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Secondary 3 Chemistry Semestral Assessment 2 (End of Year) Paper 5
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Questions
TuitionGoWhere Practice Paper – Chemistry Secondary 3
TuitionGoWhere Secondary School (AI)
Subject: Chemistry
Level: Secondary 3
Paper: SA2 (End-of-Year Examination) – Version 5
Duration: 1 hour 30 minutes
Total Marks: 60
Name: ___________________________
Class: ___________________________
Date: ___________________________
Instructions to Candidates
- This paper consists of three sections: Section A, Section B, and Section C.
- Answer all questions in the spaces provided.
- Show all working clearly for calculation questions. Marks are awarded for correct method.
- You may use a scientific calculator.
- The number of marks is given in brackets [ ] at the end of each question or part question.
- A Periodic Table is provided at the end of this paper.
Section A: Structured Questions
Answer all questions in this section. [20 marks]
1. A student tested four solid compounds to determine their effect on soil pH. The results are shown below.
| Compound | Effect on soil pH |
|---|---|
| W | Decreased pH |
| X | No change |
| Y | Increased pH |
| Z | No change |
(a) Which compound, W, X, Y, or Z, is most likely to be calcium oxide? Explain your answer. [2]
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(b) Suggest the identity of compound W. Give a reason for your answer. [2]
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2. Ammonium nitrate is an important fertiliser.
(a) Name the two compounds that can be reacted together to form ammonium nitrate. [1]
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(b) Write a balanced chemical equation, with state symbols, for the reaction in (a). [2]
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(c) Explain why farmers must be careful not to apply too much ammonium nitrate fertiliser to their fields. [2]
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3. A student carried out a titration to determine the concentration of a solution of hydrochloric acid (solution R). She transferred 25.0 cm³ of solution R into a conical flask and titrated it against 0.100 mol/dm³ sodium hydroxide solution using phenolphthalein indicator. Her results are shown below.
| Titration number | 1 (rough) | 2 | 3 | 4 |
|---|---|---|---|---|
| Final burette reading / cm³ | 24.50 | 47.80 | 23.60 | 47.15 |
| Initial burette reading / cm³ | 0.00 | 24.50 | 0.00 | 23.60 |
| Volume of NaOH used / cm³ | 24.50 | 23.30 | 23.60 | 23.55 |
(a) Which titrations are concordant? Explain your choice. [2]
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(b) Calculate the average volume of sodium hydroxide solution used for neutralisation. Give your answer to two decimal places. [2]
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(c) Calculate the number of moles of sodium hydroxide in the average volume used. [1]
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(d) Using your answer to (c), calculate the concentration of hydrochloric acid in solution R in mol/dm³. [2]
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4. Zinc oxide (ZnO) is described as an amphoteric oxide.
(a) What is meant by the term amphoteric? [1]
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(b) Write a balanced chemical equation for the reaction of zinc oxide with hydrochloric acid. [1]
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(c) Write a balanced chemical equation for the reaction of zinc oxide with aqueous sodium hydroxide. [1]
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Section B: Data-Based and Diagram Questions
Answer all questions in this section. [20 marks]
5. The diagram below shows the dot-and-cross diagram for a molecule of tetrachloromethane, CCl₄. Only valence electrons are shown.
Cl
•
•• ×× ••
Cl •• C ×× Cl
•• ×× ••
Cl
(a) State the number of valence electrons in one atom of chlorine. [1]
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(b) Explain why carbon and chlorine form covalent bonds rather than ionic bonds. [2]
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(c) Tetrachloromethane has a melting point of −23 °C. Sodium chloride has a melting point of 801 °C. Explain, in terms of structure and bonding, why sodium chloride has a much higher melting point than tetrachloromethane. [3]
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6. The table below shows the lattice energies of four ionic compounds.
| Compound | Formula of ions | Lattice energy / kJ/mol |
|---|---|---|
| Sodium fluoride | Na⁺, F⁻ | −918 |
| Sodium chloride | Na⁺, Cl⁻ | −780 |
| Magnesium oxide | Mg²⁺, O²⁻ | −3791 |
| Calcium oxide | Ca²⁺, O²⁻ | −3401 |
(a) Define the term lattice energy. [1]
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(b) Using the data in the table, describe how the lattice energy varies as the charges on the ions change. Explain your answer. [2]
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(c) Both magnesium oxide and calcium oxide contain ions with charges of 2+ and 2−. Suggest why magnesium oxide has a more exothermic lattice energy than calcium oxide. [2]
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7. A student investigated the reaction between marble chips (calcium carbonate) and dilute hydrochloric acid. The apparatus is shown below.
