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Primary 6 PSLE Mathematics Data Analysis Quiz

Free P6 PSLE Maths Data Analysis quiz, LongCat AI version, with questions, answers, and PSLE-focused practice for Singapore students.

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Primary 6 PSLE Mathematics AI Generated Generated by LongCat 2.0 LLM Updated 2026-08-17

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Questions

Primary 6 PSLE Mathematics Quiz - Data Analysis

Name: ____________________
Class: ____________________
Date: ____________________
Score: ________ / 40

Duration: 50 minutes
Total Marks: 40

Instructions

Answer all questions.
Show all working clearly in the space provided.
Calculators are not allowed.
Read each question carefully before answering.

Section A: Mean, Median, Mode, and Range (Questions 1–10)

Questions 1–5 are worth 1 mark each. Questions 6–10 are worth 2 marks each.

1.
The table below shows the number of books read by 5 students in a month.

Student	Ali	Bala	Carol	Devi	Ethan
Books	4	6	5	6	9

What is the mean number of books read?

2.
Using the data from Question 1, what is the mode of the number of books read?

3.
The heights (in cm) of 6 children are: 120, 135, 128, 142, 130, 125.

What is the range of the heights?

4.
The test scores of 5 pupils are: 78, 85, 92, 85, 70.

What is the median score?

5.
A set of 4 numbers has a mean of 15. Three of the numbers are 12, 18, and 10.

What is the fourth number?

6.
The table shows the number of goals scored by players in a football tournament.

Goals Scored	0	1	2	3	4
Number of Players	3	7	5	3	2

(a) How many players participated in the tournament?

(b) What is the mean number of goals scored per player? (Give your answer correct to 1 decimal place.)

7.
The masses (in kg) of 5 parcels are: 2.4, 3.1, 2.8, 3.5, and 2.2.

(a) Find the median mass.

(b) Find the mean mass. (Give your answer correct to 1 decimal place.)

8.
The line graph below shows the temperature (°C) recorded at noon over 5 days.

Day	Mon	Tue	Wed	Thu	Fri
Temperature (°C)	30	33	28	35	31

(a) What is the range of the temperatures?

(b) What is the mean noon temperature over the 5 days?

9.
The ages of 7 members in a family are: 8, 12, 35, 38, 10, 14, 65.

(a) Find the median age.

(b) Find the mean age. (Give your answer correct to 1 decimal place.)

10.
The table shows the number of hours 8 students spent on homework in a week.

Hours	2	3	4	5	6
Number of Students	1	2	3	1	1

(a) What is the mode of the data?

(b) Calculate the mean number of hours spent on homework.

(c) A new student joins the group and spends 10 hours on homework. Without recalculating, explain how this affects the mean and the median.

Section B: Tables, Charts, and Graphs (Questions 11–16)

Questions 11–13 are worth 2 marks each. Questions 14–16 are worth 3 marks each.

11.
The bar graph shows the number of fruits sold at a stall on Saturday.

Fruit	Apples	Bananas	Oranges	Grapes	Mangoes
Number Sold	25	40	30	15	35

(a) How many fruits were sold altogether?

(b) What fraction of the fruits sold were bananas? Give your answer in its simplest form.

12.
The pie chart below represents how Meiling spent her day. The angles for each activity are shown.

Activity	Angle
Sleep	120°
School	108°
Homework	54°
Play	48°
Meals	30°

If Meiling spent 9 hours in school, how many hours did she spend sleeping?

13.
The table shows the number of visitors to a zoo over 4 months.

Month	March	April	May	June
Visitors	2,400	3,600	1,800	4,200

(a) What was the total number of visitors over the 4 months?

(b) What was the mean number of visitors per month?

14.
The line graph shows the water level (in cm) in a tank over 6 hours during a rainstorm.

Hour	0	1	2	3	4	5	6
Water Level (cm)	10	14	22	30	28	20	16

(a) What was the increase in water level from Hour 0 to Hour 3?

(b) During which hour did the water level decrease the most? Explain your answer.

15.
The table shows the scores of two classes in a Mathematics quiz.

Score	0–20	21–40	41–60	61–80	81–100
Class 6A (number of pupils)	2	3	8	10	7
Class 6B (number of pupils)	1	4	12	8	5

(a) How many pupils are there in Class 6A?

(b) Which class has more pupils scoring 61–100?

(c) A pupil says, "Class 6A did better because more pupils scored 81–100." Do you agree? Explain your answer using data from the table.

16.
The bar graph shows the number of books borrowed from a library each day over a week.

Day	Mon	Tue	Wed	Thu	Fri	Sat	Sun
Books Borrowed	45	30	25	40	55	70	20

(a) What is the range of the number of books borrowed?

(b) What is the median number of books borrowed?

Section C: Data Analysis Problem Sums (Questions 17–20)

Questions 17–20 are worth 4 marks each.

