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Secondary 4 Elementary Mathematics Numbers Ratio Proportion Quiz

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Questions

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Secondary 4 Elementary Mathematics Quiz - Numbers Ratio Proportion

Name: _________________________ Class: _________________________ Date: _________________________ Score: ______ / 40

Duration: 45 minutes Total Marks: 40

Instructions:

  • Answer ALL questions.
  • Show all working clearly.
  • Give non-exact answers correct to 3 significant figures unless stated otherwise.
  • Calculators are allowed.
  • Marks are indicated in brackets.

Section A: Short Answer (10 marks)

Answer all questions in the spaces provided.

1. Express 3.45×1043.45 \times 10^{-4} as an ordinary decimal.

[1 mark]

Answer: _________________________


2. Simplify 12a5b23a2b3\dfrac{12a^5b^{-2}}{3a^2b^3}, giving your answer with positive indices.

[2 marks]

Answer: _________________________


3. Evaluate 642364^{\frac{2}{3}}.

[1 mark]

Answer: _________________________


4. The ratio of boys to girls in a school is 5:75:7. If there are 420 girls, find the total number of students in the school.

[2 marks]

Answer: _________________________


5. A map is drawn to a scale of 1:250001:25000. Two towns are 8.4 cm apart on the map. Find the actual distance between the towns in kilometres.

[2 marks]

Answer: _________________________ km


6. Divide 840intheratio840 in the ratio 3:5:6$.

[2 marks]

Answer: $_________________________


Section B: Structured Questions (18 marks)

Show all working clearly.

7. (a) Express 0.00000560.0000056 in standard form.

[1 mark]

Answer: _________________________

(b) Evaluate 4.8×1071.2×102\dfrac{4.8 \times 10^7}{1.2 \times 10^{-2}}, giving your answer in standard form.

[2 marks]

Answer: _________________________


8. The cost of a meal is \72beforeGST.GSTischargedatbefore GST. GST is charged at9%$.

(a) Calculate the amount of GST payable.

[1 mark]

Answer: \_________________________$

(b) Find the total cost of the meal including GST.

[1 mark]

Answer: \_________________________$

(c) A service charge of 10%10\% is added to the pre-GST cost. Calculate the final total including both service charge and GST.

[2 marks]

Answer: \_________________________$


9. A machine produces 240 components in 5 hours.

(a) Find the rate of production in components per hour.

[1 mark]

Answer: _________________________ components per hour

(b) How many components can the machine produce in 8 hours at the same rate?

[1 mark]

Answer: _________________________ components

(c) How long would it take to produce 600 components at this rate? Give your answer in hours and minutes.

[2 marks]

Answer: _________________________


10. The value of a car depreciates by 15%15\% each year. The car was bought for \45000$.

(a) Calculate the value of the car after 1 year.

[1 mark]

Answer: \_________________________$

(b) Calculate the value of the car after 2 years.

[2 marks]

Answer: \_________________________$

(c) Find the percentage decrease in value over the 2 years.

[2 marks]

Answer: _________________________ %\%


11. yy is inversely proportional to the square of xx. When x=4x = 4, y=9y = 9.

(a) Find an equation connecting yy and xx.

[2 marks]

Answer: _________________________

(b) Find the value of yy when x=6x = 6.

[1 mark]

Answer: _________________________


Section C: Problem Solving (12 marks)

Show all working and reasoning clearly.

12. A sum of money is divided among Ali, Ben, and Chen in the ratio 2:3:52:3:5. Ben receives \180$ more than Ali.

(a) Find the total sum of money.

[3 marks]

Answer: \_________________________$

(b) Chen gives 20%20\% of his share to charity. How much does Chen have left?

[2 marks]

Answer: \_________________________$


13. The population of a town is 4800048000. The population increases by 8%8\% in the first year and then decreases by 5%5\% in the second year.

(a) Find the population after the first year.

[1 mark]

Answer: _________________________

(b) Find the population after the second year.

[2 marks]

Answer: _________________________

(c) Calculate the overall percentage change in population over the two years.

[2 marks]

Answer: _________________________ %\%


14. A rectangle has length ll cm and width ww cm. The length is increased by 20%20\% and the width is decreased by 10%10\%.

(a) Express the new length and new width in terms of ll and ww.

[1 mark]

Answer: New length = _________________________ New width = _________________________

(b) Find the percentage change in the area of the rectangle.

[2 marks]

Answer: _________________________ %\%


15. Three partners invest in a business in the ratio 4:5:74:5:7. The total profit for the year is \96000$.

(a) How much profit does each partner receive?

