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Primary 6 PSLE Mathematics Multiplication Division Quiz

Free P6 PSLE Maths Multiplication Division quiz, Ox Exam version, with questions, answers, and PSLE-focused practice for Singapore students.

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Primary 6 PSLE Mathematics From Real Exams Generated by Ox Alpha Updated 2026-08-27

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Questions

Primary 6 PSLE Mathematics Quiz - Multiplication Division

TuitionGoWhere Exam Practice (AI)

Subject: Mathematics Level: Primary 6 PSLE Assessment: SA2 Practice Quiz - Version 1 of 5 Topic: Multiplication and Division Duration: 90 minutes Total Marks: 70

Name: ________________________

Class: ________________________

Date: ________________________

Score: ______________ / 70

Instructions:

Answer all 20 questions.
Show all working clearly. Marks are awarded for method as well as final answers.
Give fractions in their simplest form and include units where required.
Do not use a calculator unless your teacher instructs otherwise.

Section A: Direct Calculation (Questions 1-5, 10 marks)

Work out each answer. Show the key step of your method.

Question 1.

Calculate $476 \times 38$ . (2 marks)

Question 2.

Calculate $9108 \div 12$ . (2 marks)

Question 3.

Calculate $\frac{5}{6} \times \frac{3}{10}$ . Give your answer in its simplest form. (2 marks)

Question 4.

Calculate $\frac{7}{8} \div \frac{3}{4}$ . Give your answer as a mixed number in its simplest form. (2 marks)

Question 5.

Calculate $48 \div 6 \times 4$ . (2 marks)

Section B: Short Problems (Questions 6-10, 15 marks)

Question 6.

One screw has a mass of $12.5$ g. What is the total mass of $48$ such screws? Give your answer in grams. (3 marks)

Question 7.

Mr Lim has $8.4$ litres of juice. He pours all the juice equally into bottles, using exactly $0.35$ litre for each bottle. How many bottles does he fill? (3 marks)

Question 8.

A container holds $\frac{9}{10}$ kg of flour. The flour is packed equally into bags of $\frac{3}{20}$ kg each. How many bags are packed? (3 marks)

Question 9.

A stack of $250$ identical sheets of paper has a thickness of $2.5$ cm. Find the thickness of one sheet in millimetres. (3 marks)

Question 10.

A durian costs $\$ 27 $. A watermelon costs$ \frac{2}{3} $of the price of the durian. What is the total cost of$ 4$ such watermelons? (3 marks)

Section C: Problem Solving (Questions 11-15, 20 marks)

Question 11.

$8$ identical notebooks cost $\$ 34.40 $altogether. Using the unitary method, find the cost of$ 13$ such notebooks. (4 marks)

Question 12.

Caleb has $45$ marbles. Ben has $4$ times as many marbles as Caleb. Farah has $3$ times as many marbles as Ben. How many marbles do the three children have altogether? (4 marks)

Question 13.

A barrel contains $9$ litres of oil. (a) How many $\frac{2}{5}$ -litre bottles can be completely filled? (2 marks) (b) How much oil is left over? Give your answer in litres. (2 marks)

Question 14.

A square has an area of $196 \text{ cm}^2$ . Find the perimeter of the square. (4 marks)

Question 15.

The average of $5$ numbers is $48$ . One number is removed, and the average of the remaining $4$ numbers becomes $50$ . Find the number that was removed. (4 marks)

Section D: Challenging Problems (Questions 16-20, 25 marks)

Question 16.

Siti had $4$ times as many stamps as Ravi. After Siti gave $36$ stamps to Ravi, both of them had the same number of stamps. How many stamps did Siti have at first? (5 marks)

Question 17.

A machine packs sweets into bags at a rate of $345$ sweets per minute. Each bag holds exactly $15$ sweets. Every filled bag is sold for $\$ 2 $. (a) How many bags does the machine fill in$ 25 $minutes? **(3 marks)** (b) What is the total amount of money collected from selling all the bags filled in$ 25$ minutes? (2 marks)

Question 18.

Mei spent $\frac{1}{4}$ of her money on a bag. She then spent $\frac{5}{6}$ of her remaining money on a pair of shoes. She had $\$ 55$ left. How much money did she have at first? (5 marks)

Question 19.

Tap A alone can fill an empty tank in $12$ hours. Tap B alone can fill the same empty tank in $4$ hours. Both taps are turned on at the same time. How many hours will they take to fill the tank completely? (5 marks)

Question 20.

In a box, the number of red beads was $5$ times the number of blue beads. After $96$ red beads and $12$ blue beads were removed, the number of red beads left was $3$ times the number of blue beads left. How many beads were there in the box at first? (5 marks)

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Answers

Primary 6 PSLE Mathematics Quiz - Multiplication Division: Answer Key

TuitionGoWhere Exam Practice (AI) - SA2 Practice Quiz, Version 1 of 5

Total Marks: 70

General marking note: Accept any correct alternative method (e.g. model drawing instead of algebra). Deduct the answer mark only once per question for missing/wrong units.

