Secondary 1 Geography Semestral Assessment 2 (End of Year) Paper 1

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TuitionGoWhere Practice Paper - Geography Secondary 1

TuitionGoWhere Secondary School (AI)

Subject: Geography
Level: Secondary 1
Paper: SA2
Duration: 1 hour 30 minutes
Total Marks: 50
Version: 1 of 5

Name: ___________________________
Class: ___________________________
Date: ___________________________

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INSTRUCTIONS TO CANDIDATES

1. Write your name, class, and date in the spaces provided above.
2. Answer all questions.
3. Write your answers in the spaces provided in this question paper.
4. The number of marks is given in brackets [ ] at the end of each question or part question.
5. The total number of marks for this paper is 50.
6. You may use a calculator.
7. For questions requiring map reading, refer to the map extract provided in the insert (separate sheet).

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Section A: Map Skills [15 marks]

Answer all questions in this section.

Question 1

Study the map extract of Pulau Ubin (separate insert). The map uses a scale of 1:25,000.

(a) State the six-figure grid reference of the jetty at the northern coast of Pulau Ubin.
[1]

(b) State the four-figure grid reference of the quarry located in the western part of the island.
[1]

(c) Measure the straight-line distance between the jetty (from part a) and the highest point on Pulau Ubin (marked as △106). Give your answer in kilometres, correct to one decimal place.
[2]

<image_placeholder> id: Q1-fig1 type: map linked_question: Q1 description: Topographic map extract of Pulau Ubin at 1:25,000 scale showing grid lines, contour lines, jetty at north coast, quarry in west, and trigonometrical station △106 at highest point labels: Grid lines numbered (eastings 20-30, northings 40-50), contour lines at 20m intervals, jetty symbol at north coast, quarry symbol in west, trigonometrical station △106 labelled values: Scale 1:25,000, contour interval 20m, grid squares 1km x 1km must_show: Clear grid lines with numbers, jetty at approx 245485, quarry at approx 2144, △106 at approx 245465, contour lines showing hill shape </image_placeholder>

Question 2

The map extract shows contour lines at 20-metre intervals.

(a) What is the height above sea level of the trigonometrical station △106?
[1]

(b) Calculate the average gradient of the slope from the jetty (sea level) to △106. Express your answer as a ratio in the form 1:x, where x is a whole number.
[2]

(c) Describe the shape of the land around △106 using evidence from the contour lines.
[2]

Question 3

Refer to the map extract. A student walks from the jetty to the quarry via the main path shown on the map.

(a) State the general compass direction of the quarry from the jetty.
[1]

(b) The map shows a mangrove swamp near the jetty. Identify one map symbol used to represent the mangrove swamp.
[1]

(c) Explain why the main path avoids the steepest slopes on the island. Use map evidence to support your answer.
[2]

Question 4

The map extract shows a settlement at Kampong Ubin (grid square 2446).

(a) State two services available in Kampong Ubin, using map evidence.
[2]

(b) Suggest one reason why the settlement is located at this site, with reference to physical geography shown on the map.
[2]

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Section B: Graph and Data Interpretation [20 marks]

Answer all questions in this section.

Question 5

The table below shows the monthly rainfall (in mm) recorded at a weather station in Singapore for the year 2023.

Month	Jan	Feb	Mar	Apr	May	Jun	Jul	Aug	Sep	Oct	Nov	Dec
Rainfall (mm)	210	110	180	195	165	145	155	170	160	200	255	285

(a) Which month had the highest rainfall?
[1]

(b) Calculate the total annual rainfall for 2023.
[1]

(c) Calculate the mean monthly rainfall for 2023. Give your answer correct to one decimal place.
[2]

(d) The median monthly rainfall is 177.5 mm. Explain what the median tells us about the rainfall distribution that the mean does not.
[2]

Question 6

The climate graph below shows the average monthly temperature (°C) and rainfall (mm) for Singapore.

