chemical equations for its reactions with: (i) hydrochloric acid [1] (ii) sodium hydroxide [1]
(c) Silicon dioxide, SiO₂, does not react with water. Explain why, referring to its structure. [2]
End of Quiz
Answers
Secondary 4 Pure Chemistry Quiz - Atomic Structure Bonding (Answer Key)
Total Marks: 40
Section A: Multiple Choice Questions [10 marks]
-
Answer: B [1]
- Explanation: The nucleus contains protons and neutrons, not electrons. Electrons orbit the nucleus. The mass of an electron is approximately 1/1840 (or 1/1836) the mass of a proton. Neutrons are neutral (no charge). The atomic number equals the number of protons, not neutrons.
- Key concept: Subatomic particle properties.
-
Answer: A [1]
- Working: Ion X³⁻ has 10 electrons. Since it has a 3- charge, the neutral atom has 10 - 3 = 7 electrons = 7 protons (atomic number = 7). Mass number = protons + neutrons = 7 + 8 = 15.
- Key concept: Ion charge = protons - electrons; Mass number = protons + neutrons.
-
Answer: B [1]
- Explanation: Mg atomic number = 12, electronic configuration = 2,8,2. Mg²⁺ loses 2 electrons from the outer shell, giving 2,8 (same as neon).
- Key concept: Cation formation by losing outer shell electrons.
-
Answer: B [1]
- Explanation: Group number for main group elements = number of valence electrons. Group 16 → 6 valence electrons. Period 3 indicates 3 electron shells.
- Key concept: Periodic Table group and valence electrons relationship.
-
Answer: C [1]
- Explanation: NH₄Cl contains NH₄⁺ (covalent bonds within the ion, including one coordinate bond) and Cl⁻. The attraction between NH₄⁺ and Cl⁻ is ionic. NaCl is purely ionic. CO₂ and H₂ are purely covalent.
- Key concept: Polyatomic ions contain covalent bonds; ionic compounds form between oppositely charged ions.
-
Answer: C [1]
- Explanation: Giant covalent structures (e.g., diamond, SiO₂) have very high melting points (>1500 °C) due to strong covalent bonds throughout the lattice. Substance Y (1650 °C) fits this. W (-114 °C) is simple molecular. X (801 °C) is giant ionic (NaCl). Z (-188 °C) is simple molecular.
- Key concept: Structure type determines melting point magnitude.
-
Answer: B [1]
- Explanation: Metallic bonding involves a lattice of positive metal ions surrounded by a 'sea of delocalised electrons'. The electrons are not shared in fixed pairs (that's covalent) and metallic bonds are non-directional. Metals conduct electricity well because electrons are mobile.
- Key concept: Metallic bonding model and properties.
-
Answer: C [1]
- Explanation: Both diamond and graphite have giant covalent structures with strong covalent bonds throughout, giving them very high melting points. They differ in electrical conductivity (graphite conducts, diamond doesn't), hardness (diamond is hardest, graphite is soft), and density (diamond ~3.5 g/cm³, graphite ~2.2 g/cm³).
- Key concept: Allotropes share some properties (melting point) but differ in others due to structure.
-
Answer: C [1]
- Explanation: PCl₅ has 5 bonding pairs and 0 lone pairs around the central P atom. According to VSEPR theory, this gives a trigonal bipyramidal shape (AX₅).
- Key concept: VSEPR theory for 5 electron domains.
-
Answer: A [1]
- Explanation: Oxygen has 6 valence electrons. In H₂O, it forms 2 single bonds with H atoms (sharing 2 electrons) and retains 2 lone pairs (4 electrons). Total = 2 bonding pairs + 2 lone pairs = 8 electrons around O.
- Key concept: Dots-and-crosses for simple covalent molecules; octet rule.
Section B: Structured Questions [18 marks]
-
(a) Particle A [1] - It has equal numbers of protons (11) and electrons (11), so it is neutral. [1]
- Marking: 1 mark for identifying A, 1 mark for correct explanation (protons = electrons).
(b) Particle B [1] - It has 17 protons and 18 electrons, giving a net charge of -1. Chemical symbol: Cl⁻ [1]
- Marking: 1 mark for identifying B, 1 mark for correct symbol with charge.
(c) Isoelectronic [1] (or "isoelectronic species/ions")
- Marking: 1 mark for correct term.
-
(a) Dots-and-crosses diagram [3]
- Expected diagram features:
- Left: Na atom (2,8,1) with 1 dot in outer shell; Cl atom (2,8,7) with 7 crosses in outer shell
- Arrow showing transfer of 1 electron (dot) from Na to Cl
- Right: Na⁺ ion in square brackets with 2,8 configuration (no outer electrons shown or empty shell) and + charge; Cl⁻ ion in square brackets with 2,8,8 configuration (8 crosses/dots) and - charge
- Marking: 1 mark for correct Na and Cl atoms before transfer; 1 mark for electron transfer arrow; 1 mark for correct ions with charges and square brackets.
