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Secondary 1 Mathematics Semestral Assessment 2 (End of Year) Paper 1

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TuitionGoWhere Exam Practice (AI) — SA2 Practice Paper Answer Key

Mathematics Secondary 1 — Numbers, Ratio & Proportion (Version 1 of 5)

Total Marks: 60


Section A (20 marks)

1. [2 marks]
24:36=2412:3612=2:324 : 36 = \frac{24}{12} : \frac{36}{12} = 2 : 3
Answer: 2:32 : 3
Teaching note: Divide both terms by HCF 12. Simplest form means no common factor other than 1.

2. [2 marks]
1.21.2 m =120= 120 cm. 45120×100%=37.5%\frac{45}{120} \times 100\% = 37.5\%
Answer: 37.5%37.5\%
Teaching note: Convert to same unit before percentage. Common mistake: using 1.2 directly without converting.

3. [2 marks]
4x>12x<3-4x > 12 \Rightarrow x < -3 (divide by -4, reverse sign)
Answer: x<3x < -3
Teaching note: Dividing by negative reverses inequality.

4. [2 marks]
Flour : Sugar =5:2= 5 : 2. 250250 g flour 250÷5=50\rightarrow 250 \div 5 = 50 g per unit. Sugar =2×50=100= 2 \times 50 = 100 g.
Answer: 100100 g
Teaching note: Use unitary method.

5. [2 marks]
1010 min =600= 600 s. Total mass =500×600=300000= 500 \times 600 = 300\,000 g =300= 300 kg. Bags =300÷2=150= 300 \div 2 = 150.
Answer: 150150 bags
Teaching note: Convert time to seconds; bag mass to grams or total to kg consistently.

6. [2 marks]
Increase =108=2= 10 - 8 = 2. 28×100%=25%\frac{2}{8} \times 100\% = 25\%.
Answer: 25%25\%
Teaching note: Percentage increase = change/original × 100.

7. [2 marks]
33 units =211= 21 \Rightarrow 1 unit =7= 7. Girls =4×7=28= 4 \times 7 = 28.
Answer: 2828
Teaching note: Ratio parts method.

8. [2 marks]
15%15\% of 80=1280 = 12. 8012=6880 - 12 = 68.
Answer: 6868
Teaching note: Decrease = original × (1 - %).

9. [2 marks]
Speed =240÷3=80= 240 \div 3 = 80 km/h.
Answer: 8080 km/h
Teaching note: Average speed = distance/time.

10. [2 marks]
Red =2×18=36= 2 \times 18 = 36.
Answer: 3636
Teaching note: Direct ratio application.


Section B (18 marks)

11. [3 marks]
Let stamps =x= x, coins =2x= 2x. New stamps =1.75x= 1.75x. Coins constant =2x= 2x.
New total =1.75x+2x=3.75x= 1.75x + 2x = 3.75x. Original total =3x= 3x.
Percentage decrease in coins relative to new total: coins are 2x2x out of 3.75x3.75x, so "decrease" interpreted as coins' share drop: original share =2x/3x=66.7%= 2x/3x = 66.7\%, new share =2x/3.75x=53.3%= 2x/3.75x = 53.3\%, drop in share =13.3= 13.3 pts. But if asked decrease in number of coins (constant) vs new total items, coins did not decrease in count. Mark scheme: state coins constant (1), new total (1), explain no decrease in coin count but share reduced (1).
Answer: Coins unchanged; percentage of total fell from 6623%66\frac{2}{3}\% to 5313%53\frac{1}{3}\%.
Teaching note: Careful reading; ratio constraint removed.

12. [3 marks]
3q>9q<3-3q > 9 \Rightarrow q < -3. Number line: open circle at 3-3, arrow left.
Answer: q<3q < -3, diagram as placeholder.
Teaching note: Open circle for strict inequality.

13. [3 marks]
22 h =7200= 7200 s. Mass =40×7200=288000= 40 \times 7200 = 288\,000 g =288= 288 kg. Bags =288÷1.2=240= 288 \div 1.2 = 240.
Answer: 240240 bags
Teaching note: Unit consistency.

14. [3 marks]
Cycling =502015=15= 50 - 20 - 15 = 15. Percentage =1550×100%=30%= \frac{15}{50} \times 100\% = 30\%.
Answer: 30%30\%
Teaching note: Find remainder first.

15. [3 marks]
Apples =3u= 3u, oranges =5u= 5u. After: 5u+10=7u2u=10u=55u + 10 = 7u \Rightarrow 2u = 10 \Rightarrow u = 5. Apples =15= 15.
Answer: 1515
Teaching note: Same apple count, solve for u.

16. [3 marks]
Discount =40×0.30=12= 40 \times 0.30 = 12. Sale price =28= 28. Percent paid =70%= 70\%.
Answer: \28,, 70%$
Teaching note: Discount then subtract.


Section C (22 marks)

17. [5 marks]
(a) [2] Increase =60= 60, 60200×100=30%\frac{60}{200} \times 100 = 30\%.
(b) [3] March =260×0.9=234= 260 \times 0.9 = 234.
Answer: (a) 30%30\% (b) 234234 items

18. [5 marks]
Ali : Bob : Cai =2:3:5= 2 : 3 : 5. Cai - Ali =3= 3 units =1201= 120 \Rightarrow 1 unit =40= 40. Total =10= 10 units =400= 400.
Answer: \400$

19. [5 marks]
(a) [1] Net =30.5=2.5= 3 - 0.5 = 2.5 L/min.
(b) [2] Time =50÷2.5=20= 50 \div 2.5 = 20 min.
(c) [2] First half (10 min) fills 25 L, remaining 25 L at 3 L/min =813= 8\frac{1}{3} min, total =1813= 18\frac{1}{3} min.
Answer: (a) 2.52.5 (b) 2020 min (c) 181318\frac{1}{3} min

20. [5 marks]
(a) [2] Stamps new =1.5x= 1.5x, coins new =2.4x= 2.4x.
(b) [3] Total orig =4x= 4x, new =3.9x= 3.9x, change =0.1x= -0.1x, 0.1x4x×100=2.5%\frac{-0.1x}{4x} \times 100 = -2.5\%.
Answer: (a) 1.5x,2.4x1.5x, 2.4x (b) decrease 2.5%2.5\%