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Primary 6 PSLE Mathematics Multiplication Division Quiz

Free P6 PSLE Maths Multiplication Division quiz, Ox AI version, with questions, answers, and PSLE-focused practice for Singapore students.

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Primary 6 PSLE Mathematics AI Generated Generated by Ox Alpha Updated 2026-08-27

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Primary 6 PSLE Mathematics Quiz - Multiplication Division: Answer Key

Version: 1 of 5 | Total Marks: 60 | Duration: 60 minutes

Marking guidance: Award method (M) marks for correct strategy even if a slip occurs late; award answer (A) marks for accurate, correctly-united final answers.

Answer 1.

Answer: 9342 (2 marks)

  • Concept: Split 27 into 20+720 + 7 and multiply each part.
  • 346×20=6920346 \times 20 = 6920
  • 346×7=2422346 \times 7 = 2422
  • 6920+2422=93426920 + 2422 = 9342
  • Check: 9342÷27=3469342 \div 27 = 346. ✓
  • Marking: M1 for correct partial products/column method, A1 for 9342.
  • Common mistake: Misaligning place values when adding partial products.

Answer 2.

Answer: 508 (2 marks)

  • Concept: Long division, one digit-place at a time.
  • 81÷16=581 \div 16 = 5 remainder 11; bring down 2 → 12÷16=012 \div 16 = 0 remainder 1212 (write the 0); bring down 8 → 128÷16=8128 \div 16 = 8.
  • Quotient: 508. Check: 508×16=8128508 \times 16 = 8128. ✓
  • Marking: M1 for structured long division, A1 for 508.
  • Common mistake: Omitting the zero in the tens place, giving 58.

Answer 3.

Answer: 48 (2 marks)

  • Concept: Order of operations — do ÷\div and ×\times first, working left to right, then ++.
  • 36÷6=636 \div 6 = 6; then 6×4=246 \times 4 = 24; then 24+24=4824 + 24 = 48.
  • Marking: M1 for correct order of operations, A1 for 48.
  • Common mistake: Adding first (24+36=6024 + 36 = 60), which gives a wrong result.

Answer 4.

Answer: 150 (2 marks)

  • Method: 3.75×40=375×40÷100=15000÷100=1503.75 \times 40 = 375 \times 40 \div 100 = 15000 \div 100 = 150.
  • Alternative: 3.75×4=153.75 \times 4 = 15, then ×10=150\times 10 = 150.
  • Marking: M1 for valid method, A1 for 150.
  • Common mistake: Placing the decimal point wrongly (e.g., 15.00 vs 150).

Answer 5.

Answer: 3.6 (2 marks)

  • Method: 17×3=5117 \times 3 = 51, remainder 10.210.2. Place the decimal point, then 102102 tenths ÷17=6\div 17 = 6 tenths.
  • Result: 3.63.6. Check: 17×3.6=61.217 \times 3.6 = 61.2. ✓
  • Marking: M1 for correct division process, A1 for 3.6.

Answer 6.

Answer: 42 (2 marks)

  • Concept: Multiplication and division are inverse operations, so the missing factor is found by dividing.
  • 1890÷45=421890 \div 45 = 42.
  • Check: 45×42=189045 \times 42 = 1890. ✓
  • Marking: M1 for dividing 1890 by 45, A1 for 42.

Answer 7.

Answer: 10 000 (2 marks)

  • Concept: Rounding makes numbers friendly for mental estimation.
  • 498500498 \approx 500 (nearest ten); 212021 \approx 20 (nearest ten).
  • Estimate: 500×20=10000500 \times 20 = 10\,000.
  • Marking: M1 for both correct roundings, A1 for 10 000.
  • Note: The exact value 10 458 is close to the estimate, showing the estimate is reasonable.

Answer 8.

