Secondary 1 Geography Practice Paper 5

TuitionGoWhere Practice Paper — Answer Key

Geography Secondary 1 — Map, Graph & Data Skills (Version 5)

Section A: Map Skills

Q1. [1 mark]

• Answer: Accept any valid 4-figure grid reference in the southern portion of the map (e.g., 1221, 1321, 1422 — depends on map provided).
• Marking note: Award 1 mark for a correct 4-figure grid reference with easting first, then northing. Accept only answers that fall within the southern half of the map extract.

Q2. [2 marks]

• Answer: Accept any valid 6-figure grid reference (e.g., 135274 — depends on map).
• Method: Divide the grid square into tenths. Estimate how many tenths across (easting) and how many tenths up (northing) the temple is located. For example, if the temple is about 5/10 across grid square 1327 and 4/10 up, the 6-figure reference is 135274.
• Marking note: Award 1 mark for the correct 6-figure reference and 1 mark for showing the estimation method (dividing into tenths). Common error: reversing easting and northing — penalise if the order is wrong.

Q3. [1 mark]

• Answer: Northwest (factory at 1424 is north and west of school at 1226).
• Marking note: Accept "NW" or "northwest". Do not accept vague answers like "up and left" — students must use compass directions.

Q4. [2 marks]

• Answer: Closely spaced contour lines indicate that the land is steep. This is because the elevation changes rapidly over a short horizontal distance.
• Marking note: Award 1 mark for stating "steep" and 1 mark for explaining that closely spaced contours mean a rapid change in height over a short distance. Accept equivalent phrasing.

Q5. [2 marks]

• Answer (any two of the following, 1 mark each):
  • The area has low contour values (e.g., below 20 m), indicating low elevation.
  • The area is near a river, which often floods low-lying areas.
  • The contour lines are widely spaced, indicating flat land.
  • The presence of a floodplain symbol or marshy area on the map.
• Marking note: Award 1 mark per valid piece of map evidence. Answers must refer to specific map features, not general statements.

Q6. [3 marks]

• Answer (example working):
  • Measure the road distance on the map using a piece of string or ruler (e.g., 8 cm).
  • Convert using the scale: 8 cm × 50,000 = 400,000 cm = 4 km.
  • The approximate distance is 4 km (accept 3.5–4.5 km depending on measurement).
• Marking note: Award 1 mark for measuring the road distance, 1 mark for applying the scale correctly, and 1 mark for the final answer in kilometres. Common error: forgetting to convert cm to km — penalise if the answer is left in cm.

Q7. [2 marks]

• Answer: Land use: Woodland / Forest (depends on map).
• Reason: The map shows tree symbols or green shading in grid square 1627, which indicates woodland.
• Marking note: Award 1 mark for correct land use identification and 1 mark for a valid reason linked to map evidence. Accept other valid land uses if supported by the map (e.g., residential, agricultural).

Q8. [2 marks]

• Answer (any two of the following, 1 mark each):
  • The settlement is near a road, providing access for transport and trade.
  • The settlement is near a river, providing a source of water for daily use.
  • The settlement is on flat land (widely spaced contours), making it easier to build houses.
  • The settlement is on higher ground, reducing the risk of flooding.
• Marking note: Award 1 mark per valid reason. Reasons must be supported by map evidence. Do not accept generic answers like "it is a nice place" without map reference.

Section B: Graph & Data Interpretation

Q9. [1 mark]

• Answer: Month
• Marking note: Award 1 mark for "month" or "time (month)". The independent variable is the one that is controlled or categorised — in this case, the months of the year.

Q10. [1 mark]

• Answer: December, 310 mm
• Marking note: Award 1 mark for both the correct month and the correct amount. Accept "Dec" for December.

Q11. [2 marks]

• Answer:
  • Working: 220 + 110 + 150 + 170 + 180 + 140 + 120 + 130 + 140 + 160 + 250 + 310 = 2,080 mm
• Marking note: Award 1 mark for showing the addition of all 12 values and 1 mark for the correct total. Accept minor arithmetic errors if the method is clearly shown (error carried forward).

Q12. [2 marks]

• Answer: Rainfall generally decreases from February (110 mm) to July (120 mm), with some fluctuations. It drops from 110 mm in February to a low of 120 mm in July, though there is a slight rise and fall in between (e.g., March to May shows an increase, then June to July shows a decrease).
• Marking note: Award 1 mark for identifying the overall decreasing trend and 1 mark for referencing specific data values to support the description. Accept answers that note the fluctuation as long as the overall trend is identified.

