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Primary 6 PSLE Mathematics Practice Paper 5

Free P6 PSLE Maths Practice Paper 5, Nemo3 AI version, with questions, answers, and PSLE-focused practice for Singapore students.

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Primary 6 PSLE Mathematics AI Generated Generated by NVIDIA Nemotron 3 Ultra 550B A55B Free Updated 2026-08-17

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Answers

TuitionGoWhere Practice Paper - Mathematics Primary 6 PSLE (Answer Key)

Subject: Mathematics
Level: Primary 6 PSLE
Paper: Practice Paper Version 5
Total Marks: 100


BOOKLET A: Multiple-Choice Questions (20 marks)

1.

Answer: (1) 7,050,009
Explanation: "Seven million" = 7,000,000; "fifty thousand" = 50,000; "nine" = 9. Sum = 7,050,009.
Common mistake: Confusing "fifty thousand" (50,000) with "five hundred thousand" (500,000) → Option (2).


2.

Answer: (4) 800,000
Explanation: In 4,826,315, the digit 8 is in the hundred thousands place. Place value = 8 × 100,000 = 800,000.
Place value check: 4 (millions), 8 (hundred thousands), 2 (ten thousands), 6 (thousands), 3 (hundreds), 1 (tens), 5 (ones).


3.

Answer: (2) 3,490,000
Explanation: To round to the nearest ten thousand, look at the thousands digit (7 in 3,487,652). Since 7 ≥ 5, round up the ten thousands digit (8 → 9). All digits to the right become 0. Result: 3,490,000.


4.

Answer: (2) 27
Working:
72÷8×3+4512×472 \div 8 \times 3 + 45 - 12 \times 4
=9×3+4548= 9 \times 3 + 45 - 48 (Division and multiplication from left to right)
=27+4548= 27 + 45 - 48
=7248= 72 - 48
=24= 24
Wait — recheck: 9×3=279 \times 3 = 27, 12×4=4812 \times 4 = 48, 27+45=7227 + 45 = 72, 7248=2472 - 48 = 24.
Correction: Answer is 24, which is Option (1).
Marking note: The correct answer is (1) 24. The key above had an error.
Correct Answer: (1) 24


5.

Answer: (1) 7,474
Working:
Dividend = (Divisor × Quotient) + Remainder
=(6×1,245)+4= (6 \times 1,245) + 4
=7,470+4= 7,470 + 4
=7,474= 7,474


6.

Answer: (2) 56
Explanation: Common multiples of 6 and 8 are multiples of LCM(6, 8) = 24. Multiples of 24: 24, 48, 72, 96...
Wait — 56 is not a multiple of 24. Let's check each option:

  • 54 ÷ 6 = 9, 54 ÷ 8 = 6.75 ✗
  • 56 ÷ 6 = 9.33, 56 ÷ 8 = 7 ✗
  • 60 ÷ 6 = 10, 60 ÷ 8 = 7.5 ✗
  • 64 ÷ 6 = 10.67, 64 ÷ 8 = 8 ✗
    None of the options are common multiples of 6 and 8.
    Error in question design. The LCM of 6 and 8 is 24. Multiples between 50 and 70: only 48 and 72.
    Correction needed: Change question to "common multiple of 7 and 8" → LCM = 56. Then (2) 56 is correct.
    For this answer key, assuming intended question was "common multiple of 7 and 8":
    Answer: (2) 56
    Explanation: LCM of 7 and 8 = 56. 56 is between 50 and 70.

7.

Answer: (1) 63
Working:
Other number = 1,008÷16=631,008 \div 16 = 63.
Check: 63×16=63×10+63×6=630+378=1,00863 \times 16 = 63 \times 10 + 63 \times 6 = 630 + 378 = 1,008. ✓


8.

Answer: (2) 2,453,000
Working:
Interval size = (2,460,0002,450,000)÷10=10,000÷10=1,000(2,460,000 - 2,450,000) \div 10 = 10,000 \div 10 = 1,000.
X is at the 3rd interval from 2,450,000:
2,450,000+3×1,000=2,453,0002,450,000 + 3 \times 1,000 = 2,453,000.
Visual check: The number line has 10 equal intervals, so each interval = 1,000. 3rd mark = 2,453,000.


9.

Answer: (1) 15,000
Working:
January: 8,750
February: 8,7501,250=7,5008,750 - 1,250 = 7,500
March: 7,500×2=15,0007,500 \times 2 = 15,000


10.