17.
The mean weight of 4 children is 32 kg. When a fifth child joins the group, the mean weight becomes 34 kg.

(a) What is the total weight of the first 4 children?

(b) What is the total weight of all 5 children?

18.
The table shows the number of stamps collected by 4 friends.

Friend	Wei Ming	Siti	Raj	Hannah
Stamps	120	80	160	?

The mean number of stamps collected by the 4 friends is 130.

(a) How many stamps does Hannah have?

(b) Wei Ming gives some stamps to Siti. After this, Wei Ming and Siti have the same number of stamps. How many stamps did Wei Ming give to Siti?

19.
The line graph shows the number of ice cream cones sold at a shop over 5 days.

Day	Mon	Tue	Wed	Thu	Fri
Cones Sold	80	120	100	140	60

(a) What is the mean number of ice cream cones sold per day?

(b) On Saturday, the shop sold enough cones to raise the 6-day mean to 110. How many cones were sold on Saturday?

(c) The shop owner wants the mean over the 6 days to be 120 instead. How many cones would need to be sold on Saturday for this to happen?

20.
The table shows the test marks of 6 pupils in a Mathematics test.

Pupil	A	B	C	D	E	F
Mark	72	85	68	90	78	?

The mean mark of the 6 pupils is 80.

(a) What is the total marks of all 6 pupils?

(b) What mark did Pupil F score?

(d) The teacher then discovers that Pupil C's mark was recorded incorrectly. Pupil C's actual mark was 75. What is the corrected mean mark? (Use the original marks before the 5-mark bonus.)

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Answers

Primary 6 PSLE Mathematics Quiz - Data Analysis

Answer Key

Section A: Mean, Median, Mode, and Range

1. (1 mark)
Mean = (4 + 6 + 5 + 6 + 9) ÷ 5 = 30 ÷ 5 = 6 books
Answer: 6

2. (1 mark)
The mode is the value that appears most frequently. 6 appears twice; all others appear once.
Answer: 6

3. (1 mark)
Range = Highest − Lowest = 142 − 120 = 22 cm
Answer: 22 cm

4. (1 mark)
Arrange in order: 70, 78, 85, 85, 92. The middle value is 85.
Answer: 85

5. (1 mark)
Total of 4 numbers = 15 × 4 = 60.
Sum of three known numbers = 12 + 18 + 10 = 40.
Fourth number = 60 − 40 = 20
Answer: 20

6. (2 marks)
(a) Total players = 3 + 7 + 5 + 3 + 2 = 20 players
(b) Total goals = (0 × 3) + (1 × 7) + (2 × 5) + (3 × 3) + (4 × 2) = 0 + 7 + 10 + 9 + 8 = 34
Mean = 34 ÷ 20 = 1.7 goals
Answers: (a) 20 (b) 1.7

7. (2 marks)
(a) Arrange in order: 2.2, 2.4, 2.8, 3.1, 3.5. Median = 2.8 kg
(b) Mean = (2.4 + 3.1 + 2.8 + 3.5 + 2.2) ÷ 5 = 14.0 ÷ 5 = 2.8 kg
Answers: (a) 2.8 kg (b) 2.8 kg

8. (2 marks)
(a) Range = 35 − 28 = 7°C
(b) Mean = (30 + 33 + 28 + 35 + 31) ÷ 5 = 157 ÷ 5 = 31.4°C
Answers: (a) 7°C (b) 31.4°C

9. (2 marks)
(a) Arrange in order: 8, 10, 12, 14, 35, 38, 65. Median = 14 years
(b) Mean = (8 + 12 + 35 + 38 + 10 + 14 + 65) ÷ 7 = 182 ÷ 7 = 26.0 years
(c) The median (14) is lower than the mean (26) because the two adult ages (35, 38) and especially the grandparent age (65) pull the mean upward. The median is not affected by extreme values and better represents the typical age of the group.
Answers: (a) 14 (b) 26.0 (c) Median is not affected by extreme values; the older ages skew the mean upward.

10. (2 marks)
(a) Mode = 4 hours (most frequent: 3 students)
(b) Total hours = (2 × 1) + (3 × 2) + (4 × 3) + (5 × 1) + (6 × 1) = 2 + 6 + 12 + 5 + 6 = 31
Mean = 31 ÷ 8 = 3.875 hours (or 3.9 hours to 1 d.p.)
(c) The mean will increase because 10 is much higher than the current values, pulling the average up. The median will stay the same or increase slightly — with 9 data points, the median is the 5th value when ordered. The original ordered data is: 2, 3, 3, 4, 4, 4, 5, 6. Adding 10 gives: 2, 3, 3, 4, 4, 4, 5, 6, 10. The median remains 4.
Answers: (a) 4 (b) 3.875 (c) Mean increases; median stays at 4.

