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Secondary 4 Elementary Mathematics Vectors Matrices Quiz

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Secondary 4 Elementary Mathematics AI Generated Generated by Gemma 4 31B Updated 2026-06-03

Questions

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Secondary 4 Elementary Mathematics Quiz - Vectors Matrices

Name: ________________________
Class: ________________________
Date: ________________________
Score: ________ / 50

Duration: 60 Minutes
Total Marks: 50
Instructions: Answer all questions. Show all necessary working. Calculators are permitted.


Section A: Matrices (Questions 1–10)

  1. Given matrix A=(3250)A = \begin{pmatrix} 3 & -2 \\ 5 & 0 \end{pmatrix} and matrix B=(1432)B = \begin{pmatrix} 1 & 4 \\ -3 & 2 \end{pmatrix}, find A+BA + B.

    [2 marks]

  2. If M=(4713)M = \begin{pmatrix} 4 & 7 \\ -1 & 3 \end{pmatrix}, find the matrix 3M3M.

    [2 marks]

  3. Given P=(2501)P = \begin{pmatrix} 2 & 5 \\ 0 & -1 \end{pmatrix} and Q=(3241)Q = \begin{pmatrix} 3 & -2 \\ 4 & 1 \end{pmatrix}, calculate PQP - Q.

    [2 marks]

  4. Find the product of (23)(41)\begin{pmatrix} 2 & 3 \end{pmatrix} \begin{pmatrix} 4 \\ -1 \end{pmatrix}.

    [2 marks]

  5. Given R=(1234)R = \begin{pmatrix} 1 & 2 \\ 3 & 4 \end{pmatrix} and S=(0112)S = \begin{pmatrix} 0 & 1 \\ -1 & 2 \end{pmatrix}, find RSRS.

    [3 marks]

  6. Determine if RS=SRRS = SR for the matrices in Question 5. Show your working.

    [3 marks]

  7. Find the value of xx and yy if (x23y)+(4125)=(7318)\begin{pmatrix} x & 2 \\ -3 & y \end{pmatrix} + \begin{pmatrix} 4 & 1 \\ 2 & 5 \end{pmatrix} = \begin{pmatrix} 7 & 3 \\ -1 & 8 \end{pmatrix}.

    [3 marks]

  8. Given A=(2103)A = \begin{pmatrix} 2 & 1 \\ 0 & 3 \end{pmatrix}, find a matrix B=(abcd)B = \begin{pmatrix} a & b \\ c & d \end{pmatrix} such that AB=(1001)AB = \begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix}.

    [4 marks]

  9. A matrix C=(10203040)C = \begin{pmatrix} 10 & 20 \\ 30 & 40 \end{pmatrix} represents the number of apples and oranges sold by two shops. If the price of an apple is \0.50andanorangeisand an orange is$0.80,representthepricesasamatrix, represent the prices as a matrix Pandfindand findPC$ to determine the total revenue for each shop.

    [4 marks]

  10. Solve for the matrix XX in the equation 2X+(1423)=(51007)2X + \begin{pmatrix} 1 & 4 \\ -2 & 3 \end{pmatrix} = \begin{pmatrix} 5 & 10 \\ 0 & 7 \end{pmatrix}.

    [4 marks]


Section B: Vectors (Questions 11–20)

  1. Given vector a=(34)\mathbf{a} = \begin{pmatrix} 3 \\ -4 \end{pmatrix}, find the magnitude a|\mathbf{a}|.

    [2 marks]

  2. If AB=(25)\vec{AB} = \begin{pmatrix} 2 \\ 5 \end{pmatrix} and BC=(13)\vec{BC} = \begin{pmatrix} -1 \\ 3 \end{pmatrix}, find AC\vec{AC}.

    [2 marks]

  3. Given u=(42)\mathbf{u} = \begin{pmatrix} 4 \\ 2 \end{pmatrix} and v=(26)\mathbf{v} = \begin{pmatrix} -2 \\ 6 \end{pmatrix}, find 2u3v2\mathbf{u} - 3\mathbf{v}.


    [3 marks]

  4. Point PP has position vector OP=(52)\vec{OP} = \begin{pmatrix} 5 \\ 2 \end{pmatrix} and point QQ has position vector OQ=(14)\vec{OQ} = \begin{pmatrix} -1 \\ 4 \end{pmatrix}. Find the vector PQ\vec{PQ}.

    [2 marks]

  5. Find the unit vector in the direction of w=(34)\mathbf{w} = \begin{pmatrix} 3 \\ 4 \end{pmatrix}.

    [3 marks]

  6. In triangle OABOAB, OA=a\vec{OA} = \mathbf{a} and OB=b\vec{OB} = \mathbf{b}. MM is the midpoint of ABAB. Express OM\vec{OM} in terms of a\mathbf{a} and b\mathbf{b}.

