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Primary 6 PSLE Mathematics Semestral Assessment 2 (End of Year) Paper 3

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TuitionGoWhere Practice Paper - Mathematics Primary 6 PSLE

TuitionGoWhere Exam Practice (AI)

Subject: Mathematics
Level: Primary 6 PSLE
Paper: SA2 Version 3
Duration: 1 hour 30 minutes
Total Marks: 80

Name: ________________________
Class: Primary 6 ________
Date: ________________________

INSTRUCTIONS TO CANDIDATES

  1. Do not open this booklet until you are told to do so.
  2. Follow all instructions carefully.
  3. Answer all questions.
  4. Write your answers in this booklet.
  5. The number of marks is given in brackets [ ] at the end of each question or part question.
  6. Show your working clearly in the space provided.
  7. The total marks for this paper is 80.

BOOKLET A: Multiple-Choice Questions (20 marks)

Questions 1 to 10 carry 2 marks each. For each question, four options are given. Choose the correct answer and write its number (1, 2, 3 or 4) in the brackets provided.

1. In the number 4 826 593, which digit is in the ten thousands place? [2]

(1) 2
(2) 6
(3) 8
(4) 4

Answer: (_____)

2. Round off 7 485 629 to the nearest hundred thousand. [2]

(1) 7 400 000
(2) 7 490 000
(3) 7 500 000
(4) 7 580 000

Answer: (_____)

3. Which of the following is a common multiple of 6 and 8? [2]

(1) 24
(2) 36
(3) 42
(4) 54

Answer: (_____)

4. Find the value of 5 000 000 − 3 847 219. [2]

(1) 1 152 781
(2) 1 153 781
(3) 2 152 781
(4) 2 153 781

Answer: (_____)

5. A factory produced 8 450 toys in January. In February, it produced 1 250 more toys than in January. How many toys were produced in February? [2]

(1) 7 200
(2) 9 700
(3) 9 600
(4) 9 800

Answer: (_____)

6. What is the product of 4 328 and 27? [2]

(1) 116 856
(2) 116 756
(3) 115 856
(4) 115 756

Answer: (_____)

7. Divide 6 732 by 12. What is the remainder? [2]

(1) 0
(2) 4
(3) 6
(4) 8

Answer: (_____)

8. There are 3 456 apples. They are packed equally into 24 boxes. How many apples are in each box? [2]

(1) 144
(2) 142
(3) 134
(4) 124

Answer: (_____)

9. A number when divided by 15 gives a quotient of 428 and a remainder of 7. What is the number? [2]

(1) 6 427
(2) 6 420
(3) 6 413
(4) 6 407

Answer: (_____)

10. Mr Tan had 12500.Hespent12 500. He spent 3 850 on a television and $1 275 on a refrigerator. How much money had he left? [2]

(1) 7375(2)7 375 (2) 7 475
(3) 8375(4)8 375 (4) 8 475

Answer: (_____)

BOOKLET B: Short-Answer Questions (25 marks)

Questions 11 to 20 carry 1 or 2 marks each. Write your answers in the spaces provided. Show your working clearly.

11. Write 6 040 508 in words. [1]

12. Find the value of 8 000 000 − 4 729 386. [2]

13. List all the factors of 36. [1]

14. Find the lowest common multiple (LCM) of 9 and 12. [2]

15. Multiply 3 407 by 35. [2]

16. Divide 9 876 by 18. Write your answer as a quotient and remainder. [2]

17. A number is 4 500 when rounded to the nearest hundred. What is the greatest possible value of this number? [2]

18. Find the value of 72 × (45 + 15) ÷ 9. [2]

19. There are 5 280 marbles. They are shared equally among 16 children. How many marbles does each child get? [2]

20. A book has 432 pages. Muthu reads 27 pages each day. How many days will he take to finish reading the book? [2]

BOOKLET C: Structured / Long-Answer Questions (35 marks)

Questions 21 to 25 carry 3 to 5 marks each. Show your working clearly and write your answers in the spaces provided.

21. A stadium has 45 680 seats. On Saturday, 28 475 seats were occupied. On Sunday, 3 250 more seats were occupied than on Saturday. [3]

(a) How many seats were occupied on Sunday?
(b) How many seats were not occupied on Sunday?

22. A factory packed 12 480 bottles of juice into cartons. Each carton contained 24 bottles. [3]

(a) How many cartons were used?
(b) If each carton was sold for $18, how much money was collected from the sale of all the cartons?

23. Mrs Lim bought some pens and pencils. She bought 3 times as many pens as pencils. Each pen cost 2andeachpencilcost2 and each pencil cost 1. She spent a total of $140. [4]

(a) How many pencils did she buy?
(b) How many pens did she buy?