Section B: Tables, Charts, and Graphs

11. (2 marks)
(a) Total = 25 + 40 + 30 + 15 + 35 = 145 fruits
(b) Fraction = 40/145 = 8/29 (divide numerator and denominator by 5)
Answers: (a) 145 (b) 8/29

12. (2 marks)
School = 108° corresponds to 9 hours.
Each degree = 9 ÷ 108 = 1/12 hour.
Sleep = 120° → 120 × (1/12) = 10 hours
Answer: 10 hours

13. (2 marks)
(a) Total = 2,400 + 3,600 + 1,800 + 4,200 = 12,000 visitors
(b) Mean = 12,000 ÷ 4 = 3,000 visitors per month
Answers: (a) 12,000 (b) 3,000

14. (3 marks)
(a) Increase = 30 − 10 = 20 cm
(b) Hour 3 to Hour 4: 30 − 28 = 2 cm decrease. Hour 4 to Hour 5: 28 − 20 = 8 cm decrease. Hour 5 to Hour 6: 20 − 16 = 4 cm decrease. The greatest decrease is from Hour 4 to Hour 5 (8 cm).
(c) Mean = (10 + 14 + 22 + 30 + 28 + 20 + 16) ÷ 7 = 140 ÷ 7 = 20 cm
Answers: (a) 20 cm (b) Hour 4 to Hour 5, decrease of 8 cm (c) 20 cm

15. (3 marks)
(a) Class 6A total = 2 + 3 + 8 + 10 + 7 = 30 pupils
(b) Class 6A: 10 + 7 = 17 pupils scored 61–100. Class 6B: 8 + 5 = 13 pupils scored 61–100. Class 6A has more.
(c) Partially agree. While Class 6A has more pupils in the 81–100 range (7 vs 5), Class 6B has more pupils in the 41–60 range (12 vs 8). Without knowing the exact scores within each range, we cannot definitively say which class performed better overall. However, Class 6A does have more high scorers (61–100: 17 vs 13).
Answers: (a) 30 (b) Class 6A (c) Class 6A has more pupils scoring 61–100 (17 vs 13), but exact comparison requires individual scores.

16. (3 marks)
(a) Range = 70 − 20 = 50 books
(b) Arrange in order: 20, 25, 30, 40, 45, 55, 70. Median = 40 books
(c) Mean = (45 + 30 + 25 + 40 + 55 + 70 + 20) ÷ 7 = 285 ÷ 7 = 40.7 (approx). The librarian's claim of 45 is not correct; the actual mean is approximately 40.7 books.
Answers: (a) 50 (b) 40 (c) No, mean ≈ 40.7, not 45.

Section C: Data Analysis Problem Sums

17. (4 marks)
(a) Total weight of 4 children = 32 × 4 = 128 kg
(b) Total weight of 5 children = 34 × 5 = 170 kg
(c) Weight of fifth child = 170 − 128 = 42 kg
Answers: (a) 128 kg (b) 170 kg (c) 42 kg

18. (4 marks)
(a) Total stamps = 130 × 4 = 520. Hannah = 520 − (120 + 80 + 160) = 520 − 360 = 160 stamps
(b) After transfer, Wei Ming and Siti have equal amounts. Combined = 120 + 80 = 200. Each has 200 ÷ 2 = 100. Wei Ming gave 120 − 100 = 20 stamps to Siti.
(c) Total stamps remain 520 (no stamps added or removed). New mean = 520 ÷ 4 = 130 stamps (unchanged).
Answers: (a) 160 (b) 20 (c) 130

19. (4 marks)
(a) Mean = (80 + 120 + 100 + 140 + 60) ÷ 5 = 500 ÷ 5 = 100 cones
(b) Required total for 6 days = 110 × 6 = 660. Saturday = 660 − 500 = 160 cones
(c) Required total for mean of 120 = 120 × 6 = 720. Saturday = 720 − 500 = 220 cones
Answers: (a) 100 (b) 160 (c) 220

20. (4 marks)
(a) Total marks = 80 × 6 = 480
(b) Pupil F = 480 − (72 + 85 + 68 + 90 + 78) = 480 − 393 = 87 marks
(c) Adding 5 marks to each of 6 pupils adds 30 to the total. New total = 480 + 30 = 510. New mean = 510 ÷ 6 = 85 marks. (Alternatively: new mean = 80 + 5 = 85.)
(d) Original total = 480. Corrected total = 480 − 68 + 75 = 487. Corrected mean = 487 ÷ 6 = 81.2 marks (to 1 d.p.)
Answers: (a) 480 (b) 87 (c) 85 (d) 81.2

Mark Summary

Section	Questions	Marks
A: Mean, Median, Mode, Range	1–5 (1 mark each), 6–10 (2 marks each)	5 + 10 = 15
B: Tables, Charts, Graphs	11–13 (2 marks each), 14–16 (3 marks each)	6 + 9 = 15
C: Data Analysis Problem Sums	17–20 (4 marks each)	16
Total	20 questions	40 marks

Note: This quiz was generated using syllabus-aligned LLM-inferred templates. It is designed to complement PSLE preparation and does not claim to be derived from past-year examination papers.