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Primary 6 PSLE Mathematics Practice Paper 1

Free P6 PSLE Maths Practice Paper 1, LongCat AI version, with questions, answers, and PSLE-focused practice for Singapore students.

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Primary 6 PSLE Mathematics AI Generated Generated by LongCat 2.0 LLM Updated 2026-08-17

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Questions

TuitionGoWhere Practice Paper - Mathematics Primary 6 PSLE

TuitionGoWhere Practice Paper (AI)

Subject: Mathematics Level: Primary 6 (PSLE) Paper: Practice Paper 1 of 5 — Whole Numbers Duration: 50 minutes Total Marks: 40

Name: ___________________________ Class: ___________________________ Date: ___________________________

Instructions

Answer all questions.
Show your working clearly in the space provided. Marks are awarded for correct steps even if the final answer is wrong.
Do not use a calculator.
Write your answers in the spaces provided.
The number of marks available is shown in brackets [ ] at the end of each question or part-question.

Section A: Short Answer (10 marks)

Questions 1–5. Each question carries 2 marks. Write your answer in the space provided.

1. Write the following number in numerals.

Five million, two hundred and six thousand, and forty-three

Answer: ___________________________ [2]

2. Round 4,785,362 to the nearest hundred thousand.

Answer: ___________________________ [2]

3. Find the value of 7 × 10,000 + 3 × 1,000 + 5 × 100 + 8 × 1.

Answer: ___________________________ [2]

4. List all the factors of 48.

Answer: ___________________________ [2]

5. Find the smallest number that is a multiple of both 18 and 24.

Answer: ___________________________ [2]

Section B: Structured Questions (20 marks)

Questions 6–15. Each question carries 2 marks. Show your working clearly.

6. Arrange the following numbers in order, starting with the smallest.

5,230,019 | 5,032,910 | 5,320,109 | 5,023,091

Answer: ___________________________ [2]

7. A factory produced 3,285,617 toys in January and 2,974,386 toys in February. How many toys did the factory produce in the two months altogether?

Answer: ___________________________ [2]

8. Find the highest common factor (HCF) of 36 and 60.

Answer: ___________________________ [2]

9. What is the least number that must be subtracted from 10,000 so that the remainder is exactly divisible by 36?

Answer: ___________________________ [2]

10. A number is divisible by both 8 and 15. What is the smallest possible value of this number?

Answer: ___________________________ [2]

11. Write 60,405,200 in words.

Answer: ___________________________ [2]

12. The population of a town is 3,450,678. What is the place value of the digit 5 in this number?

Answer: ___________________________ [2]

13. Find the product of the LCM and HCF of 24 and 36.

Answer: ___________________________ [2]

14. A shopkeeper packed 1,250 apples into bags of 24 apples each. How many full bags did he pack? How many apples were left over?

Answer: Full bags: _______________ Leftover apples: _______________ [2]

15. Express 84 as a product of its prime factors.

Answer: ___________________________ [2]

Section C: Problem Sums (10 marks)

Questions 16–20. Show all working clearly. Marks are awarded for correct steps.

16. A school ordered 4,500 chairs for its new hall. The chairs were delivered in 18 equal shipments. How many chairs were in each shipment? [2]

17. The sum of two numbers is 96,435. One of the numbers is 47,286. Find the difference between the two numbers. [2]

18. A farmer has 1,440 eggs. He packs them into cartons of 12 eggs each. He then packs the cartons into boxes, with 5 cartons in each box. How many boxes does he need? [3]

19. Three traffic lights at a junction change their signals at regular intervals. The first light changes every 40 seconds, the second every 60 seconds, and the third every 90 seconds. If all three lights change together at 8:00 a.m., at what time will they next change together? [3]

20. A number when divided by 35 gives a quotient of 1,248 and a remainder of 17. (a) Find the number. [2] (b) If this number is now divided by 25, what is the quotient and remainder? [1]

End of Paper

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Answers

TuitionGoWhere Practice Paper — Answer Key

Mathematics Primary 6 PSLE — Whole Numbers (Version 1 of 5)

Section A: Short Answer

1. 5,206,043 [2]

Award 2 marks for the correct numeral.
Common mistake: writing 5,260,043 (confusing hundred thousands and ten thousands place).

2. 4,800,000 [2]

The digit in the ten thousands place is 8, so we round up.
4,785,362 → 4,800,000 (nearest hundred thousand).
Award 2 marks for correct answer.

3. 73,508 [2]

7 × 10,000 = 70,000
3 × 1,000 = 3,000
5 × 100 = 500
8 × 1 = 8
Total = 70,000 + 3,000 + 500 + 8 = 73,508
Award 2 marks for correct answer.

