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Secondary 3 Combined Science Semestral Assessment 2 (End of Year) Paper 1

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Questions

TuitionGoWhere Practice Paper - Combined Science Secondary 3

TuitionGoWhere Secondary School (AI)


Subject:	Combined Science (Physical Sciences)
Level:	Secondary 3
Paper:	SA2 Practice — Version 1 of 5
Duration:	60 minutes
Total Marks:	50

Name: ___________________________ Class: __________ Date: _______________

Instructions

Write your answers in the spaces provided.
Show all working for calculation questions. Marks are awarded for correct method even if the final answer is wrong.
Use appropriate scientific terminology where required.
The number of marks for each question is shown in brackets [ ].
You may use a calculator where necessary.

Section A: Multiple Choice Questions [10 marks]

Questions 1–10: Choose the most accurate answer. Each question carries 1 mark.

1. Which of the following is the correct statement of the Principle of Conservation of Energy?

(a) Energy can be created but not destroyed. (b) Energy cannot be created or destroyed, only converted from one form to another. (c) Energy is always lost during energy conversions. (d) Energy can be destroyed but not created.

2. A ball is dropped from a height of 5.0 m. Ignoring air resistance, what is its speed just before it hits the ground? (Take g = 10 m/s²)

(a) 5.0 m/s (b) 7.1 m/s (c) 10 m/s (d) 12 m/s

3. Which form of energy is stored in a stretched spring?

(a) Kinetic energy (b) Gravitational potential energy (c) Elastic potential energy (d) Thermal energy

4. A 2.0 kg object is lifted vertically through a height of 3.0 m. What is the work done against gravity? (Take g = 10 N/kg)

(a) 6.0 J (b) 20 J (c) 30 J (d) 60 J

5. Which of the following is the correct unit for power?

(a) Joule (b) Newton (c) Watt (d) Pascal

6. A machine has an efficiency of 75%. If the total energy input is 400 J, what is the useful energy output?

(a) 100 J (b) 200 J (c) 300 J (d) 350 J

7. When a car brakes to a stop, what happens to most of its kinetic energy?

(a) It disappears. (b) It is converted to thermal energy in the brakes and tyres. (c) It is stored as potential energy. (d) It is converted to light energy.

8. Which of the following is an example of a non-renewable energy source?

(a) Solar (b) Wind (c) Natural gas (d) Hydroelectric

9. A force of 50 N is applied to move a box 4.0 m along a horizontal surface. What is the work done by the force?

(a) 12.5 J (b) 54 J (c) 200 J (d) 250 J

10. The power output of a motor is 200 W. How much work does it do in 10 seconds?

Section B: Structured Response [25 marks]

Questions 11–18: Answer all questions in the spaces provided.

11. State the Principle of Conservation of Energy. [2]

12. A student of mass 50 kg runs up a flight of stairs that is 6.0 m high in 8.0 seconds.

(a) Calculate the gravitational potential energy gained by the student. (Take g = 10 N/kg) [2]

(b) Calculate the power developed by the student. [2]

13. The diagram below (not shown) shows a roller coaster car starting from rest at point A, which is 20 m above the ground, and moving along the track to point B at ground level.

(a) State the form of energy the car has at point A. [1]

(b) Ignoring friction, calculate the speed of the car when it reaches point B. (Take g = 10 m/s²) [3]

14. A crane lifts a concrete block of mass 500 kg vertically through a height of 12 m in 15 seconds.

(a) Calculate the weight of the concrete block. (Take g = 10 N/kg) [1]

(b) Calculate the work done by the crane in lifting the block. [2]

15. Explain what is meant by the efficiency of a machine. Include the word equation for efficiency in your answer. [3]

16. A motor has an input power of 500 W and a useful output power of 400 W.

(a) Calculate the efficiency of the motor. [2]

(b) State what happens to the "lost" energy. [1]

17. Describe the energy conversions that take place when a person bounces on a trampoline, from the moment they reach the highest point to the moment they leave the trampoline surface on the way back up. [3]

18. A 0.5 kg ball is thrown vertically upwards with an initial speed of 14 m/s.

(a) Calculate the maximum height reached by the ball. (Take g = 10 m/s²) [3]

(b) State one assumption you made in your calculation. [1]

Section C: Data-Based Question [15 marks]

Questions 19–20: Study the information below and answer the questions that follow.

19. A student investigated the efficiency of a simple pulley system. She used the pulley to lift different loads and measured the effort required each time. Her results are shown in the table below.

Load / N	Effort / N	Load raised / m	Effort distance / m
10	6.0	0.50	1.50
20	10.0	0.50	1.50
30	14.0	0.50	1.50
40	18.0	0.50	1.50

(a) Calculate the useful work done when the load is 30 N. [2]

(b) Calculate the total work done by the effort when the load is 30 N. [2]

(d) State how the efficiency changes as the load increases. Use data from the table to support your answer. [2]

(e) Suggest a reason for the trend you described in (d). [1]

20. The diagram below (not shown) shows a Sankey diagram for an electric fan. The total input energy is 100 J per second.

