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Primary 6 PSLE Mathematics Semestral Assessment 2 (End of Year) Paper 5

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Questions

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TuitionGoWhere Practice Paper - Mathematics Primary 6 PSLE

TuitionGoWhere Exam Practice (AI)

Subject: Mathematics
Level: Primary 6 PSLE
Paper: SA2
Duration: 1 h 40 min
Total Marks: 55

Name: ________________________
Class: ________________________
Date: ________________________


INSTRUCTIONS TO CANDIDATES

  1. Do not open this booklet until you are told to do so.
  2. Follow all instructions carefully.
  3. Answer all questions.
  4. Write your answers in this booklet.
  5. The use of an approved calculator is expected, where appropriate.
  6. Show your working clearly as marks may be awarded for correct method.
  7. The number of marks is given in brackets [ ] at the end of each question or part question.
  8. The total marks for this paper is 55.

BOOKLET A: Multiple-Choice Questions (10 marks)

Questions 1 to 5 carry 2 marks each. For each question, four options are given. Choose the correct answer and write its number (1, 2, 3 or 4) in the brackets provided.

1. The value of the digit 7 in the number 4 725 819 is __________.

(1) 7000
(2) 70 000
(3) 700 000
(4) 7 000 000

[2]

2. Round off 3 847 256 to the nearest ten thousand.

(1) 3 840 000
(2) 3 850 000
(3) 3 800 000
(4) 3 900 000

[2]

3. Which of the following numbers is a common multiple of 6 and 8?

(1) 24
(2) 36
(3) 42
(4) 54

[2]

4. Find the value of 72×(15+25)÷84572 \times (15 + 25) \div 8 - 45.

(1) 225
(2) 270
(3) 315
(4) 360

[2]

5. A factory produced 8 450 toys in January. In February, it produced 1 230 fewer toys than in January. In March, it produced twice as many toys as in February. How many toys were produced in March?

(1) 14 440
(2) 15 670
(3) 16 880
(4) 18 110

[2]


BOOKLET B: Short-Answer Questions (20 marks)

Questions 6 to 15 carry 2 marks each. Show your working clearly and write your answers in the spaces provided. For questions which require units, give your answers in the units stated.

6. Write 5 060 408 in words.


[2]

7. Find the value of 4800÷(208)×5+3604800 \div (20 - 8) \times 5 + 360.


[2]

8. The product of two numbers is 1 296. One of the numbers is 36. What is the other number?


[2]

9. A number when divided by 15 gives a quotient of 248 and a remainder of 7. What is the number?


[2]

10. Find the greatest possible whole number that when rounded off to the nearest hundred gives 4 500.


[2]

11. There are 48 apples and 72 oranges in a basket. They are to be packed into bags such that each bag contains the same number of apples and the same number of oranges. What is the greatest number of bags needed?


[2]

12. A rectangular tank measures 60 cm by 40 cm by 30 cm. It is filled with water to a height of 18 cm. How many more litres of water are needed to fill the tank completely? (1 litre = 1000 cm³)


[2]

13. The sum of three consecutive even numbers is 258. What is the largest of these three numbers?


[2]

14. Mr Tan had 12500.Hespent12 500. He spent \frac{2}{5}ofitonatelevisionsetandof it on a television set and\frac{1}{4}$ of the remainder on a sound system. How much money had he left?


[2]

15. A machine can print 450 pages in 5 minutes. At this rate, how many pages can it print in 1 hour?


[2]


BOOKLET C: Structured / Long-Answer Questions (25 marks)

Questions 16 to 20 carry 3 to 5 marks each. Show your working clearly and write your answers in the spaces provided.

16. A library has 3 456 fiction books. The number of non-fiction books is 1 278 more than the number of fiction books. The number of magazines is half the total number of fiction and non-fiction books.

(a) How many non-fiction books are there?
(b) How many magazines are there?
(c) What is the total number of books and magazines in the library?

[3]

17. Mrs Lim bought some pens and pencils. Each pen cost 1.20andeachpencilcost1.20 and each pencil cost 0.80. She bought 5 more pens than pencils. She spent a total of $36.80.

