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Primary 6 PSLE Mathematics Weighted Assessment 2 (Term 3) Paper 5

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Questions

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TuitionGoWhere Exam Practice (AI) - Mathematics Primary 6 PSLE

School: TuitionGoWhere Secondary School (AI)
Subject: Mathematics
Level: Primary 6
Paper: WA2 (Weighted Assessment 2) - Version 5
Duration: 1 hour 30 minutes
Total Marks: 60
Name: __________________________
Class: __________________________
Date: __________________________

Instructions to Candidates:

  1. This paper consists of three sections: A, B, and C.
  2. Answer all questions.
  3. Write your answers in the spaces provided.
  4. For questions in Section B and C, you must show your working clearly. Marks may be awarded for method even if the final answer is incorrect.
  5. Unless otherwise stated, give your answers in the simplest form.
  6. Use π=227\pi = \frac{22}{7} or 3.143.14 where appropriate.

Section A: Multiple Choice Questions (10 marks)

For each question, four options are given. Choose the correct answer and write its number (1, 2, 3, or 4) in the brackets provided. Each question carries 1 mark.

1. What is the value of the digit 7 in the number 4,702,150? (1) 700 (2) 7,000 (3) 70,000 (4) 700,000 [ ]

2. Which of the following numbers is divisible by both 4 and 9? (1) 1,236 (2) 2,304 (3) 3,412 (4) 4,518 [ ]

3. Round off 58,492 to the nearest thousand. (1) 58,000 (2) 58,400 (3) 58,500 (4) 59,000 [ ]

4. What is the smallest number that can be added to 1,234 to make it divisible by 5? (1) 1 (2) 2 (3) 3 (4) 4 [ ]

5. Which of the following is a prime number? (1) 51 (2) 57 (3) 61 (4) 63 [ ]

6. Find the Highest Common Factor (HCF) of 18 and 24. (1) 3 (2) 6 (3) 12 (4) 72 [ ]

7. Find the Lowest Common Multiple (LCM) of 6 and 8. (1) 12 (2) 24 (3) 48 (4) 96 [ ]

8. 45,000−12,345=45,000 - 12,345 = _______ (1) 32,655 (2) 32,755 (3) 33,655 (4) 33,755 [ ]

9. What is the remainder when 1,000 is divided by 7? (1) 2 (2) 4 (3) 5 (4) 6 [ ]

10. Which expression represents "5 more than the product of 3 and nn"? (1) 3(n+5)3(n + 5) (2) 3n+53n + 5 (3) 5n+35n + 3 (4) n+3×5n + 3 \times 5 [ ]

Section B: Short Answer Questions (20 marks)

Write your answers in the spaces provided. Show your working where necessary. Each question carries 2 marks.

11. Write the following number in words: 2,040,005.

12. Express 360 as a product of its prime factors. Leave your answer in index notation.

13. Find the value of 12+8×5−10÷212 + 8 \times 5 - 10 \div 2.

14. The sum of two numbers is 450. One number is twice the other. Find the smaller number.

15. A number is divisible by 3 and 5. It is between 40 and 60. What is the number?

16. Evaluate 23+32−412^3 + 3^2 - 4^1.

17. Mr. Tan has 120 apples. He packs them into boxes of 8. How many boxes does he need?

18. Find the value of nn if 3n+7=223n + 7 = 22.

19. What is the difference between the largest 5-digit odd number and the smallest 5-digit even number?

20. List all the factors of 24.

Section C: Long Answer Questions (30 marks)

Show your working clearly. Marks are awarded for method and accuracy. Each question carries 5 marks unless otherwise stated.

21. Mrs. Lim bought some beads. She used 13\frac{1}{3} of them to make a necklace and 14\frac{1}{4} of the remainder to make a bracelet. She had 120 beads left. (a) What fraction of the original beads was left? (b) How many beads did she have at first?

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22. The table below shows the number of visitors to a museum over 5 days.

DayMonTueWedThuFri
Visitors1,2001,5001,1001,8001,400

(a) Find the average number of visitors per day. (b) On Saturday, the number of visitors was 20% more than on Friday. How many visitors were there on Saturday?

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23. Box A and Box B contain some marbles. If 10 marbles are moved from Box A to Box B, both boxes will have the same number of marbles. If 20 marbles are moved from Box B to Box A, Box A will have 3 times as many marbles as Box B. (a) How many more marbles were in Box A than Box B at first? (b) How many marbles were in Box A at first?

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24. A factory produces toys. Every day, it produces 150 more toys than the previous day. On Monday, it produced 500 toys. (a) How many toys were produced on Thursday? (b) What was the total number of toys produced from Monday to Friday?

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25. Mr. Koh wants to tile a rectangular floor measuring 12 m by 8 m with square tiles. He wants to use the largest possible square tiles such that no tiles need to be cut. (a) What is the length of the side of each square tile in metres? (b) How many such tiles are needed to cover the floor?

<br> <br> <br> <br> <br>

26. There are some chickens and rabbits in a farm. There are 30 heads and 84 legs altogether. (a) How many rabbits are there? (b) How many chickens are there?

