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Primary 6 PSLE Mathematics Geometry Quiz

Free P6 PSLE Maths Geometry quiz, Ox AI version, with questions, answers, and PSLE-focused practice for Singapore students.

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Primary 6 PSLE Mathematics AI Generated Generated by Ox Alpha Updated 2026-08-27

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Answers

Primary 6 PSLE Mathematics Quiz - Geometry: Answer Key

Total Marks: 53

Answer 1.

Circumference =2×3.14×7=43.96 cm= 2 \times 3.14 \times 7 = \mathbf{43.96 \text{ cm}} [1]

Answer 2.

Radius =12÷2=6= 12 \div 2 = 6 cm; Area =3.14×6×6=113.04 cm2= 3.14 \times 6 \times 6 = \mathbf{113.04 \text{ cm}^2} [1]

Answer 3.

Volume =5×5×5=125 cm3= 5 \times 5 \times 5 = \mathbf{125 \text{ cm}^3} [1]

Answer 4.

Q=18075=105\angle Q = 180^\circ - 75^\circ = \mathbf{105^\circ} (adjacent angles of a parallelogram are supplementary) [1]

Answer 5.

Height =240÷(8×5)=240÷40=6 cm= 240 \div (8 \times 5) = 240 \div 40 = \mathbf{6 \text{ cm}} [1]

Answer 6.

Perimeter =(3.14×14÷2)+14=21.98+14=35.98 cm= (3.14 \times 14 \div 2) + 14 = 21.98 + 14 = \mathbf{35.98 \text{ cm}} [2]

  • M1: half-circumference plus diameter
  • A1: 35.9835.98 cm

Answer 7.

Area =14×3.14×10×10=78.5 cm2= \frac{1}{4} \times 3.14 \times 10 \times 10 = \mathbf{78.5 \text{ cm}^2} [2]

  • M1: quarter of circle area
  • A1: 78.5 cm278.5 \text{ cm}^2

Answer 8.

Third angle =1804267=71= 180^\circ - 42^\circ - 67^\circ = \mathbf{71^\circ} [2]

  • M1: angle sum of triangle is 180180^\circ
  • A1: 7171^\circ

Answer 9.

Area =3.14×(6232)=3.14×27=84.78 cm2= 3.14 \times (6^2 - 3^2) = 3.14 \times 27 = \mathbf{84.78 \text{ cm}^2} [2]

  • M1: subtract inner area from outer area
  • A1: 84.78 cm284.78 \text{ cm}^2

Answer 10.

Volume =30×20×15=9000 cm3=9 litres= 30 \times 20 \times 15 = 9000 \text{ cm}^3 = \mathbf{9 \text{ litres}} [2]

  • M1: volume in cm3\text{cm}^3
  • A1: 99 \ell

Answer 11.

Area =12×7=84 cm2= 12 \times 7 = \mathbf{84 \text{ cm}^2} [2]

  • M1: base times perpendicular height
  • A1: 84 cm284 \text{ cm}^2

Answer 12.

Each base angle =(18040)÷2=70= (180^\circ - 40^\circ) \div 2 = \mathbf{70^\circ} [2]

  • M1: subtract apex angle, divide by two equal base angles
  • A1: 7070^\circ each

Answer 13.

Surface area =6×4×4=96 cm2= 6 \times 4 \times 4 = \mathbf{96 \text{ cm}^2} [2]

  • M1: six equal square faces
  • A1: 96 cm296 \text{ cm}^2

Answer 14.

Radius =62.8÷(2×3.14)=62.8÷6.28=10 cm= 62.8 \div (2 \times 3.14) = 62.8 \div 6.28 = \mathbf{10 \text{ cm}} [2]

  • M1: rearrange circumference formula
  • A1: 1010 cm

Answer 15.

Rectangle =20×12=240= 20 \times 12 = 240; Semicircle =12×3.14×6×6=56.52= \frac{1}{2} \times 3.14 \times 6 \times 6 = 56.52; Remaining area =24056.52=183.48 cm2= 240 - 56.52 = \mathbf{183.48 \text{ cm}^2} [2]

  • M1: rectangle minus semicircle
  • A1: 183.48 cm2183.48 \text{ cm}^2

Answer 16.

Circumference =2×3.14×15=94.2= 2 \times 3.14 \times 15 = 94.2 m; Cost = 94.2 \times 12 = \mathbf{\1130.40}$ [4]

  • M1: correct circumference formula
  • A1: 94.294.2 m
  • M1: multiply by rate
  • A1: \1130.40$

Answer 17.

(a) Volume =40×30×25=30000 cm3= 40 \times 30 \times 25 = \mathbf{30000 \text{ cm}^3} [2] (b) 60%60\% of 30000=18000 cm3=18 litres30000 = 18000 \text{ cm}^3 = \mathbf{18 \text{ litres}} [3]

  • (a) M1: multiply dimensions; A1: 30000 cm330000 \text{ cm}^3
  • (b) M1: find 60%60\%; M1: convert using 1000 cm3=11000 \text{ cm}^3 = 1 \ell; A1: 1818 \ell

Answer 18.

Area of square =14×14=196 cm2= 14 \times 14 = 196 \text{ cm}^2; Radius of semicircle =7= 7 cm; Area of semicircle =12×3.14×7×7=76.93 cm2= \frac{1}{2} \times 3.14 \times 7 \times 7 = 76.93 \text{ cm}^2; Shaded area =19676.93=119.07 cm2= 196 - 76.93 = \mathbf{119.07 \text{ cm}^2} [5]

  • M1: area of square
  • M1: identify radius as half the side
  • M1: area of semicircle
  • A1: 76.93 cm276.93 \text{ cm}^2
  • A1: 119.07 cm2119.07 \text{ cm}^2

Answer 19.

Base area of tank =50×40=2000 cm2= 50 \times 40 = 2000 \text{ cm}^2; Volume of cube =20×20×20=8000 cm3= 20 \times 20 \times 20 = 8000 \text{ cm}^3; Water level rise =8000÷2000=4= 8000 \div 2000 = 4 cm; New depth =18+4=22 cm= 18 + 4 = \mathbf{22 \text{ cm}} [7]

  • M1: base area
  • M1: cube volume
  • M1: divide to find rise
  • A1: rise =4= 4 cm
  • M1: add original depth
  • A1: 2222 cm
  • A1: correct units throughout

Answer 20.

(a) Two straight sections =2×100=200= 2 \times 100 = 200 m; Two semicircles == one full circle of diameter 6060 m: 3.14×60=188.43.14 \times 60 = 188.4 m; Perimeter =200+188.4=388.4 m= 200 + 188.4 = \mathbf{388.4 \text{ m}} [3] (b) Rectangle =100×60=6000 m2= 100 \times 60 = 6000 \text{ m}^2; Circle =3.14×30×30=2826 m2= 3.14 \times 30 \times 30 = 2826 \text{ m}^2; Total area =6000+2826=8826 m2= 6000 + 2826 = \mathbf{8826 \text{ m}^2} [4]

  • (a) M1: recognise two semicircles form one circle; A1: 188.4188.4 m; A1: 388.4388.4 m
  • (b) M1: rectangle area; M1: circle area with radius 3030 m; A1: 2826 m22826 \text{ m}^2; A1: 8826 m28826 \text{ m}^2

End of Answer Key