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Secondary 4 Combined Science Biology Genetics Inheritance Quiz

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Questions

Secondary 4 Combined Science Biology Quiz - Genetics Inheritance

Name: __________________________
Class: __________________________
Date: __________________________
Score: ________ / 40

Duration: 45 minutes
Total Marks: 40

Instructions:

Answer all questions.
Write your answers in the spaces provided.
For genetic diagrams, clearly show parental genotypes, gametes, and offspring genotypes/phenotypes.
Use standard genetic notation (e.g., capital letter for dominant allele, lowercase for recessive).

Section A: Multiple Choice Questions (Questions 1–5)

Choose the correct answer and write the letter in the box provided.

1. Which of the following best defines the term allele?
A. A section of DNA that codes for a protein.
B. An alternative form of a gene found at the same locus on a chromosome.
C. The physical appearance of an organism.
D. The genetic makeup of an organism.

Answer: [____] [1 mark]

2. In pea plants, the allele for tall height (T) is dominant to the allele for short height (t). A heterozygous tall plant is crossed with a short plant. What is the probability that an offspring will be short?
A. 0%
B. 25%
C. 50%
D. 100%

Answer: [____] [1 mark]

3. Which of the following statements about mitosis is correct?
A. It produces four genetically different daughter cells.
B. It reduces the chromosome number by half.
C. It is involved in the production of gametes.
D. It produces two genetically identical daughter cells.

Answer: [____] [1 mark]

4. A man with blood group A (genotype $I^A I^O$ ) marries a woman with blood group B (genotype $I^B I^O$ ). Which blood groups are possible in their children?
A. A and B only
B. A, B, and O
C. A, B, AB, and O
D. AB and O only

Answer: [____] [1 mark]

5. Haemophilia is a sex-linked recessive condition caused by an allele on the X chromosome. Which of the following genotypes represents a female carrier?
A. $X^H X^H$
B. $X^H X^h$
C. $X^h X^h$
D. $X^H Y$

Answer: [____] [1 mark]

Section B: Structured Questions (Questions 6–15)

6. Cystic fibrosis is a genetic disorder caused by a recessive allele ( $f$ ). The normal allele is dominant ( $F$ ).
Two parents who do not have cystic fibrosis have a child with the disorder.

(a) State the genotype of the child.
_________________________________________________________________________ [1]

(b) State the genotypes of the parents.
_________________________________________________________________________ [1]

_________________________________________________________________________ [2]

7. The diagram below shows a pair of homologous chromosomes.

Image pending generation for this question.

      Chromosome 1          Chromosome 2
      -----------           -----------
      |    A    |           |    a    |
      -----------           -----------
      |    B    |           |    b    |
      -----------           -----------

(a) Define the term locus.
_________________________________________________________________________ [1]

(b) If allele A codes for brown eyes and allele a codes for blue eyes, which allele is dominant if the individual has brown eyes?
_________________________________________________________________________ [1]

_________________________________________________________________________ [2]

8. In humans, the ability to roll the tongue is controlled by a dominant allele ( $R$ ). Non-rolling is recessive ( $r$ ).
A man who is homozygous dominant for tongue rolling marries a woman who cannot roll her tongue.

(a) Complete the genetic diagram below to show the possible genotypes and phenotypes of their offspring.

Parental Phenotypes: Tongue Roller x Non-Roller
Parental Genotypes: _____________ _____________

Gametes: _____________ _____________

Offspring Genotypes: _____________________________

Offspring Phenotypes: _____________________________ [4]

(b) What is the probability that their first child will be a non-roller?
_________________________________________________________________________ [1]

9. Sickle cell anaemia is caused by a mutation in the gene for haemoglobin.
Allele $H^A$ = Normal haemoglobin (dominant)
Allele $H^S$ = Sickle cell haemoglobin (recessive)

Individuals with genotype $H^S H^S$ have sickle cell anaemia. Individuals with genotype $H^A H^S$ are carriers and have sickle cell trait (mild symptoms).

(a) Two carriers ( $H^A H^S$ ) have a child. Calculate the probability that the child will have sickle cell anaemia. Show your working.

_________________________________________________________________________ [3]

(b) Suggest why the sickle cell allele is more common in regions where malaria is prevalent.

_________________________________________________________________________ [2]

10. The flowchart below shows the process of protein synthesis.

DNA $\rightarrow$ Process X $\rightarrow$ mRNA $\rightarrow$ Process Y $\rightarrow$ Protein

(a) Name Process X.
_________________________________________________________________________ [1]

(b) Name Process Y.
_________________________________________________________________________ [1]

(c) State where in the cell Process Y occurs.
_________________________________________________________________________ [1]

11. Colour blindness is a sex-linked recessive trait.
Let $X^N$ = Normal vision allele
Let $X^n$ = Colour blindness allele

A colour-blind man marries a woman who is homozygous for normal vision.

