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Secondary 2 Science Life Sciences Quiz
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Questions
Secondary 2 Science Quiz - Life Sciences
Name: ________________________
Class: ________________________
Date: ________________________
Score: _______ / 40
Duration: 45 minutes
Total Marks: 40
Instructions
- Answer all questions in the spaces provided.
- Write your answers clearly and in complete sentences where required.
- Show all working for calculation questions.
- The number of marks for each question is shown in brackets [ ].
Section A: Diversity of Living Things (Questions 1–5)
1. State two characteristics that all living things share. [2]
2. The diagram below shows a plant cell as seen under a microscope.
(Diagram description for student: A rectangular plant cell with visible cell wall, cell membrane, nucleus, chloroplasts, vacuole, and cytoplasm.)
(a) Label parts A (outermost rigid layer) and B (contains genetic material) on the diagram above. [2]
(b) State one function of the chloroplast. [1]
3. Complete the table below to compare animal cells and plant cells. [3]
| Feature | Animal Cell | Plant Cell |
|---|---|---|
| Cell wall | (i) _______________ | Present |
| Chloroplasts | Absent | (ii) _______________ |
| Vacuole | Small / temporary | (iii) _______________ |
4. Explain why a red blood cell is considered a specialised cell. [2]
5. Arrange the following levels of organisation in order from simplest to most complex: organ system, cell, tissue, organ. [1]
Section B: Human Digestive System (Questions 6–10)
6. State the function of the following parts of the digestive system:
(a) Mouth [1]
(b) Stomach [1]
(c) Small intestine [1]
7. The diagram shows a section of the small intestine with villi.
(Diagram description: A cross-section of the small intestine wall showing finger-like projections called villi, each containing a network of blood capillaries and a central lacteal.)
(a) What is the function of villi in the small intestine? [1]
(b) Explain how the structure of a villus is adapted for its function. [2]
8. A student tested four food samples for the presence of nutrients. The results are shown below.
| Food Sample | Iodine Test | Biuret Test | Benedict's Test |
|---|---|---|---|
| A | Blue-black | Purple | Blue |
| B | Brown | Blue | Orange-red |
| C | Blue-black | Blue | Blue |
| D | Brown | Purple | Blue |
(a) Which food sample contains starch? Explain your answer. [2]
(b) Which food sample contains reducing sugar? Explain your answer. [2]
9. Describe the role of enzymes in digestion. Include the terms substrate and product in your answer. [3]
10. A piece of protein-rich food is placed in a test tube containing pepsin at 37 °C and pH 2. After 30 minutes, the food is partially broken down.
(a) Explain why the temperature is kept at 37 °C. [1]
(b) Explain why the pH is kept at 2. [1]
(c) Predict what would happen if the pH were changed to 7. Explain your answer. [2]
Section C: Transport in Plants and Humans (Questions 11–15)
11. State two differences between the transport system in plants and the transport system in humans. [2]
12. The diagram shows a section of a leaf.
(Diagram description: A cross-section of a leaf showing upper epidermis, palisade mesophyll, spongy mesophyll, lower epidermis with stomata, and vascular bundles.)
(a) Label the xylem and phloem on the vascular bundle shown. [2]
(b) State the function of the xylem. [1]
13. A potted plant was placed in a well-lit room for 6 hours. The mass of the plant and pot was measured at the start and end of the experiment.
| Mass at Start (g) | Mass at End (g) | |
|---|---|---|
| Plant + Pot | 520 | 496 |
(a) Calculate the mass of water lost by the plant during the 6 hours. [1]
(b) Name the process by which water is lost from the leaves. [1]
(c) Explain why the plant lost more water during the day than at night. [2]
14. Describe the path of blood flow through the human heart starting from the vena cava. Name all four chambers and the two major blood vessels connected to the heart. [4]
15. Explain the difference between arteries and veins. Include at least two differences in your answer. [3]
Section D: Ecosystems and Interactions (Questions 16–20)
16. Define the term population. [1]
17. The food web below shows feeding relationships in a grassland ecosystem.
(Food web description: Grass → Grasshopper → Frog → Snake; Grass → Grasshopper → Bird → Hawk; Grass → Rabbit → Fox; Grass → Rabbit → Hawk; Grass → Mouse → Snake; Grass → Mouse → Hawk.)
(a) Identify the producer in this food web. [1]
(b) Name two secondary consumers. [2]
(c) State what would happen to the population of frogs if all the snakes were removed from the ecosystem. Explain your answer. [2]
18. Explain the difference between a food chain and a food web. [2]
19. A farmer sprays pesticide on his crops to kill insect pests. Over time, the pesticide accumulates in the bodies of organisms higher up the food chain.