Answer 1.

$476 \times 38$ Split $38 = 30 + 8$ : $476 \times 30 = 14280$ and $476 \times 8 = 3808$ . Total: $14280 + 3808 = \mathbf{18088}$ Marks: 1 mark for correct partial products, 1 mark for final answer. Common mistake: forgetting the place-value zero in $14280$ , giving $1428 + 3808$ .

Answer 2.

$9108 \div 12$ by long division: $91 \div 12 = 7$ remainder $7$ ; bring down $0$ : $70 \div 12 = 5$ remainder $10$ ; bring down $8$ : $108 \div 12 = 9$ . Quotient: $\mathbf{759}$ . Check: $759 \times 12 = 9108$ . ✓ Marks: 1 mark for correct division steps, 1 mark for answer (or valid check).

Answer 3.

Multiply numerators and denominators: $\frac{5 \times 3}{6 \times 10} = \frac{15}{60}$ . Simplify: $\frac{15}{60} = \mathbf{\frac{1}{4}}$ . Idea: multiplying fractions means "of", so $\frac{5}{6}$ of $\frac{3}{10}$ ; cross-simplifying $5$ with $10$ and $3$ with $6$ also gives $\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}$ directly. Marks: 1 mark for correct product, 1 mark for simplest form.

Answer 4.

Dividing by a fraction means multiplying by its reciprocal: $\frac{7}{8} \div \frac{3}{4} = \frac{7}{8} \times \frac{4}{3} = \frac{28}{24} = \

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Primary 6 PSLE Mathematics Quiz - Multiplication Division: Answer Key

TuitionGoWhere Exam Practice (AI) - SA2 Practice Quiz, Version 1 of 5

Total Marks: 70

General marking note: Accept any correct alternative method (e.g. model drawing instead of algebra). Deduct the answer mark only once per question for missing/wrong units.

Answer 1.

Answer 2.

$9108 \div 12$ by long division: $91 \div 12 = 7$ r $7$ ; bring down $0$ : $70 \div 12 = 5$ r $10$ ; bring down $8$ : $108 \div 12 = 9$ . Quotient: $\mathbf{759}$ . Check: $759 \times 12 = 9108$ . ✓ Marks: 1 mark for correct division steps, 1 mark for answer (or valid check).

Answer 3.

$\frac{5}{6} \times \frac{3}{10} = \frac{15}{60}$ . Simplify: $\frac{15}{60} = \mathbf{\frac{1}{4}}$ . Cross-simplifying ( $5$ with $10$ , $3$ with $6$ ) gives $\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}$ directly. Marks: 1 mark for product, 1 mark for simplest form.

Answer 4.

Dividing by a fraction means multiplying by its reciprocal: $\frac{7}{8} \div \frac{3}{4} = \frac{7}{8} \times \frac{4}{3} = \frac{28}{24} = \frac{7}{6} = \mathbf{1\frac{1}{6}}$ Marks: 1 mark for correct method (reciprocal), 1 mark for mixed number in simplest form. Common mistake: flipping the first fraction instead of the second, or leaving $\frac{7}{6}$ without converting.

Answer 5.

Work from left to right: $48 \div 6 = 8$ , then $8 \times 4 = \mathbf{32}$ . Marks: 2 marks for correct answer following order of operations. Common mistake: doing $6 \times 4 = 24$ first, then $48 \div 24 = 2$ .

Answer 6.

Total mass $= 12.5 \times 48$ . $12.5 \times 48 = 12.5 \times 50 - 12.5 \times 2 = 625 - 25 = \mathbf{600 \text{ g}}$ Marks: 1 mark for method (multiplication), 1 mark for value, 1 mark for unit "g".

Answer 7.

Number of bottles $= 8.4 \div 0.35 = 840 \div 35 = \mathbf{24}$ bottles. Check: $24 \times 0.35 = 8.4$ litres. ✓ Marks: 1 mark for correct operation, 1 mark for value, 1 mark for answer statement.

Answer 8.

Number of bags $= \frac{9}{10} \div \frac{3}{20} = \frac{9}{10} \times \frac{20}{3} = \frac{180}{30} = \mathbf{6}$ bags. Marks: 1 mark for reciprocal method, 1 mark for working, 1 mark for answer.

Answer 9.

Thickness of one sheet $= 2.5 \text{ cm} \div 250 = 0.01$ cm. Convert: $0.01 \text{ cm} = \mathbf{0.1}$ mm. Marks: 1 mark for dividing correctly, 1 mark for conversion to mm, 1 mark for answer with unit. Common mistake: answering $0.01$ (cm) instead of converting to millimetres.

Answer 10.

Watermelon price $= \frac{2}{3} \times 27 = \$ 18 $. Total cost of$ 4 $watermelons$ = 4 \times 18 = \mathbf{$72} $. *Marks: 1 mark for finding one watermelon's price, 1 mark for multiplying by 4, 1 mark for answer with \$ .*

Answer 11.