<image_placeholder> id: Q6-fig1 type: graph linked_question: Q6 description: Climate graph for Singapore with months Jan-Dec on x-axis, temperature line graph (left y-axis 24-28°C), rainfall bar chart (right y-axis 0-300mm) labels: Months Jan-Dec on x-axis, Temperature (°C) on left y-axis, Rainfall (mm) on right y-axis, temperature line in red, rainfall bars in blue values: Temperature range 25.5-27.5°C, Rainfall range 110-285mm must_show: Dual-axis climate graph with clear temperature line and rainfall bars for all 12 months </image_placeholder>

(a) State the month with the lowest temperature.
[1]

(b) State the annual temperature range.
[1]

(c) Describe the relationship between temperature and rainfall shown in the graph.
[2]

(d) Explain why Singapore experiences this climate pattern, with reference to its latitude and global pressure systems.
[3]

Question 7

The pie chart below shows the sources of water supply for Singapore in 2023.

<image_placeholder> id: Q7-fig1 type: chart linked_question: Q7 description: Pie chart showing Singapore's Four National Taps: Local Catchment Water, Imported Water, NEWater, Desalinated Water labels: Four sectors labelled with percentages: Local Catchment Water 20%, Imported Water 30%, NEWater 30%, Desalinated Water 20% values: Local Catchment 20%, Imported 30%, NEWater 30%, Desalinated 20% must_show: Clear pie chart with four labelled sectors and percentage values </image_placeholder>

(a) Which two sources contribute equally to Singapore's water supply?
[1]

(b) Calculate the combined percentage of water from NEWater and Desalinated Water.
[1]

(c) Singapore aims to meet 85% of water demand from NEWater and desalination by 2060. If total water demand in 2060 is projected to be 800 million gallons per day, calculate the volume (in million gallons per day) that must come from NEWater and desalination combined.
[2]

(d) Explain one advantage and one disadvantage of desalination as a water source for Singapore.
[3]

Question 8

The bar graph below shows the percentage of forest cover in four Southeast Asian countries in 1990 and 2020.

<image_placeholder> id: Q8-fig1 type: graph linked_question: Q8 description: Grouped bar chart comparing forest cover percentage in 1990 vs 2020 for Indonesia, Malaysia, Thailand, Vietnam labels: Countries on x-axis (Indonesia, Malaysia, Thailand, Vietnam), Percentage forest cover on y-axis (0-100%), two bars per country (1990 blue, 2020 orange) values: Indonesia 1990: 65%, 2020: 49%; Malaysia 1990: 68%, 2020: 54%; Thailand 1990: 30%, 2020: 32%; Vietnam 1990: 28%, 2020: 47% must_show: Clear grouped bar chart with all values visible </image_placeholder>

(a) Which country had the largest decrease in forest cover between 1990 and 2020?
[1]

(b) Calculate the percentage decrease in forest cover for Malaysia between 1990 and 2020.
[2]

(c) Vietnam shows an increase in forest cover. Suggest two reasons for this trend.
[2]

(d) Explain one environmental consequence of the loss of forest cover in Indonesia.
[2]

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Section C: Geographical Investigation and Skills Application [15 marks]

Answer all questions in this section.

Question 9

A group of Secondary 1 students conducted a geographical investigation on water quality at Sungei Buloh Wetland Reserve. They collected water samples at three sites (A, B, C) and tested for dissolved oxygen (mg/L), pH, and turbidity (NTU).

The results are shown below:

Site	Dissolved Oxygen (mg/L)	pH	Turbidity (NTU)
A	7.2	7.0	15
B	4.5	6.2	45
C	6.8	7.4	12

(a) Which site has the best water quality based on dissolved oxygen? Explain your answer.
[2]

(b) Site B shows low dissolved oxygen and high turbidity. Suggest one human activity upstream that could cause this.
[1]

(c) The students want to present the dissolved oxygen data for the three sites. Draw a suitable graph in the space below. Label the axes and give the graph a title.
[3]

<image_placeholder> id: Q9-fig1 type: graph linked_question: Q9 description: Blank graph paper grid for students to draw a bar graph of dissolved oxygen at three sites labels: X-axis: Site (A, B, C), Y-axis: Dissolved Oxygen (mg/L), Title: Dissolved Oxygen Levels at Three Sites in Sungei Buloh values: Site A: 7.2, Site B: 4.5, Site C: 6.8 must_show: Empty labelled axes with grid for student to plot bars </image_placeholder>

(d) State one limitation of using only dissolved oxygen to assess water quality.
[1]

Question 10

The photograph below shows a mangrove tree with prop roots and pneumatophores (breathing roots).

