Primary 6 PSLE Mathematics Semestral Assessment 2 (End of Year) Paper 4

<!-- TuitionGoWhere generation metadata: stage=3-1; model=qwen/qwen3.7-plus; model_label=Qwen3.7 Plus; generated=2026-06-04; Sources: Stage 2-1 real exam-derived templates and Stage 2-2 exam-enriched syllabus. -->

TuitionGoWhere Practice Paper - Mathematics Primary 6 PSLE

TuitionGoWhere Exam Practice (AI)

Subject: Mathematics
Level: Primary 6
Paper: SA2 Practice Paper (Version 4 of 5)
Topic Focus: Whole Numbers
Duration: 1 hour 15 minutes
Total Marks: 40

Name: __________________________
Class: __________________________
Date: __________________________
Score: ________ / 40

---

Instructions to Candidates

1. This paper consists of 20 questions.
2. Answer all questions.
3. Write your answers in the spaces provided.
4. For questions requiring working, show your working clearly. Marks may be awarded for method marks even if the final answer is incorrect.
5. Unless otherwise specified, give your answers in the simplest form.
6. The use of calculators is not allowed for this practice set to strengthen mental arithmetic and heuristic skills, consistent with foundational Whole Number mastery.

---

Section A: Multiple Choice Questions (Questions 1 – 5)

Each question carries 1 mark. Choose the correct answer and write its number (1, 2, 3, or 4) in the brackets provided.

1. What is the value of the digit 7 in the number 4,702,195?
(1) 700
(2) 7,000
(3) 70,000
(4) 700,000
[ ______ ]

2. Which of the following numbers is divisible by both 4 and 9?
(1) 3,216
(2) 4,536
(3) 5,124
(4) 6,018
[ ______ ]

3. Round off 8,459,321 to the nearest ten thousand.
(1) 8,450,000
(2) 8,459,000
(3) 8,460,000
(4) 8,500,000
[ ______ ]

4. Find the product of 205 and 38.
(1) 7,780
(2) 7,790
(3) 7,800
(4) 7,890
[ ______ ]

5. Which of the following expressions has the largest value?
(1) $12 \times (8 + 4) \div 2$
(2) $12 \times 8 + 4 \div 2$
(3) $(12 \times 8 + 4) \div 2$
(4) $12 + 8 \times 4 \div 2$
[ ______ ]

---

Section B: Short Answer Questions (Questions 6 – 15)

Each question carries 2 marks. Write your answer in the space provided. Show your working where necessary.

6. Write "three million, forty-five thousand and six" in numerals.
Answer: __________________________

7. Find the sum of 45,678 and 12,905.
Answer: __________________________

8. What is the remainder when 5,432 is divided by 11?
Answer: __________________________

9. Express 72 as a product of its prime factors. Leave your answer in index notation.
Answer: __________________________

10. Find the Highest Common Factor (HCF) of 24 and 36.
Answer: __________________________

11. Find the Lowest Common Multiple (LCM) of 8 and 12.
Answer: __________________________

12. Calculate the value of $150 - 25 \times 4 + 10$.
Answer: __________________________

13. A factory produces 1,250 toys every day. How many toys does it produce in 28 days?
Answer: __________________________

14. Mr. Tan has $5,000. He buys 15 identical chairs for$120 each. How much money does he have left?
Answer: $__________________________

15. Fill in the missing number in the box.
$4,500 \div \boxed{\phantom{00}} = 90$
Answer: __________________________

---

Section C: Long Answer Questions (Questions 16 – 20)

Each question carries 4 marks. Show your working clearly. Full marks will not be awarded for answers without working.

16. There are 4,500 spectators at a stadium. $\frac{2}{5}$ of them are adults. Of the remaining spectators, $\frac{1}{3}$ are children and the rest are seniors.
(a) How many adults are there?
(b) How many seniors are there?

<br> <br> <br> <br> <br>

17. A box contains red, blue, and green marbles. The ratio of red marbles to blue marbles is 3 : 5. The ratio of blue marbles to green marbles is 10 : 7.
(a) Find the ratio of red marbles to blue marbles to green marbles.
(b) If there are 120 blue marbles, how many green marbles are there?

<br> <br> <br> <br> <br>

18. Study the number pattern below.
Pattern 1: $1 \times 2 + 1 = 3$
Pattern 2: $2 \times 3 + 2 = 8$
Pattern 3: $3 \times 4 + 3 = 15$
Pattern 4: $4 \times 5 + 4 = 24$

(a) Write down the expression for Pattern 10.
(b) Find the value of the 10th pattern.
(c) Which pattern has a value of 99?

