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Primary 6 PSLE Mathematics Data Analysis Quiz

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Primary 6 PSLE Mathematics AI Generated Generated by Ox Alpha Updated 2026-08-27

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Answers - Primary 6 PSLE Mathematics Quiz - Data Analysis

Key idea used throughout: Average=TotalNumber of data\text{Average} = \dfrac{\text{Total}}{\text{Number of data}}, so Total=Average×Number of data\text{Total} = \text{Average} \times \text{Number of data}.

Answer 1.

Sum =12+18+24+9+27=90= 12 + 18 + 24 + 9 + 27 = 90 Average =90÷5== 90 \div 5 = 18 [2] Teaching note: Add all values first, then divide by the count (5). Common mistake: dividing by the largest value or miscounting the number of values.

Answer 2.

Total =250×8== 250 \times 8 = 2000 g [2] Teaching note: Rearrange Average × Count = Total. Units must be grams. Common mistake: multiplying by 5 or writing 2 without units.

Answer 3.

Total =14+11+16+7=48= 14 + 11 + 16 + 7 = 48 Average =48÷4== 48 \div 4 = 12 books [2] Teaching note: Read each row of the table carefully; all four pupils count, even the smallest value.

Answer 4.

From the graph: Wednesday (best) = 60 drinks; Thursday (worst) = 25 drinks. Difference =6025== 60 - 25 = 35 drinks [2: M1 for reading both values correctly, A1 for difference] Expected visual: bars at 45, 30, 60, 25, 50 with y-axis to 70. Common mistake: subtracting adjacent bars instead of highest minus lowest.

Answer 5.

Total of 3 numbers =20×3=60= 20 \times 3 = 60 Third number =601625=6041== 60 - 16 - 25 = 60 - 41 = 19 [2] Teaching note: Multiply the average by the count to get the total, then subtract the known values. Common mistake: subtracting from 20 instead of from the total 60.

Answer 6.

Total of 6 tests =78×6=468= 78 \times 6 = 468 New total =46868=400= 468 - 68 = 400 New average =400÷5== 400 \div 5 = 80 [3: M1 total, M1 removal, A1 average] Teaching note: Removing a low score raises the average — check your answer makes sense. Common mistake: dividing by 6 again instead of 5.

Answer 7.

Sum of temperatures =24+28+33+35+30=150= 24 + 28 + 33 + 35 + 30 = 150°C Average =150÷5== 150 \div 5 = 30°C [3: M1 reading values, M1 sum, A1 average] Expected visual: points at (8 a.m., 24), (10 a.m., 28), (12 p.m., 33), (2 p.m., 35), (4 p.m., 30). Common mistake: misreading gridlines between labelled steps.

Answer 8.

Original total =48×4=192= 48 \times 4 = 192 kg New total =50×3=150= 50 \times 3 = 150 kg Mass of boy who left =192150== 192 - 150 = 42 kg [3: M1, M1, A1] Teaching note: Compare the two totals. The leaver must be lighter than 48 kg since the average rose when he left — use this to check.

Answer 9.

(a) Badminton: 20%20\% of 240=20100×240=240 = \frac{20}{100} \times 240 = 48 pupils [1]

(b) Difference =40%25%=15%= 40\% - 25\% = 15\% of 240 =15100×240== \frac{15}{100} \times 240 = 36 pupils [2: M1 percentage difference, A1 value] Teaching note: With pie charts, compare percentages first, then convert once. Common mistake: finding each amount separately and subtracting wrongly (96 − 60 = 36 works too, but the percentage method is faster).

Answer 10.

Group A total =150×20=3000= 150 \times 20 = 3000 cm Group B total =145×30=4350= 145 \times 30 = 4350 cm Overall average =(3000+4350)÷50=7350÷50== (3000 + 4350) \div 50 = 7350 \div 50 = 147 cm [3: M1, M1, A1] Teaching note: Never average the two averages (148 is wrong) unless group sizes are equal. Always rebuild the totals first.

Answer 11.

Total of 4 numbers =26×4=104= 26 \times 4 = 104 x=104233119=10473=x = 104 - 23 - 31 - 19 = 104 - 73 = 31 [3: M1, M1, A1] Teaching note: Work backwards from the average to the total. Check: (23+31+19+31)÷4=104÷4=26(23+31+19+31)\div 4 = 104 \div 4 = 26. ✓

Answer 12.

Original total = 18 \times 5 = \90NewtotalNew total= 19.50 \times 6 = $117Costof6thitemCost of 6th item= 117 - 90 = **27** [3: M1, M1, A1] Teaching note: The new item must pull the average up, so it costs more than $18 — check against this. Common mistake: forgetting the total changed from 5 items to 6.

Answer 13.

Total =40+55+35+50+70=250= 40 + 55 + 35 + 50 + 70 = 250 Average =250÷5== 250 \div 5 = 50 books [3: M1 reading, M1 sum, A1 average] Expected visual: bars at 40, 55, 35, 50, 70. Common mistake: counting only weekdays shown incorrectly or arithmetic slip in the sum.