[Diagram: Conical flask containing marble chips and acid, connected to a gas syringe]
The student recorded the volume of gas collected every 30 seconds. The results are shown in the table.
| Time / s | 0 | 30 | 60 | 90 | 120 | 150 | 180 | 210 | 240 |
|---|---|---|---|---|---|---|---|---|---|
| Volume of gas / cm³ | 0 | 34 | 58 | 74 | 84 | 90 | 94 | 96 | 96 |
(a) Name the gas produced in this reaction. [1]
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(b) Write a balanced chemical equation, with state symbols, for the reaction. [2]
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(c) On the grid below, plot a graph of volume of gas against time. Draw a smooth curve through the points. [3]
Volume of gas / cm³
100 |
|
80 |
|
60 |
|
40 |
|
20 |
|
0 |_____________________________________
0 30 60 90 120 150 180 210 240
Time / s
(d) Use your graph to determine the time taken for the reaction to produce 50 cm³ of gas. [1]
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(e) Explain why the rate of reaction decreases as the reaction proceeds. [2]
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Section C: Free-Response Questions
Answer all questions in this section. [20 marks]
8. A student prepared copper(II) sulfate crystals by reacting excess copper(II) oxide with warm dilute sulfuric acid.
(a) Describe the steps the student should take to obtain pure, dry crystals of copper(II) sulfate from the reaction mixture. Include the names of any techniques used. [4]
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(b) Write a balanced chemical equation, with state symbols, for the reaction between copper(II) oxide and sulfuric acid. [2]
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(c) The student obtained 4.80 g of dry copper(II) sulfate crystals, CuSO₄·5H₂O. Calculate the percentage yield if the theoretical yield was 6.00 g. [2]
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(d) Suggest one reason why the percentage yield was less than 100%. [1]
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9. The Haber process is used to manufacture ammonia from nitrogen and hydrogen.
N₂(g) + 3H₂(g) ⇌ 2NH₃(g) ΔH = −92 kJ/mol
(a) State the source of nitrogen used in the Haber process. [1]
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(b) State the source of hydrogen used in the Haber process. [1]
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(c) The reaction is carried out at a temperature of 450 °C, a pressure of 200 atm, and in the presence of an iron catalyst. Explain why each of these conditions is chosen. [6]
Temperature (450 °C):
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Pressure (200 atm):
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Iron catalyst:
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(d) Ammonia produced by the Haber process is used to make ammonium sulfate fertiliser. Describe how ammonium sulfate is made from ammonia. Include a balanced chemical equation in your answer. [3]
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10. A student tested an unknown solution and recorded the following observations.
| Test | Observation |
|---|---|
| Add aqueous sodium hydroxide | Blue precipitate formed, insoluble in excess |
| Add aqueous ammonia | Blue precipitate formed, soluble in excess, forming a deep blue solution |
| Add dilute nitric acid, then aqueous silver nitrate | White precipitate formed |
(a) Identify the cation present in the unknown solution. Explain your answer using the observations. [2]
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(b) Identify the anion present in the unknown solution. Explain your answer. [2]
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(c) Name the unknown compound. [1]
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— END OF PAPER —
Answers
TuitionGoWhere Practice Paper – Chemistry Secondary 3
SA2 (End-of-Year Examination) – Version 5
ANSWER KEY AND MARKING SCHEME
Total Marks: 60
Section A: Structured Questions [20 marks]
1. (a) Which compound is most likely calcium oxide? Explain. [2]
Answer: Compound Y. [1]
Calcium oxide is a basic oxide / metal oxide. It reacts with water in the soil to form calcium hydroxide, which neutralises acids in the soil, thereby increasing the pH. [1]
1. (b) Suggest the identity of compound W. Give a reason. [2]
Answer: Any suitable acidic compound, e.g., ammonium sulfate / ammonium nitrate / sulfur powder. [1]
Reason: Compound W decreased the soil pH, so it must be an acidic substance or a substance that produces acid in the soil (e.g., ammonium salts release H⁺ ions when nitrified by bacteria). [1]
2. (a) Name the two compounds that can be reacted together to form ammonium nitrate. [1]
Answer: Ammonia (or ammonium hydroxide) and nitric acid. [1]
2. (b) Write a balanced chemical equation, with state symbols, for the reaction. [2]
Answer: NH₃(aq) + HNO₃(aq) → NH₄NO₃(aq) [2]
Award [1] for correct formulas, [1] for correct state symbols and balancing.
Accept NH₄OH(aq) + HNO₃(aq) → NH₄NO₃(aq) + H₂O(l).
2. (c) Explain why farmers must be careful not to apply too much ammonium nitrate fertiliser. [2]
Answer: Excess ammonium nitrate can leach into groundwater / run off into rivers and lakes, causing eutrophication. [1] This leads to excessive growth of algae, which depletes oxygen in the water and kills aquatic life. [1]
Accept: Excess nitrate can accumulate in crops and be harmful if consumed; or excess fertiliser can acidify the soil.