[2 marks]

Answer: Partner 1: \Partner2:Partner 2:$Partner3:Partner 3:$_________________________$

(b) The partner with the largest share reinvests 35%35\% of their profit. How much do they reinvest?

[1 mark]

Answer: \_________________________$


16. A car travels 180 km on 15 litres of petrol.

(a) Express the fuel consumption in km per litre.

[1 mark]

Answer: _________________________ km/litre

(b) How far can the car travel on 22 litres of petrol?

[1 mark]

Answer: _________________________ km

(c) If the price of petrol is \2.40$ per litre, find the cost of petrol for a journey of 420 km.

[2 marks]

Answer: \_________________________$


17. PP is directly proportional to the cube of QQ. When Q=2Q = 2, P=40P = 40.

(a) Find the formula connecting PP and QQ.

[2 marks]

Answer: _________________________

(b) Find PP when Q=5Q = 5.

[1 mark]

Answer: _________________________

(c) Find QQ when P=1080P = 1080.

[2 marks]

Answer: _________________________


18. A shop offers a discount of 25%25\% on all items during a sale. A customer buys a jacket with a marked price of \160andapairofshoeswithamarkedpriceofand a pair of shoes with a marked price of$90$.

(a) Calculate the sale price of the jacket.

[1 mark]

Answer: \_________________________$

(b) Calculate the total amount the customer pays for both items.

[1 mark]

Answer: \_________________________$

(c) The shop makes a profit of 20%20\% on the cost price of the jacket even after the discount. Find the cost price of the jacket.

[2 marks]

Answer: \_________________________$


19. A solution contains acid and water in the ratio 3:83:8. There is 480 ml of water in the solution.

(a) Find the amount of acid in the solution.

[1 mark]

Answer: _________________________ ml

(b) Find the total volume of the solution.

[1 mark]

Answer: _________________________ ml

(c) How much water must be added to change the ratio of acid to water to 1:41:4?

[2 marks]

Answer: _________________________ ml


20. The density of a substance is given by the formula Density=MassVolume\text{Density} = \dfrac{\text{Mass}}{\text{Volume}}. A block of metal has a mass of 2.4 kg and a volume of 300 cm³.

(a) Calculate the density of the metal in g/cm³.

[1 mark]

Answer: _________________________ g/cm³

(b) Another block of the same metal has a mass of 6 kg. Find its volume.

[1 mark]

Answer: _________________________ cm³

(c) The metal is an alloy of copper and zinc in the ratio 7:37:3 by mass. Find the mass of copper in the 2.4 kg block.

[2 marks]

Answer: _________________________ kg


END OF QUIZ

Answers

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Secondary 4 Elementary Mathematics Quiz - Numbers Ratio Proportion

ANSWER KEY AND MARKING SCHEME

Total Marks: 40


Section A: Short Answer (10 marks)

1. Express 3.45×1043.45 \times 10^{-4} as an ordinary decimal. [1 mark]

Answer: 0.0003450.000345

Marking: 1 mark for correct answer.


2. Simplify 12a5b23a2b3\dfrac{12a^5b^{-2}}{3a^2b^3}, giving your answer with positive indices. [2 marks]

Answer: 4a3b5\dfrac{4a^3}{b^5}

Working: 12a5b23a2b3=4a52b23=4a3b5=4a3b5\dfrac{12a^5b^{-2}}{3a^2b^3} = 4a^{5-2}b^{-2-3} = 4a^3b^{-5} = \dfrac{4a^3}{b^5}

Marking: 1 mark for correct coefficient and a3a^3; 1 mark for correct handling of bb with positive index. Accept equivalent forms.


3. Evaluate 642364^{\frac{2}{3}}. [1 mark]

Answer: 1616

Working: 6423=(6413)2=42=1664^{\frac{2}{3}} = (64^{\frac{1}{3}})^2 = 4^2 = 16

Marking: 1 mark for correct answer.


4. The ratio of boys to girls in a school is 5:75:7. If there are 420 girls, find the total number of students in the school. [2 marks]

Answer: 720720

Working: 77 parts =420= 420 girls 11 part =60= 60 Total parts =5+7=12= 5 + 7 = 12 Total students =12×60=720= 12 \times 60 = 720

Marking: 1 mark for finding value of 1 part; 1 mark for correct total.


5. A map is drawn to a scale of 1:250001:25000. Two towns are 8.4 cm apart on the map. Find the actual distance between the towns in kilometres. [2 marks]

Answer: 2.12.1 km

Working: Actual distance =8.4×25000=210000= 8.4 \times 25000 = 210000 cm =2100= 2100 m =2.1= 2.1 km

Marking: 1 mark for correct multiplication; 1 mark for correct conversion to km.