(a) If the useful output energy (kinetic energy of the air) is 65 J per second, calculate the wasted energy per second. [1]

(b) Calculate the efficiency of the electric fan. [2]

(d) Give two ways in which the efficiency of the electric fan could be improved. [2]

END OF PAPER

Answers

TuitionGoWhere Practice Paper — Answer Key

Combined Science (Physical Sciences) Secondary 3 — SA2 Practice, Version 1 of 5

Section A: Multiple Choice Questions [10 marks]

1. (b) Energy cannot be created or destroyed, only converted from one form to another.

[1 mark] Award mark for selecting (b). The principle must include both "cannot be created or destroyed" AND "converted from one form to another" for a complete statement.

2. (c) 10 m/s

[1 mark] Using v² = u² + 2as: v² = 0 + 2(10)(5.0) = 100, so v = 10 m/s.

3. (c) Elastic potential energy

[1 mark] A stretched spring stores elastic potential energy.

4. (d) 60 J

[1 mark] W = mgh = 2.0 × 10 × 3.0 = 60 J.

5. (c) Watt

[1 mark] The SI unit of power is the watt (W).

6. (c) 300 J

[1 mark] Useful output = 75% × 400 = 0.75 × 400 = 300 J.

7. (b) It is converted to thermal energy in the brakes and tyres.

[1 mark] Braking converts kinetic energy to thermal energy through friction. Energy is conserved, not destroyed.

8. (c) Natural gas

[1 mark] Natural gas is a fossil fuel and is non-renewable. Solar, wind, and hydroelectric are renewable.

9. (c) 200 J

[1 mark] W = F × d = 50 × 4.0 = 200 J.

[1 mark] W = P × t = 200 × 10 = 2000 J.

Section B: Structured Response [25 marks]

11. State the Principle of Conservation of Energy. [2]

[2 marks] Energy cannot be created or destroyed. It can only be converted from one form to another (or transferred from one object to another).
[1 mark] Award 1 mark for "cannot be created or destroyed" only.
[1 mark] Award 1 mark for "converted from one form to another" (or equivalent wording such as "transferred").
Common mistake: Saying "energy is conserved" without elaboration — award 0 marks as this merely restates the name of the principle.

12. A student of mass 50 kg runs up a flight of stairs that is 6.0 m high in 8.0 seconds.

(a) Calculate the gravitational potential energy gained by the student. (Take g = 10 N/kg) [2]

GPE = mgh = 50 × 10 × 6.0 = 3000 J
[1 mark] Correct substitution: 50 × 10 × 6.0
[1 mark] Correct answer with unit: 3000 J

(b) Calculate the power developed by the student. [2]

P = W / t = 3000 / 8.0 = 375 W
[1 mark] Correct substitution: 3000 / 8.0 (or their answer from (a) / 8.0)
[1 mark] Correct answer with unit: 375 W
Marking note: Allow error carried forward from (a) provided method is correct.

13. Roller coaster from point A (20 m high) to point B (ground level).

(a) State the form of energy the car has at point A. [1]

[1 mark] Gravitational potential energy (GPE).
Accept: "Potential energy" alone.

(b) Ignoring friction, calculate the speed of the car at point B. (Take g = 10 m/s²) [3]

Using conservation of energy: GPE at A = KE at B
mgh = ½mv²
gh = ½v²
v² = 2gh = 2 × 10 × 20 = 400
v = 20 m/s
[1 mark] Correct energy conservation equation or statement
[1 mark] Correct substitution: v² = 2 × 10 × 20
[1 mark] Correct answer with unit: 20 m/s

[1 mark] Some energy is converted to thermal energy (heat) due to friction between the car and the track (and/or air resistance).
Accept: "Energy is lost to friction" or "energy is lost to the surroundings as heat."

14. A crane lifts a concrete block of mass 500 kg vertically through 12 m in 15 s.

(a) Calculate the weight of the concrete block. (Take g = 10 N/kg) [1]

[1 mark] W = mg = 500 × 10 = 5000 N

(b) Calculate the work done by the crane in lifting the block. [2]

W = F × d = 5000 × 12 = 60,000 J (or 60 kJ)
[1 mark] Correct substitution: 5000 × 12
[1 mark] Correct answer with unit: 60,000 J

P = W / t = 60,000 / 15 = 4000 W (or 4.0 kW)
[1 mark] Correct substitution: 60,000 / 15
[1 mark] Correct answer with unit: 4000 W
Marking note: Allow error carried forward from (b).

