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Primary 6 PSLE Mathematics Whole Numbers Quiz

Free P6 PSLE Maths Whole Numbers quiz, Nemo3 AI version, with questions, answers, and PSLE-focused practice for Singapore students.

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Primary 6 PSLE Mathematics Quiz - Whole Numbers (Answer Key)

Total Marks: 50


Section A: Multiple-Choice Questions (10 marks)

1. What is the value of the digit 7 in the number 4,728,391? [2]

Answer: (2) 700,000

Explanation:
The digit 7 is in the hundred thousands place.
Value = 7 × 100,000 = 700,000.

Common mistake: Confusing place values (e.g., thinking it's 70,000 which is the ten thousands place).


2. Round 3,847,256 to the nearest ten thousand. [2]

Answer: (2) 3,850,000

Explanation:
Look at the digit in the thousands place (7). Since 7 ≥ 5, round up the ten thousands digit (4) to 5.
3,847,256 → 3,850,000.

Common mistake: Rounding to the nearest thousand (3,847,000) or hundred thousand (3,800,000) instead.


3. Which of the following numbers is divisible by both 3 and 4? [2]

Answer: (2) 2,352

Explanation:
A number divisible by both 3 and 4 must be divisible by 12.
Check each option:

  • 1,234: Sum of digits = 10 (not divisible by 3) ✗
  • 2,352: Sum of digits = 12 (divisible by 3); last two digits 52 ÷ 4 = 13 (divisible by 4) ✓
  • 3,476: Sum of digits = 20 (not divisible by 3) ✗
  • 4,589: Sum of digits = 26 (not divisible by 3) ✗

4. Find the value of 48×25×448 \times 25 \times 4. [2]

Answer: (1) 4,800

Explanation:
Use the associative property to group numbers for easier mental calculation:
48×25×4=48×(25×4)=48×100=4,80048 \times 25 \times 4 = 48 \times (25 \times 4) = 48 \times 100 = 4,800.

Alternative: 48×25=1,20048 \times 25 = 1,200, then 1,200×4=4,8001,200 \times 4 = 4,800.


5. A number when divided by 8 gives a quotient of 1,234 and a remainder of 5. What is the number? [2]

Answer: (1) 9,877

Explanation:
Use the division algorithm: Dividend = Divisor × Quotient + Remainder
Number = 8 × 1,234 + 5 = 9,872 + 5 = 9,877.


Section B: Short-Answer Questions (20 marks)

6. Write 6,040,305 in words. [2]

Answer: Six million forty thousand three hundred and five

Explanation:
Break down by place value periods:

  • 6,000,000 = Six million
  • 040,000 = Forty thousand (the zero in hundred thousands is not read)
  • 305 = Three hundred and five

Marking: 1 mark for "Six million", 1 mark for "forty thousand three hundred and five" (accept without "and").


7. Find the product of 3,407 and 28. [2]

Answer: 95,396

Working:

    3,407
  ×    28
  -------
   27,256   (3,407 × 8)
+ 68,140    (3,407 × 20)
  -------
   95,396

Marking: 1 mark for correct method (partial products), 1 mark for correct final answer.


8. Divide 84,372 by 12. [2]

Answer: 7,031

Working (Long Division):

      7,031
12) 84,372
    -84
     ---
      03
      -0
      ---
      37
     -36
      ---
       12
      -12
       ---
        0

Check: 7,031 × 12 = 84,372 ✓

Marking: 1 mark for correct method, 1 mark for correct final answer.


9. Find the value of 72×(15098)÷672 \times (150 - 98) \div 6. [2]

Answer: 624

Working:
Step 1: Brackets first: 15098=52150 - 98 = 52
Step 2: 72×52÷672 \times 52 \div 6
Step 3: Division before multiplication (left to right): 72÷6=1272 \div 6 = 12
Step 4: 12×52=62412 \times 52 = 624

Alternative: 72×52=3,74472 \times 52 = 3,744, then 3,744÷6=6243,744 \div 6 = 624.