Answer 14.

Total age of 4 people =13×4=52= 13 \times 4 = 52 years Total age of 3 friends =5210=42= 52 - 10 = 42 years Average =42÷3== 42 \div 3 = 14 years [3: M1, M1, A1] Teaching note: Remove Ravi's age from the total before finding the friends' average. Since Ravi is below average, the friends' average (14) must exceed 13 — a useful check.

Answer 15.

Total distance =120+180=300= 120 + 180 = 300 km Total time =2+3=5= 2 + 3 = 5 h Average speed =300÷5== 300 \div 5 = 60 km/h [3: M1, M1, A1] Teaching note: Average speed uses total distance ÷ total time, never the average of 60 km/h and 60 km/h blindly — always rebuild totals.

Answer 16.

First 4 days: 85×4=34085 \times 4 = 340 cupcakes First 5 days: 88×5=44088 \times 5 = 440 cupcakes 5th day: 440340=440 - 340 = 100 cupcakes [4: M1, M1, M1 subtraction, A1 with unit] Teaching note: Each total comes from Average × Count. The 5th-day sales are simply the extra amount added to reach the new total. Common mistake: using 85 × 5 or 88 × 4.

Answer 17.

Original total =3.4×6=20.4= 3.4 \times 6 = 20.4 kg Remaining 5 melons =20.44.8=15.6= 20.4 - 4.8 = 15.6 kg New total =3.6×6=21.6= 3.6 \times 6 = 21.6 kg New watermelon =21.615.6== 21.6 - 15.6 = 6 kg [4: M1, M1, M1, A1 with unit] Teaching note: Removing then replacing changes only one melon, so compare totals. The new melon must exceed 4.8 kg since the average rose — check confirms 6 > 4.8. ✓

Answer 18.

Total for 5 days =100×5=500= 100 \times 5 = 500 loaves Known total =96+84+120=300= 96 + 84 + 120 = 300 loaves Wednesday + Thursday =500300=200= 500 - 300 = 200 loaves Wednesday =200÷2== 200 \div 2 = 100 loaves [4: M1, M1, M1, A1] Teaching note: Equal unknown values mean splitting their combined total equally. Verify: (96+84+100+100+120)÷5=500÷5=100(96+84+100+100+120)\div 5 = 500 \div 5 = 100. ✓

Answer 19.

(a) Walk: 25%25\% of 720=25100×720=720 = \frac{25}{100} \times 720 = 180 pupils [2: M1, A1]

(b) Difference =35%20%=15%= 35\% - 20\% = 15\% of 720 =15100×720== \frac{15}{100} \times 720 = 108 pupils [2: M1, A1] Expected visual: sectors Car 35%, Bus 20

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Answers - Primary 6 PSLE Mathematics Quiz - Data Analysis

Key idea: Average=TotalCount\text{Average} = \dfrac{\text{Total}}{\text{Count}}, so Total=Average×Count\text{Total} = \text{Average} \times \text{Count}.

Answer 1.

Sum =12+18+24+9+27=90= 12 + 18 + 24 + 9 + 27 = 90 Average =90÷5== 90 \div 5 = 18 [2] Teaching note: Add all values first, then divide by the count (5). Common mistake: miscounting the number of values.

Answer 2.

Total =250×8== 250 \times 8 = 2000 g [2] Teaching note: Rearrange Average × Count = Total. Units must be grams. Common mistake: multiplying by 5 or omitting units.

Answer 3.

Total =14+11+16+7=48= 14 + 11 + 16 + 7 = 48 Average =48÷4== 48 \div 4 = 12 books [2] Teaching note: Read each table row carefully; all four pupils count.

Answer 4.

From the graph: Wednesday (best) = 60 drinks; Thursday (worst) = 25 drinks. Difference =6025== 60 - 25 = 35 drinks [2: M1 reading both values, A1 difference] Expected visual: bars at 45, 30, 60, 25, 50 with y-axis to 70. Common mistake: subtracting adjacent bars instead of highest minus lowest.

Answer 5.

Total of 3 numbers =20×3=60= 20 \times 3 = 60 Third number =601625== 60 - 16 - 25 = 19 [2] Teaching note: Work from the total (60), not from the average (20). Common mistake: subtracting from 20.

Answer 6.

Total of 6 tests =78×6=468= 78 \times 6 = 468 New total =46868=400= 468 - 68 = 400 New average =400÷5== 400 \div 5 = 80 [3: M1 total, M1 removal, A1 average] Teaching note: Removing a low score raises the average — check your answer makes sense. Common mistake: dividing by 6 instead of 5.

Answer 7.

Sum =24+28+33+35+30=150= 24 + 28 + 33 + 35 + 30 = 150°C Average =150÷5== 150 \div 5 = 30°C [3: M1 reading values, M1 sum, A1 average] Expected visual: points at (8 a.m., 24), (10 a.m., 28), (12 p.m., 33), (2 p.m., 35), (4 p.m., 30). Common mistake: misreading gridlines between labelled steps.

Answer 8.

