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Primary 6 PSLE Mathematics Measurement Quiz

Free P6 PSLE Maths Measurement quiz, Ox Exam version, with questions, answers, and PSLE-focused practice for Singapore students.

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Primary 6 PSLE Mathematics From Real Exams Generated by Ox Alpha Updated 2026-08-27

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Questions

Primary 6 PSLE Mathematics Quiz - Measurement

Name: ______________________ Class: ____________ Date: ______________ Score: __________ / 61

Duration: 75 minutes | Total Marks: 61 | Paper: SA2 Practice - Version 1 of 5 | Topic: Measurement

Instructions:

Answer all 20 questions. Show clear working for every question.
Give all final answers with correct units.
Use $\pi = 3.14$ unless the question tells you otherwise.
Do not use a calculator. Marks are shown in brackets [ ].

Section A (Questions 1-5) - Short Answers - 2 marks each

Question 1.

Convert the following. (a) 4.2 km = __________ m (b) 2750 g = __________ kg [2]

Question 2.

A circular sticker has a diameter of 3 cm. Using $\pi = 3.14$ , find its circumference. [2]

Answer: ______________________

Question 3.

A circle has a radius of 10 cm. Using $\pi = 3.14$ , find its area. [2]

Answer: ______________________

Question 4.

A wooden block is a cuboid measuring 9 cm by 4 cm by 5 cm. Find its volume. [2]

Answer: ______________________

Question 5.

A cube has a volume of 125 cm³. Find the length of each edge of the cube. [2]

Answer: ______________________

Section B (Questions 6-15) - Structured Questions - 3 marks each

Question 6.

A semicircle has a diameter of 14 cm. Using $\pi = \frac{22}{7}$ , find the perimeter of the semicircle. Remember that the perimeter includes the curved edge and the diameter. [3]

Answer: ______________________

Question 7.

A quadrant (quarter circle) has a radius of 8 cm. Using $\pi = 3.14$ , find (a) its area, (b) its perimeter. [3]

Answers: (a) ______________ (b) ______________

Question 8.

The figure shows a rectangle measuring 20 cm by 14 cm. A semicircle of diameter 14 cm is joined to the rectangle along its shorter (14 cm) side. Using $\pi = \frac{22}{7}$ , find the total area of the figure. [3]

Image pending generation: diagram for Q8.

Answer: ______________________

Question 9.

A cuboid has a volume of 480 cm³. Its length is 10 cm and its width is 6 cm. Find its height. [3]

Answer: ______________________

Question 10.

An empty rectangular tank measures 40 cm by 30 cm by 25 cm. Water is poured in until it reaches a height of 12 cm. Find the volume of water in the tank, giving your answer in litres. (1000 cm³ = 1 litre) [3]

Answer: ______________________

Question 11.

A cube has a volume of 216 cm³. Find (a) the length of each edge, (b) the total surface area of the cube. [3]

Answers: (a) ______________ (b) ______________

Question 12.

The figure shows a piece of cardboard cut from a rectangle 12 cm long and 8 cm wide. A quarter circle of radius 8 cm has been cut away, with its centre at the top-left corner of the rectangle. The arc runs from the bottom-left corner to a point 8 cm along the top edge, leaving 4 cm of the top edge intact. Using $\pi = 3.14$ , find the perimeter of the remaining piece of cardboard. [3]

Image pending generation: diagram for Q12.

Answer: ______________________

Question 13.

A circle has a circumference of 62.8 cm. Using $\pi = 3.14$ , find (a) its diameter, (b) its radius. [3]

Answers: (a) ______________ (b) ______________

Question 14.

The figure shows a square of side 14 cm. The largest possible circle is drawn inside the square, touching all four sides. The region outside the circle but inside the square is shaded. Using $\pi = \frac{22}{7}$ , find the area of the shaded region. [3]

Image pending generation: diagram for Q14.

Answer: ______________________

Question 15.

A rectangular container measuring 25 cm by 20 cm by 15 cm is completely filled with orange juice. The juice is poured into cups that hold 250 ml each. How many full cups can be filled? (1000 cm³ = 1 litre = 1000 ml) [3]

Answer: ______________________

Section C (Questions 16-20) - Word Problems - 4 or 5 marks

Question 16.

The figure shows a running track formed from a rectangle 20 m long and 10 m wide, with a semicircle attached to each of the two shorter ends. Each semicircle has a diameter of 10 m. Using $\pi = 3.14$ , find (a) the perimeter of the whole outer boundary of the track, (b) the total area enclosed by the track. [4]

Image pending generation: diagram for Q16.

Answers: (a) ______________ (b) ______________

Question 17.

An empty rectangular tank measures 50 cm by 40 cm by 30 cm. A tap pours water into the tank at a rate of 2 litres per minute. How many minutes will it take for the water to reach a height of 24 cm? (1000 cm³ = 1 litre) [4]

Answer: ______________________

Question 18.

A rectangular tank has a base of 25 cm by 16 cm and contains water to a depth of 10 cm. A metal cube of edge 8 cm is lowered gently into the water and becomes fully submerged without any water overflowing. Find the new depth of the water. [4]

Answer: ______________________

Question 19.

A circular pond has a radius of 6 m. A path of width 1 m is built around the pond, so the outer edge of the path is a circle of radius 7 m. Using $\pi = 3.14$ , find (a) the area of the path, (b) the total cost to tar the path if tarring costs $8 per square metre. [4]

Answers: (a) ______________ (b) ______________

Question 20.