Answer: 2148 and 4728 (2 marks)

  • Concept: Divisible by both 3 and 4 means divisible by 12.
  • Test for 3 (digit sum divisible by 3): 2148 → 15 ✓; 3150 → 9 ✓; 4728 → 21 ✓; 5310 → 9 ✓.
  • Test for 4 (last two digits divisible by 4): 48 ✓; 50 ✗; 28 ✓; 10 ✗.
  • Only 2148 and 4728 pass both tests.
  • Marking: A2 for both correct; A1 for one correct with evidence of testing.

Answer 9.

Answer: 7 buses (2 marks)

  • 250÷40=6250 \div 40 = 6 remainder 1010.
  • Six buses seat only 240 pupils, so the remaining 10 pupils still need a bus.
  • Smallest number of buses: 6+1=76 + 1 = 7.
  • Marking: M1 for division with remainder, A1 for 7.
  • Common mistake: Answering 6 — always round up for grouping real people/objects.

Answer 10.

Answer: 99 stickers (2 marks)

  • Concept: Use units. Ravi has 1 unit; Mei has 3 units.
  • Total: 1u+3u=4u=1321u + 3u = 4u = 132, so 1u=132÷4=331u = 132 \div 4 = 33.
  • Mei: 3×33=993 \times 33 = 99 stickers.
  • Marking: M1 for unit model or equation, A1 for 99.
  • Common mistake: Giving 33 (Ravi's amount) instead of Mei's.

Answer 11.

Answer: $45.50 (3 marks)

  • Step 1 (unit cost): 26 \div 8 = \3.25$ per notebook.
  • Step 2 (scale up): 3.25 \times 14 = \45.50$.
  • Concept: Unitary method — find the value of one item first, then multiply.
  • Marking: M1 for 26÷826 \div 8, A1 for 3.253.25, A1 for final 45.50with45.50 with sign.

Answer 12.

Answer: 1012 pages (3 marks)

  • Step 1 (rate): 345÷15=23345 \div 15 = 23 pages per minute.
  • Step 2 (total): 23×44=101223 \times 44 = 1012 pages.
  • Concept: Rate = total ÷ time; new total = rate × new time.
  • Marking: M1 for finding rate, A1 for 23 pages/min, A1 for 1012 pages.

Answer 13.

Answer: 24 full boxes, 120 tarts left over (3 marks)

  • Step 1: 6000÷2456000 \div 245. Since 245×24=5880245 \times 24 = 5880, quotient is 24.
  • Step 2: Leftover =60005880=120= 6000 - 5880 = 120 tarts.
  • Concept: The quotient gives complete groups; the remainder is what cannot fill another box.
  • Marking: M1 for division setup, A1 for 24 boxes, A1 for 120 tarts.
  • Common mistake: Rounding the quotient instead of reporting quotient and

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Primary 6 PSLE Mathematics Quiz - Multiplication Division: Answer Key

Version: 1 of 5 | Total Marks: 60 | Duration: 60 minutes

Marking guidance: Award method (M) marks for correct strategy even if a slip occurs late; award answer (A) marks for accurate, correctly-united final answers.

Answer 1.

Answer: 9342 (2 marks)

  • Split 27 into 20+720 + 7: 346×20=6920346 \times 20 = 6920; 346×7=2422346 \times 7 = 2422; sum =9342= 9342.
  • Check: 9342÷27=3469342 \div 27 = 346. ✓
  • Marking: M1 partial products/column method, A1 for 9342.
  • Common mistake: Misaligning place values when adding partial products.

Answer 2.

Answer: 508 (2 marks)

  • Long division: 81÷16=581 \div 16 = 5 r 11; bring down 2 → write 0; bring down 8 → 128÷16=8128 \div 16 = 8. Quotient: 508.
  • Check: 508×16=8128508 \times 16 = 8128. ✓
  • Marking: M1 structured long division, A1 for 508.
  • Common mistake: Omitting the zero in the tens place, giving 58.

Answer 3.

Answer: 48 (2 marks)

  • Order of operations: 36÷6=636 \div 6 = 6, then 6×4=246 \times 4 = 24, then 24+24=4824 + 24 = 48.
  • Marking: M1 correct order of operations, A1 for 48.
  • Common mistake: Adding first (24+36=6024 + 36 = 60).