<br> <br> <br> <br> <br>

19. Mrs. Lim bought some apples and oranges. She bought 3 times as many apples as oranges. Each apple cost $2 and each orange cost$3. She spent a total of $180.
(a) How many oranges did she buy?
(b) How many fruits did she buy altogether?

<br> <br> <br> <br> <br>

20. A warehouse stores boxes in stacks. Each stack has 12 boxes. The warehouse has 45 such stacks.
(a) How many boxes are there in total?
(b) If 150 boxes are removed and the remaining boxes are repacked into new stacks of 10 boxes each, how many new stacks are formed?
(c) If each new stack requires a label that costs $0.50, what is the total cost of the labels?

<br> <br> <br> <br> <br> <br> <br>

*** End of Paper ***

<!-- TuitionGoWhere generation metadata: stage=3-1; model=qwen/qwen3.7-plus; model_label=Qwen3.7 Plus; generated=2026-06-04; Sources: Stage 2-1 real exam-derived templates and Stage 2-2 exam-enriched syllabus. -->

Answer Key and Marking Scheme

Subject: Mathematics Primary 6
Topic: Whole Numbers
Paper: SA2 Practice Paper (Version 4)

---

Section A: Multiple Choice Questions (1 mark each)

1. (4)
Reasoning: The number is 4,702,195. The digit 7 is in the hundred thousands place. Value = $7 \times 100,000 = 700,000$.

2. (2)
Reasoning:

• Divisibility by 4: Last two digits must be divisible by 4.
  • 3,216 (16 is div by 4) - Yes
  • 4,536 (36 is div by 4) - Yes
  • 5,124 (24 is div by 4) - Yes
  • 6,018 (18 is not div by 4) - No
• Divisibility by 9: Sum of digits must be divisible by 9.
  • 3,216: $3+2+1+6=12$ (No)
  • 4,536: $4+5+3+6=18$ (Yes)
  • 5,124: $5+1+2+4=12$ (No)
    Only 4,536 is divisible by both.

3. (3)
Reasoning: To round 8,459,321 to the nearest ten thousand, look at the thousands digit (9). Since $9 \ge 5$, round up the ten thousands digit (5 becomes 6). Result: 8,460,000.

4. (2)
Reasoning: $205 \times 38$.
$205 \times 30 = 6,150$
$205 \times 8 = 1,640$
$6,150 + 1,640 = 7,790$.

5. (2)
Reasoning:
(1) $12 \times 12 \div 2 = 144 \div 2 = 72$
(2) $96 + 2 = 98$
(3) $(96 + 4) \div 2 = 100 \div 2 = 50$
(4) $12 + 32 \div 2 = 12 + 16 = 28$
Largest value is 98.

---

Section B: Short Answer Questions (2 marks each)

6. 3,045,006
Working:
Millions: 3
Hundred Thousands: 0
Ten Thousands: 4
Thousands: 5
Hundreds: 0
Tens: 0
Ones: 6
Note: Ensure zeros are placed correctly for empty positions.

7. 58,583
Working:
45,678

• 12,905

---

58,583

8. 1
Working:
$5,432 \div 11$
$54 \div 11 = 4$ rem 10
$103 \div 11 = 9$ rem 4
$42 \div 11 = 3$ rem 9? Wait.
Let's re-calculate:
$11 \times 493 = 5,423$.
$5,432 - 5,423 = 9$.
Correction in mental check:
$5432 / 11$:
$54/11 = 4$ (rem 10) -> 103
$103/11 = 9$ (rem 4) -> 42
$42/11 = 3$ (rem 9).
Answer is 9.
Self-Correction for Answer Key: The question asks for remainder.
$11 \times 493 = 5423$.
$5432 - 5423 = 9$.
Answer: 9

9. $2^3 \times 3^2$
Working:
$72 = 8 \times 9$
$8 = 2 \times 2 \times 2 = 2^3$
$9 = 3 \times 3 = 3^2$
So, $72 = 2^3 \times 3^2$.

10. 12
Working:
Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24
Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36
Common Factors: 1, 2, 3, 4, 6, 12
Highest Common Factor is 12.

11. 24
Working:
Multiples of 8: 8, 16, 24, 32...
Multiples of 12: 12, 24, 36...
Lowest Common Multiple is 24.

12. 60
Working:
Order of operations (BODMAS): Multiplication first.
$25 \times 4 = 100$
Expression becomes: $150 - 100 + 10$
Subtraction and Addition from left to right:
$150 - 100 = 50$
$50 + 10 = 60$

13. 35,000
Working:
$1,250 \times 28$
$1,250 \times 20 = 25,000$
$1,250 \times 8 = 10,000$
$25,000 + 10,000 = 35,000$

**14. $3,200** *Working:* Cost of chairs:$15 \times 120$$15 \times 12 = 180$, so$15 \times 120 = 1,800$. Money left:$5,000 - 1,800 = 3,200$.