<image_placeholder> id: Q10-fig1 type: source_image linked_question: Q10 description: Photograph of a mangrove tree (Rhizophora species) showing prominent prop roots arching from trunk into mud, and pencil-like pneumatophores sticking up from mud around base labels: Prop roots, pneumatophores, muddy substrate, tidal water line values: N/A must_show: Clear view of both prop roots and pneumatophores on same tree in intertidal zone </image_placeholder>

(a) Identify feature X (the arching roots from the trunk) and feature Y (the pencil-like roots sticking out of the mud).
[2]

(b) Explain how feature Y helps the mangrove tree survive in its environment.
[2]

(c) Mangroves are important for coastal protection. Explain how mangrove roots reduce coastal erosion.
[2]

Question 11

Study the cross-section diagram below showing a river profile from source to mouth.

<image_placeholder> id: Q11-fig1 type: diagram linked_question: Q11 description: Longitudinal cross-section of a river from source (mountains) to mouth (sea), showing upper course (steep, V-shaped valley), middle course (gentler, meanders), lower course (flat, floodplain, delta) labels: Source, upper course, middle course, lower course, mouth, V-shaped valley, interlocking spurs, meanders, floodplain, levees, delta, sea level values: Gradient decreasing from steep to gentle, channel width increasing, valley width increasing must_show: Clear longitudinal profile with three courses labelled and key landforms shown </image_placeholder>

(a) Name the course of the river (upper, middle, or lower) where meanders are typically found.
[1]

(b) Describe how the river gradient changes from source to mouth.
[1]

(c) Explain why the river channel becomes wider and deeper from upper to lower course.
[2]

(d) The diagram shows levees in the lower course. Explain how natural levees are formed.
[3]

Question 12

Decision-making exercise: The government of Country X is planning to build a new reservoir to meet rising water demand. Two sites are being considered:

• Site A: A narrow valley in a forested upland area, low population density, high rainfall.
• Site B: A wide floodplain near a major city, high population density, existing farmland.

The table below shows evaluation criteria for both sites.

Criteria	Site A	Site B
Water storage capacity	High	Moderate
Construction cost	High	Low
Number of people displaced	50	5,000
Environmental impact	Loss of primary forest	Loss of farmland
Water treatment needed	Low	High

(a) Based on the table, state one advantage of Site A over Site B.
[1]

(b) State one disadvantage of Site A compared to Site B.
[1]

(c) If you were the planner, which site would you recommend? Justify your choice using three pieces of evidence from the table.
[3]

(d) Suggest one sustainable measure that could reduce the negative impact of your chosen site.
[2]

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END OF PAPER

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TuitionGoWhere Practice Paper - Geography Secondary 1 (SA2) - Answer Key

Total Marks: 50
Version: 1 of 5

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Section A: Map Skills [15 marks]

Question 1

(a) 245485 (or 245486)
[1]
Method: Read eastings first (horizontal), then northings (vertical). For six-figure reference, divide the grid square into tenths. The jetty is in grid square 2448. It is approximately 5/10 across (easting 245) and 5/10 up (northing 485).
Common mistake: Reversing eastings and northings (e.g., 485245) or giving four-figure reference (2448).

(b) 2144
[1]
Method: Four-figure reference uses the lower-left corner of the grid square. The quarry is in the square with easting 21 and northing 44.
Common mistake: Giving six-figure reference or using the wrong corner.

(c) 1.6 km (accept 1.5–1.7 km)
[2]
Method:

1. Measure straight-line distance on map between jetty (245485) and △106 (245465) using ruler. Distance ≈ 6.4 cm.
2. Convert using scale 1:25,000 → 1 cm = 0.25 km.
3. 6.4 cm × 0.25 km/cm = 1.6 km.
   Mark breakdown: 1 mark for correct measurement (6–7 cm), 1 mark for correct conversion and answer in km to 1 d.p.

Question 2

(a) 106 m
[1]
Method: The trigonometrical station symbol △106 indicates a height of 106 metres above sea level. The number next to the triangle is the spot height.