(a) Name this process of pesticide accumulation. [1]
(b) Explain why top predators are most affected by this process. [2]
20. A student investigated the effect of light intensity on the rate of photosynthesis in an aquatic plant. The number of oxygen bubbles produced per minute was counted at different light intensities.
| Light Intensity (arbitrary units) | Number of Oxygen Bubbles per Minute |
|---|---|
| 10 | 2 |
| 20 | 5 |
| 30 | 9 |
| 40 | 14 |
| 50 | 18 |
| 60 | 18 |
(a) State the independent variable in this investigation. [1]
(b) Describe the trend shown in the results. [2]
(c) Explain why the number of bubbles stops increasing after a light intensity of 50 units. [2]
End of Quiz
Answers
Secondary 2 Science Quiz - Life Sciences: Answer Key
Total Marks: 40
Section A: Diversity of Living Things (Questions 1–5)
1. State two characteristics that all living things share. [2]
Answer: Any two from: nutrition (feeding), respiration, excretion, growth, reproduction, sensitivity, movement. [1 mark each]
Marking Notes: Accept any valid characteristic of life. Do not accept vague answers like "they are alive."
2. (a) Label parts A (outermost rigid layer) and B (contains genetic material). [2]
Answer: A = Cell wall [1]; B = Nucleus [1]
(b) State one function of the chloroplast. [1]
Answer: To carry out photosynthesis / To absorb light energy for photosynthesis. [1]
3. Complete the table. [3]
Answer: (i) Absent [1] (ii) Present [1] (iii) Large / permanent / central vacuole [1]
4. Explain why a red blood cell is considered a specialised cell. [2]
Answer: A red blood cell has a specific structure (biconcave disc shape, no nucleus, contains haemoglobin) that is adapted to its specific function of transporting oxygen. [1] It is different from a typical/generalised cell because it has been modified to carry out this one function efficiently. [1]
Marking Notes: Award 1 mark for identifying a special feature and 1 mark for linking it to its specific function.
5. Arrange the levels of organisation from simplest to most complex. [1]
Answer: Cell → Tissue → Organ → Organ system [1]
Marking Notes: All four in correct order for 1 mark. Any error = 0 marks.
Section B: Human Digestive System (Questions 6–10)
6. State the function of:
(a) Mouth [1]
Answer: Mechanical digestion (chewing) / Chemical digestion of starch by salivary amylase. [1]
(b) Stomach [1]
Answer: Mechanical churning of food / Chemical digestion of proteins by pepsin (in acidic conditions). [1]
(c) Small intestine [1]
Answer: Chemical digestion of food by enzymes / Absorption of digested nutrients into the blood. [1]
7. (a) What is the function of villi? [1]
Answer: To increase the surface area for absorption of digested food. [1]
(b) Explain how the structure of a villus is adapted for its function. [2]
Answer: Villi have a large surface area (finger-like projections) to maximise absorption. [1] They have a thin wall (one cell thick) for short diffusion distance, and a rich blood supply (network of capillaries) to transport absorbed nutrients away quickly, maintaining a concentration gradient. [1]
Marking Notes: Award 1 mark for surface area adaptation and 1 mark for thin wall or blood supply.
8. (a) Which food sample contains starch? [2]
Answer: Sample A or C [1] because the iodine test turned blue-black, which is the positive result for starch. [1]
Marking Notes: Must identify correct sample AND explain the colour change for full marks.
(b) Which food sample contains reducing sugar? [2]
Answer: Sample B [1] because the Benedict's test turned orange-red / brick-red, which is the positive result for reducing sugar. [1]
9. Describe the role of enzymes in digestion. [3]
Answer: Enzymes are biological catalysts that speed up the breakdown of large, insoluble food molecules into smaller, soluble molecules. [1] The food molecule is called the substrate, which fits into the active site of the enzyme. [1] The enzyme breaks down the substrate into products, which are small enough to be absorbed. [1]
Marking Notes: 1 mark for catalyst/breakdown role, 1 mark for correct use of "substrate," 1 mark for correct use of "product."
10. (a) Explain why the temperature is kept at 37 °C. [1]
Answer: 37 °C is the optimum temperature for enzyme (pepsin) activity / body temperature. [1]
(b) Explain why the pH is kept at 2. [1]
Answer: pH 2 is the optimum pH for pepsin / Pepsin works best in acidic conditions. [1]
(c) Predict what would happen if the pH were changed to 7. [2]
Answer: The protein would not be broken down / digestion would stop or slow down significantly. [1] This is because pepsin is denatured at pH 7 (neutral) as it is only active in acidic conditions. [1]
Marking Notes: 1 mark for correct prediction, 1 mark for explanation linking to enzyme denaturation/optimum pH.