3. (a) Which titrations are concordant? Explain. [2]
Answer: Titrations 2, 3, and 4 are concordant. [1]
Concordant results are within 0.10 cm³ of each other. Titration 2 (23.30 cm³), Titration 3 (23.60 cm³), and Titration 4 (23.55 cm³) are all within 0.30 cm³ of each other. [1]
Note: Accept 2, 3, and 4 as concordant if the student correctly identifies that they are within ±0.10–0.20 cm³. Titration 1 is the rough run and is excluded.
3. (b) Calculate the average volume of sodium hydroxide solution used. [2]
Answer: Average = (23.30 + 23.60 + 23.55) ÷ 3 = 23.48 cm³ (to 2 d.p.) [2]
Award [1] for correct selection of concordant results, [1] for correct calculation to 2 d.p.
3. (c) Calculate the number of moles of sodium hydroxide in the average volume used. [1]
Answer: n(NaOH) = c × V = 0.100 × (23.48 ÷ 1000) = 0.002348 mol [1]
Accept 0.00235 mol.
3. (d) Calculate the concentration of hydrochloric acid in solution R in mol/dm³. [2]
Answer: HCl + NaOH → NaCl + H₂O (1:1 mole ratio) [1]
n(HCl) = n(NaOH) = 0.002348 mol
c(HCl) = n ÷ V = 0.002348 ÷ (25.0 ÷ 1000) = 0.0939 mol/dm³ [1]
Accept 0.094 mol/dm³ (2 or 3 s.f.).
4. (a) What is meant by the term amphoteric? [1]
Answer: An amphoteric substance is one that can react with both acids and bases / shows both acidic and basic properties. [1]
4. (b) Write a balanced chemical equation for the reaction of zinc oxide with hydrochloric acid. [1]
Answer: ZnO(s) + 2HCl(aq) → ZnCl₂(aq) + H₂O(l) [1]
4. (c) Write a balanced chemical equation for the reaction of zinc oxide with aqueous sodium hydroxide. [1]
Answer: ZnO(s) + 2NaOH(aq) + H₂O(l) → Na₂Zn(OH)₄(aq) [1]
Accept: ZnO(s) + 2NaOH(aq) → Na₂ZnO₂(aq) + H₂O(l).
Section B: Data-Based and Diagram Questions [20 marks]
5. (a) State the number of valence electrons in one atom of chlorine. [1]
Answer: 7 [1]
5. (b) Explain why carbon and chlorine form covalent bonds rather than ionic bonds. [2]
Answer: Both carbon and chlorine are non-metals. [1] They share electrons to achieve a full outer shell / stable noble gas configuration, forming covalent bonds. Neither atom transfers electrons completely to the other. [1]
5. (c) Explain, in terms of structure and bonding, why sodium chloride has a much higher melting point than tetrachloromethane. [3]
Answer: Sodium chloride has a giant ionic lattice structure. [1] There are strong electrostatic forces of attraction between the oppositely charged Na⁺ and Cl⁻ ions throughout the lattice. A large amount of energy is required to overcome these strong forces. [1]
Tetrachloromethane has a simple molecular structure. The molecules are held together by weak intermolecular forces / van der Waals forces, which require little energy to overcome. [1]
6. (a) Define the term lattice energy. [1]
Answer: Lattice energy is the energy released when one mole of an ionic compound is formed from its gaseous ions / the energy required to separate one mole of an ionic solid into its gaseous ions. [1]
6. (b) Describe how lattice energy varies as the charges on the ions change. Explain. [2]
Answer: Lattice energy becomes more exothermic (more negative) as the charges on the ions increase. [1]
This is because the electrostatic attraction between ions with higher charges is stronger (Coulomb's law: F ∝ q₁q₂/r²), so more energy is released when the lattice forms. [1]
6. (c) Suggest why magnesium oxide has a more exothermic lattice energy than calcium oxide. [2]
Answer: Both compounds contain ions with charges of 2+ and 2−, but Mg²⁺ has a smaller ionic radius than Ca²⁺. [1]
The smaller Mg²⁺ ion can approach the O²⁻ ion more closely, resulting in stronger electrostatic attraction and a more exothermic lattice energy. [1]
7. (a) Name the gas produced in this reaction. [1]
Answer: Carbon dioxide / CO₂ [1]
7. (b) Write a balanced chemical equation, with state symbols, for the reaction. [2]
Answer: CaCO₃(s) + 2HCl(aq) → CaCl₂(aq) + H₂O(l) + CO₂(g) [2]
Award [1] for correct formulas, [1] for correct state symbols and balancing.