Answer: (3) 4 : 7
Working:
Girls = 48, Boys = 36, Total = 48 + 36 = 84.
Ratio girls : total = 48 : 84 = divide by 12 → 4 : 7.
Common mistake: Giving girls : boys = 48 : 36 = 4 : 3 (Option 2) instead of girls : total.


BOOKLET B: Short-Answer and Structured Questions (80 marks)

11.

Answer: Six million, thirty thousand, four hundred and five
Marking: 1 mark for correct millions/thousands grouping, 1 mark for correct words and hyphenation.
Acceptable variants: "Six million thirty thousand four hundred five" (no "and" is acceptable in some conventions).


12.

Answer: 1,800
Working:
5,600÷(4020×2)+300×65,600 \div ( 40 - 20 \times 2 ) + 300 \times 6
=5,600÷(4040)+1,800= 5,600 \div ( 40 - 40 ) + 1,800 (Brackets first: multiplication before subtraction)
=5,600÷0+1,800= 5,600 \div 0 + 1,800
Error: Division by zero is undefined.
Question flaw: 4020×2=4040=040 - 20 \times 2 = 40 - 40 = 0.
Correction for valid question: Change to 5,600÷(4010×2)+300×65,600 \div ( 40 - 10 \times 2 ) + 300 \times 6
Then: 4020=2040 - 20 = 20, 5,600÷20=2805,600 \div 20 = 280, 300×6=1,800300 \times 6 = 1,800, 280+1,800=2,080280 + 1,800 = 2,080.
Or: 5,600÷(4020)×2+300×65,600 \div ( 40 - 20 ) \times 2 + 300 \times 6 → different.
For this key, assuming intended bracket was (4010×2)(40 - 10 \times 2):
Answer: 2,080
Working (corrected):
5,600÷(4010×2)+300×65,600 \div ( 40 - 10 \times 2 ) + 300 \times 6
=5,600÷(4020)+1,800= 5,600 \div ( 40 - 20 ) + 1,800
=5,600÷20+1,800= 5,600 \div 20 + 1,800
=280+1,800= 280 + 1,800
=2,080= 2,080
Marking note: Original question has division by zero. If student writes "undefined" or "error", award full marks for mathematical correctness.


13.

Answer: 42
Working (Prime factorisation):
84=22×3×784 = 2^2 \times 3 \times 7
126=2×32×7126 = 2 \times 3^2 \times 7
GCF = 2×3×7=422 \times 3 \times 7 = 42.
Alternative (Euclidean algorithm):
126÷84=1126 \div 84 = 1 remainder 42
84÷42=284 \div 42 = 2 remainder 0 → GCF = 42.
Marking: 1 mark for method (factorisation or listing factors), 1 mark for correct answer.


14.

Answer: 15
Working (Backwards/Algebra):
Let the number be xx.
7x+15=1207x + 15 = 120
7x=12015=1057x = 120 - 15 = 105
x=105÷7=15x = 105 \div 7 = 15.
Check: 15×7=10515 \times 7 = 105, 105+15=120105 + 15 = 120. ✓
Marking: 1 mark for correct equation or backward steps, 1 mark for answer.


15.

Answer: 460
Working (Sum and Difference method):
Let the numbers be LL (larger) and SS (smaller).
L+S=1,200L + S = 1,200
LS=280L - S = 280
Add: 2L=1,4802L = 1,480L=740L = 740
S=1,200740=460S = 1,200 - 740 = 460.
Alternative: Smaller = (SumDifference)÷2=(1,200280)÷2=920÷2=460(Sum - Difference) \div 2 = (1,200 - 280) \div 2 = 920 \div 2 = 460.
Marking: 1 mark for method, 1 mark for answer.


16.

Answer: $2,100
Working (Fraction of Remainder / Model Method):

Method 1: Fraction tracking
Let initial amount = 1 whole (or 15 units for common denominator).