Answer 4.

Answer: 150 (2 marks)

  • 3.75×40=375×40÷100=15000÷100=1503.75 \times 40 = 375 \times 40 \div 100 = 15000 \div 100 = 150.
  • Alternative: 3.75×4=153.75 \times 4 = 15, then ×10=150\times 10 = 150.
  • Marking: M1 valid method, A1 for 150.
  • Common mistake: Placing the decimal point wrongly.

Answer 5.

Answer: 3.6 (2 marks)

  • 17×3=5117 \times 3 = 51, remainder 10.210.2; then 102102 tenths ÷17=6\div 17 = 6 tenths.
  • Result: 3.63.6. Check: 17×3.6=61.217 \times 3.6 = 61.2. ✓
  • Marking: M1 correct division process, A1 for 3.6.

Answer 6.

Answer: 42 (2 marks)

  • Missing factor found by dividing: 1890÷45=421890 \div 45 = 42.
  • Check: 45×42=189045 \times 42 = 1890. ✓
  • Marking: M1 dividing 1890 by 45, A1 for 42.

Answer 7.

Answer: 10 000 (2 marks)

  • 498500498 \approx 500 (nearest ten); 212021 \approx 20 (nearest ten).
  • Estimate: 500×20=10000500 \times 20 = 10\,000.
  • Marking: M1 both roundings, A1 for 10 000.
  • Note: Exact value 10 458 shows the estimate is reasonable.

Answer 8.

Answer: 2148 and 4728 (2 marks)

  • Divisible by both 3 and 4 means divisible by 12.
  • Digit sums (÷3): 2148 → 15 ✓; 3150 → 9 ✓; 4728 → 21 ✓; 5310 → 9 ✓.
  • Last two digits (÷4): 48 ✓; 50 ✗; 28 ✓; 10 ✗.
  • Only 2148 and 4728 pass both tests.
  • Marking: A2 both correct; A1 one correct with evidence of testing.

Answer 9.

Answer: 7 buses (2 marks)

  • 250÷40=6250 \div 40 = 6 remainder 1010; six buses seat only 240 pupils.
  • Smallest number needed: 6+1=76 + 1 = 7.
  • Marking: M1 division with remainder, A1 for 7.
  • Common mistake: Answering 6 — always round up when grouping people/objects.

Answer 10.

Answer: 99 stickers (2 marks)

  • Units: Ravi has 1 unit; Mei has 3 units. Total 4u=1324u = 132, so 1u=331u = 33.
  • Mei: 3×33=993 \times 33 = 99 stickers.
  • Marking: M1 unit model or equation, A1 for 99.
  • Common mistake: Giving 33 (Ravi's amount) instead of Mei's.

Answer 11.

Answer: $45.50 (3 marks)

  • Step 1 (unit cost): 26 \div 8 = \3.25$ per notebook.
  • Step 2 (scale up): 3.25 \times 14 = \45.50$.
  • Concept: Unitary method — find one item's value first, then multiply.
  • Marking: M1 for 26÷826 \div 8, A1 for 3.253.25, A1 for final 45.50with45.50 with sign.

Answer 12.

Answer: 1012 pages (3 marks)

  • Step 1 (rate): 345÷15=23345 \div 15 = 23 pages per minute.
  • Step 2 (total): 23×44=101223 \times 44 = 1012 pages.
  • Concept: Rate = total ÷ time; new total = rate × new time.
  • Marking: M1 finding rate, A1 for 23 pages/min, A1 for 1012 pages.

Answer 13.

Answer: 24 full boxes, 120 tarts left over (3 marks)

  • Step 1: 6000÷2456000 \div 245; since 245×24=5880245 \times 24 = 5880, the quotient is 24.
  • Step 2: Leftover =60005880=120= 6000 - 5880 = 120 tarts.
  • Concept: Quotient gives complete groups; remainder cannot fill another box.
  • Marking: M1 division setup, A1 for 24 boxes, A1 for 120 tarts.
  • Common mistake: Rounding instead of reporting quotient and remainder separately.

