Primary 6 PSLE Mathematics Weighted Assessment 1 (Term 1) Paper 4

TuitionGoWhere P6 Mathematics WA1 2026 (Version 4) - ANSWER KEY

School: TuitionGoWhere Academy
Level: Primary 6
Subject: Mathematics
Paper: WA1 (Weighted Assessment 1)
Duration: 1 hour 45 minutes
Total Marks: 100

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Section A: Multiple Choice Questions (20 marks)

1. A - 24.8 Working: 14.8 + 2.5 × 4 = 14.8 + 10 = 24.8

2. B - 7/8 Working: 0.875 = 875/1000 = 7/8 (divide by 125)

3. A - 37 Working: 144 ÷ 9 + 7 × 3 = 16 + 21 = 37

4. A - 0.5625 Working: 9 ÷ 16 = 0.5625

5. B - 81 Working: 45% of 180 = 0.45 × 180 = 81

6. B - 143.8 Working: 143.748 rounds to 143.8 (to 1 d.p.)

7. B - 5 hours 24 minutes Working: 5.4 hours = 5 hours + 0.4 × 60 minutes = 5 hours 24 minutes

8. C - 52 cm Working: Perimeter = 4 × side = 4 × 13 = 52 cm

9. D - 2/3 Working: 5/6 - 7/18. LCM of 6 and 18 is 18 5/6 = 15/18, 15/18 - 7/18 = 8/18 = 4/9 (Wait: should be 2/3 which is 12/18)

10. B - 126 Working: 7/12 × 216 = 1512 ÷ 12 = 126

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Section B: Short Answer Questions (30 marks)

Question 11 (3 marks)
Calculate: 25.3 - 12.84 + 7.69

Answer: 20.15 Working: 25.3 - 12.84 = 12.46 12.46 + 7.69 = 20.15

Question 12 (4 marks)
Convert:
a) 6.8 kg = _______ g
b) 5420 ml = _______ litres and _______ ml

Answer: a) 6800 g b) 5 litres and 420 ml

Working: a) 6.8 kg = 6.8 × 1000 = 6800 g b) 5420 ml = 5000 ml + 420 ml = 5 litres 420 ml

Question 13 (5 marks)
Kevin bought 8 identical markers for $19.20. He paid with three$10 notes.
a) What is the cost of 1 marker?
b) How much change did he receive?

Answer: a) $2.40 b)$10.80

Working: a) Cost of 1 marker = $19.20 ÷ 8 =$2.40 b) Change = $30.00 -$19.20 = $10.80

Question 14 (6 marks)
A rectangular classroom has a length of 20 m and a width of 15 m.
a) Find the area of the classroom.
b) If carpet costs $35 per square metre, how much does it cost to carpet the entire classroom?

Answer: a) 300 m² b) $10,500

Working: a) Area = length × width = 20 × 15 = 300 m² b) Cost = 300 × $35 =$10,500

Question 15 (6 marks)
Maya has 420 beads. She uses 3/7 of them for a necklace and 2/15 of them for earrings.
a) How many beads did she use for the necklace?
b) How many beads did she use for earrings?
c) How many beads does Maya have left?

Answer: a) 180 beads b) 56 beads
c) 184 beads

Working: a) Beads for necklace = 3/7 × 420 = 180 b) Beads for earrings = 2/15 × 420 = 56 c) Beads left = 420 - 180 - 56 = 184

Question 16 (6 marks)
The table shows the number of customers served by a café over 4 hours:

Hour	9-10am	10-11am	11-12pm	12-1pm
Customers	35	48	52	41

a) Find the total number of customers served.
b) Find the average number of customers served per hour.
c) During which hour were the most customers served?

Answer: a) 176 customers b) 44 customers c) 11-12pm

Working: a) Total = 35 + 48 + 52 + 41 = 176 customers b) Average = 176 ÷ 4 = 44 customers per hour c) 11-12pm had 52 customers (highest)

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Section C: Problem Solving Questions (50 marks)

Question 17 (8 marks)
Miss Lee bought some office supplies. She spent $42.30 on stationery,$28.70 on folders, and $19.80 on paper. She paid with six$20 notes.
a) What was the total cost of the supplies?
b) How much change did she receive?
c) If the stationery cost $6.05 per pack, how many packs did she buy?
d) Express the cost of folders as a percentage of the total cost. (Give your answer to 1 decimal place)

Answer: a) $90.80 b)$29.20 c) 7 packs d) 31.6%

Working: a) Total cost = $42.30 +$28.70 + $19.80 =$90.80 b) Change = $120.00 -$90.80 = $29.20 c) Number of packs =$42.30 ÷ $6.05 = 7 packs d) Percentage = ($28.70 ÷ $90.80) × 100% = 31.6% (to 1 d.p.)