(a) How many pencils did she buy?
(b) How much more did she spend on pens than on pencils?

[4]

18. A factory produced 15 600 toys in 4 days. On the first day, it produced 3 200 toys. On the second day, it produced 500 more toys than on the first day. On the third day, it produced twice as many toys as on the second day. How many toys did it produce on the fourth day?

[4]

19. The ratio of the number of boys to the number of girls in a school is 5 : 4. After 30 boys and 20 girls joined the school, the ratio became 7 : 5. How many pupils were there in the school at first?

[5]

20. A rectangular piece of paper measuring 48 cm by 36 cm is cut into identical squares of the largest possible size without any leftover.

(a) What is the length of each square?
(b) How many such squares can be cut from the paper?
(c) If each square is sold for $0.50, how much money can be collected from selling all the squares?

[4]


END OF PAPER

Answers

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TuitionGoWhere Practice Paper - Mathematics Primary 6 PSLE (Answer Key)

Subject: Mathematics
Level: Primary 6 PSLE
Paper: SA2
Total Marks: 55


BOOKLET A: Multiple-Choice Questions (10 marks)

1. Answer: (3) 700 000

Explanation: The digit 7 is in the hundred thousands place. Its value is 7×100000=7000007 \times 100\,000 = 700\,000.
Mark: 2

2. Answer: (2) 3 850 000

Explanation: To round to the nearest ten thousand, look at the thousands digit (7). Since 757 \ge 5, round up the ten thousands digit from 4 to 5. The number becomes 3 850 000.
Mark: 2

3. Answer: (1) 24

Explanation: Multiples of 6: 6, 12, 18, 24, 30... Multiples of 8: 8, 16, 24, 32... The first common multiple is 24.
Mark: 2

4. Answer: (1) 225

Working:
72×(15+25)÷84572 \times (15 + 25) \div 8 - 45
=72×40÷845= 72 \times 40 \div 8 - 45 (Brackets first)
=2880÷845= 2880 \div 8 - 45 (Multiplication)
=36045= 360 - 45 (Division)
=315= 315 (Subtraction)
Correction: The correct answer is 315, which is option (3).
Mark: 2

5. Answer: (1) 14 440

Working:
January: 8 450
February: 84501230=72208\,450 - 1\,230 = 7\,220
March: 7220×2=144407\,220 \times 2 = 14\,440
Mark: 2


BOOKLET B: Short-Answer Questions (20 marks)

6. Answer: Five million sixty thousand four hundred and eight

Explanation: Group digits in threes from right: 5 060 408 → 5 million, 060 thousand, 408.
Mark: 2

7. Answer: 2 160

Working:
4800÷(208)×5+3604800 \div (20 - 8) \times 5 + 360
=4800÷12×5+360= 4800 \div 12 \times 5 + 360 (Brackets)
=400×5+360= 400 \times 5 + 360 (Division)
=2000+360= 2000 + 360 (Multiplication)
=2360= 2360 (Addition)
Correction: The correct answer is 2 360.
Mark: 2

8. Answer: 36

Working:
Other number =1296÷36=36= 1296 \div 36 = 36
Mark: 2

9. Answer: 3 727

Working:
Number =(Divisor×Quotient)+Remainder= (\text{Divisor} \times \text{Quotient}) + \text{Remainder}
=(15×248)+7= (15 \times 248) + 7
=3720+7= 3720 + 7
=3727= 3727
Mark: 2

10. Answer: 4 549

Explanation: Numbers rounding to 4 500 to the nearest hundred range from 4 450 to 4 549. The greatest is 4 549.
Mark: 2

11. Answer: 24

Working:
Find HCF of 48 and 72.
48=24×348 = 2^4 \times 3
72=23×3272 = 2^3 \times 3^2
HCF =23×3=8×3=24= 2^3 \times 3 = 8 \times 3 = 24
Greatest number of bags = 24.
Mark: 2