Answer 14.

Answer: Other number = 36; Sum = 57 (3 marks)

  • Step 1: 756÷21=36756 \div 21 = 36.
  • Step 2: Sum =36+21=57= 36 + 21 = 57.
  • Concept: Product ÷ known factor gives the unknown factor.
  • Marking: M1 for 756÷21756 \div 21, A1 for 36, A1 for 57.

Answer 15.

Answer: 81 chairs in 9 rows (3 marks)

  • A square array needs a perfect square: rows × columns with equal values.
  • Perfect squares between 80 and 100: only 81=9×981 = 9 \times 9 (6464 and 100100 fall outside the range).
  • So there are 81 chairs arranged in 9 rows of 9.
  • Marking: M1 recognising a square number is needed, A1 for 81, A1 for 9 rows.

Answer 16.

Answer: $40 spent; 2 extra pens (4 marks)

  • Step 1: 58÷6=958 \div 6 = 9 remainder 44, so 9 packs give only 54 pens — not enough.
  • Step 2: She must buy 1010 packs: 10×6=6010 \times 6 = 60 pens.
  • Cost: 10 \times \4 = $40.Extrapens:. Extra pens: 60 - 58 = 2$.
  • Marking: M1 rounding up to 10 packs, A1 cost $40, A1 extra 2 pens, A1 working/units.
  • Common mistake: Buying 9 packs ($36) — insufficient pens.

Answer 17.

Answer: 116 more ducks (4 marks)

  • Units: chickens = 1 unit, ducks = 5 units; total 6u=1746u = 174, so 1u=174÷6=291u = 174 \div 6 = 29.
  • Ducks =5×29=145= 5 \times 29 = 145; chickens =29= 29.
  • Difference: 14529=116145 - 29 = 116.
  • Marking: M1 model/equation, A1 for 29 (or 145), A1 difference 116, A1 working.
  • Common mistake: Finding counts but forgetting to subtract.

Answer 18.

Answer: 15 (4 marks)

  • Reverse each step: final answer 25 → multiply by 7: 25×7=17525 \times 7 = 175.
  • Add back 35: 175+35=210175 + 35 = 210.
  • Divide by 14: 210÷14=15210 \div 14 = 15.
  • Check forward: 15×14=21015 \times 14 = 210; 21035=175210 - 35 = 175; 175÷7=25175 \div 7 = 25. ✓
  • Marking: M1 reversing steps, A1 for 175, A1 for 210, A1 for 15.

Answer 19.

(a) Answer: 150 mL (b) Answer: 30 cups (4 marks)

  • (a) 2.42.4 litres =2400= 2400 mL; 2400÷16=1502400 \div 16 = 150 mL per cup.
  • (b) 4.54.5 litres =4500= 4500 mL; 4500÷150=304500 \div 150 = 30 cups exactly, so 30 cups can be filled completely.
  • Marking: (a) M1 conversion to mL, A1 for 150 mL; (b) M1 division by cup size, A1 for 30.
  • Common mistake: Dividing litres directly without converting to millilitres.

Answer 20.

Answer: 68 pages per chapter (5 marks)

  • Step 1 (time): 10:45 to 11:05 = 20 minutes.
  • Step 2 (total pages): 38×20=76038 \times 20 = 760 pages.
  • Step 3 (chapter pages): 76012=748760 - 12 = 748 pages for the 11 chapters.
  • Step 4: 748÷11=68748 \div 11 = 68 pages per chapter.
  • Check: (11×68)+12=748+12=760(11 \times 68) + 12 = 748 + 12 = 760. ✓
  • Marking: M1 time elapsed, A1 for 760, M1 subtracting photo section, A1/M1 for 748÷11748 \div 11, A1 for 68.
  • Common mistake: Forgetting to remove the 12-page photo section before dividing.