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Primary 6 PSLE Mathematics Area Perimeter Quiz

Free Exam-Derived Primary 6 PSLE Mathematics Area Perimeter quiz with questions and answers for Singapore students. This page is rendered as a direct URL so the questions and answers can be discovered without pressing in-page buttons.

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Primary 6 PSLE Mathematics From Real Exams Generated by Claude Sonnet 4 Updated 2026-06-03

Questions

P6 Maths Quiz: Area and Perimeter

Questions: 20 Time: 40 minutes Total Marks: 30

Section A: Multiple Choice Questions (10 marks)

Choose the best answer for each question. Each question carries 1 mark.

  1. A square has perimeter 48 cm. What is its area? a) 144 cm² b) 169 cm² c) 192 cm² d) 200 cm²

  2. The circumference of a circle is 44 cm. What is its radius? (Take π = 22/7) a) 6 cm b) 7 cm c) 8 cm d) 14 cm

  3. A rectangle has area 96 cm² and width 8 cm. What is its perimeter? a) 32 cm b) 38 cm c) 40 cm d) 44 cm

  4. What is the area of a triangle with base 15 cm and height 12 cm? a) 90 cm² b) 108 cm² c) 180 cm² d) 27 cm²

  5. A trapezium has parallel sides 12 cm and 8 cm, and height 5 cm. What is its area? a) 40 cm² b) 50 cm² c) 60 cm² d) 100 cm²

  6. The area of a circle is 154 cm². What is its diameter? (Take π = 22/7) a) 7 cm b) 14 cm c) 21 cm d) 28 cm

  7. A regular hexagon has perimeter 42 cm. What is the length of each side? a) 6 cm b) 7 cm c) 8 cm d) 9 cm

  8. The area of a parallelogram is 144 cm² and its base is 16 cm. What is its height? a) 8 cm b) 9 cm c) 12 cm d) 18 cm

  9. A rhombus has diagonals 10 cm and 24 cm. What is its area? a) 120 cm² b) 240 cm² c) 68 cm² d) 340 cm²

  10. The perimeter of a rectangular field is 120 m. If its length is 35 m, what is its area? a) 875 m² b) 1050 m² c) 1225 m² d) 1400 m²

Section B: Short Answer Questions (10 marks)

Answer all questions. Show your working clearly.

  1. Find the area of a sector with radius 14 cm and central angle 90°. (Take π = 22/7) (3 marks)

  2. A rectangular swimming pool is 20 m long and 12 m wide. A tile border 1 m wide surrounds the pool. What is the area of the tile border? (3 marks)

  3. The area of an equilateral triangle is 36√3 cm². Find the length of each side. (2 marks)

  4. A circle is inscribed in a square of side 28 cm. Find the area between the square and the circle. (Take π = 22/7) (2 marks)

Section C: Problem Solving Questions (10 marks)

Answer all questions. Show your working clearly.

  1. A composite figure consists of a rectangle 16 cm × 10 cm with a quarter circle cut out from one corner. The quarter circle has radius 4 cm. Find the area of the remaining figure. (Take π = 22/7) (4 marks)

  2. Two squares have a combined perimeter of 120 cm. If one square has side 20 cm, find: (6 marks) a) The side length of the other square (2 marks) b) The difference in their areas (4 marks)

Answers

P6 Mathematics - Area & Perimeter Quiz 1 - Answer Key

Duration: 40 minutes
Total Marks: 30


Section A: Multiple Choice Questions (10 marks)

Question 1 (2 marks)
A rectangle has length 12 cm and width 8 cm. What is its perimeter?
Answer: B) 40 cm

  • Perimeter = 2(length + width) = 2(12 + 8) = 2 × 20 = 40 cm

Question 2 (2 marks)
The area of a square is 144 cm². What is the length of one side?
Answer: A) 12 cm

  • Area = side², so side = √144 = 12 cm

Question 3 (2 marks)
What is the area of a triangle with base 16 cm and height 9 cm?
Answer: A) 72 cm²