(a) State the genotype of the father.
_________________________________________________________________________ [1]

(b) State the genotype of the mother.
_________________________________________________________________________ [1]

Parental Genotypes: _____________ x _____________
Gametes: _____________ _____________
Offspring Genotypes: _____________________________
Offspring Phenotypes: _____________________________ [4]

(d) What is the probability that a daughter from this couple will be a carrier?
_________________________________________________________________________ [1]

12. A species of flower has two alleles for petal colour: Red ( $R$ ) and White ( $W$ ). These alleles show codominance.
Heterozygous plants ( $RW$ ) have pink flowers.

(a) Define codominance.

_________________________________________________________________________ [2]

(b) A pink-flowered plant is crossed with a white-flowered plant.
Predict the phenotypic ratio of the offspring. Show your genetic diagram.

_________________________________________________________________________ [4]

13. Down syndrome is a condition caused by non-disjunction during meiosis.

(a) Explain what is meant by non-disjunction.

_________________________________________________________________________ [2]

(b) State the normal number of chromosomes in a human gamete and in a human somatic cell.
Gamete: _______
Somatic Cell: _______ [2]

14. In a certain breed of cattle, the allele for black coat colour ( $B$ ) is dominant to the allele for red coat colour ( $b$ ).
A farmer wants to determine if a black bull is homozygous ( $BB$ ) or heterozygous ( $Bb$ ).

(a) Name the type of cross used to determine the genotype of the bull.
_________________________________________________________________________ [1]

(b) Describe the cross the farmer should perform and the expected results if the bull is heterozygous.

_________________________________________________________________________ [3]

15. Mutations are changes in the DNA sequence.

(a) State one factor that can increase the rate of mutation.
_________________________________________________________________________ [1]

(b) Explain why most mutations in somatic cells are not passed on to offspring.

_________________________________________________________________________ [2]

Section C: Free Response Questions (Questions 16–20)

16. Explain the relationship between DNA, genes, and chromosomes.

_________________________________________________________________________ [3]

17. Describe the structure of a DNA molecule. Include details about the backbone and base pairing.

_________________________________________________________________________ [4]

18. Albinism is a recessive condition where individuals lack pigment in their skin, hair, and eyes.
Two parents with normal pigmentation have an albino child.

(a) Deduce the genotypes of the parents. Use $A$ for the normal allele and $a$ for the albino allele.
_________________________________________________________________________ [1]

(b) The parents plan to have another child. What is the probability that this child will have normal pigmentation?
_________________________________________________________________________ [1]

_________________________________________________________________________ [3]

19. Compare and contrast mitosis and meiosis. Give two differences and one similarity.

Difference 1:

_________________________________________________________________________ [2]

Difference 2:

_________________________________________________________________________ [2]

Similarity:
_________________________________________________________________________ [1]

20. A gene codes for the production of insulin. A mutation occurs in this gene.

(a) Explain how this mutation could affect the structure of the insulin protein.

_________________________________________________________________________ [3]

(b) Suggest how this change in structure might affect the function of insulin.

_________________________________________________________________________ [2]

*** End of Quiz ***

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Answers

Secondary 4 Combined Science Biology Quiz - Genetics Inheritance (Answer Key)

Total Marks: 40

Section A: Multiple Choice Questions

1. B
Explanation: An allele is an alternative form of a gene at the same locus. A is a gene, C is phenotype, D is genotype.

2. C
Explanation: Cross $Tt \times tt$ . Gametes: $T, t$ and $t, t$ . Offspring: $Tt, Tt, tt, tt$ . 2 out of 4 are $tt$ (short). Probability = 50%.

3. D
Explanation: Mitosis produces two genetically identical daughter cells for growth and repair. Meiosis produces four genetically different gametes.

4. C
Explanation: Cross $I^A I^O \times I^B I^O$ . Gametes: $(I^A, I^O)$ and $(I^B, I^O)$ . Offspring: $I^A I^B$ (AB), $I^A I^O$ (A), $I^B I^O$ (B), $I^O I^O$ (O). All four blood groups are possible.

5. B
Explanation: A carrier has one normal allele and one recessive allele but does not show the disease. Females have two X chromosomes. $X^H X^h$ is a carrier. $X^h X^h$ is affected.