<br> <br> <br> <br> <br>

Answers

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Answer Key and Marking Scheme - Mathematics Primary 6 PSLE (WA2 Version 5)

Section A: Multiple Choice Questions (10 marks)

1. (4)

  • Reasoning: The digit 7 is in the hundred-thousands place. Value = 7×100,000=700,0007 \times 100,000 = 700,000.
  • Common Mistake: Confusing place value positions (e.g., choosing 70,000).

2. (2)

  • Reasoning:
    • Divisible by 4: Last two digits must be divisible by 4.
      • 1,236 (36 ÷\div 4 = 9) - Yes
      • 2,304 (04 ÷\div 4 = 1) - Yes
      • 3,412 (12 ÷\div 4 = 3) - Yes
      • 4,518 (18 ÷\div 4 = 4.5) - No
    • Divisible by 9: Sum of digits must be divisible by 9.
      • 1,236: 1+2+3+6=121+2+3+6=12 (No)
      • 2,304: 2+3+0+4=92+3+0+4=9 (Yes)
      • 3,412: 3+4+1+2=103+4+1+2=10 (No)
    • Only 2,304 is divisible by both.

3. (1)

  • Reasoning: Look at the hundreds digit (4). Since 4<54 < 5, round down. 58,492 becomes 58,000.

4. (1)

  • Reasoning: Numbers divisible by 5 end in 0 or 5. The next number ending in 0 or 5 after 1,234 is 1,235.
    • 1,235−1,234=11,235 - 1,234 = 1.

5. (3)

  • Reasoning:
    • 51 = 3×173 \times 17 (Not prime)
    • 57 = 3×193 \times 19 (Not prime)
    • 61 has only factors 1 and 61 (Prime)
    • 63 = 9×79 \times 7 (Not prime)

6. (2)

  • Reasoning:
    • Factors of 18: 1, 2, 3, 6, 9, 18
    • Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24
    • Common factors: 1, 2, 3, 6. Highest is 6.

7. (2)

  • Reasoning:
    • Multiples of 6: 6, 12, 18, 24, 30...
    • Multiples of 8: 8, 16, 24, 32...
    • Lowest Common Multiple is 24.

8. (1)

  • Reasoning: 45,000−12,34532,655\begin{array}{r} 45,000 \\ - 12,345 \\ \hline 32,655 \end{array}

9. (4)

  • Reasoning: 1,000÷7=1421,000 \div 7 = 142 remainder 66.
    • Check: 142×7=994142 \times 7 = 994. 1,000−994=61,000 - 994 = 6.

10. (2)

  • Reasoning: "Product of 3 and nn" is 3n3n. "5 more than" means add 5. Result: 3n+53n + 5.

Section B: Short Answer Questions (20 marks)

11. Two million, forty thousand and five.

  • Marking: 1 mark for "Two million", 1 mark for "forty thousand and five". Spelling must be correct.

12. 23×32×52^3 \times 3^2 \times 5

  • Working:
    • 360÷2=180360 \div 2 = 180
    • 180÷2=90180 \div 2 = 90
    • 90÷2=4590 \div 2 = 45
    • 45÷3=1545 \div 3 = 15
    • 15÷3=515 \div 3 = 5
    • 5÷5=15 \div 5 = 1
    • Prime factors: 2,2,2,3,3,52, 2, 2, 3, 3, 5.
    • Index notation: 23×32×52^3 \times 3^2 \times 5.

13. 47

  • Working: Follow BODMAS/PEMDAS.
    • Multiplication/Division first: 8×5=408 \times 5 = 40 and 10÷2=510 \div 2 = 5.
    • Expression becomes: 12+40−512 + 40 - 5.
    • Addition/Subtraction: 52−5=4752 - 5 = 47.

14. 150

  • Working:
    • Let smaller number be uu. Larger number is 2u2u.
    • u+2u=450u + 2u = 450
    • 3u=4503u = 450
    • u=150u = 150.

15. 45

  • Working:
    • Divisible by 3 and 5 means divisible by 15.
    • Multiples of 15: 15, 30, 45, 60...
    • Between 40 and 60: Only 45 fits.

16. 13

  • Working:
    • 23=82^3 = 8
    • 32=93^2 = 9
    • 41=44^1 = 4
    • 8+9−4=17−4=138 + 9 - 4 = 17 - 4 = 13.

17. 15 boxes

  • Working:
    • 120÷8=15120 \div 8 = 15.
    • No remainder, so exactly 15 boxes.

18. 5

  • Working:
    • 3n+7=223n + 7 = 22
    • 3n=22−73n = 22 - 7
    • 3n=153n = 15
    • n=15÷3=5n = 15 \div 3 = 5.

19. 89,999

  • Working:
    • Largest 5-digit odd number: 99,999.
    • Smallest 5-digit even number: 10,000.
    • Difference: 99,999−10,000=89,99999,999 - 10,000 = 89,999.

20. 1, 2, 3, 4, 6, 8, 12, 24

  • Marking: All 8 factors must be listed correctly. Missing one or including a non-factor results in 0 marks.

