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Primary 6 PSLE Mathematics Volume Quiz
Free P6 PSLE Maths Volume quiz, Exam version, with questions, answers, and PSLE-focused practice for Singapore students.
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Primary 6 PSLE Mathematics Quiz - Volume: Answer Key
Total Marks: 40
Section A: Multiple-Choice Questions (Questions 1 to 5)
(2 marks each)
1. Answer: B) 3 cm
- Working: Height = Volume ÷ (Length × Width) = 120 cm³ ÷ (8 cm × 5 cm) = 120 cm³ ÷ 40 cm² = 3 cm.
- Concept: To find a missing dimension of a cuboid when the volume and the other two dimensions are known, divide the volume by the product of the two known dimensions.
- Common Mistake: Students might multiply all three numbers instead of dividing.
2. Answer: A) 4 cm
- Working: Edge length = ∛Volume = ∛64 cm³ = 4 cm.
- Concept: The volume of a cube is edge × edge × edge (edge³). To find the edge length from the volume, find the cube root. 4 × 4 × 4 = 64.
- Common Mistake: Students might find the square root (8) instead of the cube root.
3. Answer: C) 4 cm
- Working: Height = Volume ÷ Base Area = 240 cm³ ÷ 60 cm² = 4 cm.
- Concept: The volume of a cuboid is Base Area × Height. Therefore, Height = Volume ÷ Base Area.
- Common Mistake: Students might try to find the length and width separately, which is unnecessary.
4. Answer: C) 9000 cm³
- Working: Volume = Length × Width × Height = 30 cm × 20 cm × 15 cm = 9000 cm³.
- Concept: The volume of a rectangular tank is found by multiplying its length, width, and height.
- Common Mistake: Students might forget to multiply all three dimensions or make a calculation error (e.g., 30 × 20 = 600, 600 × 15 = 9000).
5. Answer: C) 6 cm
- Working: Area of square base = side × side = 6 cm × 6 cm = 36 cm². Height = Volume ÷ Base Area = 216 cm³ ÷ 36 cm² = 6 cm.
- Concept: First find the area of the square base, then use the formula Height = Volume ÷ Base Area.
- Common Mistake: Students might assume the height is the same as the side of the square base without calculating.
Section B: Short-Answer Questions (Questions 6 to 15)
(2 marks each)
6. Answer: 6 cm
- Working: Width = Volume ÷ (Length × Height) = 360 cm³ ÷ (12 cm × 5 cm) = 360 cm³ ÷ 60 cm² = 6 cm.
- Concept: To find a missing dimension, divide the volume by the product of the other two dimensions.
- Marking: 1 mark for correct method, 1 mark for correct answer.
7. Answer: 150 cm²
- Working: Edge length = ∛125 cm³ = 5 cm. Area of one face = 5 cm × 5 cm = 25 cm². Total surface area = 6 × 25 cm² = 150 cm².
- Concept: A cube has 6 identical square faces. First find the edge length using the cube root, then find the area of one face, and finally multiply by 6.
- Marking: 1 mark for finding edge length, 1 mark for correct total surface area.
8. Answer: 12 000 cm³
- Working: Volume of water = Length × Width × Depth of water = 40 cm × 25 cm × 12 cm = 12 000 cm³.
- Concept: When finding the volume of water in a tank, use the depth of the water as the height.
- Marking: 1 mark for correct method, 1 mark for correct answer.
9. Answer: 6 cm
- Working: Height = Volume ÷ (Length × Width) = 480 cm³ ÷ (10 cm × 8 cm) = 480 cm³ ÷ 80 cm² = 6 cm.
- Concept: To find a missing dimension, divide the volume by the product of the other two dimensions.
- Marking: 1 mark for correct method, 1 mark for correct answer.
10. Answer: 729 cm³
- Working: Volume = Edge × Edge × Edge = 9 cm × 9 cm × 9 cm = 729 cm³.
- Concept: The volume of a cube is found by cubing the edge length.
- Marking: 1 mark for correct method, 1 mark for correct answer.
11. Answer: 30 litres
- Working: Volume in cm³ = 50 cm × 30 cm × 20 cm = 30 000 cm³. Volume in litres = 30 000 cm³ ÷ 1000 cm³/litre = 30 litres.
- Concept: 1 litre = 1000 cm³. To convert from cm³ to litres, divide by 1000.
- Marking: 1 mark for correct volume in cm³, 1 mark for correct conversion to litres.
12. Answer: 7 cm
- Working: Height = Volume ÷ Base Area = 343 cm³ ÷ 49 cm² = 7 cm.
- Concept: The volume of a cuboid is Base Area × Height. Therefore, Height = Volume ÷ Base Area.
- Marking: 1 mark for correct method, 1 mark for correct answer.
13. Answer: 40 cm
- Working: Volume of water in first tank = 60 cm × 40 cm × 25 cm = 60 000 cm³. Height in second tank = Volume ÷ (Length × Width) = 60 000 cm³ ÷ (50 cm × 30 cm) = 60 000 cm³ ÷ 1500 cm² = 40 cm.