Unitary method: cost of $1$ notebook $= \$ 34.40 \div 8 = $4.30 $. Cost of$ 13 $notebooks$ = 13 \times $4.30 = \mathbf{$55.90}$. Marks: 1 mark for unit cost, 1 mark for method, 1 mark for value, 1 mark for answer with units.

Answer 12.

Caleb: $45$ . Ben: $4 \times 45 = 180$ . Farah: $3 \times 180 = 540$ . Altogether: $45 + 180 + 540 = \mathbf{765}$ marbles. Marks: 1 mark for Ben, 1 mark for Farah, 1 mark for addition, 1 mark for answer. Common mistake: taking Farah as $3 \times 45 = 135$ instead of $3$ times Ben.

Answer 13.

(a) $\frac{2}{5}$ -litre bottles: $9 \div \frac{2}{5} = 9 \times \frac{5}{2} = 22.5$ , so only $\mathbf{22}$ bottles can be completely filled. (2 marks) (b) Oil used: $22 \times \frac{2}{5} = \frac{44}{5} = 8.8$ litres. Left over: $9 - 8.8 = \mathbf{0.5}$ litre (i.e. $\frac{1}{2}$ litre). (2 marks) Common mistake (a): rounding $22.5$ up to $23$ bottles.

Answer 14.

Area of square $= \text{side} \times \text{side} = 196$ , so side $= \sqrt{196} = 14$ cm. Perimeter $= 4 \times 14 = \mathbf{56 \text{ cm}}$ . Marks: 1 mark for recognising side × side, 1 mark for side = 14, 1 mark for perimeter method, 1 mark for answer with units.

Answer 15.

Total of $5$ numbers $= 5 \times 48 = 240$ . Total of remaining $4$ numbers $= 4 \times 50 = 200$ . Number removed $= 240 - 200 = \mathbf{40}$ . Marks: 1 mark for each total, 1 mark for subtraction, 1 mark for answer.

Answer 16.

Let Ravi have $u$ stamps; Siti has $4u$ . Difference $= 3u$ . After Siti gives $36$ to Ravi they are equal, so the gap closes by $2 \times 36 = 72$ : $3u = 72 \Rightarrow u = 24$ . Siti at first $= 4u = \mathbf{96}$ stamps. Check: Siti $96 - 36 = 60$ ; Ravi $24 + 36 = 60$ . Equal ✓ Marks: 1 mark for model/units, 1 mark for difference reasoning, 1 mark for $u = 24$ , 1 mark for Siti = 96, 1 mark for answer statement.

Answer 17.

(a) Sweets packed in $25$ min: $345 \times 25 = 8625$ sweets. Bags filled: $8625 \div 15 = \mathbf{575}$ bags. (3 marks) (b) Money collected: $575 \times \$ 2 = \mathbf{$1150} $. *(2 marks)* *Marks (a): 1 for total sweets, 1 for division, 1 for answer; (b): 1 for method, 1 for answer with \$ .*

Answer 18.

After buying the bag, Mei has $\frac{3}{4}$ of her money left. She spends $\frac{5}{6}$ of that, so she keeps $\frac{1}{6}$ of it: $\frac{1}{6} \times \frac{3}{4} = \frac{1}{8}$ of her original money. $\frac{1}{8}$ of money $= \$ 55 $, so money at first$ = 55 \times 8 = \mathbf{$440} $. *Check:$ \frac{1}{4} \times 440 = 110 $on bag; left$ 330 $; shoes use$ \frac{5}{6} \times 330 = 275 $; left$ 330 - 275 = 55 $✓* *Marks: 1 for fraction kept after bag, 1 for fraction kept after shoes, 1 for linking$ \frac{1}{8} $to \$ 55, 1 for value, 1 for answer with units.*

Answer 19.

In $1$ hour, Tap A fills $\frac{1}{12}$ of the tank; Tap B fills $\frac{1}{4} = \frac{3}{12}$ . Together per hour: $\frac{1}{12} + \frac{3}{12} = \frac{4}{12} = \frac{1}{3}$ of the tank. Time to fill the tank $= 1 \div \frac{1}{3} = \mathbf{3}$ hours. Marks: 1 for individual rates, 1 for combined rate, 1 for method, 1 for value, 1 for answer with hours.

Answer 20.

At first: blue $= u$ , red $= 5u$ . After removals: red left $= 5u - 96$ ; blue left $= u - 12$ ; and $5u - 96 = 3(u - 12)$ . $5u - 96 = 3u - 36 \Rightarrow 2u = 60 \Rightarrow u = 30$ . Beads at first: red $= 150$ , blue $= 30$ ; total $= 150 + 30 = \mathbf{180}$ beads. Check: after removals, red $= 54$ , blue $= 18$ ; $54 = 3 \times 18$ ✓ Marks: 1 for defining units, 1 for forming equation/model, 1 for solving $u = 30$ , 1 for both counts, 1 for total with answer statement.

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