    [3 marks]

  7. Given XY=3a2b\vec{XY} = 3\mathbf{a} - 2\mathbf{b} and YZ=a+4b\vec{YZ} = \mathbf{a} + 4\mathbf{b}, find XZ\vec{XZ} in terms of a\mathbf{a} and b\mathbf{b}.

    [3 marks]

  8. In a quadrilateral ABCDABCD, AB=u\vec{AB} = \mathbf{u} and AD=v\vec{AD} = \mathbf{v}. If DC=2u\vec{DC} = 2\mathbf{u}, express AC\vec{AC} in terms of u\mathbf{u} and v\mathbf{v}.

    [4 marks]

  9. Point RR lies on the line segment PQPQ such that PR:RQ=1:3PR:RQ = 1:3. Given OP=p\vec{OP} = \mathbf{p} and OQ=q\vec{OQ} = \mathbf{q}, express OR\vec{OR} in terms of p\mathbf{p} and q\mathbf{q}.

    [4 marks]

  10. Given a=(k3)\mathbf{a} = \begin{pmatrix} k \\ 3 \end{pmatrix} and b=(21)\mathbf{b} = \begin{pmatrix} 2 \\ -1 \end{pmatrix}. If a\mathbf{a} and b\mathbf{b} are parallel, find the value of kk.

    [4 marks]

Answers

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Secondary 4 Elementary Mathematics Quiz - Vectors Matrices (Answer Key)

  1. (3+12+4530+2)=(4222)\begin{pmatrix} 3+1 & -2+4 \\ 5-3 & 0+2 \end{pmatrix} = \begin{pmatrix} 4 & 2 \\ 2 & 2 \end{pmatrix} [2 marks]

  2. (3(4)3(7)3(1)3(3))=(122139)\begin{pmatrix} 3(4) & 3(7) \\ 3(-1) & 3(3) \end{pmatrix} = \begin{pmatrix} 12 & 21 \\ -3 & 9 \end{pmatrix} [2 marks]

  3. (235(2)0411)=(1742)\begin{pmatrix} 2-3 & 5-(-2) \\ 0-4 & -1-1 \end{pmatrix} = \begin{pmatrix} -1 & 7 \\ -4 & -2 \end{pmatrix} [2 marks]

  4. (2×4)+(3×1)=83=5(2 \times 4) + (3 \times -1) = 8 - 3 = 5 [2 marks]

  5. RS=((10+21)(11+22)(30+41)(31+42))=(25411)RS = \begin{pmatrix} (1\cdot 0 + 2\cdot -1) & (1\cdot 1 + 2\cdot 2) \\ (3\cdot 0 + 4\cdot -1) & (3\cdot 1 + 4\cdot 2) \end{pmatrix} = \begin{pmatrix} -2 & 5 \\ -4 & 11 \end{pmatrix} [3 marks]

  6. SR=((01+13)(02+14)(11+23)(12+24))=(3456)SR = \begin{pmatrix} (0\cdot 1 + 1\cdot 3) & (0\cdot 2 + 1\cdot 4) \\ (-1\cdot 1 + 2\cdot 3) & (-1\cdot 2 + 2\cdot 4) \end{pmatrix} = \begin{pmatrix} 3 & 4 \\ 5 & 6 \end{pmatrix}. Since RSSRRS \neq SR, they are not equal. [3 marks]

  7. x+4=7x=3x + 4 = 7 \Rightarrow x = 3; y+5=8y=3y + 5 = 8 \Rightarrow y = 3. [3 marks]

  8. Let B=(abcd)B = \begin{pmatrix} a & b \\ c & d \end{pmatrix}. 2a+c=12a + c = 1, 2b+3d=02b + 3d = 0, 0a+3c=00a + 3c = 0, 0b+3d=10b + 3d = 1. From 3c=0,c=03c = 0, c = 0. Then 2a=1a=0.52a = 1 \Rightarrow a = 0.5. From 3d=1,d=1/33d = 1, d = 1/3. Then 2b+3(1/3)=02b=1b=0.52b + 3(1/3) = 0 \Rightarrow 2b = -1 \Rightarrow b = -0.5. B=(0.50.501/3)B = \begin{pmatrix} 0.5 & -0.5 \\ 0 & 1/3 \end{pmatrix} [4 marks]

  9. P=(0.50.8)P = \begin{pmatrix} 0.5 & 0.8 \end{pmatrix}. PC=(0.50.8)(10203040)=((5+24)(10+32))=(2942)PC = \begin{pmatrix} 0.5 & 0.8 \end{pmatrix} \begin{pmatrix} 10 & 20 \\ 30 & 40 \end{pmatrix} = \begin{pmatrix} (5+24) & (10+32) \end{pmatrix} = \begin{pmatrix} 29 & 42 \end{pmatrix}. Revenue: Shop 1 = \29,Shop2=, Shop 2 = $42$. [4 marks]