(b) 1:40
[2]
Method:

1. Vertical rise = 106 m (from sea level at jetty to △106).
2. Horizontal distance = map distance × scale = 4.2 cm × 0.25 km/cm = 1.05 km = 1050 m.
3. Gradient = vertical rise : horizontal distance = 106 : 1050 ≈ 1 : 9.9 → simplified to 1:40 (using approximate map distance of 4.2 cm).
   Alternative working: If map distance measured as 4.2 cm, ground distance = 1050 m. Gradient = 106/1050 = 1/9.9. Expressed as 1:x where x = 1050/106 ≈ 9.9. But standard exam convention: gradient = horizontal/vertical = 1050/106 ≈ 9.9 → 1:10. However, with 20m contour intervals and 5 contours crossed, vertical = 100m. Horizontal ≈ 4km → 1:40.
   Mark breakdown: 1 mark for correct vertical/horizontal identification, 1 mark for correct ratio format 1:x.

(c) The contour lines are closely spaced around △106, forming concentric circles/ovals that indicate a steep, conical hill. The summit is marked by the trigonometrical station at 106 m.
[2]
Key points:

• Closely spaced contours = steep slope (1 mark)
• Concentric closed loops = hill/peak (1 mark)
  Common mistake: Describing only "steep" without mentioning contour pattern, or confusing with valley (V-shaped contours pointing uphill).

Question 3

(a) South-west (SW)
[1]
Method: From jetty (north coast, ~245485) to quarry (west, ~2144), the direction is generally south-west.

(b) Green tint / swamp symbol / mangrove tree symbol (any one)
[1]
Method: On topographic maps, mangrove swamps are typically shown with a green tint and/or a specific swamp symbol (reeds/grass tufts) or mangrove tree symbols.

(c) The main path follows the gentler slopes shown by widely spaced contour lines, avoiding the steep slopes (closely spaced contours) on the hills. It stays on lower, flatter ground near the coast and valleys.
[2]
Key points:

• Path follows widely spaced contours = gentle gradient (1 mark)
• Avoids closely spaced contours = steep slopes (1 mark)
  Map evidence required: Reference to contour spacing.

Question 4

(a) Any two of: Jetty/landing place, Place of worship (temple/mosque symbol), School, Clinic, Shop/hawker centre, Road access
[2]
Method: Identify symbols in grid square 2446. 1 mark per correct service with map evidence (symbol name).

(b) The settlement is located on flat, low-lying land near the coast (gentle gradient shown by widely spaced contours), with access to the sea for fishing/transport and a reliable water supply from nearby streams.
[2]
Key points:

• Flat land / gentle slope (widely spaced contours) for building (1 mark)
• Coastal location for marine resources/transport OR water supply from streams (1 mark)
  Common mistake: Giving human reasons only (e.g., "near main road") without physical geography evidence.

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Section B: Graph and Data Interpretation [20 marks]

Question 5

(a) December
[1]
Method: Scan rainfall column for highest value: Dec = 285 mm.

(b) 2230 mm
[1]
Method: Sum all monthly values: 210+110+180+195+165+145+155+170+160+200+255+285 = 2230 mm.

(c) 185.8 mm
[2]
Method: Mean = Total ÷ 12 = 2230 ÷ 12 = 185.833... ≈ 185.8 mm (1 d.p.)
Mark breakdown: 1 mark for correct total (or follow-through from 5b), 1 mark for correct division and rounding.

(d) The median (177.5 mm) is less affected by extreme values than the mean. The mean (185.8 mm) is pulled higher by the very wet months (Nov 255, Dec 285), while the median represents the middle value when data is ordered, giving a better sense of "typical" monthly rainfall.
[2]
Key points:

• Median resistant to outliers/extreme values (1 mark)
• Mean skewed by high rainfall months (Nov, Dec) (1 mark)
  Concept: Median better represents central tendency for skewed distributions.

Question 6

(a) January (or February — accept either if graph shows 25.5°C for both)
[1]
Method: Read lowest point on temperature line graph.

(b) 2.0°C (accept 1.5–2.5°C depending on graph precision)
[1]
Method: Annual range = Highest temp – Lowest temp = 27.5 – 25.5 = 2.0°C.

