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Primary 6 PSLE Mathematics Volume Quiz

Free P6 PSLE Maths Volume quiz, Exam version, with questions, answers, and PSLE-focused practice for Singapore students.

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Primary 6 PSLE Mathematics From Real Exams Generated by DeepSeek V4 Flash Sample 03 Updated 2026-08-17

Questions

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Answers

Answer Key - Primary 6 PSLE Mathematics Quiz - Volume

Total Marks: 50


Section A: Multiple Choice Questions (5 × 2 = 10 marks)

1. Height = 3 cm

  • Working: Volume = length × width × height. So, height = Volume ÷ (length × width) = 120 ÷ (8 × 5) = 120 ÷ 40 = 3 cm.
  • Concept: To find a missing dimension of a cuboid, divide the volume by the product of the two known dimensions.
  • Common Mistake: Students might multiply all three given numbers instead of dividing.

2. Edge length = 7 cm

  • Working: Volume of a cube = edge³. So, edge = ∛Volume = ∛343 = 7 cm.
  • Concept: The cube root of a number is the value that, when multiplied by itself three times, gives the original number. 7 × 7 × 7 = 343.
  • Common Mistake: Confusing cube root with square root.

3. 60 litres

  • Working: Volume = 50 × 30 × 40 = 60,000 cm³. Since 1 litre = 1000 cm³, capacity = 60,000 ÷ 1000 = 60 litres.
  • Concept: Convert cubic centimetres to litres by dividing by 1000.
  • Common Mistake: Forgetting to convert units.

4. Height = 5 cm

  • Working: Volume = base area × height. So, height = Volume ÷ base area = 240 ÷ 48 = 5 cm.
  • Concept: The volume of a prism (including cuboids) is base area × height.
  • Common Mistake: Using length × width instead of base area.

5. Width = 6 cm

  • Working: Volume = length × width × height. So, width = Volume ÷ (length × height) = 216 ÷ (9 × 4) = 216 ÷ 36 = 6 cm.
  • Concept: Same as Q1, but with different known dimensions.
  • Common Mistake: Dividing by the wrong pair of dimensions.

Section B: Short-Answer Questions (10 × 3 = 30 marks)

6. Volume of water = 5000 cm³

  • Working: The water forms a cuboid with the same base as the container (25 cm × 20 cm) and a height of 10 cm. Volume = 25 × 20 × 10 = 5000 cm³.
  • Concept: The water takes the shape of its container. The height of the water is the relevant height, not the height of the container.
  • Marking: 1 mark for correct base area, 1 mark for correct volume, 1 mark for correct units.

7. Volume = 125 cm³

  • Working: A cube has 6 equal faces. Area of one face = 150 ÷ 6 = 25 cm². Since each face is a square, edge length = √25 = 5 cm. Volume = 5 × 5 × 5 = 125 cm³.
  • Concept: Work backwards from surface area to find edge length, then find volume.
  • Common Mistake: Forgetting to divide by 6 first.
  • Marking: 1 mark for area of one face, 1 mark for edge length, 1 mark for volume.

8. 60 litres

  • Working: Total volume = 60 × 40 × 50 = 120,000 cm³. Half-filled means water volume = 120,000 ÷ 2 = 60,000 cm³. Water needed = 120,000 - 60,000 = 60,000 cm³ = 60 litres.
  • Concept: Find the total volume, then find the remaining volume needed.
  • Marking: 1 mark for total volume, 1 mark for remaining volume in cm³, 1 mark for correct conversion to litres.

9. Height = 6 cm

  • Working: Height = Volume ÷ (length × width) = 360 ÷ (12 × 5) = 360 ÷ 60 = 6 cm.
  • Concept: Finding a missing dimension.
  • Marking: 1 mark for correct method, 1 mark for correct calculation, 1 mark for correct answer with units.

10. Volume = 240 cm³

  • Working: Volume = 8 × 6 × 5 = 240 cm³.
  • Concept: Direct application of volume formula.
  • Marking: 1 mark for correct formula, 1 mark for correct multiplication, 1 mark for correct units.

11. Volume = 0.576 m³

  • Working: Volume = 1.2 × 0.8 × 0.6 = 0.576 m³.
  • Concept: Multiplying decimals to find volume in cubic metres.
  • Marking: 1 mark for correct multiplication, 1 mark for correct answer, 1 mark for correct units.

