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Primary 6 PSLE Mathematics Practice Paper 3
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TuitionGoWhere Practice Paper - Mathematics Primary 6 PSLE
TuitionGoWhere Practice Paper (AI)
Subject: Mathematics Level: Primary 6 (PSLE) Paper: Practice Paper — Whole Numbers Version: 3 of 5 Duration: 50 minutes Total Marks: 40
Name: ________________________ Class: ________________________ Date: ________________________
Instructions
- Write your name, class, and date in the spaces provided above.
- Answer all questions in the spaces provided.
- Show all working clearly. Marks will be awarded for correct working even if the final answer is wrong.
- Do not use a calculator.
- The number of marks available for each question is shown in brackets, e.g. [2].
- Check your work before submitting.
Section A: Short Answer Questions (20 marks)
Questions 1–10. Each question carries 2 marks. Write your answer in the space provided.
1. Write the following number in numerals.
Five million, two hundred and three thousand, six hundred and nine
Answer: ________________________ [2]
2. What is the value of the digit 7 in the number 3 725 408?
Answer: ________________________ [2]
3. Arrange the following numbers in order, starting with the smallest.
4 502 100 | 4 205 010 | 4 025 100 | 4 520 001
Answer: _______ , _______ , _______ , _______ [2]
4. Round 8 473 629 to the nearest hundred thousand.
Answer: ________________________ [2]
5. Find the Highest Common Factor (HCF) of 36 and 84.
Answer: ________________________ [2]
6. Find the Lowest Common Multiple (LCM) of 15 and 25.
Answer: ________________________ [2]
7. Express 72 as a product of its prime factors. Give your answer in index notation.
Answer: ________________________ [2]
8. List all the factors of 60.
Answer: ________________________ [2]
9. A number is divisible by both 4 and 6. It lies between 50 and 80. What is the number?
Answer: ________________________ [2]
10. What is the missing digit □?
□3 456 is divisible by 9.
Answer: ________________________ [2]
Section B: Structured Questions (12 marks)
Questions 11–13. Show all working clearly.
11. The population of a town is 2 345 678. In the following year, the population increased by 185 940.
(a) What is the new population of the town? [2]
(b) Round the new population to the nearest ten thousand. [1]
Answer (a): ________________________
Answer (b): ________________________
12. A factory produces 1 250 toys per day. The toys are packed into boxes of 24.
(a) How many full boxes can be packed in one day? [2]
(b) How many toys are left over? [1]
Answer (a): ________________________
Answer (b): ________________________
13. The HCF of two numbers is 8 and their LCM is 96. One of the numbers is 32. Find the other number. [3]
Answer: ________________________
Section C: Problem-Solving Questions (8 marks)
Questions 14–15. Show all working clearly. Explain your reasoning where required.
14. A school organised a fun run. There were 3 600 participants. They were divided into teams of 15 for the first round. For the second round, the organisers regrouped all participants into teams of 20.
(a) How many teams were there in the first round? [2]
(b) How many teams were there in the second round? [2]
Answer (a): ________________________
Answer (b): ________________________
15. The chart below shows the number of visitors to a science exhibition over four days.
| Day | Visitors |
|---|---|
| Monday | 24 560 |
| Tuesday | 31 285 |
| Wednesday | 18 740 |
| Thursday | 27 415 |
(a) Find the total number of visitors over the four days. [2]
(b) Round each day's visitors to the nearest thousand. Then estimate the total number of visitors. [2]
Answer (a): ________________________
Answer (b): ________________________
— End of Paper —
Answers
TuitionGoWhere Practice Paper — Answer Key
Mathematics Primary 6 PSLE — Whole Numbers (Version 3 of 5)
Section A: Short Answer Questions (20 marks)
1. 5 203 609 [2]
Working: Five million = 5 000 000; two hundred and three thousand = 203 000; six hundred and nine = 609. Combined: 5 000 000 + 203 000 + 609 = 5 203 609.
Marking: Award 2 marks for the correct numeral. Award 1 mark if the student writes the correct words but makes a place-value error (e.g., 5 230 609).
2. 700 000 [2]
Working: In 3 725 408, the digit 7 is in the hundred-thousands place. Value = 7 × 100 000 = 700 000.
Marking: Award 2 marks for 700 000. Accept "7 hundred thousand" or "hundred-thousands place" with value. Award 1 mark if the student identifies the correct place but gives an incorrect value (e.g., 70 000).
3. 4 025 100 , 4 205 010 , 4 502 100 , 4 520 001 [2]
Working: Compare digit by digit from the left. All numbers start with 4 million. Compare the hundred-thousands digit: 0 < 2 < 5 = 5. For 4 502 100 and 4 520 001, the ten-thousands digits are 0 and 2 respectively, so 4 502 100 < 4 520 001.
Order: 4 025 100 < 4 205 010 < 4 502 100 < 4 520 001.
Marking: Award 2 marks for the correct order. Award 1 mark if two adjacent numbers are swapped but the rest are correct.
4. 8 500 000 [2]
Working: The hundred-thousands digit is 4 (in 8 473 629). The ten-thousands digit is 7, which is ≥ 5, so we round up. 8 473 629 rounded to the nearest hundred thousand = 8 500 000.
Marking: Award 2 marks for 8 500 000. Common mistake: writing 8 470 000 (rounding to nearest ten thousand) — award 0 marks.