24. A number is between 5 000 and 6 000. When it is divided by 7, the remainder is 3. When it is divided by 9, the remainder is 5. What is the number? [4]

25. A school has 1 240 pupils. 3/8 of the pupils are boys. 2/5 of the girls wear spectacles. [5]

(a) How many girls are there in the school?
(b) How many girls wear spectacles?
(c) What fraction of the total pupils are girls who wear spectacles? Express your answer in the simplest form.

END OF PAPER

Total Marks: 80

Answers

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TuitionGoWhere Practice Paper - Mathematics Primary 6 PSLE (Answer Key)

Subject: Mathematics
Level: Primary 6 PSLE
Paper: SA2 Version 3
Total Marks: 80

BOOKLET A: Multiple-Choice Questions (20 marks)

1. Answer: (1) 2 [2]

Explanation:
The number is 4 826 593.
Place values from left:

  • 4 → millions
  • 8 → hundred thousands
  • 2 → ten thousands
  • 6 → thousands
  • 5 → hundreds
  • 9 → tens
  • 3 → ones

The digit in the ten thousands place is 2.

2. Answer: (3) 7 500 000 [2]

Explanation:
To round 7 485 629 to the nearest hundred thousand:

  • Look at the ten thousands digit: 8
  • Since 8 ≥ 5, round up the hundred thousands digit (4) to 5
  • All digits to the right become 0
  • Result: 7 500 000

3. Answer: (1) 24 [2]

Explanation:
Multiples of 6: 6, 12, 18, 24, 30, 36, 42, 48...
Multiples of 8: 8, 16, 24, 32, 40, 48...
Common multiples: 24, 48, 72...
The smallest common multiple (LCM) is 24.

4. Answer: (1) 1 152 781 [2]

Working:

  5 000 000
− 3 847 219
-----------
  1 152 781

Check: 1 152 781 + 3 847 219 = 5 000 000 ✓

5. Answer: (2) 9 700 [2]

Working:
January: 8 450 toys
February: 8 450 + 1 250 = 9 700 toys

6. Answer: (1) 116 856 [2]

Working:

    4 328
  ×    27
  -------
   30 296   (4 328 × 7)
+ 86 560    (4 328 × 20)
  -------
  116 856

7. Answer: (1) 0 [2]

Working:
6 732 ÷ 12 = 561 exactly
12 × 561 = 6 732
Remainder = 0

8. Answer: (1) 144 [2]

Working:
3 456 ÷ 24 = 144
Check: 144 × 24 = 3 456 ✓

9. Answer: (1) 6 427 [2]

Working:
Number = (Divisor × Quotient) + Remainder
= (15 × 428) + 7
= 6 420 + 7
= 6 427

10. Answer: (1) $7 375 [2]

Working:
Total spent = 3850+3 850 + 1 275 = 5125Moneyleft=5 125 Money left = 12 500 − 5125=∗∗5 125 = **7 375**

BOOKLET B: Short-Answer Questions (25 marks)

11. Answer: Six million forty thousand five hundred eight [1]

Explanation:
6 040 508 = 6 000 000 + 40 000 + 500 + 8
In words: Six million forty thousand five hundred eight
(Note: "and" is not used in standard mathematical writing for whole numbers in Singapore curriculum)

12. Answer: 3 270 614 [2]

Working:

  8 000 000
− 4 729 386
-----------
  3 270 614

Check: 3 270 614 + 4 729 386 = 8 000 000 ✓

13. Answer: 1, 2, 3, 4, 6, 9, 12, 18, 36 [1]

Explanation:
Factors of 36 come in pairs:
1 × 36 = 36
2 × 18 = 36
3 × 12 = 36
4 × 9 = 36
6 × 6 = 36
All factors: 1, 2, 3, 4, 6, 9, 12, 18, 36

14. Answer: 36 [2]

Working:
Multiples of 9: 9, 18, 27, 36, 45, 54...
Multiples of 12: 12, 24, 36, 48, 60...
LCM = 36

Alternative method (prime factorisation):
9 = 3²
12 = 2² × 3
LCM = 2² × 3² = 4 × 9 = 36

15. Answer: 119 245 [2]

Working:

    3 407
  ×    35
  -------
   17 035   (3 407 × 5)
+ 102 210   (3 407 × 30)
  -------
  119 245

16. Answer: Quotient 548, Remainder 12 [2]

Working:
9 876 ÷ 18
18 × 500 = 9 000
9 876 − 9 000 = 876
18 × 40 = 720
876 − 720 = 156
18 × 8 = 144
156 − 144 = 12

Quotient = 500 + 40 + 8 = 548
Remainder = 12

Check: 548 × 18 + 12 = 9 864 + 12 = 9 876 ✓

17. Answer: 4 549 [2]

Explanation:
When rounding to the nearest hundred, numbers from 4 450 to 4 549 round to 4 500.
The greatest possible value is 4 549.
(4 550 would round to 4 600)

18. Answer: 480 [2]

Working:
Follow order of operations (brackets first):
72 × (45 + 15) ÷ 9
= 72 × 60 ÷ 9
= 4 320 ÷ 9
= 480

Alternative: 72 ÷ 9 = 8, then 8 × 60 = 480

19. Answer: 330 [2]

Working:
5 280 ÷ 16 = 330
Check: 330 × 16 = 5 280 ✓

20. Answer: 16 [2]

Working:
432 ÷ 27 = 16
Check: 16 × 27 = 432 ✓
Muthu will take 16 days to finish the book.