  10. 2X=(511040(2)73)=(4624)X=(2312)2X = \begin{pmatrix} 5-1 & 10-4 \\ 0-(-2) & 7-3 \end{pmatrix} = \begin{pmatrix} 4 & 6 \\ 2 & 4 \end{pmatrix} \Rightarrow X = \begin{pmatrix} 2 & 3 \\ 1 & 2 \end{pmatrix} [4 marks]

  11. a=32+(4)2=9+16=25=5|\mathbf{a}| = \sqrt{3^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5 [2 marks]

  12. AC=AB+BC=(25)+(13)=(18)\vec{AC} = \vec{AB} + \vec{BC} = \begin{pmatrix} 2 \\ 5 \end{pmatrix} + \begin{pmatrix} -1 \\ 3 \end{pmatrix} = \begin{pmatrix} 1 \\ 8 \end{pmatrix} [2 marks]

  13. 2(42)3(26)=(84)(618)=(1414)2\begin{pmatrix} 4 \\ 2 \end{pmatrix} - 3\begin{pmatrix} -2 \\ 6 \end{pmatrix} = \begin{pmatrix} 8 \\ 4 \end{pmatrix} - \begin{pmatrix} -6 \\ 18 \end{pmatrix} = \begin{pmatrix} 14 \\ -14 \end{pmatrix} [3 marks]

  14. PQ=OQOP=(14)(52)=(62)\vec{PQ} = \vec{OQ} - \vec{OP} = \begin{pmatrix} -1 \\ 4 \end{pmatrix} - \begin{pmatrix} 5 \\ 2 \end{pmatrix} = \begin{pmatrix} -6 \\ 2 \end{pmatrix} [2 marks]

  15. w=32+42=5|\mathbf{w}| = \sqrt{3^2 + 4^2} = 5. Unit vector = 15(34)=(0.60.8)\frac{1}{5} \begin{pmatrix} 3 \\ 4 \end{pmatrix} = \begin{pmatrix} 0.6 \\ 0.8 \end{pmatrix} [3 marks]

  16. AB=ba\vec{AB} = \mathbf{b} - \mathbf{a}. AM=12(ba)\vec{AM} = \frac{1}{2}(\mathbf{b} - \mathbf{a}). OM=OA+AM=a+12b12a=12a+12b\vec{OM} = \vec{OA} + \vec{AM} = \mathbf{a} + \frac{1}{2}\mathbf{b} - \frac{1}{2}\mathbf{a} = \frac{1}{2}\mathbf{a} + \frac{1}{2}\mathbf{b} [3 marks]

  17. XZ=XY+YZ=(3a2b)+(a+4b)=4a+2b\vec{XZ} = \vec{XY} + \vec{YZ} = (3\mathbf{a} - 2\mathbf{b}) + (\mathbf{a} + 4\mathbf{b}) = 4\mathbf{a} + 2\mathbf{b} [3 marks]

  18. AC=AB+BC\vec{AC} = \vec{AB} + \vec{BC}. Since DC=2u\vec{DC} = 2\mathbf{u} and ABCDABCD is a quad, BC=BA+AD+DC\vec{BC} = \vec{BA} + \vec{AD} + \vec{DC} is not necessarily true unless it's a parallelogram. Correct path: AC=AB+BC\vec{AC} = \vec{AB} + \vec{BC}. If BC\vec{BC} is not given, we use AC=AD+DC=v+2u\vec{AC} = \vec{AD} + \vec{DC} = \mathbf{v} + 2\mathbf{u} (assuming DD is the vertex). Wait, AC=AB+BC\vec{AC} = \vec{AB} + \vec{BC}. If DC=2u\vec{DC} = 2\mathbf{u}, then CD=2u\vec{CD} = -2\mathbf{u}. AC=AD+DC=v+2u\vec{AC} = \vec{AD} + \vec{DC} = \mathbf{v} + 2\mathbf{u} [4 marks]

  19. PR=14PQ=14(qp)\vec{PR} = \frac{1}{4}\vec{PQ} = \frac{1}{4}(\mathbf{q} - \mathbf{p}). OR=OP+PR=p+14q14p=34p+14q\vec{OR} = \vec{OP} + \vec{PR} = \mathbf{p} + \frac{1}{4}\mathbf{q} - \frac{1}{4}\mathbf{p} = \frac{3}{4}\mathbf{p} + \frac{1}{4}\mathbf{q} [4 marks]

  20. Parallel vectors: a=kb\mathbf{a} = k\mathbf{b}. (k3)=m(21)3=m(1)m=3\begin{pmatrix} k \\ 3 \end{pmatrix} = m \begin{pmatrix} 2 \\ -1 \end{pmatrix} \Rightarrow 3 = m(-1) \Rightarrow m = -3. Then k=(3)(2)=6k = (-3)(2) = -6. [4 marks]