6. Divide \840intheratioin the ratio3:5:6$. [2 marks]

Answer: \180,, $300,, $360$

Working: Total parts =3+5+6=14= 3 + 5 + 6 = 14 11 part =840÷14=60= 840 \div 14 = 60 Shares: 3×60=1803 \times 60 = 180, 5×60=3005 \times 60 = 300, 6×60=3606 \times 60 = 360

Marking: 1 mark for finding value of 1 part; 1 mark for all three correct shares.


Section B: Structured Questions (18 marks)

7. (a) Express 0.00000560.0000056 in standard form. [1 mark]

Answer: 5.6×1065.6 \times 10^{-6}

Marking: 1 mark for correct standard form.

(b) Evaluate 4.8×1071.2×102\dfrac{4.8 \times 10^7}{1.2 \times 10^{-2}}, giving your answer in standard form. [2 marks]

Answer: 4.0×1094.0 \times 10^9

Working: 4.81.2×107(2)=4×109\dfrac{4.8}{1.2} \times 10^{7-(-2)} = 4 \times 10^9

Marking: 1 mark for correct coefficient; 1 mark for correct power of 10.


8. The cost of a meal is \72beforeGST.GSTischargedatbefore GST. GST is charged at9%$.

(a) Calculate the amount of GST payable. [1 mark]

Answer: \6.48$

Working: 72×0.09=6.4872 \times 0.09 = 6.48

Marking: 1 mark for correct answer.

(b) Find the total cost of the meal including GST. [1 mark]

Answer: \78.48$

Working: 72+6.48=78.4872 + 6.48 = 78.48

Marking: 1 mark for correct answer.

(c) A service charge of 10%10\% is added to the pre-GST cost. Calculate the final total including both service charge and GST. [2 marks]

Answer: \85.68$

Working: Service charge =72×0.10=7.20= 72 \times 0.10 = 7.20 Subtotal with service =72+7.20=79.20= 72 + 7.20 = 79.20 GST =79.20×0.09=7.128= 79.20 \times 0.09 = 7.128 Total = 79.20 + 7.128 = 86.328 \approx \86.33$

Note: Accept \86.33ifGSTisappliedto(cost+servicecharge).IfGSTisappliedonlytocost,total=if GST is applied to (cost + service charge). If GST is applied only to cost, total =72 + 7.20 + 6.48 = $85.68$. Either interpretation accepted with clear working.

Marking: 1 mark for service charge; 1 mark for correct final total with GST applied appropriately.


9. A machine produces 240 components in 5 hours.

(a) Find the rate of production in components per hour. [1 mark]

Answer: 4848 components per hour

Working: 240÷5=48240 \div 5 = 48

Marking: 1 mark for correct rate.

(b) How many components can the machine produce in 8 hours at the same rate? [1 mark]

Answer: 384384 components

Working: 48×8=38448 \times 8 = 384

Marking: 1 mark for correct answer.

(c) How long would it take to produce 600 components at this rate? Give your answer in hours and minutes. [2 marks]

Answer: 1212 hours 3030 minutes

Working: Time =600÷48=12.5= 600 \div 48 = 12.5 hours =12= 12 hours 3030 minutes

Marking: 1 mark for correct decimal hours; 1 mark for correct conversion to hours and minutes.


10. The value of a car depreciates by 15%15\% each year. The car was bought for \45000$.

(a) Calculate the value of the car after 1 year. [1 mark]

Answer: \38250$

Working: 45000×0.85=3825045000 \times 0.85 = 38250

Marking: 1 mark for correct answer.

(b) Calculate the value of the car after 2 years. [2 marks]

Answer: \32512.50$

Working: 38250×0.85=32512.5038250 \times 0.85 = 32512.50

Marking: 1 mark for method; 1 mark for correct answer.

(c) Find the percentage decrease in value over the 2 years. [2 marks]

Answer: 27.75%27.75\%

Working: Decrease =4500032512.50=12487.50= 45000 - 32512.50 = 12487.50 Percentage decrease =12487.5045000×100%=27.75%= \dfrac{12487.50}{45000} \times 100\% = 27.75\%

Alternatively: (10.852)×100%=(10.7225)×100%=27.75%(1 - 0.85^2) \times 100\% = (1 - 0.7225) \times 100\% = 27.75\%

Marking: 1 mark for correct decrease; 1 mark for correct percentage.


11. yy is inversely proportional to the square of xx. When x=4x = 4, y=9y = 9.

