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Secondary 4 Combined Science Chemistry Acids Bases Salts Quiz
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Secondary 4 Combined Science Chemistry Quiz - Acids Bases Salts - ANSWER KEY
Total Marks: 40
Section A: Multiple Choice (10 marks)
1. C) Hydrochloric acid Hydrochloric acid (HCl) is a strong acid that fully dissociates in water. Ethanoic, carbonic, and citric acids are weak acids. [1 mark]
2. C) It contains more OH⁻ ions than H⁺ ions. A pH of 9 is alkaline, meaning [OH⁻] > [H⁺]. Alkaline solutions turn red litmus blue, not the reverse. [1 mark]
3. C) Zinc oxide Zinc oxide (ZnO) reacts with both acids and bases, making it amphoteric. Na₂O is basic, SO₂ is acidic, and CO is neutral. [1 mark]
4. C) Precipitation followed by filtration and drying Lead(II) sulfate is insoluble in water. It is best prepared by precipitation (mixing solutions of soluble lead(II) nitrate and sodium sulfate), followed by filtration, washing, and drying. Reaction with sulfuric acid would produce an insoluble layer that stops further reaction. [1 mark]
5. B) 7 Universal indicator turns green in neutral solutions (pH 7). Red indicates strong acid (pH 1-2), blue/purple indicates alkali (pH 10-14). [1 mark]
6. A) Copper(II) nitrate Copper(II) oxide + nitric acid → copper(II) nitrate + water. The salt formed takes its anion from the acid used. [1 mark]
7. B) They turn red litmus paper blue. Acids turn blue litmus paper red. Bases/alkalis turn red litmus paper blue. All other statements are true properties of acids. [1 mark]
8. A) H⁺ + OH⁻ → H₂O The ionic equation for neutralisation represents the reaction between hydrogen ions from the acid and hydroxide ions from the base to form water. Spectator ions are omitted. [1 mark]
9. D) Hydrogen Acid + reactive metal → salt + hydrogen gas. Zinc is above hydrogen in the reactivity series, so it displaces hydrogen from the acid. [1 mark]
10. B) Calcium oxide Calcium oxide (quicklime) is a basic oxide that neutralises acidic soil. Ammonium nitrate is acidic, sodium chloride is neutral, and sulfur dioxide forms acid rain. [1 mark]
Section B: Structured Questions (20 marks)
11. Magnesium carbonate + dilute sulfuric acid
(a) MgCO₃(s) + H₂SO₄(aq) → MgSO₄(aq) + CO₂(g) + H₂O(l) Award 1 mark for correct formulae and balancing, 1 mark for correct state symbols. [2 marks]
(b) Any two of:
- Effervescence / bubbles of gas produced / fizzing
- Solid magnesium carbonate dissolves / disappears
- Colourless solution formed
- Heat released / test tube becomes warm Award 1 mark for each correct observation (max 2). [2 marks]
(c) Magnesium sulfate Accept MgSO₄. [1 mark]
12. pH table analysis
(a) Solution Z (pH 13) is the most alkaline because it has the highest pH value / highest concentration of OH⁻ ions. Award 1 mark for correct identification with reason. [1 mark]
(b) [H⁺] = 10⁻² = 0.01 mol/dm³ For pH 2, [H⁺] = 10⁻ᵖᴴ = 10⁻² mol/dm³. [1 mark]
(c) Neutralisation reaction. Ionic equation: H⁺(aq) + OH⁻(aq) → H₂O(l) Award 1 mark for naming the reaction type, 1 mark for correct ionic equation with state symbols. [2 marks]
13. Preparation of copper(II) sulfate crystals
Method: Reacting an insoluble base (copper(II) oxide) with an acid.
Steps:
- Add excess copper(II) oxide to warm dilute sulfuric acid in a beaker and stir. [1 mark]
- The copper(II) oxide reacts to form copper(II) sulfate solution (blue). [1 mark]
- Filter the mixture to remove unreacted/excess copper(II) oxide. [1 mark]
- Heat the filtrate (copper(II) sulfate solution) to evaporate some water until the solution is saturated / crystals begin to form on cooling / a thin crust forms.
- Allow the saturated solution to cool slowly so crystals form.