Marking: 1 mark for correct order of operations, 1 mark for correct final answer.


10. What is the greatest possible whole number that when rounded to the nearest hundred gives 5,600? [2]

Answer: 5,649

Explanation:
When rounding to the nearest hundred, numbers from 5,550 to 5,649 round to 5,600.
The greatest whole number in this range is 5,649.

Common mistake: Answering 5,650 (which rounds to 5,700) or 5,600 (which is the rounded value, not the original).


11. Find the sum of all the common factors of 36 and 48. [2]

Answer: 91

Working:
Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36
Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
Common factors: 1, 2, 3, 4, 6, 12
Sum = 1 + 2 + 3 + 4 + 6 + 12 = 28

Wait, let me recalculate: 1+2+3+4+6+12 = 28, not 91. Let me check again.

Actually: 1+2=3, +3=6, +4=10, +6=16, +12=28. Correct answer: 28

Marking: 1 mark for listing common factors correctly, 1 mark for correct sum.


12. A number is a multiple of 7. When it is divided by 5, the remainder is 3. What is the smallest possible value of this number if it is greater than 50? [2]

Answer: 63

Working:
Multiples of 7 greater than 50: 56, 63, 70, 77, 84, 91, 98...
Check remainder when divided by 5:

  • 56 ÷ 5 = 11 remainder 1 ✗
  • 63 ÷ 5 = 12 remainder 3 ✓

Alternative method: The number = 5k + 3 = 7m. Testing values: 5(12)+3=63=7(9).


13. Find the value of 5,000,0003,487,2915,000,000 - 3,487,291. [2]

Answer: 1,512,709

Working:

  5,000,000
- 3,487,291
-----------
  1,512,709

Check: 1,512,709 + 3,487,291 = 5,000,000 ✓

Marking: 1 mark for correct method (regrouping across zeros), 1 mark for correct final answer.


14. There are 2,345 apples. They are packed into boxes of 15 apples each. How many apples are left unpacked? [2]

Answer: 5

Working:
2,345 ÷ 15 = 156 remainder 5
(156 × 15 = 2,340; 2,345 - 2,340 = 5)

Marking: 1 mark for correct division, 1 mark for correct remainder.


15. Evaluate 24×37+24×6324 \times 37 + 24 \times 63. [2]

Answer: 2,400

Working:
Use the distributive property:
24×37+24×63=24×(37+63)=24×100=2,40024 \times 37 + 24 \times 63 = 24 \times (37 + 63) = 24 \times 100 = 2,400

Alternative: 24×37=88824 \times 37 = 888, 24×63=1,51224 \times 63 = 1,512, 888+1,512=2,400888 + 1,512 = 2,400.

Marking: 1 mark for using distributive property or correct individual products, 1 mark for correct final answer.


Section C: Structured / Long-Answer Questions (20 marks)

16. A factory produced 45,680 toys in January. In February, it produced 3,420 fewer toys than in January. In March, it produced twice as many toys as in February. How many toys did the factory produce in the three months altogether? [4]

Answer: 169,780 toys

Working:
January: 45,680 toys
February: 45,680 - 3,420 = 42,260 toys
March: 42,260 × 2 = 84,520 toys
Total: 45,680 + 42,260 + 84,520 = 172,460 toys

Wait, let me recalculate:
45,680 + 42,260 = 87,940
87,940 + 84,520 = 172,460

Correct answer: 172,460 toys

Marking:

  • 1 mark for February production (42,260)
  • 1 mark for March production (84,520)
  • 1 mark for correct addition of all three months
  • 1 mark for correct final answer with units

17. Mr Tan had some money. He spent 25\frac{2}{5} of it on a television set and 13\frac{1}{3} of the remainder on a washing machine. He had $1,200 left. How much money did Mr Tan have at first? [4]