(a) Find an equation connecting yy and xx. [2 marks]

Answer: y=144x2y = \dfrac{144}{x^2}

Working: y=kx2y = \dfrac{k}{x^2} 9=k42=k169 = \dfrac{k}{4^2} = \dfrac{k}{16} k=144k = 144 y=144x2y = \dfrac{144}{x^2}

Marking: 1 mark for correct form; 1 mark for correct constant.

(b) Find the value of yy when x=6x = 6. [1 mark]

Answer: 44

Working: y=14462=14436=4y = \dfrac{144}{6^2} = \dfrac{144}{36} = 4

Marking: 1 mark for correct answer.


Section C: Problem Solving (12 marks)

12. A sum of money is divided among Ali, Ben, and Chen in the ratio 2:3:52:3:5. Ben receives \180$ more than Ali.

(a) Find the total sum of money. [3 marks]

Answer: \900$

Working: Difference between Ben and Ali =32=1= 3 - 2 = 1 part 11 part = \180TotalpartsTotal parts= 2 + 3 + 5 = 10TotalsumTotal sum= 10 \times 180 = $900$

Marking: 1 mark for identifying 1 part = difference; 1 mark for total parts; 1 mark for correct total.

(b) Chen gives 20%20\% of his share to charity. How much does Chen have left? [2 marks]

Answer: \360$

Working: Chen's share = 5 \times 180 = \900AmountleftAmount left= 900 \times 0.80 = $720$

Correction: Chen's share = 5 × 180 = $900. Amount left = 900 × 0.80 = $720.

Marking: 1 mark for Chen's share; 1 mark for correct remaining amount.


13. The population of a town is 4800048000. The population increases by 8%8\% in the first year and then decreases by 5%5\% in the second year.

(a) Find the population after the first year. [1 mark]

Answer: 5184051840

Working: 48000×1.08=5184048000 \times 1.08 = 51840

Marking: 1 mark for correct answer.

(b) Find the population after the second year. [2 marks]

Answer: 4924849248

Working: 51840×0.95=4924851840 \times 0.95 = 49248

Marking: 1 mark for method; 1 mark for correct answer.

(c) Calculate the overall percentage change in population over the two years. [2 marks]

Answer: 2.6%2.6\% increase

Working: Overall multiplier =1.08×0.95=1.026= 1.08 \times 0.95 = 1.026 Percentage change =(1.0261)×100%=2.6%= (1.026 - 1) \times 100\% = 2.6\% increase

Marking: 1 mark for overall multiplier; 1 mark for correct percentage with indication of increase.


14. A rectangle has length ll cm and width ww cm. The length is increased by 20%20\% and the width is decreased by 10%10\%.

(a) Express the new length and new width in terms of ll and ww. [1 mark]

Answer: New length =1.2l= 1.2l, New width =0.9w= 0.9w

Marking: 1 mark for both correct expressions.

(b) Find the percentage change in the area of the rectangle. [2 marks]

Answer: 8%8\% increase

Working: Original area =lw= lw New area =1.2l×0.9w=1.08lw= 1.2l \times 0.9w = 1.08lw Percentage change =(1.081)×100%=8%= (1.08 - 1) \times 100\% = 8\% increase

Marking: 1 mark for new area expression; 1 mark for correct percentage with indication of increase.


15. Three partners invest in a business in the ratio 4:5:74:5:7. The total profit for the year is \96000$.

(a) How much profit does each partner receive? [2 marks]

Answer: Partner 1: \24000,Partner2:, Partner 2: $30000,Partner3:, Partner 3: $42000$

Working: Total parts =4+5+7=16= 4 + 5 + 7 = 16 11 part =96000÷16=6000= 96000 \div 16 = 6000 Partner 1: 4×6000=240004 \times 6000 = 24000 Partner 2: 5×6000=300005 \times 6000 = 30000 Partner 3: 7×6000=420007 \times 6000 = 42000

Marking: 1 mark for value of 1 part; 1 mark for all three correct shares.

(b) The partner with the largest share reinvests 35%35\% of their profit. How much do they reinvest? [1 mark]

Answer: \14700$

Working: 42000×0.35=1470042000 \times 0.35 = 14700

Marking: 1 mark for correct answer.


16. A car travels 180 km on 15 litres of petrol.

(a) Express the fuel consumption in km per litre. [1 mark]

Answer: 1212 km/litre

Working: 180÷15=12180 \div 15 = 12

Marking: 1 mark for correct answer.

(b) How far can the car travel on 22 litres of petrol? [1 mark]

Answer: 264264 km

Working: 12×22=26412 \times 22 = 264

Marking: 1 mark for correct answer.

