From Real Exams Quiz

Primary 6 PSLE Mathematics Volume Quiz

Free P6 PSLE Maths Volume quiz, Exam version, with questions, answers, and PSLE-focused practice for Singapore students.

These static practice materials are generated from the site's syllabus and paper-generation workflow, with source and model context shown so students and parents can evaluate the material before use.

Primary 6 PSLE Mathematics From Real Exams Generated by DeepSeek V4 Flash Sample 02 Updated 2026-08-17

Questions

Free quiz and exam paper access

Enter your details to view this paper

Your access is remembered on this device.

Answers

Answer Key: Primary 6 PSLE Mathematics Quiz - Volume

Total Marks: 60


Section A: Multiple-Choice Questions (10 marks)

1. (A) 7.5 litres [2 marks]

  • Working: Volume = 25 cm × 20 cm × 15 cm = 7500 cm³. Since 1 litre = 1000 cm³, 7500 cm³ ÷ 1000 = 7.5 litres.
  • Teaching Note: Remember that volume in cm³ can be converted to litres by dividing by 1000. The formula for volume of a cuboid is length × width × height.
  • Common Mistake: Forgetting to convert cm³ to litres or dividing by the wrong conversion factor.

2. (B) 6 cm [2 marks]

  • Working: Volume of a cube = side³. So, side = ∛(216) = 6 cm.
  • Teaching Note: The cube root (∛) is the inverse operation of cubing. Since 6 × 6 × 6 = 216, the side length is 6 cm.
  • Common Mistake: Confusing cube root with square root.

3. (B) 5 cm [2 marks]

  • Working: Volume = base area × height. So, height = volume ÷ base area = 240 cm³ ÷ 48 cm² = 5 cm.
  • Teaching Note: The formula V = l × w × h can be rearranged. Since base area = l × w, we have V = base area × h. So h = V ÷ base area.
  • Common Mistake: Using the wrong formula or forgetting to divide.

4. (D) 7200 cm³ [2 marks]

  • Working: Volume of water = length × width × depth = 30 cm × 20 cm × 12 cm = 7200 cm³.
  • Teaching Note: The volume of water in a tank is calculated using the same formula as the tank's volume, but using the depth of the water instead of the height of the tank.
  • Common Mistake: Using the height of the tank instead of the depth of water.

5. (C) 6 cm [2 marks]

  • Working: Volume = length × width × height. So, height = volume ÷ (length × width) = 360 cm³ ÷ (12 cm × 5 cm) = 360 ÷ 60 = 6 cm.
  • Teaching Note: When finding a missing dimension, divide the volume by the product of the other two known dimensions.
  • Common Mistake: Forgetting to multiply length and width first before dividing.

Section B: Short-Answer Questions (20 marks)

6. 30 litres [2 marks]

  • Working: Volume = 40 cm × 25 cm × 30 cm = 30000 cm³. 30000 cm³ ÷ 1000 = 30 litres.
  • Teaching Note: Always check if the answer needs to be in litres. Remember 1 litre = 1000 cm³.
  • Marking: 1 mark for correct volume in cm³, 1 mark for correct conversion to litres.

7. 8 cm [2 marks]

  • Working: ∛512 = 8 cm. Check: 8 × 8 × 8 = 512.
  • Teaching Note: Practice recognizing perfect cubes: 1³=1, 2³=8, 3³=27, 4³=64, 5³=125, 6³=216, 7³=343, 8³=512, 9³=729, 10³=1000.
  • Marking: 1 mark for correct method, 1 mark for correct answer.

8. 6 cm [2 marks]

  • Working: Height = volume ÷ base area = 480 cm³ ÷ 80 cm² = 6 cm.
  • Teaching Note: Base area is the area of the bottom face (length × width).
  • Marking: 1 mark for correct formula, 1 mark for correct answer.

9. 24 cm [2 marks]

  • Working: Volume of water = 36 litres = 36000 cm³. Depth = volume ÷ (length × width) = 36000 ÷ (50 × 30) = 36000 ÷ 1500 = 24 cm.
  • Teaching Note: First convert litres to cm³ by multiplying by 1000. Then use the formula depth = volume ÷ (length × width).
  • Marking: 1 mark for correct conversion, 1 mark for correct answer.

10. 7.5 cm [2 marks]

  • Working: Width = volume ÷ (length × height) = 720 ÷ (12 × 8) = 720 ÷ 96 = 7.5 cm.
  • Teaching Note: The formula can be rearranged to find any missing dimension. Width = V ÷ (l × h).
  • Marking: 1 mark for correct method, 1 mark for correct answer.

11. 60 litres [2 marks]

  • Working: Volume of water = 60 cm × 40 cm × 25 cm = 60000 cm³. 60000 cm³ ÷ 1000 = 60 litres.
  • Teaching Note: Use the depth of water (25 cm), not the height of the tank (35 cm).
  • Marking: 1 mark for correct volume in cm³, 1 mark for correct conversion.

12. 64 cubes [2 marks]

  • Working: Volume of large cube = 8 cm × 8 cm × 8 cm = 512 cm³. Volume of small cube = 2 cm × 2 cm × 2 cm = 8 cm³. Number of cubes = 512 ÷ 8 = 64.
  • Teaching Note: Alternatively, the number of cubes along each edge is 8 ÷ 2 = 4. So total cubes = 4 × 4 × 4 = 64.
  • Marking: 1 mark for correct method, 1 mark for correct answer.