Section C: Long Answer Questions (30 marks)

21. (a) 12\frac{1}{2} (b) 240 beads

  • Concept: Fraction of Remainder.
  • Working:
    • (a)
      • Used for necklace: 13\frac{1}{3}. Remainder: 1−13=231 - \frac{1}{3} = \frac{2}{3}.
      • Used for bracelet: 14\frac{1}{4} of remainder = 14×23=212=16\frac{1}{4} \times \frac{2}{3} = \frac{2}{12} = \frac{1}{6}.
      • Total used: 13+16=26+16=36=12\frac{1}{3} + \frac{1}{6} = \frac{2}{6} + \frac{1}{6} = \frac{3}{6} = \frac{1}{2}.
      • Fraction left: 1−12=121 - \frac{1}{2} = \frac{1}{2}.
    • (b)
      • 12\frac{1}{2} of total = 120 beads.
      • Total = 120×2=240120 \times 2 = 240 beads.
  • Marking: 2 marks for correct fraction in (a), 3 marks for correct calculation and answer in (b).

22. (a) 1,400 (b) 1,680

  • Concept: Average and Percentage Increase.
  • Working:
    • (a)
      • Sum = 1,200+1,500+1,100+1,800+1,400=7,0001,200 + 1,500 + 1,100 + 1,800 + 1,400 = 7,000.
      • Average = 7,000÷5=1,4007,000 \div 5 = 1,400.
    • (b)
      • Friday visitors = 1,400.
      • Increase = 20%20\% of 1,400=0.2×1,400=2801,400 = 0.2 \times 1,400 = 280.
      • Saturday visitors = 1,400+280=1,6801,400 + 280 = 1,680.
  • Marking: 2 marks for (a), 3 marks for (b).

23. (a) 20 (b) 50

  • Concept: Constant Difference / Algebra / Model Method.
  • Working:
    • (a)
      • If 10 moved from A to B makes them equal, A must have had 20 more than B initially.
      • Let AA be initial A, BB be initial B.
      • A−10=B+10⇒A−B=20A - 10 = B + 10 \Rightarrow A - B = 20.
      • Difference is 20.
    • (b)
      • If 20 moved from B to A:
      • New A = A+20A + 20. New B = B−20B - 20.
      • New A = 3×3 \times New B.
      • Substitute A=B+20A = B + 20:
      • (B+20)+20=3(B−20)(B + 20) + 20 = 3(B - 20)
      • B+40=3B−60B + 40 = 3B - 60
      • 100=2B100 = 2B
      • B=50B = 50.
      • A=50+20=70A = 50 + 20 = 70.
      • Correction Check: If A=70, B=50. Move 20 from B to A: A=90, B=30. 90=3×3090 = 3 \times 30. Correct.
      • Question asks for Box A at first: 70.
      • Wait, let me re-read carefully. "If 20 marbles are moved from Box B to Box A... Box A will have 3 times as many as Box B."
      • My calculation: B=50,A=70B=50, A=70.
      • Let's check the first condition: Move 10 from A to B. A=60, B=60. Equal. Correct.
      • Answer for (b) is 70.
  • Marking: 2 marks for (a), 3 marks for (b).

24. (a) 950 (b) 3,500

  • Concept: Arithmetic Progression.
  • Working:
    • Mon: 500
    • Tue: 500+150=650500 + 150 = 650
    • Wed: 650+150=800650 + 150 = 800
    • Thu: 800+150=950800 + 150 = 950
    • Fri: 950+150=1,100950 + 150 = 1,100
    • (a) Thursday production: 950.
    • (b) Total: 500+650+800+950+1,100500 + 650 + 800 + 950 + 1,100.
      • Sum = 3,500.
  • Marking: 2 marks for (a), 3 marks for (b).

25. (a) 4 m (b) 6 tiles

  • Concept: HCF for tiling without cutting.
  • Working:
    • (a) Find HCF of 12 and 8.
      • Factors of 12: 1, 2, 3, 4, 6, 12.
      • Factors of 8: 1, 2, 4, 8.
      • HCF = 4. Side length = 4 m.
    • (b)
      • Number of tiles along length: 12÷4=312 \div 4 = 3.
      • Number of tiles along width: 8÷4=28 \div 4 = 2.
      • Total tiles: 3×2=63 \times 2 = 6.
  • Marking: 2 marks for (a), 3 marks for (b).

26. (a) 12 rabbits (b) 18 chickens

  • Concept: Assumption Method or Algebra.
  • Working:
    • Let RR be rabbits, CC be chickens.
    • R+C=30R + C = 30 (Heads)
    • 4R+2C=844R + 2C = 84 (Legs)
    • From first eq: C=30−RC = 30 - R.
    • Substitute into second eq:
      • 4R+2(30−R)=844R + 2(30 - R) = 84
      • 4R+60−2R=844R + 60 - 2R = 84
      • 2R=242R = 24
      • R=12R = 12.
    • C=30−12=18C = 30 - 12 = 18.
    • Check: 12×4+18×2=48+36=8412 \times 4 + 18 \times 2 = 48 + 36 = 84. Correct.
  • Marking: 2.5 marks for (a), 2.5 marks for (b). Working must be shown.