  • Area = ½ × base × height = ½ × 16 × 9 = 72 cm²

Question 4 (2 marks)
A circle has radius 7 cm. What is its circumference? (Take π = 22/7)
Answer: B) 44 cm

  • Circumference = 2πr = 2 × 22/7 × 7 = 44 cm

Question 5 (2 marks)
The area of a parallelogram is 84 cm² and its height is 12 cm. What is the length of its base?
Answer: B) 7 cm

  • Area = base × height, so base = area ÷ height = 84 ÷ 12 = 7 cm

Section B: Short Answer Questions (10 marks)

Question 6 (3 marks)
Find the area of a rhombus with diagonals 16 cm and 12 cm.

Answer: 96 cm²

  • Area of rhombus = ½ × d₁ × d₂ = ½ × 16 × 12 = 96 cm²

Question 7 (4 marks)
A rectangular garden is 25 m long and 18 m wide. A path 2 m wide surrounds the garden. What is the area of the path?

Answer: 188 m²

  • Garden area = 25 × 18 = 450 m²
  • Total area (garden + path) = (25 + 4) × (18 + 4) = 29 × 22 = 638 m²
  • Path area = 638 - 450 = 188 m²

Question 8 (3 marks)
The perimeter of a regular pentagon is 85 cm. What is the length of each side?

Answer: 17 cm

  • Pentagon has 5 equal sides
  • Length of each side = 85 ÷ 5 = 17 cm

Section C: Problem Solving Questions (10 marks)

Question 9 (5 marks)
A compound figure consists of a rectangle 20 cm × 12 cm with a semicircle attached to one of the longer sides. Find the total area of the figure. (Take π = 22/7)

Answer: 306 cm²

  • Rectangle area = 20 × 12 = 240 cm²
  • Semicircle radius = 20 ÷ 2 = 10 cm
  • Semicircle area = ½ × πr² = ½ × 22/7 × 10² = ½ × 22/7 × 100 = 1100/14 = 1100 ÷ 14 ≈ 78.57 cm²
  • Wait, let me recalculate: ½ × 22/7 × 100 = 22 × 100 ÷ 14 = 2200 ÷ 14 ≈ 157.14 cm²
  • Actually: ½ × 22/7 × 100 = 11 × 100 ÷ 7 = 1100/7 ≈ 157.14 cm²
  • But let me be more precise: 1100/7 = 157 1/7 cm²
  • Total area = 240 + 157 1/7 = 397 1/7 cm²
  • Wait, that seems wrong. Let me recalculate more carefully.
  • Semicircle area = ½πr² = ½ × 22/7 × 10² = ½ × 22/7 × 100 = 22 × 50/7 = 1100/7 cm²
  • 1100/7 = 157 1/7 ≈ 157.14 cm²
  • Total = 240 + 157.14 = 397.14 cm²
  • But this seems high for a P6 problem. Let me double-check the radius.
  • The semicircle is attached to one of the longer sides (20 cm), so diameter = 20 cm, radius = 10 cm ✓
  • So total area ≈ 397 cm² or exactly 240 + 1100/7 = (1680 + 1100)/7 = 2780/7 cm²

Actually, let me present a cleaner calculation:

  • Rectangle area = 20 × 12 = 240 cm²
  • Semicircle radius = 10 cm
  • Semicircle area = ½ × 22/7 × 10² = 11 × 100/7 = 1100/7 cm² ≈ 157.1 cm²
  • Total area = 240 + 157.1 = 397.1 cm² ≈ 397 cm²

Question 10 (5 marks)
A rectangular field has the same area as a square field with side 60 m. If the rectangular field is 80 m long, what is its perimeter?

Answer: 250 m

  • Square area = 60² = 3600 m²
  • Rectangular field area = 3600 m² (same as square)
  • Length = 80 m, so width = 3600 ÷ 80 = 45 m
  • Perimeter = 2(80 + 45) = 2 × 125 = 250 m

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