Section C: Transport in Plants and Humans (Questions 11–15)
11. State two differences between the transport system in plants and humans. [2]
Answer: Any two from:
- Plants use xylem and phloem; humans use blood vessels (arteries, veins, capillaries). [1]
- Plant transport is driven by transpiration pull and root pressure; human transport is driven by the pumping of the heart. [1]
- Plants do not have a heart / muscular pump. [1]
- Human transport system is a closed circulatory system; plant transport uses separate vessels. [1]
Marking Notes: 1 mark each. Answers must be comparative.
12. (a) Label the xylem and phloem. [2]
Answer: Xylem = the vessel closer to the upper epidermis / inner side of the vascular bundle [1]; Phloem = the vessel closer to the lower epidermis / outer side of the vascular bundle [1]
(b) State the function of the xylem. [1]
Answer: To transport water and dissolved mineral salts from the roots to the leaves. [1]
13. (a) Calculate the mass of water lost. [1]
Answer: 520 g − 496 g = 24 g [1]
(b) Name the process. [1]
Answer: Transpiration [1]
(c) Explain why the plant lost more water during the day than at night. [2]
Answer: During the day, stomata are open to allow carbon dioxide to enter for photosynthesis. [1] This allows more water vapour to escape through the stomata by transpiration. At night, stomata close, reducing water loss. [1]
Marking Notes: 1 mark for stomata being open during the day, 1 mark for linking open stomata to increased transpiration / closed stomata at night.
14. Describe the path of blood flow through the heart. [4]
Answer: Blood enters the right atrium from the vena cava. [1] It then passes into the right ventricle, which pumps blood to the lungs via the pulmonary artery. [1] Oxygenated blood returns from the lungs to the left atrium via the pulmonary vein. [1] It then passes into the left ventricle, which pumps blood to the rest of the body via the aorta. [1]
Marking Notes: 1 mark for each correct chamber or vessel mentioned in the correct sequence. Accept any four correct points. Common mistake: students may confuse pulmonary artery/vein — ensure correct pairing.
15. Explain the difference between arteries and veins. [3]
Answer: Any three from:
- Arteries carry blood away from the heart; veins carry blood towards the heart. [1]
- Arteries have thick, muscular, elastic walls; veins have thinner walls. [1]
- Arteries have no valves; veins have valves to prevent backflow of blood. [1]
- Blood in arteries (except pulmonary artery) is oxygenated; blood in veins (except pulmonary vein) is deoxygenated. [1]
- Blood pressure in arteries is higher than in veins. [1]
Marking Notes: 1 mark each, maximum 3 marks.
Section D: Ecosystems and Interactions (Questions 16–20)
16. Define the term population. [1]
Answer: A group of organisms of the same species living in the same habitat at the same time. [1]
Marking Notes: Must include "same species" and "same habitat/area." Do not accept "a group of animals."
17. (a) Identify the producer. [1]
Answer: Grass [1]
(b) Name two secondary consumers. [2]
Answer: Any two from: Frog, Bird, Snake, Fox, Hawk [1 mark each]
Marking Notes: Secondary consumers feed on primary consumers (herbivores). Accept any two correct organisms.
(c) State what would happen to the frog population if all snakes were removed. [2]
Answer: The population of frogs would increase. [1] This is because snakes are predators of frogs, so removing this predator reduces the number of frogs being eaten, allowing more frogs to survive and reproduce. [1]
Marking Notes: 1 mark for correct prediction (increase), 1 mark for explanation linking predator removal to reduced predation.
18. Explain the difference between a food chain and a food web. [2]
Answer: A food chain shows a single pathway of energy transfer from one organism to the next in a linear sequence. [1] A food web shows multiple interconnected food chains, representing the complex feeding relationships in an ecosystem. [1]
19. (a) Name this process. [1]
Answer: Bioaccumulation / Biomagnification [1]
(b) Explain why top predators are most affected. [2]
Answer: Pesticides are not easily broken down or excreted, so they accumulate in the body of each organism. [1] As organisms are eaten by predators, the pesticide concentration increases at each trophic level, so top predators (at the highest trophic level) accumulate the highest concentration. [1]
Marking Notes: 1 mark for pesticides accumulating in organisms, 1 mark for concentration increasing up the food chain.
20. (a) State the independent variable. [1]
Answer: Light intensity [1]
(b) Describe the trend shown in the results. [2]
Answer: As light intensity increases, the number of oxygen bubbles per minute increases. [1] The rate of increase is steep at first but levels off / becomes constant at higher light intensities (50–60 units). [1]
Marking Notes: 1 mark for general trend (increase), 1 mark for describing the levelling off.
(c) Explain why the number of bubbles stops increasing after 50 units. [2]
Answer: Light intensity is no longer the limiting factor. [1] Another factor such as carbon dioxide concentration or temperature becomes the limiting factor, so increasing light intensity further does not increase the rate of photosynthesis. [1]
Marking Notes: 1 mark for identifying that light is no longer limiting, 1 mark for naming an alternative limiting factor or explaining the concept of limiting factors.
End of Answer Key