5. 12 [2]
Working:
- Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36
- Factors of 84: 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84
- Common factors: 1, 2, 3, 4, 6, 12
- HCF = 12
Alternative method (prime factorisation):
- 36 = 2² × 3²
- 84 = 2² × 3 × 7
- HCF = 2² × 3 = 12
Marking: Award 2 marks for 12. Award 1 mark for correct method with arithmetic error.
6. 75 [2]
Working:
- Multiples of 15: 15, 30, 45, 60, 75, 90, …
- Multiples of 25: 25, 50, 75, 100, …
- LCM = 75
Alternative method:
- 15 = 3 × 5; 25 = 5²
- LCM = 3 × 5² = 3 × 25 = 75
Marking: Award 2 marks for 75. Award 1 mark for correct method with minor error.
7. 2³ × 3² [2]
Working:
- 72 ÷ 2 = 36
- 36 ÷ 2 = 18
- 18 ÷ 2 = 9
- 9 ÷ 3 = 3
- 3 ÷ 3 = 1
- 72 = 2 × 2 × 2 × 3 × 3 = 2³ × 3²
Marking: Award 2 marks for 2³ × 3². Award 1 mark if the student lists prime factors without index notation (2 × 2 × 2 × 3 × 3). Award 0 marks if any factor is not prime.
8. 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60 [2]
Working: Find factor pairs of 60:
- 1 × 60, 2 × 30, 3 × 20, 4 × 15, 5 × 12, 6 × 10
- Factors: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60
Marking: Award 2 marks for all 12 factors listed correctly. Award 1 mark if at least 8 factors are correct and no incorrect factors are listed. Deduct 1 mark if factors are listed but not in order (still award 1 mark minimum if all correct).
9. 72 (accept also 60 if only one answer required; both 60 and 72 are valid) [2]
Working: A number divisible by both 4 and 6 must be divisible by LCM(4, 6) = 12.
- Multiples of 12 between 50 and 80: 60, 72
- If one answer is required: 72 (or 60 — both are correct; accept either)
Note: If the question expects a single answer, the most natural choice is 72 (the larger value), but 60 is equally valid. Accept either.
Marking: Award 2 marks for 60 or 72. Award 1 mark for correct method (listing multiples of 12) with minor error.
10. 9 [2]
Working: For a number to be divisible by 9, the sum of its digits must be divisible by 9.
- Sum of known digits: 9 + 3 + 4 + 5 + 6 = 27
- 27 is already divisible by 9, so □ = 0 or 9 (since 27 + 0 = 27 and 27 + 9 = 36, both divisible by 9)
- Since □ is the leading digit of a 6-digit number, □ cannot be 0.
- Therefore, □ = 9
Marking: Award 2 marks for 9. Award 1 mark if the student writes 0 or 9 without justification. If the student writes only 0, award 0 marks (leading zero would make it a 5-digit number).
Section B: Structured Questions (12 marks)
11.
(a) 2 531 618 [2]
Working: 2 345 678 + 185 940 = 2 531 618
Marking: Award 2 marks for correct answer. Award 1 mark for correct addition with a carry error.
(b) 2 530 000 [1]
Working: 2 531 618 — the thousands digit is 1 (< 5), so round down to 2 530 000.
Marking: Award 1 mark for 2 530 000.
12.
(a) 52 [2]
Working: 1 250 ÷ 24 = 52 remainder 2. Number of full boxes = 52.
Marking: Award 2 marks for 52. Award 1 mark for correct division with minor error.
(b) 2 [1]
Working: 52 × 24 = 1 248. Remainder = 1 250 − 1 248 = 2 toys.
Marking: Award 1 mark for 2.
13. 24 [3]
Working: For two numbers, HCF × LCM = Product of the two numbers.
- Let the other number be n.
- 8 × 96 = 32 × n
- 768 = 32 × n
- n = 768 ÷ 32 = 24
Verification: HCF(32, 24) = 8 ✓; LCM(32, 24) = 96 ✓
Marking: Award 3 marks for correct answer with working. Award 2 marks for correct formula with arithmetic error. Award 1 mark for stating the formula HCF × LCM = product of two numbers.
Section C: Problem-Solving Questions (8 marks)
14.
(a) 240 [2]
Working: 3 600 ÷ 15 = 240 teams.
Marking: Award 2 marks for 240. Award 1 mark for correct division with error.
(b) 180 [2]
Working: 3 600 ÷ 20 = 180 teams.
Marking: Award 2 marks for 180. Award 1 mark for correct division with error.
15.
(a) 102 000 [2]
Working: 24 560 + 31 285 + 18 740 + 27 415 = 102 000
Step-by-step:
- 24 560 + 31 285 = 55 845
- 55 845 + 18 740 = 74 585
- 74 585 + 27 415 = 102 000
Marking: Award 2 marks for 102 000. Award 1 mark for correct addition with one carry error.
(b) Estimated total = 102 000 [2]
Working:
- Monday: 24 560 → 25 000 (round to nearest thousand; 560 ≥ 500, round up)
- Tuesday: 31 285 → 31 000 (285 < 500, round down)
- Wednesday: 18 740 → 19 000 (740 ≥ 500, round up)
- Thursday: 27 415 → 27 000 (415 < 500, round down)
- Estimated total = 25 000 + 31 000 + 19 000 + 27 000 = 102 000
Marking: Award 2 marks for correct rounded values and total. Award 1 mark for correct rounding of at least 3 days and a reasonable estimated total.
Total: 40 marks