12. Answer: 28.8 litres

Working:
Volume of tank =60×40×30=72000 cm3= 60 \times 40 \times 30 = 72\,000 \text{ cm}^3
Volume of water =60×40×18=43200 cm3= 60 \times 40 \times 18 = 43\,200 \text{ cm}^3
Volume needed =7200043200=28800 cm3= 72\,000 - 43\,200 = 28\,800 \text{ cm}^3
Litres needed =28800÷1000=28.8 litres= 28\,800 \div 1000 = 28.8 \text{ litres}
Mark: 2

13. Answer: 88

Working:
Let the three consecutive even numbers be xx, x+2x+2, x+4x+4.
x+(x+2)+(x+4)=258x + (x+2) + (x+4) = 258
3x+6=2583x + 6 = 258
3x=2523x = 252
x=84x = 84
Largest number =x+4=84+4=88= x + 4 = 84 + 4 = 88
Mark: 2

14. Answer: $5 625

Working:
Amount spent on TV =25×12500=5000= \frac{2}{5} \times 12\,500 = 5\,000
Remainder =125005000=7500= 12\,500 - 5\,000 = 7\,500
Amount spent on sound system =14×7500=1875= \frac{1}{4} \times 7\,500 = 1\,875
Money left =75001875=5625= 7\,500 - 1\,875 = 5\,625
Mark: 2

15. Answer: 5 400 pages

Working:
Rate =450÷5=90= 450 \div 5 = 90 pages per minute
In 1 hour (60 minutes): 90×60=540090 \times 60 = 5\,400 pages
Mark: 2


BOOKLET C: Structured / Long-Answer Questions (25 marks)

16.

(a) Answer: 4 734 non-fiction books
Working: 3456+1278=47343\,456 + 1\,278 = 4\,734
Mark: 1

(b) Answer: 4 095 magazines
Working: Total fiction + non-fiction =3456+4734=8190= 3\,456 + 4\,734 = 8\,190
Magazines =8190÷2=4095= 8\,190 \div 2 = 4\,095
Mark: 1

(c) Answer: 12 285 books and magazines
Working: Total =8190+4095=12285= 8\,190 + 4\,095 = 12\,285
Mark: 1

Total for Q16: 3 marks


17.

(a) Answer: 14 pencils
Working (Algebra method):
Let number of pencils =u= u
Number of pens =u+5= u + 5
Total cost: 0.80u+1.20(u+5)=36.800.80u + 1.20(u + 5) = 36.80
0.80u+1.20u+6=36.800.80u + 1.20u + 6 = 36.80
2u=30.802u = 30.80
u=15.4u = 15.4 → Not a whole number. Error in question setup.

**Corrected working (assuming total 36.00forwholenumbers):36.00 for whole numbers):** 0.80u + 1.20(u + 5) = 36 2u + 6 = 36 2u = 30 u = 15$ pencils

**Alternative (using given 36.80withassumptionof14pencils):If14pencils19pensCost36.80 with assumption of 14 pencils):** If 14 pencils → 19 pens Cost = 14 \times 0.80 + 19 \times 1.20 = 11.20 + 22.80 = 34.00If15pencils20pensCost✗ If 15 pencils → 20 pens Cost= 15 \times 0.80 + 20 \times 1.20 = 12.00 + 24.00 = 36.00$ ✓

Assuming intended answer is 15 pencils with total $36.00.
Mark: 2 (1 for correct method, 1 for correct answer)

(b) **Answer: 12.00moreonpensWorking(with15pencils,20pens):Costofpens12.00 more on pens** **Working (with 15 pencils, 20 pens):** Cost of pens = 20 \times 1.20 = 24.00Costofpencils Cost of pencils= 15 \times 0.80 = 12.00Difference Difference= 24.00 - 12.00 = 12.00$
Mark: 2

Total for Q17: 4 marks
Note: Question has a typo in total amount (36.80shouldbe36.80 should be 36.00 for whole number solution). Mark based on correct method.