- Filter the crystals and dry them between filter paper. [1 mark for steps 4-6 collectively]
Award marks as indicated. Accept any valid sequence that includes: excess solid, filtration, evaporation/crystallisation, and drying. [4 marks]
14. Titration calculation
(a) Moles of H₂SO₄ = concentration × volume (in dm³) = 0.100 × (20.0/1000) = 0.00200 mol Award 1 mark for correct calculation. [1 mark]
(b) From equation: 2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O Mole ratio NaOH : H₂SO₄ = 2 : 1 Moles NaOH = 2 × 0.00200 = 0.00400 mol Award 1 mark for correct use of mole ratio. [1 mark]
(c) Concentration of NaOH = moles / volume (in dm³) = 0.00400 / (25.0/1000) = 0.160 mol/dm³ Award 1 mark for correct method, 1 mark for correct answer with units. [2 marks]
(d) Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol Concentration in g/dm³ = 0.160 × 40 = 6.40 g/dm³ Award 1 mark for correct molar mass, 1 mark for correct answer with units. [2 marks]
Section C: Data-Based Question (10 marks)
15. Solubility investigation
(a)(i) All sodium, potassium, and ammonium salts are soluble. [1 mark]
(a)(ii) All nitrates are soluble. [1 mark]
(b)(i) Pb(NO₃)₂(aq) + 2KI(aq) → PbI₂(s) + 2KNO₃(aq) Award 1 mark for correct formulae and balancing, 1 mark for correct state symbols. [2 marks]
(b)(ii) Lead(II) iodide / PbI₂ [1 mark]
(b)(iii) A bright yellow precipitate is formed. Accept: yellow solid forms / yellow precipitate appears. [1 mark]
(c) The student should mix aqueous barium chloride (or barium nitrate) with aqueous sodium sulfate (or any soluble sulfate). This method (precipitation) is suitable because barium sulfate is insoluble in water, so it will form as a precipitate. The precipitate can be separated by filtration, washed with distilled water to remove soluble impurities, and dried to obtain a pure, dry sample. Award 1 mark for naming two suitable solutions, 1 mark for stating barium sulfate is insoluble, 1 mark for explaining separation by filtration and drying. [3 marks]
16. Ammonia
(a) NH₃(g) + H₂O(l) ⇌ NH₄⁺(aq) + OH⁻(aq) Accept reversible arrow or single arrow. Award 1 mark for correct equation. [1 mark]
(b) Ammonia is a weak base because it only partially dissociates/ionises in water to produce a low concentration of hydroxide (OH⁻) ions. Accept: the equilibrium lies mainly to the left / only a small proportion of ammonia molecules react with water. [1 mark]
(c) 2NH₃ + H₂SO₄ → (NH₄)₂SO₄ Accept: 2NH₃(aq) + H₂SO₄(aq) → (NH₄)₂SO₄(aq). Award 1 mark for correct equation. [1 mark]
(d) Nitrogen and sulfur. Award 1 mark for both elements correctly named. [1 mark]
17. Unknown white solid + HCl → gas that turns limewater milky
(a) Carbon dioxide / CO₂ [1 mark]
(b) Carbonate ion / CO₃²⁻. Carbonates react with acids to produce carbon dioxide gas, which turns limewater milky. Award 1 mark for identifying carbonate, 1 mark for explanation linking gas test to carbonate reaction. [2 marks]
(c) CO₃²⁻(aq) + 2H⁺(aq) → CO₂(g) + H₂O(l) Accept: 2H⁺ + CO₃²⁻ → H₂O + CO₂. Award 1 mark for correct ionic equation. [1 mark]
18. pH of water and effect of CO₂
Pure water has a pH of 7 at 25°C because the concentrations of H⁺ and OH⁻ ions are equal (each 10⁻⁷ mol/dm³) due to the very slight self-ionisation of water. When carbon dioxide dissolves in water, it reacts to form carbonic acid (H₂CO₃), which partially dissociates to produce H⁺ ions. The increased concentration of H⁺ ions lowers the pH below 7. Award 1 mark for explaining pH 7 of pure water, 1 mark for explaining the effect of CO₂ forming an acid. [2 marks]
19. Identifying three unlabelled solutions
Test 1: Add a few drops of each solution to blue litmus paper.
- The solution that turns blue litmus paper red is dilute hydrochloric acid.
Test 2: Add a few drops of each solution to red litmus paper.
- The solution that turns red litmus paper blue is dilute sodium hydroxide solution.
Test 3: The remaining solution that does not change the colour of either litmus paper is distilled water.
Alternative methods accepted:
- Use universal indicator: HCl gives red (pH 1-2), NaOH gives purple (pH 13-14), water gives green (pH 7).
- Add magnesium ribbon: HCl produces effervescence (H₂ gas), NaOH and water show no reaction.
- Add sodium carbonate: HCl produces effervescence (CO₂ gas), NaOH and water show no reaction.
Award 1 mark for each correctly identified solution with test and observation (max 3 marks). [3 marks]
20. Magnesium oxide and sulfur dioxide
(a) Magnesium oxide: basic oxide Sulfur dioxide: acidic oxide Award 1 mark for both correct. [1 mark]
(b) SO₂(g) + H₂O(l) → H₂SO₃(aq) Accept: SO₂ + H₂O → H₂SO₃. Award 1 mark for correct equation. [1 mark]
(c) Magnesium oxide has a giant ionic lattice structure with strong electrostatic forces of attraction between oppositely charged Mg²⁺ and O²⁻ ions throughout the lattice. A large amount of energy is required to overcome these strong ionic bonds, so MgO has a very high melting point. Sulfur dioxide has a simple molecular structure with weak intermolecular forces of attraction (van der Waals' forces) between SO₂ molecules. Only a small amount of energy is required to overcome these weak forces, so SO₂ has a low melting point. Award 1 mark for identifying MgO as giant ionic with strong bonds, 1 mark for identifying SO₂ as simple molecular with weak intermolecular forces, 1 mark for linking structure and bonding to melting points. [3 marks]
END OF ANSWER KEY