13. 11250 cm³ [2 marks]

  • Working: Volume of tank = 45 cm × 25 cm × 20 cm = 22500 cm³. Half-filled volume = 22500 ÷ 2 = 11250 cm³.
  • Teaching Note: "Half-filled" means the volume of water is half the total volume of the tank.
  • Marking: 1 mark for correct total volume, 1 mark for correct half volume.

14. 5 cm [2 marks]

  • Working: Height = volume ÷ (length × width) = 1000 ÷ (20 × 10) = 1000 ÷ 200 = 5 cm.
  • Teaching Note: Always check that your answer makes sense. A height of 5 cm with a base of 20 cm by 10 cm gives a volume of 1000 cm³.
  • Marking: 1 mark for correct method, 1 mark for correct answer.

15. 15.552 litres [2 marks]

  • Working: Volume = 36 cm × 24 cm × 18 cm = 15552 cm³. 15552 cm³ ÷ 1000 = 15.552 litres.
  • Teaching Note: The answer can be left as a decimal. Some questions may ask for the answer to be rounded.
  • Marking: 1 mark for correct volume in cm³, 1 mark for correct conversion.

Section C: Problem-Solving Questions (30 marks)

16. 25 cm [6 marks]

  • Working:
    1. Volume of water in first tank = 50 cm × 40 cm × 30 cm = 60000 cm³.
    2. The water is poured into the second tank. The volume remains the same.
    3. Depth in second tank = volume ÷ (length × width) = 60000 ÷ (60 × 40) = 60000 ÷ 2400 = 25 cm.
  • Teaching Note: When water is poured from one container to another, the volume of water stays the same. Only the shape of the container changes.
  • Marking Scheme:
    • 2 marks for correct volume of first tank
    • marks for correct method to find depth
    • 1 mark for correct answer
    • Deduct 1 mark for missing or incorrect units

17. 17.5 cm [6 marks]

  • Working:
    1. Volume of water initially = 80 cm × 50 cm × 15 cm = 60000 cm³.
    2. Volume of metal cube = 10 cm × 10 cm × 10 cm = 1000 cm³.
    3. When the cube is placed in the tank, it displaces its own volume of water. The water level rises.
    4. Total volume of water + cube = 60000 + 1000 = 61000 cm³.
    5. New depth = total volume ÷ (length × width) = 61000 ÷ (80 × 50) = 61000 ÷ 4000 = 15.25 cm.
  • Teaching Note: When an object is fully submerged, the water level rises by an amount equal to the volume of the object divided by the base area of the tank. The rise in water level = volume of object ÷ base area of tank = 1000 ÷ (80 × 50) = 1000 ÷ 4000 = 0.25 cm. So new depth = 15 + 0.25 = 15.25 cm.
  • Marking Scheme:
    • 2 marks for correct initial water volume
    • 2 marks for correct volume of cube
    • 1 mark for correct method to find new depth
    • 1 mark for correct answer

18. 30 minutes [6 marks]

  • Working:
    1. Volume of tank = 60 cm × 40 cm × 25 cm = 60000 cm³.
    2. Convert to litres: 60000 cm³ ÷ 1000 = 60 litres.
    3. Time = volume ÷ rate = 60 litres ÷ 2 litres per minute = 30 minutes.
  • Teaching Note: Make sure the units are consistent. The volume is in cm³, but the flow rate is in litres per minute. Convert the volume to litres first.
  • Marking Scheme:
    • 2 marks for correct volume in cm³
    • 2 marks for correct conversion to litres
    • 1 mark for correct method to find time
    • 1 mark for correct answer

19. 14000 cm³ [6 marks]

  • Working:
    1. Volume of water initially = 84 litres = 84000 cm³.
    2. Base area of tank = 70 cm × 40 cm = 2800 cm².
    3. When the metal block is placed in the tank, the water level rises by 5 cm.
    4. The volume of the metal block is equal to the volume of water displaced, which is base area × rise in water level.
    5. Volume of block = 2800 cm² × 5 cm = 14000 cm³.
  • Teaching Note: The rise in water level when an object is submerged is equal to the volume of the object divided by the base area of the container. So volume of object = base area × rise in water level.
  • Marking Scheme:
    • 2 marks for correct base area
    • 2 marks for correct conversion of litres to cm³ (or correct method without conversion)
    • 1 mark for correct method
    • 1 mark for correct answer

20. 150 minutes [6 marks]

  • Working:
    1. Volume of tank = 90 cm × 60 cm × 50 cm = 270000 cm³.
    2. Convert to litres: 270000 cm³ ÷ 1000 = 270 litres.
    3. Net flow rate = inflow rate - outflow rate = 3 litres/min - 1.5 litres/min = 1.5 litres/min.
    4. Time = volume ÷ net rate = 270 litres ÷ 1.5 litres per minute = 180 minutes.
  • Teaching Note: When there is both an inflow and an outflow, the net rate is the difference between the two rates. The tank fills up at the net rate.
  • Marking Scheme:
    • 2 marks for correct volume in cm³
    • 1 mark for correct conversion to litres
    • 1 mark for correct net flow rate
    • 1 mark for correct method to find time
    • 1 mark for correct answer