15. 50
Working:
$4,500 \div \Box = 90$
$\Box = 4,500 \div 90$
$\Box = 450 \div 9$
$\Box = 50$

---

Section C: Long Answer Questions (4 marks each)

16.
(a) 1,800 adults
(b) 1,800 seniors

Working:
Total spectators = 4,500
(a) Adults = $\frac{2}{5}$ of 4,500
$4,500 \div 5 = 900$
$900 \times 2 = 1,800$ adults.

Remaining spectators = $4,500 - 1,800 = 2,700$.

(b) Children = $\frac{1}{3}$ of remainder
$\frac{1}{3}$ of 2,700 = $2,700 \div 3 = 900$ children.

Seniors = Remainder - Children
Seniors = $2,700 - 900 = 1,800$.
Alternatively: Seniors are $\frac{2}{3}$ of remainder. $\frac{2}{3} \times 2,700 = 1,800$.

Marking:
1 mark for correct number of adults.
1 mark for correct remainder.
1 mark for correct number of children or logic for seniors.
1 mark for final answer for seniors.

17.
(a) 6 : 10 : 7
(b) 84 green marbles

Working:
(a) Red : Blue = 3 : 5
Blue : Green = 10 : 7
To combine, make the 'Blue' part equal. LCM of 5 and 10 is 10.
Multiply first ratio by 2:
Red : Blue = $6 : 10$
Blue : Green = $10 : 7$
Combined Ratio Red : Blue : Green = $6 : 10 : 7$.

(b) Blue units = 10 units.
Given 120 blue marbles.
10 units = 120
1 unit = $120 \div 10 = 12$.
Green marbles = 7 units.
$7 \times 12 = 84$.

Marking:
1 mark for correct combined ratio.
1 mark for value of 1 unit.
1 mark for substitution.
1 mark for final answer.

18.
(a) $10 \times 11 + 10$
(b) 120
(c) Pattern 9

Working:
Pattern $n$: $n \times (n+1) + n$
Simplify: $n^2 + n + n = n^2 + 2n$? No, let's stick to the visual pattern.
Pattern 1: $1(2)+1 = 3$
Pattern 2: $2(3)+2 = 8$
Pattern 3: $3(4)+3 = 15$

(a) For Pattern 10 ($n=10$):
Expression: $10 \times 11 + 10$.

(b) Value:
$10 \times 11 = 110$
$110 + 10 = 120$.

(c) Value = 99.
$n \times (n+1) + n = 99$
$n^2 + n + n = 99$
$n^2 + 2n = 99$
$n(n+2) = 99$
We look for two numbers differing by 2 that multiply to 99.
$9 \times 11 = 99$.
So $n = 9$.
Check Pattern 9: $9 \times 10 + 9 = 90 + 9 = 99$.
Answer is Pattern 9.

Marking:
1 mark for correct expression in (a).
1 mark for correct value in (b).
1 mark for setting up equation or trial in (c).
1 mark for correct pattern number.

19.
(a) 20 oranges
(b) 80 fruits

Working:
Let number of oranges = $1u$.
Number of apples = $3u$ (3 times as many).
Cost of oranges = 1u \times \3 = $3u$. Cost of apples =$3u \times $2 = $6u$. Total cost =$$3u + $6u = $9u$.

Given Total cost = $180.$9u = 180$$1u = 180 \div 9 = 20$.

(a) Oranges = $1u = 20$.

(b) Total fruits = Apples + Oranges = $3u + 1u = 4u$.
$4 \times 20 = 80$ fruits.

Marking:
1 mark for defining units/ratio.
1 mark for correct cost equation.
1 mark for value of 1 unit.
1 mark for final answers (both parts).

20.
(a) 540 boxes
(b) 39 stacks
(c) $19.50

Working:
(a) Total boxes = $45 \text{ stacks} \times 12 \text{ boxes/stack}$.
$45 \times 12 = 45 \times (10 + 2) = 450 + 90 = 540$ boxes.

(b) Boxes removed = 150.
Remaining boxes = $540 - 150 = 390$ boxes.
New stack size = 10 boxes.
Number of new stacks = $390 \div 10 = 39$ stacks.

(c) Cost of labels = 39 \text{ stacks} \times \0.50$.$39 \times 0.5 = 19.5$. Total cost =$19.50.

Marking:
1 mark for total initial boxes.
1 mark for remaining boxes.
1 mark for number of new stacks.
1 mark for total cost.