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Primary 6 PSLE Mathematics Practice Paper 3
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TuitionGoWhere Practice Paper — Answer Key
Mathematics Primary 6 PSLE — Whole Numbers (Version 3 of 5)
Section A: Short Answer Questions (20 marks)
1. 5 203 609 [2]
Working: Five million = 5 000 000; two hundred and three thousand = 203 000; six hundred and nine = 609. Combined: 5 000 000 + 203 000 + 609 = 5 203 609.
Marking: Award 2 marks for the correct numeral. Award 1 mark if the student writes the correct words but makes a place-value error (e.g., 5 230 609).
2. 700 000 [2]
Working: In 3 725 408, the digit 7 is in the hundred-thousands place. Value = 7 × 100 000 = 700 000.
Marking: Award 2 marks for 700 000. Accept "7 hundred thousand" or "hundred-thousands place" with value. Award 1 mark if the student identifies the correct place but gives an incorrect value (e.g., 70 000).
3. 4 025 100 , 4 205 010 , 4 502 100 , 4 520 001 [2]
Working: Compare digit by digit from the left. All numbers start with 4 million. Compare the hundred-thousands digit: 0 < 2 < 5 = 5. For 4 502 100 and 4 520 001, the ten-thousands digits are 0 and 2 respectively, so 4 502 100 < 4 520 001.
Order: 4 025 100 < 4 205 010 < 4 502 100 < 4 520 001.
Marking: Award 2 marks for the correct order. Award 1 mark if two adjacent numbers are swapped but the rest are correct.
4. 8 500 000 [2]
Working: The hundred-thousands digit is 4 (in 8 473 629). The ten-thousands digit is 7, which is ≥ 5, so we round up. 8 473 629 rounded to the nearest hundred thousand = 8 500 000.
Marking: Award 2 marks for 8 500 000. Common mistake: writing 8 470 000 (rounding to nearest ten thousand) — award 0 marks.
5. 12 [2]
Working:
- Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36
- Factors of 84: 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84
- Common factors: 1, 2, 3, 4, 6, 12
- HCF = 12
Alternative method (prime factorisation):
- 36 = 2² × 3²
- 84 = 2² × 3 × 7
- HCF = 2² × 3 = 12
Marking: Award 2 marks for 12. Award 1 mark for correct method with arithmetic error.
6. 75 [2]
Working:
- Multiples of 15: 15, 30, 45, 60, 75, 90, …
- Multiples of 25: 25, 50, 75, 100, …
- LCM = 75
Alternative method:
- 15 = 3 × 5; 25 = 5²
- LCM = 3 × 5² = 3 × 25 = 75
Marking: Award 2 marks for 75. Award 1 mark for correct method with minor error.
7. 2³ × 3² [2]
Working:
- 72 ÷ 2 = 36
- 36 ÷ 2 = 18
- 18 ÷ 2 = 9
- 9 ÷ 3 = 3
- 3 ÷ 3 = 1
- 72 = 2 × 2 × 2 × 3 × 3 = 2³ × 3²
Marking: Award 2 marks for 2³ × 3². Award 1 mark if the student lists prime factors without index notation (2 × 2 × 2 × 3 × 3). Award 0 marks if any factor is not prime.
8. 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60 [2]
Working: Find factor pairs of 60:
- 1 × 60, 2 × 30, 3 × 20, 4 × 15, 5 × 12, 6 × 10
- Factors: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60
Marking: Award 2 marks for all 12 factors listed correctly. Award 1 mark if at least 8 factors are correct and no incorrect factors are listed. Deduct 1 mark if factors are listed but not in order (still award 1 mark minimum if all correct).
9. 72 (accept also 60 if only one answer required; both 60 and 72 are valid) [2]
Working: A number divisible by both 4 and 6 must be divisible by LCM(4, 6) = 12.
- Multiples of 12 between 50 and 80: 60, 72
- If one answer is required: 72 (or 60 — both are correct; accept either)
Note: If the question expects a single answer, the most natural choice is 72 (the larger value), but 60 is equally valid. Accept either.
Marking: Award 2 marks for 60 or 72. Award 1 mark for correct method (listing multiples of 12) with minor error.
10. 9 [2]
Working: For a number to be divisible by 9, the sum of its digits must be divisible by 9.
- Sum of known digits: 9 + 3 + 4 + 5 + 6 = 27
- 27 is already divisible by 9, so □ = 0 or 9 (since 27 + 0 = 27 and 27 + 9 = 36, both divisible by 9)
- Since □ is the leading digit of a 6-digit number, □ cannot be 0.
- Therefore, □ = 9
Marking: Award 2 marks for 9. Award 1 mark if the student writes 0 or 9 without justification. If the student writes only 0, award 0 marks (leading zero would make it a 5-digit number).
Section B: Structured Questions (12 marks)
11.
(a) 2 531 618 [2]
Working: 2 345 678 + 185 940 = 2 531 618
Marking: Award 2 marks for correct answer. Award 1 mark for correct addition with a carry error.
(b) 2 530 000 [1]
Working: 2 531 618 — the thousands digit is 1 (< 5), so round down to 2 530 000.
Marking: Award 1 mark for 2 530 000.
12.
(a) 52 [2]
Working: 1 250 ÷ 24 = 52 remainder 2. Number of full boxes = 52.
Marking: Award 2 marks for 52. Award 1 mark for correct division with minor error.
(b) 2 [1]
Working: 52 × 24 = 1 248. Remainder = 1 250 − 1 248 = 2 toys.
Marking: Award 1 mark for 2.
13. 24 [3]
Working: For two numbers, HCF × LCM = Product of the two numbers.
- Let the other number be n.
- 8 × 96 = 32 × n
- 768 = 32 × n
- n = 768 ÷ 32 = 24
Verification: HCF(32, 24) = 8 ✓; LCM(32, 24) = 96 ✓
Marking: Award 3 marks for correct answer with working. Award 2 marks for correct formula with arithmetic error. Award 1 mark for stating the formula HCF × LCM = product of two numbers.
Section C: Problem-Solving Questions (8 marks)
14.
(a) 240 [2]
Working: 3 600 ÷ 15 = 240 teams.
Marking: Award 2 marks for 240. Award 1 mark for correct division with error.
(b) 180 [2]
Working: 3 600 ÷ 20 = 180 teams.
Marking: Award 2 marks for 180. Award 1 mark for correct division with error.
15.
(a) 102 000 [2]
Working: 24 560 + 31 285 + 18 740 + 27 415 = 102 000
Step-by-step:
- 24 560 + 31 285 = 55 845
- 55 845 + 18 740 = 74 585
- 74 585 + 27 415 = 102 000
Marking: Award 2 marks for 102 000. Award 1 mark for correct addition with one carry error.
(b) Estimated total = 102 000 [2]
Working:
- Monday: 24 560 → 25 000 (round to nearest thousand; 560 ≥ 500, round up)
- Tuesday: 31 285 → 31 000 (285 < 500, round down)
- Wednesday: 18 740 → 19 000 (740 ≥ 500, round up)
- Thursday: 27 415 → 27 000 (415 < 500, round down)
- Estimated total = 25 000 + 31 000 + 19 000 + 27 000 = 102 000
Marking: Award 2 marks for correct rounded values and total. Award 1 mark for correct rounding of at least 3 days and a reasonable estimated total.
Total: 40 marks