(b) Sodium chloride has a giant ionic lattice structure with strong electrostatic forces of attraction between oppositely charged Na⁺ and Cl⁻ ions. [1] A large amount of energy is required to overcome these strong forces throughout the lattice. [1]
- Marking: 1 mark for identifying giant ionic lattice/strong electrostatic forces; 1 mark for "large amount of energy needed to overcome".
(c) In solid NaCl, ions are held in fixed positions in the lattice and cannot move. [1] In molten NaCl, the lattice is broken and ions are free to move, allowing them to carry charge. [1]
- Marking: 1 mark for "ions fixed in solid"; 1 mark for "ions mobile in molten state".
- Expected diagram features:
-
(a) Dots-and-crosses diagram for CO₂ [2]
- Expected diagram features:
- Central C atom with 4 dots
- Two O atoms, each with 6 crosses
- Two double bonds (4 shared electrons each) between C and each O
- Each O has 2 lone pairs (4 non-bonding electrons)
- No lone pairs on C
- Marking: 1 mark for correct sharing (double bonds); 1 mark for correct lone pairs on O atoms.
(b) CO₂ is a simple molecular substance. [1] It consists of discrete CO₂ molecules held together by weak intermolecular forces (van der Waals forces), which require little energy to overcome. [1]
- Marking: 1 mark for "simple molecular"; 1 mark for "weak intermolecular forces/van der Waals forces".
- Expected diagram features:
-
(a) sp² hybridisation [1]
- Explanation: Each carbon forms 3 sigma bonds in a trigonal planar arrangement (120°), characteristic of sp² hybridisation. The remaining p orbital forms the delocalised π system.
(b) Each carbon atom in graphite has one delocalised electron (from the unhybridised p orbital). [1] These delocalised electrons are free to move between the layers, allowing graphite to conduct electricity. [1]
- Marking: 1 mark for "delocalised electrons"; 1 mark for "free to move/carry charge".
(c) In graphite, carbon atoms are arranged in layers held together by weak van der Waals forces. [1] The layers can slide over each other easily, making graphite soft and slippery, hence a good lubricant. [1]
- Marking: 1 mark for "weak forces between layers"; 1 mark for "layers slide easily".
-
(a) 2Mg(s) + O₂(g) → 2MgO(s) [2]
- Marking: 1 mark for correct formulae and balancing; 1 mark for correct state symbols.
(b) Ionic lattice diagram [2]
- Expected diagram features:
- Alternating Mg²⁺ and O²⁻ ions in a regular square grid (2D projection of face-centred cubic)
- At least 3×3 ions shown
- Correct charges labelled
- Marking: 1 mark for alternating arrangement; 1 mark for correct charges and regular pattern.
(c) Solid MgO: Does not conduct - ions fixed in lattice. [1] Molten MgO: Conducts - lattice broken, ions mobile and can carry charge. [1]
- Marking: 1 mark for each correct prediction with brief explanation.
Section C: Free Response / Data-Based Questions [12 marks]
-
(a) Substance identification [4]
Substance Structure and Bonding W Giant ionic (e.g., NaCl) X Giant covalent (e.g., SiO₂) Y Simple molecular (e.g., ethanol/organic) Z Metallic (e.g., Cu) - Marking: 1 mark each for correct structure/bonding type.
(b) Solid NaCl: ions held in fixed positions in giant ionic lattice, cannot move to carry charge. [1] Molten NaCl: lattice broken, Na⁺ and Cl⁻ ions free to move and carry charge. [1]
- Marking: Same as Q12(c).
(c) SiO₂ structure diagram [2]
- Expected diagram features:
- Tetrahedral arrangement: each Si bonded to 4 O atoms
- Each O bridges 2 Si atoms (Si-O-Si)
- Extended 3D network shown
- Marking: 1 mark for tetrahedral coordination around Si; 1 mark for bridging O atoms/network structure.
(d) In metallic bonding, positive metal ions are arranged in a lattice surrounded by a sea of delocalised electrons. [1] The metallic bonds are non-directional, so layers of ions can slide past each other without breaking the metallic bonding, making copper malleable and ductile. [1]
- Marking: 1 mark for "non-directional bonds/sea of electrons"; 1 mark for "layers slide without breaking bonds".
-
(a) Element T [1] - Electronic configuration 2,8,8 (full outer shell, noble gas configuration).
(b) Elements P and Q (or R and S) [1] - P (2,1) loses 1 electron to form P⁺; Q (2,7) gains 1 electron to form Q⁻. Forms PQ (or RS). Both pairs are Group 1 and Group 17 elements.