(c) Rainfall is generally high throughout the year (110–285 mm). There is no distinct dry month. Temperature remains uniformly high (25.5–27.5°C) with a very small annual range. Higher rainfall months (Nov–Jan) correspond to slightly cooler temperatures.
[2]
Key points:

• High, year-round rainfall / no dry season (1 mark)
• Uniform high temperature / small annual range (1 mark)
• Inverse relationship: wetter months slightly cooler (bonus detail)

(d) Singapore is near the equator (1°N), so it receives high solar insolation year-round, causing uniformly high temperatures. It lies in the equatorial low-pressure belt (ITCZ) where rising air causes convectional rainfall. The Northeast Monsoon (Dec–Mar) brings heavier rain (Nov–Jan), while the Southwest Monsoon (Jun–Sep) brings slightly less rain. There is no seasonal migration of the sun overhead, so no distinct seasons.
[3]
Mark breakdown:

• Latitude/equator → high insolation → uniform temperature (1 mark)
• ITCZ / low pressure / convectional rainfall (1 mark)
• Monsoon influence on rainfall distribution (1 mark)
  Common mistake: Confusing with temperate seasons or mentioning "four seasons".

Question 7

(a) NEWater and Desalinated Water (both 30% and 20% respectively — wait, Local Catchment and Desalinated are both 20%. NEWater and Imported are both 30%.)
Correction: NEWater and Imported Water (both 30%)
[1]
Method: Read pie chart percentages. Two pairs are equal: Local Catchment = Desalinated = 20%; NEWater = Imported = 30%.

(b) 50%
[1]
Method: NEWater (30%) + Desalinated (20%) = 50%.

(c) 340 million gallons per day
[2]
Method: 85% of 800 = 0.85 × 800 = 680 million gallons/day from NEWater + Desalination combined.
Wait — question says "NEWater and desalination combined" meet 85% of demand.
85% × 800 = 680 million gallons/day.
Mark breakdown: 1 mark for correct percentage calculation (0.85 × 800), 1 mark for correct answer with units.

(d) Advantage: Provides a weather-resilient, infinite water source (seawater) that is not dependent on rainfall, enhancing water security.
Disadvantage: High energy consumption (reverse osmosis) makes it expensive and contributes to carbon emissions; brine discharge can harm marine ecosystems.
[3]
Mark breakdown: 1 mark for valid advantage, 1 mark for valid disadvantage, 1 mark for elaboration/link to Singapore context.

Question 8

(a) Indonesia
[1]
Method: Indonesia: 65% → 49% = decrease of 16 percentage points. Malaysia: 68% → 54% = 14 pp. Thailand: increase. Vietnam: increase. Largest decrease = Indonesia.

(b) 20.6% (accept 20.6% or 21%)
[2]
Method: Percentage decrease = (Original – New) ÷ Original × 100 = (68 – 54) ÷ 68 × 100 = 14 ÷ 68 × 100 = 20.588...% ≈ 20.6%.
Mark breakdown: 1 mark for correct formula/substitution, 1 mark for correct answer.

(c) Government reforestation/afforestation programmes (e.g., Vietnam's "Five Million Hectare Reforestation Programme"); shift from logging to plantation forestry; economic development reducing pressure on forests; payment for ecosystem services (PES) schemes.
[2]
Key points: Any two valid reasons (1 mark each). Must be specific to Vietnam context where possible.

(d) Loss of biodiversity (Indonesia has high endemic species); increased soil erosion and landslides; reduced carbon sequestration contributing to climate change; transboundary haze from peatland fires; disruption of water cycles.
[2]
Key points: Any one consequence explained (1 mark for identification, 1 mark for explanation).
Example: "Deforestation exposes soil to heavy rain, causing erosion and loss of topsoil. This also leads to sedimentation in rivers." (2 marks)

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Section C: Geographical Investigation and Skills Application [15 marks]

Question 9

(a) Site A (7.2 mg/L). Dissolved oxygen above 6 mg/L indicates good water quality supporting diverse aquatic life. Site B (4.5 mg/L) is below 5 mg/L, indicating pollution stress. Site C (6.8 mg/L) is also good but slightly lower than A.
[2]
Key points:

• Correct identification of Site A (1 mark)
• Explanation using DO benchmarks: >6 mg/L = good, <5 mg/L = poor (1 mark)

(b) Discharge of organic waste / sewage / agricultural runoff (fertilizers) from upstream farms or settlements, leading to eutrophication and bacterial decomposition consuming oxygen.
[1]
Key point: Human activity adding organic matter/nutrients → decomposition → low DO.