Answer: $3,000

Working:
Let the original amount be xx.
Spent on TV: 25x\frac{2}{5}x
Remainder after TV: x25x=35xx - \frac{2}{5}x = \frac{3}{5}x
Spent on washing machine: 13×35x=15x\frac{1}{3} \times \frac{3}{5}x = \frac{1}{5}x
Total spent: 25x+15x=35x\frac{2}{5}x + \frac{1}{5}x = \frac{3}{5}x
Left: x35x=25x=1,200x - \frac{3}{5}x = \frac{2}{5}x = 1,200
x=1,200÷25=1,200×52=3,000x = 1,200 \div \frac{2}{5} = 1,200 \times \frac{5}{2} = 3,000

Check:
Original: 3,000TV:3,000 TV: \frac{2}{5} \times 3,000 = 1,200Remainder: Remainder:1,800Washingmachine: Washing machine:\frac{1}{3} \times 1,800 = 600Left: Left:1,800 - 600 = 1,200$ ✓

Marking:

  • 1 mark for finding remainder after TV (35x\frac{3}{5}x)
  • 1 mark for finding amount spent on washing machine (15x\frac{1}{5}x)
  • 1 mark for setting up equation for amount left (25x=1,200\frac{2}{5}x = 1,200)
  • 1 mark for correct final answer with units

18. The sum of three consecutive even numbers is 2,394. What is the largest of these three numbers? [4]

Answer: 800

Working:
Let the three consecutive even numbers be xx, x+2x+2, x+4x+4.
x+(x+2)+(x+4)=2,394x + (x+2) + (x+4) = 2,394
3x+6=2,3943x + 6 = 2,394
3x=2,3883x = 2,388
x=796x = 796

The three numbers are 796, 798, 800.
Largest = 800.

Alternative (using average):
Average = 2,394 ÷ 3 = 798 (this is the middle number)
Largest = 798 + 2 = 800.

Marking:

  • 1 mark for representing the numbers correctly (e.g., xx, x+2x+2, x+4x+4)
  • 1 mark for forming the correct equation
  • 1 mark for solving to find the smallest/middle number
  • 1 mark for correct final answer (largest number)

19. A bookshelf has 5 shelves. The first shelf has 48 books. Each subsequent shelf has 12 more books than the previous shelf. How many books are there on the bookshelf altogether? [4]

Answer: 360 books

Working:
This is an arithmetic sequence:
Shelf 1: 48
Shelf 2: 48 + 12 = 60
Shelf 3: 60 + 12 = 72
Shelf 4: 72 + 12 = 84
Shelf 5: 84 + 12 = 96

Total = 48 + 60 + 72 + 84 + 96 = 360

Alternative (using sum formula):
Sum = n2×(first+last)=52×(48+96)=2.5×144=360\frac{n}{2} \times (\text{first} + \text{last}) = \frac{5}{2} \times (48 + 96) = 2.5 \times 144 = 360

Marking:

  • 1 mark for correctly finding books on each shelf (or using pattern)
  • 1 mark for correct addition / sum formula
  • 1 mark for correct total
  • 1 mark for correct final answer with units

20. A rectangular tank measures 60 cm by 40 cm by 30 cm. It is filled with water to a height of 20 cm. How many more litres of water are needed to fill the tank completely? (1 litre = 1,000 cm³) [4]

Answer: 24 litres

Working:
Volume of tank = 60 × 40 × 30 = 72,000 cm³
Volume of water currently = 60 × 40 × 20 = 48,000 cm³
Volume needed = 72,000 - 48,000 = 24,000 cm³
Litres needed = 24,000 ÷ 1,000 = 24 litres

Alternative:
Height needed = 30 - 20 = 10 cm
Volume needed = 60 × 40 × 10 = 24,000 cm³ = 24 litres

Marking:

  • 1 mark for finding total volume of tank (72,000 cm³)
  • 1 mark for finding current volume of water (48,000 cm³) OR height needed (10 cm)
  • 1 mark for finding volume needed in cm³ (24,000 cm³)
  • 1 mark for correct conversion to litres (24 litres) and final answer with units

End of Answer Key