(c) Formula: RQ [1] (or QR, but conventionally metal first) Dots-and-crosses diagram [2]
- Expected diagram features:
- R atom (2,8,1) with 1 dot; Q atom (2,8,7) with 7 crosses
- Electron transfer from R to Q
- R⁺ ion (2,8) in square brackets with + charge
- Q⁻ ion (2,8,8) in square brackets with - charge
- Marking: 1 mark for correct formula; 1 mark for atoms before transfer; 1 mark for ions after transfer with charges.
(d) Elements P and R are in the same group (Group 1), so they have the same number of valence electrons (1). [1] Chemical properties depend mainly on valence electrons, so they react similarly (e.g., both lose 1 electron to form +1 ions). [1]
- Marking: 1 mark for "same valence electrons"; 1 mark for "similar chemical properties due to valence electrons".
- Expected diagram features:
-
(a) Coordinate bond (or dative covalent bond) [1]
- Explanation: Both electrons in the N-H bond come from the nitrogen atom (lone pair on NH₃ donated to H⁺).
(b) NH₄⁺ dots-and-crosses diagram [3]
- Expected diagram features:
- Central N with 5 dots; 4 H atoms each with 1 cross
- 4 N-H bonds (tetrahedral)
- One bond shown as coordinate (both electrons as dots, or arrow from N to H)
- Overall +1 charge shown
- Marking: 1 mark for 4 bonding pairs; 1 mark for coordinate bond indicated; 1 mark for tetrahedral arrangement and +1 charge.
(c) SO₄²⁻ dots-and-crosses diagram [3]
- Expected diagram features:
- Central S with 6 dots; 4 O atoms each with 6 crosses
- Tetrahedral arrangement
- 2 S=O double bonds (4 shared electrons each)
- 2 S-O single bonds with negative charges on those O atoms
- Overall -2 charge
- Marking: 1 mark for tetrahedral/4 bonds; 1 mark for 2 double + 2 single bonds with charges; 1 mark for -2 overall charge.
(d) (NH₄)₂SO₄(s) → 2NH₄⁺(aq) + SO₄²⁻(aq) [1]
- Marking: 1 mark for correct formulae, balancing, and state symbols.
-
(a) Iodine is a simple molecular substance (I₂ molecules). [1] The molecules are held together by weak van der Waals forces, which require little energy to overcome, resulting in a low melting point. [1]
- Marking: 1 mark for "simple molecular"; 1 mark for "weak van der Waals forces".
(b) During sublimation, solid iodine gains heat energy. [1] The I₂ molecules vibrate more vigorously until they have enough energy to overcome the weak intermolecular forces and escape directly into the gas phase, bypassing the liquid phase. [1]
- Marking: 1 mark for "overcome intermolecular forces"; 1 mark for "solid to gas directly/no liquid phase".
(c) Iodine is a non-polar molecule. [1] It dissolves in non-polar organic solvents (like hexane) due to similar intermolecular forces (van der Waals), but is only slightly soluble in polar water because water's hydrogen bonding is much stronger and not easily disrupted by non-polar I₂. [1]
- Marking: 1 mark for "non-polar/like dissolves like"; 1 mark for "water is polar/H-bonding".
-
(a) Trend across Period 3 oxides: [3]
- Na₂O, MgO: Giant ionic (basic oxides)
- Al₂O₃: Giant ionic with covalent character (amphoteric)
- SiO₂: Giant covalent (acidic oxide)
- P₄O₁₀, SO₃, Cl₂O₇: Simple molecular (acidic oxides)
- Marking: 1 mark for ionic → covalent trend; 1 mark for basic → amphoteric → acidic trend; 1 mark for giant → simple molecular trend.
(b) (i) Al₂O₃(s) + 6HCl(aq) → 2AlCl₃(aq) + 3H₂O(l) [1] (ii) Al₂O₃(s) + 2NaOH(aq) + 3H₂O(l) → 2NaAl(OH)₄(aq) [1]
- Alternative for (ii): Al₂O₃ + 2NaOH → 2NaAlO₂ + H₂O (also accepted)
- Marking: 1 mark each for correct balanced equation with state symbols.
(c) SiO₂ has a giant covalent structure with strong Si-O bonds throughout a 3D network. [1] Water molecules cannot break these strong covalent bonds to react with SiO₂, and SiO₂ has no ionic charges or polar sites to interact with water. [1]
- Marking: 1 mark for "giant covalent/strong Si-O bonds"; 1 mark for "water cannot break bonds/no reaction".
Total: 40 marks
Common Mistakes to Watch:
- Forgetting state symbols in equations
- Not using square brackets for ions in dots-and-crosses diagrams
- Confusing "intermolecular forces" with "covalent bonds" when explaining melting points
- Missing the coordinate bond representation in NH₄⁺
- Not balancing equations correctly
- Confusing giant covalent with giant ionic structures