Q13. [2 marks]

• Answer:
  • Advantage: A bar graph makes it easy to compare the rainfall of individual months at a glance.
  • Disadvantage: A bar graph does not show the continuous trend or pattern over time as clearly as a line graph.
• Marking note: Award 1 mark for a valid advantage and 1 mark for a valid disadvantage. Accept equivalent phrasing. Common error: students may confuse bar graphs with line graphs — ensure the advantage/disadvantage is specific to bar graphs.

Q14. [3 marks]

• Answer: November (250 mm) and December (310 mm) are the wettest months because they recorded the highest rainfall amounts out of all 12 months. December recorded 310 mm, which is the highest value in the entire data set. November recorded 250 mm, which is the second highest. Together, these two months account for 560 mm of rainfall, which is significantly higher than other months.
• Marking note: Award 1 mark for identifying both months as the wettest, 1 mark for quoting specific data values (250 mm and 310 mm), and 1 mark for explaining that these are the highest values in the data set. Answers must include data references for full marks.

Q15. [2 marks]

• Answer (accept any one of the following):
  • Similarity: Both temperature and rainfall show variation throughout the year, meaning neither is constant.
  • Difference: Temperature remains relatively stable (26–28°C) throughout the year, while rainfall varies greatly (110–310 mm). This shows that Singapore has a more consistent temperature but highly variable rainfall.
• Marking note: Award 1 mark for identifying a valid similarity or difference and 1 mark for supporting the answer with data or explanation. Accept other valid comparisons.

Q16. [2 marks]

• Answer: The claim is partially correct. It is true that Singapore receives rain every month — even the driest month (February) still recorded 110 mm of rainfall. However, calling it "no dry season" is misleading because there is a clear variation in rainfall amounts. February (110 mm) receives much less rain than December (310 mm), so while it rains every month, some months are significantly drier than others.
• Marking note: Award 1 mark for evaluating the claim (agreeing partially or disagreeing) and 1 mark for using data from Table 1 to support the evaluation. Accept answers that argue the claim is correct as long as they acknowledge the variation in rainfall.

Section C: Data Response & Application

Q17. [2 marks]

• Answer:
  • Graph type: Bar graph
  • Reason: A bar graph is best for comparing discrete categories (five different stations) with numerical values (temperature). Each station is a separate category, so a bar graph allows easy comparison.
• Marking note: Award 1 mark for "bar graph" and 1 mark for a valid reason. Accept "pictograph" with a valid reason. Do not accept "line graph" — line graphs are for continuous data over time, not discrete categories.

Q18. [2 marks]

• Answer:
  • Station: C (34.0°C)
  • Reason: The concrete playground absorbs and radiates heat (concrete has a high heat capacity and is a dark surface), making the area warmer than shaded or water-adjacent locations.
• Marking note: Award 1 mark for identifying Station C and 1 mark for a valid explanation linked to the surface type (concrete) or lack of shade. Accept other valid reasons.

Q19. [3 marks]

• Answer:
  • Calculation: 32.5°C − 28.0°C = 4.5°C
  • Explanation: Station A is in an open field with no shade, so it receives direct sunlight and heats up more. Station B is under a large tree, which provides shade and reduces the amount of solar radiation reaching the ground. Additionally, trees cool the surrounding air through transpiration.
• Marking note: Award 1 mark for the correct calculation (4.5°C), 1 mark for explaining the effect of direct sunlight at Station A, and 1 mark for explaining the cooling effect of shade/transpiration at Station B. Accept equivalent explanations.

Q20. [3 marks]

• Answer: At 2 p.m., temperatures at all stations are likely to be higher than at 10 a.m. because the sun is higher in the sky and solar radiation is more intense in the afternoon. For example:
  • Station A (open field) could rise from 32.5°C to around 35°C or higher because it receives full sunlight with no shade.
  • Station C (concrete playground) could rise from 34.0°C to around 37°C because concrete retains and re-radiates heat, making it even hotter in the afternoon.
  • Station B (under a tree) would also increase but likely remain the coolest station because the tree continues to provide shade.
• Marking note: Award 1 mark for predicting that temperatures will increase, 1 mark for explaining why (more intense solar radiation in the afternoon), and 1 mark for referencing at least two stations with specific predictions. Accept reasonable temperature estimates. Answers must show understanding that shade moderates temperature increase.

END OF ANSWER KEY

This answer key is generated by TuitionGoWhere AI for practice purposes. It is not an official marking scheme from any examination board.