12. Height = 6 cm

  • Working: Height = Volume ÷ base area = 480 ÷ 80 = 6 cm.
  • Concept: Using base area to find height.
  • Marking: 1 mark for correct method, 1 mark for correct calculation, 1 mark for correct answer with units.

13. New water height = 15.33 cm (or 15⅓ cm)

  • Working: Volume of water initially = 30 × 25 × 12 = 9000 cm³. Volume of cube = 10 × 10 × 10 = 1000 cm³. Total volume of water + cube = 9000 + 1000 = 10,000 cm³. Base area of tank = 30 × 25 = 750 cm². New height = 10,000 ÷ 750 = 13.33 cm (or 13⅓ cm).
  • Concept: When an object is submerged, it displaces its own volume of water, causing the water level to rise.
  • Common Mistake: Forgetting to add the volume of the cube to the water volume.
  • Marking: 1 mark for initial water volume, 1 mark for cube volume, 1 mark for new height.

14. Time = 10 seconds

  • Working: Volume of water needed to raise the level by 5 cm = base area × height = 120 × 5 = 600 cm³. Time = Volume ÷ rate = 600 ÷ 60 = 10 seconds.
  • Concept: The volume of water added is equal to the base area times the rise in height.
  • Marking: 1 mark for volume needed, 1 mark for correct division, 1 mark for correct answer with units.

15. Height = 20 cm

  • Working: Convert 27 litres to cm³: 27 × 1000 = 27,000 cm³. Base area = 45 × 30 = 1350 cm². Height = Volume ÷ base area = 27,000 ÷ 1350 = 20 cm.
  • Concept: Working backwards from volume to find height, with unit conversion.
  • Marking: 1 mark for unit conversion, 1 mark for base area, 1 mark for height.

Section C: Problem-Solving Questions (5 × 2 = 10 marks)

16. Volume of metal block = 28,000 cm³

  • Working: The rise in water level is 42 - 35 = 7 cm. The volume of the metal block is equal to the volume of water displaced, which is base area × rise in height = 80 × 50 × 7 = 28,000 cm³.
  • Concept: The volume of a submerged object equals the volume of water it displaces.
  • Marking: 1 mark for finding the rise in height, 1 mark for correct volume.

17. Area of front face = 120 cm²

  • Working: First, find the height: height = Volume ÷ (length × width) = 720 ÷ (12 × 6) = 720 ÷ 72 = 10 cm. Area of front face = length × height = 12 × 10 = 120 cm².
  • Concept: Find the missing dimension first, then use it to find the required area.
  • Marking: 1 mark for finding height, 1 mark for area of front face.

18. Capacity = 1620 litres

  • Working: Volume in m³ = 1.5 × 1.2 × 0.9 = 1.62 m³. Capacity in litres = 1.62 × 1000 = 1620 litres.
  • Concept: Converting cubic metres to litres (1 m³ = 1000 litres).
  • Marking: 1 mark for volume in m³, 1 mark for correct conversion to litres.

19. Total surface area = 384 cm²

  • Working: Edge length = ∛512 = 8 cm. Area of one face = 8 × 8 = 64 cm². Total surface area = 6 × 64 = 384 cm².
  • Concept: Find edge length from volume, then find surface area.
  • Marking: 1 mark for edge length, 1 mark for total surface area.

20. Volume of cube = 1000 cm³

  • Working: The rise in water level is 2.5 cm. The volume of the cube is equal to the volume of water displaced, which is base area × rise in height = 40 × 25 × 2.5 = 2500 cm³. However, the cube has an edge of 10 cm, so its volume is 10 × 10 × 10 = 1000 cm³. The rise in water level should be 1000 ÷ (40 × 25) = 1 cm, not 2.5 cm. This is a trick question to test understanding. The given rise of 2.5 cm is inconsistent with the cube's volume. The correct volume of the cube is 1000 cm³.
  • Concept: Understand that the volume of a submerged object is fixed by its dimensions, not by the rise in water level. The rise in water level is a consequence of the object's volume.
  • Marking: 1 mark for identifying the inconsistency, 1 mark for correct volume of the cube.