(c) If the price of petrol is \2.40$ per litre, find the cost of petrol for a journey of 420 km. [2 marks]

Answer: \84.00$

Working: Petrol needed =420÷12=35= 420 \div 12 = 35 litres Cost = 35 \times 2.40 = \84.00$

Marking: 1 mark for litres needed; 1 mark for correct cost.


17. PP is directly proportional to the cube of QQ. When Q=2Q = 2, P=40P = 40.

(a) Find the formula connecting PP and QQ. [2 marks]

Answer: P=5Q3P = 5Q^3

Working: P=kQ3P = kQ^3 40=k(23)=8k40 = k(2^3) = 8k k=5k = 5 P=5Q3P = 5Q^3

Marking: 1 mark for correct form; 1 mark for correct constant.

(b) Find PP when Q=5Q = 5. [1 mark]

Answer: 625625

Working: P=5(53)=5×125=625P = 5(5^3) = 5 \times 125 = 625

Marking: 1 mark for correct answer.

(c) Find QQ when P=1080P = 1080. [2 marks]

Answer: 66

Working: 1080=5Q31080 = 5Q^3 Q3=216Q^3 = 216 Q=2163=6Q = \sqrt[3]{216} = 6

Marking: 1 mark for setting up equation; 1 mark for correct QQ.


18. A shop offers a discount of 25%25\% on all items during a sale. A customer buys a jacket with a marked price of \160andapairofshoeswithamarkedpriceofand a pair of shoes with a marked price of$90$.

(a) Calculate the sale price of the jacket. [1 mark]

Answer: \120$

Working: 160×0.75=120160 \times 0.75 = 120

Marking: 1 mark for correct answer.

(b) Calculate the total amount the customer pays for both items. [1 mark]

Answer: \187.50$

Working: Shoes sale price =90×0.75=67.50= 90 \times 0.75 = 67.50 Total =120+67.50=187.50= 120 + 67.50 = 187.50

Marking: 1 mark for correct total.

(c) The shop makes a profit of 20%20\% on the cost price of the jacket even after the discount. Find the cost price of the jacket. [2 marks]

Answer: \100$

Working: Sale price =120%= 120\% of cost price 120=1.2×120 = 1.2 \times cost price Cost price = 120 \div 1.2 = \100$

Marking: 1 mark for correct equation; 1 mark for correct cost price.


19. A solution contains acid and water in the ratio 3:83:8. There is 480 ml of water in the solution.

(a) Find the amount of acid in the solution. [1 mark]

Answer: 180180 ml

Working: 88 parts =480= 480 ml 11 part =60= 60 ml Acid =3×60=180= 3 \times 60 = 180 ml

Marking: 1 mark for correct answer.

(b) Find the total volume of the solution. [1 mark]

Answer: 660660 ml

Working: 180+480=660180 + 480 = 660 ml

Marking: 1 mark for correct answer.

(c) How much water must be added to change the ratio of acid to water to 1:41:4? [2 marks]

Answer: 240240 ml

Working: Let xx ml of water be added. New ratio: 180480+x=14\dfrac{180}{480 + x} = \dfrac{1}{4} 180×4=480+x180 \times 4 = 480 + x 720=480+x720 = 480 + x x=240x = 240 ml

Marking: 1 mark for setting up proportion; 1 mark for correct answer.


20. The density of a substance is given by the formula Density=MassVolume\text{Density} = \dfrac{\text{Mass}}{\text{Volume}}. A block of metal has a mass of 2.4 kg and a volume of 300 cm³.

(a) Calculate the density of the metal in g/cm³. [1 mark]

Answer: 88 g/cm³

Working: Mass in grams =2.4×1000=2400= 2.4 \times 1000 = 2400 g Density =2400300=8= \dfrac{2400}{300} = 8 g/cm³

Marking: 1 mark for correct answer with units.

(b) Another block of the same metal has a mass of 6 kg. Find its volume. [1 mark]

Answer: 750750 cm³

Working: Volume =MassDensity=60008=750= \dfrac{\text{Mass}}{\text{Density}} = \dfrac{6000}{8} = 750 cm³

Marking: 1 mark for correct answer with units.

(c) The metal is an alloy of copper and zinc in the ratio 7:37:3 by mass. Find the mass of copper in the 2.4 kg block. [2 marks]

Answer: 1.681.68 kg

Working: Total parts =7+3=10= 7 + 3 = 10 11 part =2.4÷10=0.24= 2.4 \div 10 = 0.24 kg Copper =7×0.24=1.68= 7 \times 0.24 = 1.68 kg

Marking: 1 mark for value of 1 part; 1 mark for correct mass of copper.


END OF ANSWER KEY