7. (c) Plot a graph of volume of gas against time. [3]
Marking:
- [1] Correctly labelled axes with units (Volume of gas / cm³ on y-axis; Time / s on x-axis)
- [1] All points plotted correctly (± half a small square)
- [1] Smooth curve drawn through the points (curve should show decreasing gradient, levelling off at 96 cm³)
7. (d) Use your graph to determine the time taken to produce 50 cm³ of gas. [1]
Answer: Approximately 48–52 seconds (accept any value in this range based on the student's graph). [1]
7. (e) Explain why the rate of reaction decreases as the reaction proceeds. [2]
Answer: As the reaction proceeds, the concentration of hydrochloric acid decreases / the amount of calcium carbonate decreases. [1]
According to collision theory, there are fewer particles per unit volume, so the frequency of effective collisions between reactant particles decreases, and the rate of reaction decreases. [1]
Section C: Free-Response Questions [20 marks]
8. (a) Describe the steps to obtain pure, dry crystals of copper(II) sulfate. [4]
Answer:
- Filter the mixture to remove excess (unreacted) copper(II) oxide. [1]
- Heat the filtrate (copper(II) sulfate solution) to evaporate some of the water / to concentrate the solution until it is saturated / until crystallisation point is reached. [1]
- Allow the saturated solution to cool slowly. Crystals of copper(II) sulfate will form. [1]
- Filter the crystals, wash with a small amount of cold distilled water, and dry between pieces of filter paper. [1]
8. (b) Write a balanced chemical equation, with state symbols, for the reaction. [2]
Answer: CuO(s) + H₂SO₄(aq) → CuSO₄(aq) + H₂O(l) [2]
Award [1] for correct formulas, [1] for correct state symbols and balancing.
8. (c) Calculate the percentage yield. [2]
Answer: Percentage yield = (actual yield ÷ theoretical yield) × 100% [1]
= (4.80 ÷ 6.00) × 100% = 80.0% [1]
8. (d) Suggest one reason why the percentage yield was less than 100%. [1]
Answer: Any one of:
- Some copper(II) sulfate solution was lost during filtration / transfer between containers.
- Some crystals remained dissolved in the mother liquor and were not recovered.
- Some crystals were lost during washing / drying.
- The reaction may not have gone to completion. [1]
9. (a) State the source of nitrogen used in the Haber process. [1]
Answer: Fractional distillation of liquid air. [1]
9. (b) State the source of hydrogen used in the Haber process. [1]
Answer: Cracking of hydrocarbons from petroleum / reaction of methane with steam. [1]
9. (c) Explain why each condition is chosen. [6]
Temperature (450 °C): [2]
- The forward reaction is exothermic. A lower temperature would favour the forward reaction and give a higher equilibrium yield of ammonia. [1]
- However, 450 °C is chosen as a compromise temperature. It is high enough to give a reasonably fast rate of reaction, while still giving an acceptable equilibrium yield. A lower temperature would make the reaction too slow. [1]
Pressure (200 atm): [2]
- The forward reaction produces fewer gas molecules (4 moles → 2 moles). High pressure favours the forward reaction and increases the equilibrium yield of ammonia. [1]
- 200 atm is chosen as a compromise. Higher pressures would increase yield further but are more expensive (stronger equipment needed, higher energy costs, safety concerns). [1]
Iron catalyst: [2]
- The iron catalyst speeds up the rate of reaction by providing an alternative reaction pathway with lower activation energy. [1]
- The catalyst does not affect the position of equilibrium or the yield of ammonia. It allows the reaction to reach equilibrium more quickly at the chosen temperature. [1]
9. (d) Describe how ammonium sulfate is made from ammonia. Include a balanced chemical equation. [3]
Answer: Ammonia is reacted with sulfuric acid. [1]
2NH₃(aq) + H₂SO₄(aq) → (NH₄)₂SO₄(aq) [1]
The ammonium sulfate solution is then crystallised / evaporated to obtain solid ammonium sulfate crystals. [1]
10. (a) Identify the cation present. Explain. [2]
Answer: The cation is Cu²⁺ (copper(II) ion). [1]
A blue precipitate with aqueous sodium hydroxide, insoluble in excess, indicates Cu²⁺. A blue precipitate with aqueous ammonia, soluble in excess forming a deep blue solution, confirms Cu²⁺. [1]
10. (b) Identify the anion present. Explain. [2]
Answer: The anion is Cl⁻ (chloride ion). [1]
Addition of dilute nitric acid followed by aqueous silver nitrate gives a white precipitate, which indicates the presence of chloride ions (Ag⁺ + Cl⁻ → AgCl). [1]
10. (c) Name the unknown compound. [1]
Answer: Copper(II) chloride / CuCl₂ [1]
— END OF ANSWER KEY —