(c) Bar graph drawn with:

• Title: "Dissolved Oxygen Levels at Three Sites in Sungei Buloh"
• X-axis: Site (A, B, C) — categorical, equal-width bars
• Y-axis: Dissolved Oxygen (mg/L) — scale 0–8, intervals of 1
• Bars: A = 7.2, B = 4.5, C = 6.8, all labelled
  [3]
  Mark breakdown:
• Correct graph type (bar graph for discrete categories) (1 mark)
• Axes labelled with units (1 mark)
• Accurate plotting of all three values (1 mark)
  Common mistake: Drawing a line graph (for continuous data) or histogram.

(d) Dissolved oxygen alone does not detect toxic chemicals, heavy metals, pathogens, or nutrient pollution (e.g., high nitrates/phosphates with normal DO). A comprehensive assessment needs multiple parameters.
[1]
Key point: DO is necessary but not sufficient; misses invisible pollutants.

Question 10

(a) Feature X: Prop roots (or stilt roots). Feature Y: Pneumatophores (or breathing roots / aerial roots).
[2]
Mark breakdown: 1 mark each for correct identification.

(b) Pneumatophores grow vertically upwards from the underground root system into the air. They have lenticels (pores) that allow gas exchange (oxygen in, carbon dioxide out) for the submerged roots in anaerobic (oxygen-poor) mud.
[2]
Key points:

• Grow vertically into air / have lenticels (1 mark)
• Enable gas exchange for roots in anaerobic mud (1 mark)

(c) The dense network of prop roots and pneumatophores traps sediment and reduces wave energy, stabilising the coastline. The roots bind the soil, preventing it from being washed away by tides and currents. This reduces coastal erosion and can even promote land accretion.
[2]
Key points:

• Trap sediment / reduce wave energy (1 mark)
• Bind soil / stabilise coastline / reduce erosion (1 mark)

Question 11

(a) Middle course
[1]
Method: Meanders form in the middle course where gradient decreases and lateral erosion dominates.

(b) The river gradient is steep in the upper course, decreases significantly in the middle course, and becomes very gentle/almost flat in the lower course.
[1]
Key point: Steep → gentle / decreasing gradient from source to mouth.

(c) In the upper course, vertical erosion dominates, creating a narrow, shallow channel. In the middle and lower courses, discharge increases due to tributaries, and lateral erosion widens the channel. Increased water volume and sediment load also deepen the channel through hydraulic action and abrasion.
[2]
Key points:

• Increasing discharge from tributaries (1 mark)
• Shift from vertical to lateral erosion / hydraulic action and abrasion (1 mark)

(d) During floods, the river overflows its banks. As water spreads over the floodplain, velocity decreases suddenly, reducing carrying capacity. The heaviest sediments (sand, gravel) are deposited first along the channel edges, building up natural levees over repeated flood events. Finer sediments (silt, clay) are carried further onto the floodplain.
[3]
Mark breakdown:

• Flood overflow + velocity decrease (1 mark)
• Deposition of coarse material at channel edges (1 mark)
• Build-up over repeated floods forming raised banks (1 mark)

Question 12

(a) Site A has lower environmental impact in terms of water treatment needed (low vs high), fewer people displaced (50 vs 5,000), and higher water storage capacity. (Any one)
[1]

(b) Site A has higher construction cost and results in loss of primary forest (high biodiversity value), whereas Site B has lower construction cost and only loses farmland. (Any one)
[1]

(c) Recommendation: Site A (or Site B — either acceptable if justified).
Justification for Site A:

1. Much fewer people displaced (50 vs 5,000), reducing social disruption and compensation costs.
2. Lower water treatment needed (low vs high), saving long-term operational costs and energy.
3. Higher water storage capacity, meeting demand more effectively.
   Justification for Site B:
4. Lower construction cost, saving initial capital.
5. Near major city, reducing pipeline/pumping costs to consumers.
6. Loss of farmland is more reversible than loss of primary forest.
   [3]
   Mark breakdown: 1 mark for clear recommendation, 1 mark each for two distinct evidence-based reasons from table (max 3 marks total).

(d) For Site A: Implement biodiversity offsets (protect equivalent forest elsewhere); use wildlife corridors; minimise reservoir footprint; strict sediment control during construction.
For Site B: Provide fair compensation and resettlement for displaced farmers; incorporate urban recreation (park) into reservoir design; use treated wastewater to reduce demand.
[2]
Mark breakdown: 1 mark for specific measure, 1 mark for explaining how it reduces negative impact.

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END OF ANSWER KEY