Original total =48×4=192= 48 \times 4 = 192 kg New total =50×3=150= 50 \times 3 = 150 kg Mass of boy who left =192150== 192 - 150 = 42 kg [3: M1, M1, A1] Teaching note: Compare the two totals. The leaver is below 48 kg since the average rose when he left — use this check.

Answer 9.

(a) Badminton: 20100×240=\frac{20}{100} \times 240 = 48 pupils [1]

(b) Difference =40%25%=15%= 40\% - 25\% = 15\% of 240 =15100×240== \frac{15}{100} \times 240 = 36 pupils [2: M1 percentage difference, A1 value] Teaching note: Compare percentages first, then convert once. (96 − 60 = 36 also works.)

Answer 10.

Group A total =150×20=3000= 150 \times 20 = 3000 cm Group B total =145×30=4350= 145 \times 30 = 4350 cm Overall average =7350÷50== 7350 \div 50 = 147 cm [3: M1, M1, A1] Teaching note: Never average the two averages (148 is wrong) unless group sizes are equal. Rebuild totals first.

Answer 11.

Total of 4 numbers =26×4=104= 26 \times 4 = 104 x=104233119=x = 104 - 23 - 31 - 19 = 31 [3: M1, M1, A1] Teaching note: Check: (23+31+19+31)÷4=104÷4=26(23+31+19+31)\div 4 = 104 \div 4 = 26. ✓

Answer 12.

Original total = 18 \times 5 = \90NewtotalNew total= 19.50 \times 6 = $117Costof6thitemCost of 6th item= 117 - 90 = **27** [3: M1, M1, A1] Teaching note: The new item pulls the average up, so it costs more than $18 — check confirms this.

Answer 13.

Total =40+55+35+50+70=250= 40 + 55 + 35 + 50 + 70 = 250 Average =250÷5== 250 \div 5 = 50 books [3: M1 reading, M1 sum, A1 average] Expected visual: bars at 40, 55, 35, 50, 70. Common mistake: arithmetic slip in the sum.

Answer 14.

Total age of 4 people =13×4=52= 13 \times 4 = 52 years Total age of 3 friends =5210=42= 52 - 10 = 42 years Average =42÷3== 42 \div 3 = 14 years [3: M1, M1, A1] Teaching note: Remove Ravi's age before averaging. Since Ravi is below average, the friends' average exceeds 13 — a useful check.

Answer 15.

Total distance =120+180=300= 120 + 180 = 300 km Total time =2+3=5= 2 + 3 = 5 h Average speed =300÷5== 300 \div 5 = 60 km/h [3: M1, M1, A1] Teaching note: Average speed = total distance ÷ total time, always rebuilt from totals.

Answer 16.

First 4 days: 85×4=34085 \times 4 = 340 cupcakes First 5 days: 88×5=44088 \times 5 = 440 cupcakes 5th day: 440340=440 - 340 = 100 cupcakes [4: M1, M1, M1 subtraction, A1 with unit] Teaching note: Each total comes from Average × Count. Common mistake: using 85 × 5 or 88 × 4.

Answer 17.

Original total =3.4×6=20.4= 3.4 \times 6 = 20.4 kg Remaining 5 melons =20.44.8=15.6= 20.4 - 4.8 = 15.6 kg New total =3.6×6=21.6= 3.6 \times 6 = 21.6 kg New watermelon =21.615.6== 21.6 - 15.6 = 6 kg [4: M1, M1, M1, A1 with unit] Teaching note: The new melon must exceed 4.8 kg since the average rose — check confirms 6 > 4.8. ✓

Answer 18.

Total for 5 days =100×5=500= 100 \times 5 = 500 loaves Known total =96+84+120=300= 96 + 84 + 120 = 300 loaves Wednesday + Thursday =500300=200= 500 - 300 = 200 loaves Wednesday =200÷2== 200 \div 2 = 100 loaves [4: M1, M1, M1, A1] Teaching note: Equal unknown values mean splitting their combined total equally. Verify: 500÷5=100500 \div 5 = 100. ✓

Answer 19.

(a) Walk: 25100×720=\frac{25}{100} \times 720 = 180 pupils [2: M1, A1]

(b) Difference =35%20%=15%= 35\% - 20\% = 15\% of 720 =15100×720== \frac{15}{100} \times 720 = 108 pupils [2: M1, A1] Expected visual: sectors Car 35%, Bus 20%, Walk 25%, Bicycle 20%; total 720 pupils. Common mistake: using 720 as if it were 100 pupils or misreading sector percentages.

Answer 20.

Total of 10 numbers =46×10=460= 46 \times 10 = 460 First 4 numbers =52×4=208= 52 \times 4 = 208 Last 5 numbers =44×5=220= 44 \times 5 = 220 Remaining number =460208220== 460 - 208 - 220 = 32 [4: M1, M1, M1, A1] Teaching note: The three groups (first 4, this number, last 5) make up all 10 numbers. Check: (208+32+220)÷10=460÷10=46(208 + 32 + 220) \div 10 = 460 \div 10 = 46. ✓

End of Answers