Section B: Structured Questions

6.
(a) $ff$ [1]
(b) $Ff$ and $Ff$ [1]
(c) The parents are heterozygous ( $Ff$ ). The dominant allele ( $F$ ) masks the effect of the recessive allele ( $f$ ), so they produce enough functional protein to be healthy. [2]

7.
(a) The specific position of a gene on a chromosome. [1]
(b) Allele A (brown) is dominant. [1]
(c) They are the same length, carry the same genes at the same loci, and pair up during meiosis. One comes from the mother, one from the father. [2]

8.
(a)
Parental Genotypes: $RR$ x $rr$ [1]
Gametes: $R$ ; $r$ [1]
Offspring Genotypes: All $Rr$ [1]
Offspring Phenotypes: All Tongue Rollers [1]
(b) 0% [1]

9.
(a)
Parents: $H^A H^S \times H^A H^S$
Gametes: $H^A, H^S$ and $H^A, H^S$
Offspring: $H^A H^A$ (Normal), $H^A H^S$ (Carrier), $H^A H^S$ (Carrier), $H^S H^S$ (Anaemia)
Probability of $H^S H^S$ = 1/4 or 25% [3]
(b) Carriers ( $H^A H^S$ ) have some resistance to malaria. In malaria-prone areas, carriers are more likely to survive and reproduce than those with normal haemoglobin (who may die from malaria) or those with sickle cell anaemia (who may die from the disease). This maintains the allele in the population. [2]

10.
(a) Transcription [1]
(b) Translation [1]
(c) Ribosome (in the cytoplasm) [1]

11.
(a) $X^n Y$ [1]
(b) $X^N X^N$ [1]
(c)
Parental Genotypes: $X^n Y \times X^N X^N$
Gametes: $X^n, Y$ ; $X^N$
Offspring Genotypes: $X^N X^n$ (Female), $X^N Y$ (Male)
Offspring Phenotypes: All daughters are carriers (normal vision); All sons have normal vision. [4]
(d) 100% (All daughters are $X^N X^n$ ) [1]

12.
(a) Both alleles are expressed in the phenotype of the heterozygote. Neither is dominant or recessive. [2]
(b)
Parents: $RW$ (Pink) x $WW$ (White)
Gametes: $R, W$ ; $W$
Offspring: $RW$ (Pink), $WW$ (White)
Phenotypic Ratio: 1 Pink : 1 White [4]

13.
(a) The failure of homologous chromosomes (in Meiosis I) or sister chromatids (in Meiosis II) to separate properly. [2]
(b) Gamete: 23 [1]
Somatic Cell: 46 [1]

14.
(a) Test Cross [1]
(b) Cross the black bull with a red cow (homozygous recessive, $bb$ ). If the bull is heterozygous ( $Bb$ ), approximately 50% of the offspring will be black ( $Bb$ ) and 50% will be red ( $bb$ ). If any red offspring are produced, the bull must be heterozygous. [3]

15.
(a) Ionising radiation (e.g., X-rays, UV light) or chemical mutagens (e.g., tar in cigarette smoke). [1]
(b) Somatic cells are body cells, not gametes (sex cells). Only mutations in gametes can be passed to offspring during fertilisation. [2]

Section C: Free Response Questions

16.

DNA is the molecule that carries genetic information. [1]
A gene is a specific sequence of DNA bases that codes for a protein. [1]
Chromosomes are structures made of DNA wound around proteins (histones), found in the nucleus. [1]

17.

DNA is a double helix (twisted ladder shape). [1]
The backbone consists of alternating sugar (deoxyribose) and phosphate groups. [1]
The rungs consist of nitrogenous bases paired together. [1]
Base pairing is specific: Adenine (A) pairs with Thymine (T), and Cytosine (C) pairs with Guanine (G) via hydrogen bonds. [1]

18.
(a) Parents are both $Aa$ (heterozygous). [1]
(b) 75% (or 3/4). [1]
(c) Both parents carry the recessive allele ( $a$ ) but are masked by the dominant allele ( $A$ ). Each parent passes the recessive allele ( $a$ ) to the child. The child inherits $aa$ , so the recessive phenotype is expressed. [3]

19.
Difference 1: Mitosis produces 2 daughter cells; Meiosis produces 4 daughter cells. [2]
Difference 2: Mitosis produces genetically identical cells; Meiosis produces genetically different cells. (Or: Mitosis maintains chromosome number; Meiosis halves it). [2]
Similarity: Both involve replication of DNA before division. (Or: Both involve division of the nucleus/cytoplasm). [1]

20.
(a) A mutation changes the sequence of bases in the DNA. This changes the sequence of codons on mRNA, which changes the sequence of amino acids in the protein. This alters the folding/shape of the protein. [3]
(b) Insulin functions by binding to specific receptors. If the shape changes, it may no longer fit the receptor (lock and key mechanism), so it cannot regulate blood glucose levels effectively. [2]