4. 1, 2, 3, 4, 6, 8, 12, 16, 24, 48 [2]

Award 2 marks for the complete list in any order.
Award 1 mark if at least 7 correct factors are listed with no incorrect ones.
Common mistake: omitting 1 or 48.

5. 72 [2]

Multiples of 18: 18, 36, 54, 72, 90…
Multiples of 24: 24, 48, 72, 96…
LCM = 72
Award 2 marks for correct answer. Award 1 mark for correct method (listing multiples) with arithmetic error.

Section B: Structured Questions

6. 5,023,091; 5,032,910; 5,230,019; 5,320,109 [2]

Compare digit by digit from the left (millions, then hundred thousands, then ten thousands…).
Award 2 marks for correct order. Award 1 mark if 2–3 numbers are in correct relative position.

7. 6,260,003 toys [2]

3,285,617 + 2,974,386 = 6,260,003
Award 2 marks for correct answer. Award 1 mark for correct addition setup with minor arithmetic error.

8. 12 [2]

Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36
Factors of 60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60
HCF = 12
Alternative: 36 = 2² × 3², 60 = 2² × 3 × 5 → HCF = 2² × 3 = 12
Award 2 marks for correct answer with working.

9. 28 [2]

10,000 ÷ 36 = 277 remainder 28
So 36 × 277 = 9,972
10,000 − 9,972 = 28
The least number to subtract = 28
Award 2 marks for correct answer. Award 1 mark for correct division with remainder identified.

10. 120 [2]

LCM of 8 and 15: 8 = 2³, 15 = 3 × 5 → LCM = 2³ × 3 × 5 = 120
Award 2 marks for correct answer.

11. Sixty million, four hundred and five thousand, two hundred [2]

Award 2 marks for correct answer. Accept minor variations in formatting (e.g., "and" placement).

12. Ten thousands (or 50,000) [2]

3,450,678 — the digit 5 is in the ten thousands place, representing 50,000.
Award 2 marks for correct answer.

13. 864 [2]

HCF of 24 and 36 = 12
LCM of 24 and 36 = 72
Product = 12 × 72 = 864
Note: Product of LCM and HCF of two numbers = product of the two numbers = 24 × 36 = 864
Award 2 marks for correct answer.

14. Full bags: 52, Leftover apples: 2 [2]

1,250 ÷ 24 = 52 remainder 2
24 × 52 = 1,248; 1,250 − 1,248 = 2
Award 2 marks for both correct. Award 1 mark for correct division with one part correct.

15. 84 = 2 × 2 × 3 × 7 (or 2² × 3 × 7) [2]

84 ÷ 2 = 42
42 ÷ 2 = 21
21 ÷ 3 = 7
7 ÷ 7 = 1
Award 2 marks for correct prime factorisation.

Section C: Problem Sums

16. 250 chairs [2]

4,500 ÷ 18 = 250
Award 2 marks for correct answer. Award 1 mark for correct division setup.

17. 1,863 [2]

Second number = 96,435 − 47,286 = 49,149
Difference = 49,149 − 47,286 = 1,863
Award 2 marks for correct answer. Award 1 mark for finding the second number correctly.

18. 24 boxes [3]

Step 1: Number of cartons = 1,440 ÷ 12 = 120 cartons
Step 2: Number of boxes = 120 ÷ 5 = 24 boxes
Award 3 marks for correct answer with complete working.
Award 2 marks for correct method with one arithmetic error.
Award 1 mark for finding the number of cartons correctly.

19. 8:06 a.m. [3]

Find LCM of 40, 60, and 90.
40 = 2³ × 5
60 = 2² × 3 × 5
90 = 2 × 3² × 5
LCM = 2³ × 3² × 5 = 8 × 9 × 5 = 360 seconds
360 seconds = 6 minutes
8:00 a.m. + 6 minutes = 8:06 a.m.
Award 3 marks for correct answer with complete working.
Award 2 marks for correct LCM found but time conversion error.
Award 1 mark for correct prime factorisation of at least two intervals.

20. (a) 43,697 [2]

Number = 35 × 1,248 + 17
35 × 1,248 = 43,680
43,680 + 17 = 43,697

(b) Quotient = 1,747, Remainder = 22 [1]

43,697 ÷ 25 = 1,747 remainder 22
Check: 25 × 1,747 = 43,675; 43,697 − 43,675 = 22
Award 2 marks for part (a) with correct working.
Award 1 mark for part (b) with correct quotient and remainder.

Mark Summary

Section	Marks
A (Q1–5)	10
B (Q6–15)	20
C (Q16–20)	10
Total	40

This practice paper was generated as syllabus-aligned content. It is not derived from any specific past-year examination paper.