15. Explain what is meant by the efficiency of a machine. Include the word equation. [3]

[1 mark] Efficiency is the ratio of useful energy output to total energy input (or useful work output to total work input).
[1 mark] It measures how well a machine converts input energy into useful output energy.
[1 mark] Word equation: Efficiency = (useful energy output / total energy output) × 100% (or Efficiency = useful output / total input)
Accept: Efficiency = useful power output / total power input
Common mistake: Students may omit the ×100% — accept either form (ratio or percentage).

16. A motor has an input power of 500 W and a useful output power of 400 W.

(a) Calculate the efficiency of the motor. [2]

Efficiency = (400 / 500) × 100% = 80%
[1 mark] Correct substitution: 400 / 500
[1 mark] Correct answer: 80% (or 0.80)

(b) State what happens to the "lost" energy. [1]

[1 mark] It is converted to thermal energy (heat) due to friction in the motor / resistance in the coils.
Accept: "It is wasted as heat" or "it is dissipated to the surroundings."

17. Describe the energy conversions from the highest point to leaving the trampoline surface. [3]

[1 mark] At the highest point, the person has maximum gravitational potential energy (and zero kinetic energy).
[1 mark] As the person falls towards the trampoline, GPE is converted to kinetic energy. On contact with the trampoline, KE is converted to elastic potential energy as the trampoline stretches.
[1 mark] As the trampoline pushes the person back up, elastic potential energy is converted back to kinetic energy, and then to gravitational potential energy as the person rises.
Marking note: Award marks for correct sequence of energy conversions. Must mention at least three stages for full marks.

18. A 0.5 kg ball is thrown vertically upwards with an initial speed of 14 m/s.

(a) Calculate the maximum height reached by the ball. (Take g = 10 m/s²) [3]

Using conservation of energy: KE at bottom = GPE at top
½mv² = mgh
½v² = gh
h = v² / (2g) = (14)² / (2 × 10) = 196 / 20 = 9.8 m
[1 mark] Correct energy conservation equation
[1 mark] Correct substitution: (14)² / (2 × 10)
[1 mark] Correct answer with unit: 9.8 m

(b) State one assumption you made in your calculation. [1]

[1 mark] Air resistance is negligible (ignored). OR No energy is lost to the surroundings.
Accept: "There is no air resistance" or "energy losses are negligible."

Section C: Data-Based Question [15 marks]

19. Pulley system investigation.

(a) Calculate the useful work done when the load is 30 N. [2]

Useful work = Load × distance load raised = 30 × 0.50 = 15 J
[1 mark] Correct substitution: 30 × 0.50
[1 mark] Correct answer with unit: 15 J

(b) Calculate the total work done by the effort when the load is 30 N. [2]

Total work = Effort × effort distance = 14.0 × 1.50 = 21 J
[1 mark] Correct substitution: 14.0 × 1.50
[1 mark] Correct answer with unit: 21 J

Efficiency = (useful work / total work) × 100% = (15 / 21) × 100% = 71.4% (or 71%)
[1 mark] Correct substitution: 15 / 21 (or their answers from (a) and (b))
[1 mark] Correct answer: 71% (accept 71.4%)
Marking note: Allow error carried forward.

(d) State how the efficiency changes as the load increases. Use data to support your answer. [2]

[1 mark] The efficiency increases as the load increases.
[1 mark] Supporting data: For load 10 N, efficiency = (10 × 0.50) / (6.0 × 1.50) = 5.0 / 9.0 = 55.6%. For load 40 N, efficiency = (40 × 0.50) / (18.0 × 1.50) = 20 / 27 = 74.1%. (Or any valid comparison showing increase.)
Marking note: Award the data mark for any correct calculation or comparison from the table showing increasing efficiency.

(e) Suggest a reason for the trend. [1]

[1 mark] The weight of the pulley (or friction in the pulley) remains constant, so when a larger load is lifted, the wasted energy (in lifting the pulley / overcoming friction) becomes a smaller fraction of the total work done.
Accept: "The fixed energy loss (due to the pulley weight or friction) is proportionally less significant for larger loads."

20. Sankey diagram for an electric fan. Total input energy = 100 J/s.

(a) Calculate the wasted energy per second. [1]

[1 mark] Wasted energy = 100 − 65 = 35 J/s

(b) Calculate the efficiency of the electric fan. [2]

Efficiency = (65 / 100) × 100% = 65%
[1 mark] Correct substitution: 65 / 100
[1 mark] Correct answer: 65%

[1 mark] Thermal energy (heat) / Sound energy.
Accept: "Heat" or "heat and sound."

(d) Give two ways in which the efficiency of the electric fan could be improved. [2]

[1 mark] Lubricate the moving parts to reduce friction.
[1 mark] Use better-quality bearings / use a more efficient motor / reduce air resistance on the blades.
Accept any two valid suggestions: e.g., "use smoother bearings," "improve blade design," "use a motor with lower electrical resistance."

Total: 50 marks