- Concept: The volume of water remains the same when poured into another tank. Use the new base area to find the new height.
- Marking: 1 mark for correct volume, 1 mark for correct height.
14. Answer: 1200 cm³
- Working: Volume = Length × Width × Height = 15 cm × 10 cm × 8 cm = 1200 cm³.
- Concept: The volume of a cuboid is found by multiplying its length, width, and height.
- Marking: 1 mark for correct method, 1 mark for correct answer.
15. Answer: 6 cm
- Working: Edge length = ∛216 cm³ = 6 cm.
- Concept: The volume of a cube is edge³. To find the edge length from the volume, find the cube root. 6 × 6 × 6 = 216.
- Marking: 1 mark for correct method, 1 mark for correct answer.
Section C: Problem-Solving Questions (Questions 16 to 20)
(4 marks each)
16. Answer (a): 36 000 cm³ Answer (b): 24 000 cm³
- Working:
- (a) Total volume of tank = 50 cm × 40 cm × 30 cm = 60 000 cm³. Volume of water = (3/5) × 60 000 cm³ = 36 000 cm³.
- (b) Volume needed = Total volume - Volume of water = 60 000 cm³ - 36 000 cm³ = 24 000 cm³.
- Concept: To find a fraction of a volume, multiply the total volume by the fraction. The remaining volume is the total minus the filled part.
- Marking: (a) 1 mark for total volume, 1 mark for water volume. (b) 1 mark for correct method, 1 mark for correct answer.
17. Answer (a): 16 000 cm³ Answer (b): 25.2 cm (or 25 cm if using cube root of 16000)
- Working:
- (a) Volume of cube = Volume of water displaced = Length × Width × Rise in water level = 80 cm × 50 cm × 4 cm = 16 000 cm³.
- (b) Edge length = ∛16 000 cm³. Since 25³ = 15 625 and 26³ = 17 576, the edge length is approximately 25.2 cm. (Note: For P6, they may be expected to leave it as ∛16 000 or give a decimal approximation. The exact cube root is not a whole number.)
- Concept: When an object is submerged, it displaces a volume of water equal to its own volume. The displaced water volume is calculated as the base area of the tank multiplied by the rise in water level.
- Marking: (a) 1 mark for correct method, 1 mark for correct answer. (b) 1 mark for correct method, 1 mark for correct answer (accept ∛16 000 or 25.2 cm).
18. Answer (a): 24 000 cm³ Answer (b): 33 minutes
- Working:
- (a) Total volume = 60 cm × 40 cm × 35 cm = 84 000 cm³. Initial water volume = (2/7) × 84 000 cm³ = 24 000 cm³.
- (b) Volume needed to fill = 84 000 cm³ - 24 000 cm³ = 60 000 cm³. Rate = 2 litres/min = 2000 cm³/min. Time = 60 000 cm³ ÷ 2000 cm³/min = 30 minutes.
- Concept: Find the remaining volume to be filled. Ensure units are consistent (convert litres to cm³). Time = Volume ÷ Rate.
- Marking: (a) 1 mark for total volume, 1 mark for initial water volume. (b) 1 mark for remaining volume and conversion, 1 mark for correct time.
19. Answer (a): 81 000 cm³ Answer (b): 81 containers
- Working:
- (a) Drop in water level = 40 cm - 25 cm = 15 cm. Volume poured out = 90 cm × 60 cm × 15 cm = 81 000 cm³.
- (b) Volume of one cubical container = 10 cm × 10 cm × 10 cm = 1000 cm³. Number of containers = 81 000 cm³ ÷ 1000 cm³ = 81.
- Concept: The volume of water poured out is the volume of the "slice" of water removed. Then divide the total volume by the volume of one container.
- Marking: (a) 1 mark for drop in water level, 1 mark for volume. (b) 1 mark for volume of one container, 1 mark for correct number of containers.
20. Answer (a): 225 000 cm³ Answer (b): 38 cm
- Working:
- (a) Total volume = 100 cm × 60 cm × 50 cm = 300 000 cm³. Initial water volume = (3/4) × 300 000 cm³ = 225 000 cm³.
- (b) Volume of metal cuboid = 20 cm × 15 cm × 10 cm = 3000 cm³. New total volume of water + cuboid = 225 000 cm³ + 3000 cm³ = 228 000 cm³. New water level height = New volume ÷ Base area of tank = 228 000 cm³ ÷ (100 cm × 60 cm) = 228 000 cm³ ÷ 6000 cm² = 38 cm.
- Concept: When an object is submerged, the water level rises because the object takes up space. The new total volume (water + object) divided by the base area gives the new height.
- Marking: (a) 1 mark for total volume, 1 mark for initial water volume. (b) 1 mark for volume of cuboid and new total volume, 1 mark for correct new height.




