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Primary 6 PSLE Mathematics Practice Paper 4

Free P6 PSLE Maths Practice Paper 4, Ox AI version, with questions, answers, and PSLE-focused practice for Singapore students.

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Primary 6 PSLE Mathematics AI Generated Generated by Ox Alpha Updated 2026-08-27

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Answers

TuitionGoWhere Practice Paper - Mathematics Primary 6 PSLE

Whole Numbers - Answer Key (Version 4 of 5)

Section A (2 marks each)

1. The digit 5 is in the ten thousands place. Answer: 50,000

2. Smallest first: 8,204,166; 8,204,616; 8,240,616; 8,241,066

3. (a) Nearest ten thousand: 5,950,000 (thousands digit 6 → round up) (b) Nearest hundred thousand: 5,900,000 (ten thousands digit 4 → round down)

4. 90 − 6 × 7 + 42 ÷ 7 = 90 − 42 + 6 = 54

5. Factors common to 36 and 54: greatest is 18

Section B (3 marks each)

6. 4,275 ÷ 25 = 171 boxes

7. 750 ÷ 45 = 16 remainder 30 → 16 buses not enough. Answer: 17 buses

8. (a) Row 20 = 5 + 19 × 4 = 81 chairs [2] (b) 5 + 4 × (n − 1) = 61 → 4 × (n − 1) = 56 → n − 1 = 14 → Row 15 [1]

9. (129 + 15) ÷ 6 = 144 ÷ 6 = 24

10. Let f = 50-cent coins. 50f + 20(25 − f) = 860 → 30f + 500 = 860 → 30f = 360 → f = 12 fifty-cent coins (check: 600 + 260 = 860¢ = $8.60 ✓)

Section C (3 marks each)

11. Difference at first = 2 units; difference after = 24 + 24 = 48. 2 units = 48 → 1 unit = 24. Ben had 24 marbles at first. (Check: Aini 72 − 24 = 48 = 24 + 24 ✓)

12. Father = 3u, son = u. 3u + 14 = 2(u + 14) → 3u + 14 = 2u + 28 → u = 14 years old

13. LCM of 6 and 8 = 24 seconds. 3 minutes = 180 s. 180 ÷ 24 = 7 (remainder 12). They flash together 7 times again.

14. (a) 48 ≈ 50, 112 ≈ 110 → estimate = 5,500 seats [1] (b) 48 × 112 = 5,376 seats [2]

15. Every 4 books cost 3 × 12=12 = 36. 32 ÷ 4 = 8 groups. 8 × 36=36 = **288**

Section D (4 marks each)

16. Let all be chickens: 36 × 2 = 72 legs. Extra legs = 100 − 72 = 28. Each goat adds 2 legs → goats = 28 ÷ 2 = 14. Chickens = 36 − 14 = 22 chickens (check: 44 + 56 = 100 ✓)

17. Larger = 5 × smaller + 6. Sum: 6 × smaller + 6 = 150 → 6 × smaller = 144 → smaller = 24 (larger = 126; 126 ÷ 24 = 5 R 6 ✓)

18. Same number of pens and notebooks → multiple of both 8 and 5. LCM(8, 5) = 40 pens

19. 500 ÷ 68 = 7 remainder 24. Greatest number of chairs: 7; money left: $24 (check: 7 × 68 = 476; 500 − 476 = 24 ✓)

20. In the end: total stays 480; Bala : Ali = 3 : 1 → 4 units = 480 → Ali at end = 120. Ali at first = 120 + 45 = 165 stamps (check: Bala end = 360 = 3 × 120 ✓)


Marking notes: Award method marks for correct strategy even if a final arithmetic slip occurs. For Questions 7, 13 and 19, deduct 1 mark if the remainder/context is ignored (e.g., answering 16 buses or 6 chairs).