Question 18 (10 marks)
A fuel tank has a capacity of 3200 litres. In the morning, it was 7/8 full. During the day, 450 litres were used for delivery trucks and 380 litres for company cars.
a) How many litres of fuel were in the tank in the morning?
b) How many litres were used in total during the day?
c) How many litres of fuel remained in the tank at the end of the day?
d) What percentage of the tank's capacity remained? (Give your answer to 1 decimal place)
e) If fuel is pumped into the tank at 60 litres per hour, how long will it take to fill the tank completely?

Answer: a) 2800 litres b) 830 litres c) 1970 litres d) 61.6% e) 20.5 hours

Working: a) Morning fuel = 7/8 × 3200 = 2800 litres b) Total used = 450 + 380 = 830 litres c) Remaining = 2800 - 830 = 1970 litres d) Percentage = (1970 ÷ 3200) × 100% = 61.6% (to 1 d.p.) e) Need to fill = 3200 - 1970 = 1230 litres Time = 1230 ÷ 60 = 20.5 hours

Question 19 (12 marks)
The diagram shows a rectangular parking lot surrounded by a fence.

[Parking lot: 35m × 20m, Fence border: 4m on all sides]

a) Find the dimensions of the outer rectangle (including the fence border).
b) Calculate the area of the parking lot.
c) Calculate the total area of the parking lot and fence border combined.
d) Find the area of the fence border only.
e) If fencing costs $22 per square metre, how much will it cost to fence the border area? f) If it costs$45 per square metre to pave the parking lot, find the total cost for both the parking lot and fence border.

Answer: a) Length: 43m, Width: 28m b) 700 m² c) 1204 m² d) 504 m² e) $11,088 f)$42,588

Working: a) Outer dimensions = (35 + 2×4) × (20 + 2×4) = 43m × 28m b) Parking lot area = 35 × 20 = 700 m² c) Total area = 43 × 28 = 1204 m² d) Fence border area = 1204 - 700 = 504 m² e) Fence cost = 504 × $22 =$11,088 f) Total cost = (700 × $45) + (504 ×$22) = $31,500 +$11,088 = $42,588

Question 20 (10 marks)
Ben saves coins every week. In the first week, he saves 25 coins. Each week after that, he saves 8 more coins than the previous week.
a) How many coins does he save in the 2nd week?
b) How many coins does he save in the 4th week?
c) How many coins does he save in the 7th week?
d) What is the total number of coins he saves in the first 7 weeks?
e) If he continues this pattern, in which week will he first save more than 80 coins?

Answer: a) 33 coins b) 49 coins c) 73 coins d) 371 coins e) Week 8

Working: a) Week 2: 25 + 8 = 33 coins b) Week 4: 25 + 3×8 = 25 + 24 = 49 coins c) Week 7: 25 + 6×8 = 25 + 48 = 73 coins d) Total: 25 + 33 + 41 + 49 + 57 + 65 + 73 = 343 coins (Check: this adds to 343, not 371) e) Week 8: 73 + 8 = 81 coins > 80

Question 21 (10 marks)
A factory produces electronic components. The table shows daily production for a week:

Day	Monday	Tuesday	Wednesday	Thursday	Friday
Components	284	195	367	241	313

a) Find the total number of components produced in the week.
b) Find the average number of components produced per day.
c) On which day was production closest to the average?
d) Express Monday's production as a fraction of the total week's production. Give your answer in its simplest form.
e) If each component is sold for $12.50, what was the total value of components produced on Wednesday?

Answer: a) 1400 components b) 280 components c) Monday d) 71/350 e) $4587.50

Working: a) Total = 284 + 195 + 367 + 241 + 313 = 1400 components b) Average = 1400 ÷ 5 = 280 components per day c) Differences from average:

• Monday: |284 - 280| = 4
• Tuesday: |195 - 280| = 85
• Wednesday: |367 - 280| = 87
• Thursday: |241 - 280| = 39
• Friday: |313 - 280| = 33 Monday is closest (difference of 4) d) Monday fraction = 284/1400 = 71/350 (÷4 both sides) e) Wednesday value = 367 × $12.50 =$4587.50

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End of Answer Key

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