An empty rectangular tank has a base measuring 50 cm by 40 cm and a height of 30 cm. A tap pours water into the tank at a rate of 4 litres per minute for 5 minutes. A solid metal block measuring 20 cm by 15 cm by 10 cm is then lowered gently into the tank and becomes fully submerged without any water overflowing. Find the final depth of the water in the tank. [5]

Answer: ______________________

End of Paper - Check your work carefully.

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Answers

Primary 6 PSLE Mathematics Quiz - Measurement: Answer Key

Answer 1.

(a) 4.2 km = 4200 m (multiply by 1000) (b) 2750 g = 2.75 kg (divide by 1000)

Answer 2.

Circumference = π × d = 3.14 × 3 = 9.42 cm

Answer 3.

Area = π × r × r = 3.14 × 10 × 10 = 314 cm²

Answer 4.

Volume = length × width × height = 9 × 4 × 5 = 180 cm³

Answer 5.

Edge = ∛125 = 5 cm (since 5 × 5 × 5 = 125)

Answer 6.

Curved edge = ½ × (22/7) × 14 = 44 cm Perimeter = curved edge + diameter = 44 + 14 = 58 cm Marking note: 1 mark for curved edge, 1 mark for adding the diameter, 1 mark for correct answer with units. Deduct if the diameter is omitted.

Answer 7.

(a) Area = ¼ × 3.14 × 8 × 8 = 50.24 cm² (b) Perimeter = arc + 2 radii = ¼ × (2 × 3.14 × 8) + 8 + 8 = 12.56 + 16 = 28.56 cm Marking note: A common error is forgetting one radius in part (b).

Answer 8.

Rectangle = 20 × 14 = 280 cm² Semicircle = ½ × (22/7) × 7 × 7 = 77 cm² Total area = 280 + 77 = 357 cm²

Answer 9.

Height = Volume ÷ (length × width) = 480 ÷ (10 × 6) = 480 ÷ 60 = 8 cm

Answer 10.

Volume of water = 40 × 30 × 12 = 14 400 cm³ 14 400 ÷ 1000 = 14.4 litres

Answer 11.

(a) Edge = ∛216 = 6 cm (since 6 × 6 × 6 = 216) (b) Surface area = 6 faces × (6 × 6) = 6 × 36 = 216 cm²

Answer 12.

Arc = ¼ × (2 × 3.14 × 8) = 12.56 cm Perimeter = arc + remaining top segment + right edge + bottom edge Perimeter = 12.56 + 4 + 8 + 12 = 36.56 cm New-student explanation: Trace around the shape. You travel along the curved arc, then the untouched 4 cm of the top edge, down the 8 cm right side, and along the full 12 cm bottom edge back to the start of the arc.

Answer 13.

(a) Diameter = Circumference ÷ π = 62.8 ÷ 3.14 = 20 cm (b) Radius = 20 ÷ 2 = 10 cm

Answer 14.

Square = 14 × 14 = 196 cm² Circle = (22/7) × 7 × 7 = 154 cm² Shaded area = 196 − 154 = 42 cm² New-student explanation: The shaded region is everything inside the square but outside the circle, so subtract the circle's area from the square's area.

Answer 15.

Juice = 25 × 20 × 15 = 7500 cm³ = 7500 ml Number of cups = 7500 ÷ 250 = 30 cups

Answer 16.

(a) Two straights = 20 + 20 = 40 m; two semicircles = one full circle = 3.14 × 10 = 31.4 m Perimeter = 40 + 31.4 = 71.4 m (b) Rectangle = 20 × 10 = 200 m²; two semicircles = one full circle = 3.14 × 5 × 5 = 78.5 m² Total area = 200 + 78.5 = 278.5 m² Marking note: Award method marks for combining the two semicircles into one circle.

Answer 17.

Water needed = 50 × 40 × 24 = 48 000 cm³ = 48 litres Time = 48 ÷ 2 = 24 minutes New-student explanation: First find how much water fills the tank to 24 cm, convert to litres, then divide by the rate of 2 litres per minute.

Answer 18.

Base area = 25 × 16 = 400 cm² Water volume = 400 × 10 = 4000 cm³ Cube volume = 8 × 8 × 8 = 512 cm³ New depth = (4000 + 512) ÷ 400 = 4512 ÷ 400 = 11.28 cm Marking note: The key idea is that the submerged cube pushes the water level up by adding its volume over the same base area.

Answer 19.

(a) Area of path = π × (R² − r²) = 3.14 × (7 × 7 − 6 × 6) = 3.14 × 13 = 40.82 m² (b) Cost = 40.82 × 8 = $326.56 New-student explanation: The path is a ring. Find the big circle's area, subtract the pond's area, then multiply by the cost per square metre.

Answer 20.

Water poured in = 4 × 5 = 20 litres = 20 000 cm³ Base area = 50 × 40 = 2000 cm² Depth of water alone = 20 000 ÷ 2000 = 10 cm Block volume = 20 × 15 × 10 = 3000 cm³ Final depth = (20 000 + 3000) ÷ 2000 = 23 000 ÷ 2000 = 11.5 cm Check: 11.5 cm < 30 cm tank height, so no overflow — the answer is valid.