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Secondary 4 Combined Science Biology Practice Paper 1
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TuitionGoWhere Practice Paper — Answer Key
Subject: Combined Science Biology (Secondary 4)
Paper: Practice Paper — Cells & Biomolecules
Version: 1 of 5
Section A — Short-Answer Questions
1. The cell membrane controls the movement of substances into and out of the cell. It is partially (selectively) permeable.
[1]
Marking note: Accept any valid function — e.g., "controls entry/exit of substances," "provides shape," "selectively permeable." Award 1 mark for a correct function.
2. Mitochondrion (mitochondria).
[1]
Marking note: Spelling must be sufficiently correct. Accept "mitochondria" (plural).
3. (a) The cell will swell and may burst (haemolyse).
[1]
(b) Osmosis.
[1]
Marking note for (a): Accept "swells," "bursts," "lyses." Do not accept "shrinks."
4. (a) Absent
(b) Present
(c) Small / absent / temporary
[3] — 1 mark per correct answer.
5. Any two of the following (1 mark each, max 2):
- Diffusion does not require energy; active transport requires energy (ATP).
- Diffusion occurs down a concentration gradient; active transport occurs against a concentration gradient.
- Diffusion does not require carrier proteins (simple diffusion); active transport requires carrier proteins.
[2]
Marking note: Award 1 mark per valid difference. Answers must compare the two processes, not just define one.
6. (a) Starch
[1]
(b) Benedict's solution
[1]
Marking note for (b): Accept "Benedict's reagent." Do not accept "Biuret" or "iodine."
7. Muscle cells require large amounts of energy (ATP) for contraction. Mitochondria are the site of aerobic respiration, which produces ATP. Therefore, more mitochondria are needed to meet the high energy demand.
[2]
Marking note: Award 1 mark for linking muscle cells to high energy demand, and 1 mark for linking mitochondria to ATP production / aerobic respiration.
8. (a) Digestion (or hydrolysis)
[1]
(b) Any one of: increase in temperature (up to optimum), increase in substrate concentration, increase in enzyme concentration.
[1]
Marking note for (a): Accept "hydrolysis" or "breakdown." Do not accept "synthesis."
9. Osmosis is the movement of water molecules from a region of higher water potential to a region of lower water potential across a partially (selectively) permeable membrane.
[2]
Marking note: Award 1 mark for direction of water movement (high → low water potential or dilute → concentrated solution), and 1 mark for mentioning a partially permeable membrane. Both required for full marks.
10. The concentrated salt solution has a lower (more negative) water potential than the cytoplasm of the potato cells. Water molecules move out of the potato cells by osmosis, from a region of higher water potential (inside the cell) to a region of lower water potential (the salt solution). As water leaves the cell, the cell membrane pulls away from the cell wall and the cell becomes flaccid / loses turgor pressure.
[3]
Marking note: Award 1 mark for correct water potential comparison, 1 mark for naming osmosis as the process, and 1 mark for describing the outcome (flaccid / loss of water / plasmolysis).
Section B — Structured Questions
11. (a) The 5% sucrose solution has a higher water potential than the cell sap. Water molecules move into the cell by osmosis, from a region of higher water potential (outside) to a region of lower water potential (inside the cell). The cell swells and becomes turgid as the cell membrane pushes against the rigid cell wall.
[3]
Marking note: 1 mark for water potential comparison, 1 mark for osmosis, 1 mark for turgid outcome / cell wall prevents bursting.
(b) The 20% sucrose solution has a lower water potential than the cell sap. Water molecules move out of the cell by osmosis, from a region of higher water potential (inside the cell) to a region of lower water potential (outside). The cell membrane pulls away from the cell wall and the cell becomes plasmolysed.
[3]
Marking note: 1 mark for water potential comparison, 1 mark for osmosis, 1 mark for plasmolysis description.
(c) Any one of: maintains turgidity / rigidity of plant cells; supports the plant; aids in opening of stomata; absorption of water by root hair cells.
[1]
12. (a) As temperature increases from 10 °C to 37 °C, the time for digestion decreases (amylase activity increases). From 37 °C to 70 °C, the time increases (activity decreases).
[2]
Marking note: Award 1 mark for describing the increase in activity up to 37 °C, and 1 mark for describing the decrease beyond 37 °C. Accept "activity increases then decreases" with reference to the data.
(b) 37 °C is the optimum temperature for amylase. At this temperature, enzyme molecules and substrate molecules have the most kinetic energy, leading to the most frequent successful collisions. The enzyme's active site is not yet denatured, so the rate of reaction is highest.
[2]
Marking note: 1 mark for identifying 37 °C as the optimum, 1 mark for explanation involving kinetic energy / collisions / enzyme-substrate complexes.
(c) At 70 °C, the amylase enzyme is denatured. The high temperature breaks the bonds that maintain the enzyme's three-dimensional shape, so the active site changes shape and the substrate can no longer fit. The enzyme can no longer catalyse the reaction.
[2]
Marking note: 1 mark for "denatured," 1 mark for explaining the change in active site shape / loss of function.
(d) Any one of: volume of amylase solution, concentration of amylase, volume/concentration of starch solution, pH.
[1]
13. (a) The palisade mesophyll is near the upper surface to receive maximum sunlight. These cells contain many chloroplasts and are the main site of photosynthesis, so positioning them where light intensity is greatest maximises light absorption.
[2]
Marking note: 1 mark for linking position to sunlight exposure, 1 mark for linking to photosynthesis / chloroplasts.
(b) Presence of air spaces (between the loosely packed cells).
[1]
Marking note: Accept "air spaces," "loosely packed cells," or "large intercellular spaces." These allow gases (CO₂ and O₂) to diffuse easily.
Section C — Data-Based Question
14. (a) Trypsin (Test Tube B). It took the shortest time (5 minutes) to digest the egg white, meaning it was the most effective / had the highest rate of reaction.
[2]
Marking note: 1 mark for identifying trypsin, 1 mark for justifying with reference to the shortest time / fastest rate.
(b) Amylase (Test Tube C) does not digest protein — it digests starch. Egg white is protein, so amylase cannot break it down. Test Tube D had no enzyme at all, so no digestion occurred. In both cases, the egg white remained largely undigested after 60 minutes.
[2]
Marking note: 1 mark for stating amylase does not act on protein (enzyme specificity), 1 mark for stating no enzyme means no catalysis.
(c) Pepsin's optimum pH is pH 2 (acidic). At pH 8, the alkaline conditions would denature pepsin — the enzyme's active site would change shape due to the disruption of ionic and hydrogen bonds that maintain its three-dimensional structure. The substrate (protein) would no longer fit the active site, so the enzyme would not function effectively.
[2]
Marking note: 1 mark for identifying that pH 8 is far from pepsin's optimum / alkaline conditions, 1 mark for explaining denaturation / change in active site shape.
Total: 40 marks