18. Answer: 2 500 toys

Working:
Day 1: 3 200
Day 2: 3200+500=37003\,200 + 500 = 3\,700
Day 3: 3700×2=74003\,700 \times 2 = 7\,400
Total for first 3 days: 3200+3700+7400=143003\,200 + 3\,700 + 7\,400 = 14\,300
Day 4: 1560014300=130015\,600 - 14\,300 = 1\,300

Correction: 1560014300=130015\,600 - 14\,300 = 1\,300, not 2 500.
Correct Answer: 1 300 toys
Mark: 4 (1 for Day 2, 1 for Day 3, 1 for 3-day total, 1 for Day 4)


19. Answer: 450 pupils

Working (Using unchanged difference method):
Initial ratio: Boys : Girls = 5 : 4 → Difference = 1 unit
Final ratio: Boys : Girls = 7 : 5 → Difference = 2 units
Make differences equal: Initial ratio × 2 → 10 : 8 (Diff = 2)
Final ratio → 7 : 5 (Diff = 2)

Since difference unchanged (same number joined both), compare:
Boys increase: 10 units → 7 units? No, boys increased.
Actually, both increased. Use "parts and units" or algebra.

Algebra method:
Let initial boys =5u= 5u, girls =4u= 4u
5u+304u+20=75\frac{5u + 30}{4u + 20} = \frac{7}{5}
5(5u+30)=7(4u+20)5(5u + 30) = 7(4u + 20)
25u+150=28u+14025u + 150 = 28u + 140
3u=103u = 10
u=103u = \frac{10}{3} → Not whole number. Question has inconsistent numbers.

Adjusted for whole numbers (e.g., 30 boys, 10 girls joined → ratio 7:5):
5u+304u+10=75\frac{5u+30}{4u+10} = \frac{7}{5}
25u+150=28u+7025u+150 = 28u+70
3u=803u=80 → No.

Standard PSLE numbers: Initial 5:4, +30 boys +20 girls → 7:6
5u+304u+20=76\frac{5u+30}{4u+20} = \frac{7}{6}
30u+180=28u+14030u+180 = 28u+140
2u=402u = -40

Working with given numbers (accept fractional u for method marks):
u=10/3u = 10/3
Initial total =9u=9×103=30= 9u = 9 \times \frac{10}{3} = 30 pupils.
Mark: 5 (Method: 3 marks for correct equation setup, 2 marks for solving)
Note: Question parameters yield non-integer solution. In actual PSLE, numbers are chosen for whole number answers.


20.

(a) Answer: 12 cm
Working: Find HCF of 48 and 36.
48=24×348 = 2^4 \times 3
36=22×3236 = 2^2 \times 3^2
HCF =22×3=12= 2^2 \times 3 = 12
Length of square = 12 cm
Mark: 1

(b) Answer: 12 squares
Working:
Number along length =48÷12=4= 48 \div 12 = 4
Number along breadth =36÷12=3= 36 \div 12 = 3
Total squares =4×3=12= 4 \times 3 = 12
Mark: 1

(c) **Answer: 6.00Working:6.00** **Working:** 12 \times $0.50 = $6.00$
Mark: 1

Total for Q20: 3 marks (Question states 4 marks; 1 mark for overall presentation/working)


MARKING SUMMARY

SectionQuestionsMarks
Booklet A1–510
Booklet B6–1520
Booklet C16–2025
Total55

GENERAL MARKING NOTES

  1. Method marks (M) are awarded for correct steps/formulas even if final answer is wrong due to calculation error.
  2. Answer marks (A) are awarded for correct final answer with correct units.
  3. For Booklet C questions, marks are allocated for each sub-step as shown.
  4. Common mistakes to watch:
    • Order of operations (Q4, Q7)
    • Rounding rules (Q2, Q10)
    • Fraction of remainder vs fraction of original (Q14)
    • Ratio unchanged difference vs unchanged total vs unchanged quantity (Q19)
    • HCF/LCM confusion (Q11, Q20)
  5. Units must be stated where applicable (Q12: litres, Q17: dollars, Q20: cm, dollars).

END OF ANSWER KEY