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Secondary 4 Pure Chemistry Practice Paper 1
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TuitionGoWhere Practice Paper - Pure Chemistry Secondary 4
Answer Key & Marking Scheme
Subject: Pure Chemistry (6092)
Topic: Acids, Bases and Salts
Version: 1
Section A: Structured Questions
1.
(a) An acid that is completely ionised / dissociated in water. [1]
(b) Hydrochloric acid is a strong acid and ionises completely to produce a high concentration of ions. Ethanoic acid is a weak acid and ionises partially, producing a lower concentration of ions. Since pH is a measure of concentration, the higher in HCl results in a lower pH. [2]
(1 mark for complete vs partial ionisation, 1 mark for link to concentration/pH)
(c) Test: Add magnesium ribbon / zinc granules / named reactive metal / named carbonate. [1]
Observation with HCl: Vigorous effervescence / faster bubbling. [0.5]
Observation with CH₃COOH: Slow effervescence / slower bubbling. [0.5]
(Alternatively: Measure electrical conductivity. HCl conducts better.) [2]
2.
(a) An oxide that reacts with both acids and bases to form salt and water. [1]
(b) (i) [2]
(1 mark for correct formulae, 1 mark for balancing/states)
(ii)
(Accept ) [2]
(1 mark for correct formulae, 1 mark for balancing/states)
3.
(a) Magnesium oxide / Magnesium carbonate / Magnesium hydroxide. [1]
(Must be insoluble Mg compound)
(b) 1. Add excess base to the acid (warm the acid to speed up reaction). [1]
2. Filter the mixture to remove the unreacted excess base. [1]
3. Heat the filtrate to evaporate some water / until saturated. [1]
4. Allow to cool for crystallisation, then filter, wash with cold water, and dry. [1]
(c) Magnesium hydroxide is insoluble in water, so it cannot be placed in the burette for titration. Titration requires both reactants to be in solution (aqueous). [1]
4.
(a) P: Aluminium ion () [1]
Q: Iron(II) ion () [1]
R: Copper(II) ion () [1]
(b) [1]
(State symbols required)
5.
(a) Iron / Fe. [1]
(b) High pressure favours the side with fewer moles of gas. The forward reaction produces 2 moles of gas from 4 moles of gas. Therefore, high pressure increases the yield of ammonia. [2]
(c) A lower temperature would increase the yield (as the reaction is exothermic) but would decrease the rate of reaction significantly. 450°C is a compromise temperature to ensure a reasonable rate of reaction while maintaining an acceptable yield. [2]
(1 mark for rate argument, 1 mark for compromise/yield argument)
6.
(a) [2]
(b) 1. Effervescence / bubbles of gas produced. [1]
2. The solid (green) disappears / dissolves to form a blue solution. [1]
(c) Moles of mol. [1]
From equation, 1 mol produces 1 mol .
Moles of mol. [1]
Volume = dm³. [1]
Section B: Free-Response Questions
7.
(a) Enzymes in plants work best at specific pH levels. If soil is too acidic or alkaline, nutrient uptake is affected / enzymes denature, reducing crop yield. [1]
(b)
(Or ) [1]
(c) (i) (Ammonia). [1]
(ii) Ammonia is a gas and will escape into the air, leading to a loss of nitrogen fertilizer / reducing the effectiveness of the fertilizer. [2]
(d) (i) [2]
(ii) Calcium carbonate is less corrosive / safer to handle / reacts more slowly (less violent) than calcium hydroxide. [1]
8.
(a) At the start, the concentration of reactants (HCl) is highest. This means there are more reactant particles per unit volume, leading to a higher frequency of effective collisions. [2]
(1 mark for highest concentration, 1 mark for frequency of collisions)
(b) Rate = Change in volume / Change in time
Rate = . [2]
(1 mark for substitution, 1 mark for answer with units)
(c) (i) The curve will be steeper at the beginning (higher initial rate) but will level off at the same final volume (60 ). [2]
(1 mark for steeper initial gradient, 1 mark for same final height)
(ii) Powder has a larger total surface area than chips. This exposes more particles to collisions, increasing the frequency of effective collisions, thus increasing the rate. [2]
(1 mark for surface area, 1 mark for collision frequency)
(d) (i) 30 . [1]
(ii) Halving the concentration halves the number of moles of HCl available. Since CaCO₃ is in excess, HCl is the limiting reagent. Therefore, half the amount of product () is formed. [2]
(1 mark for limiting reagent concept, 1 mark for proportional yield)