  • Spent on TV: 25\frac{2}{5} → Remainder = 125=351 - \frac{2}{5} = \frac{3}{5}
  • Spent on fridge: 13\frac{1}{3} of remainder = 13×35=15\frac{1}{3} \times \frac{3}{5} = \frac{1}{5}
  • Total spent = 25+15=35\frac{2}{5} + \frac{1}{5} = \frac{3}{5}
  • Left = 135=251 - \frac{3}{5} = \frac{2}{5}
  • 25\frac{2}{5} of money = $840
  • 15\frac{1}{5} = 840÷2=840 \div 2 = 420
  • Total (5/5) = 420×5=420 \times 5 = 2,100

Method 2: Units (15 units = LCM of 5 and 3)

  • Total = 15 units
  • TV: 25×15=6\frac{2}{5} \times 15 = 6 units → Remainder = 9 units
  • Fridge: 13×9=3\frac{1}{3} \times 9 = 3 units
  • Left = 15 - 6 - 3 = 6 units = $840
  • 1 unit = $140
  • Total = 15 × 140=140 = 2,100

Method 3: Algebra
Let initial = xx.
After TV: x25x=35xx - \frac{2}{5}x = \frac{3}{5}x
After fridge: 35x13(35x)=35x15x=25x\frac{3}{5}x - \frac{1}{3}(\frac{3}{5}x) = \frac{3}{5}x - \frac{1}{5}x = \frac{2}{5}x
25x=840\frac{2}{5}x = 840x=840×52=2,100x = 840 \times \frac{5}{2} = 2,100.

Marking breakdown (5 marks):

  • 1 mark: Correct remainder after TV (35\frac{3}{5} or 9 units)
  • 1 mark: Correct fraction spent on fridge (15\frac{1}{5} or 3 units)
  • 1 mark: Correct fraction/units left (25\frac{2}{5} or 6 units)
  • 1 mark: Correct value of 1 unit or 15\frac{1}{5} (420or420 or 140)
  • 1 mark: Correct final answer ($2,100) with unit

Common mistake: Taking 13\frac{1}{3} of original instead of remainder → 13x\frac{1}{3}x spent on fridge, leading to wrong answer.


17.

Answer: 12 minutes
Working:

Step 1: Find tank capacity
Volume = 60×40×30=72,000 cm3=72 litres60 \times 40 \times 30 = 72,000 \text{ cm}^3 = 72 \text{ litres}
(1 litre = 1,000 cm³)

Step 2: Find current water volume
35×72=43.2 litres\frac{3}{5} \times 72 = 43.2 \text{ litres}

Step 3: Find volume needed to fill
7243.2=28.8 litres72 - 43.2 = 28.8 \text{ litres}
(Alternatively: 25×72=28.8 litres\frac{2}{5} \times 72 = 28.8 \text{ litres})

Step 4: Find time at 2 litres/min
Time = 28.8÷2=14.4 minutes28.8 \div 2 = 14.4 \text{ minutes}

Step 5: Convert to minutes and seconds
0.4 min=0.4×60=24 seconds0.4 \text{ min} = 0.4 \times 60 = 24 \text{ seconds}
Answer: 14 minutes 24 seconds

Wait — recheck calculation:
28.8÷2=14.428.8 \div 2 = 14.4 minutes.
0.4×60=240.4 \times 60 = 24 seconds.
Correct answer: 14 minutes 24 seconds

Marking breakdown (5 marks):

  • 1 mark: Correct tank volume (72,000 cm³ or 72 litres)
  • 1 mark: Correct volume to fill (28.8 litres or 25×72\frac{2}{5} \times 72)
  • 1 mark: Correct division by rate (14.4 minutes)
  • 1 mark: Correct conversion of decimal to seconds (0.4 × 60 = 24 s)
  • 1 mark: Final answer in correct format (14 min 24 s)

Common mistakes:

  • Forgetting to convert cm³ to litres (using 72,000 ÷ 2 = 36,000 min)
  • Using 35\frac{3}{5} instead of 25\frac{2}{5} for volume needed
  • Incorrect decimal-to-seconds conversion (e.g., 0.4 min = 40 s)
  • Not expressing in minutes and seconds as required

MARKING SUMMARY

QuestionMarksTopic
1–10 (MCQ)20Place value, operations, factors/multiples, ratio, number line
112Number notation (words)
122Order of operations
132GCF
142Algebraic thinking / working backwards
152Sum and difference
165Fraction of remainder (PSLE heuristic)
175Volume + rate + time (multi-step)
Total100

Note to markers: Questions 4, 6, and 12 in the original paper contain errors (Q4 answer key mismatch, Q6 no correct option, Q12 division by zero). In a live paper, these would be corrected before administration. The answer key above reflects corrected versions with explanations.