BOOKLET C: Structured / Long-Answer Questions (35 marks)

21. [3 marks]

(a) Seats occupied on Sunday:
Saturday: 28 475
Sunday: 28 475 + 3 250 = 31 725 [1 mark]

(b) Seats not occupied on Sunday:
Total seats: 45 680
Occupied on Sunday: 31 725
Not occupied: 45 680 − 31 725 = 13 955 [2 marks]

Mark breakdown:

  • (a) Correct answer: 1 mark
  • (b) Correct method (subtraction) and answer: 2 marks

22. [3 marks]

(a) Number of cartons:
12 480 ÷ 24 = 520 cartons [1 mark]

(b) Total money collected:
520 × 18=∗∗18 = **9 360** [2 marks]

Working for (b):
520 × 18 = 520 × (10 + 8) = 5 200 + 4 160 = 9 360

Mark breakdown:

  • (a) Correct division and answer: 1 mark
  • (b) Correct multiplication using answer from (a) and final answer: 2 marks
    (1 mark for method, 1 mark for correct answer)

23. [4 marks]

Method 1: Using Units (Model Drawing)

Let number of pencils = 1 unit
Number of pens = 3 units

Cost of pencils = 1 unit × 1=1 = 1 unit
Cost of pens = 3 units × 2=2 = 6 units
Total cost = 1unit+1 unit + 6 units = $7 units

7units=7 units = 140
1 unit = 140÷7=∗∗140 ÷ 7 = **20**

Since 1 unit represents number of pencils, and each pencil costs 1:Numberofpencils=1: Number of pencils = 20 ÷ $1 = 20 pencils [2 marks]
Number of pens = 3 × 20 = 60 pens [2 marks]

Method 2: Algebra
Let p = number of pencils
Pens = 3p
Total cost: 1(p) + 2(3p) = 140
p + 6p = 140
7p = 140
p = 20

Pencils = 20, Pens = 60

Mark breakdown:

  • Correct setup (ratio/cost relationship): 1 mark
  • Correct calculation of 1 unit / p: 1 mark
  • Correct number of pencils: 1 mark
  • Correct number of pens: 1 mark

24. [4 marks]

Method: Systematic Listing / Chinese Remainder Theorem approach

Number is between 5 000 and 6 000.
Condition 1: Number ÷ 7 → remainder 3
Condition 2: Number ÷ 9 → remainder 5

Step 1: List numbers between 5 000 and 6 000 that give remainder 3 when divided by 7.
5 000 ÷ 7 = 714 remainder 2
So 5 001 gives remainder 3.
Numbers: 5 001, 5 008, 5 015, 5 022, 5 029, 5 036, 5 043, 5 050, 5 057, 5 064, 5 071, 5 078, 5 085, 5 092, 5 099, 5 106, 5 113, 5 120, 5 127, 5 134, 5 141, 5 148, 5 155, 5 162, 5 169, 5 176, 5 183, 5 190, 5 197, 5 204, 5 211, 5 218, 5 225, 5 232, 5 239, 5 246, 5 253, 5 260, 5 267, 5 274, 5 281, 5 288, 5 295, 5 302, 5 309, 5 316, 5 323, 5 330, 5 337, 5 344, 5 351, 5 358, 5 365, 5 372, 5 379, 5 386, 5 393, 5 400, 5 407, 5 414, 5 421, 5 428, 5 435, 5 442, 5 449, 5 456, 5 463, 5 470, 5 477, 5 484, 5 491, 5 498, 5 505, 5 512, 5 519, 5 526, 5 533, 5 540, 5 547, 5 554, 5 561, 5 568, 5 575, 5 582, 5 589, 5 596, 5 603, 5 610, 5 617, 5 624, 5 631, 5 638, 5 645, 5 652, 5 659, 5 666, 5 673, 5 680, 5 687, 5 694, 5 701, 5 708, 5 715, 5 722, 5 729, 5 736, 5 743, 5 750, 5 757, 5 764, 5 771, 5 778, 5 785, 5 792, 5 799, 5 806, 5 813, 5 820, 5 827, 5 834, 5 841, 5 848, 5 855, 5 862, 5 869, 5 876, 5 883, 5 890, 5 897, 5 904, 5 911, 5 918, 5 925, 5 932, 5 939, 5 946, 5 953, 5 960, 5 967, 5 974, 5 981, 5 988, 5 995.

Step 2: Check which of these gives remainder 5 when divided by 9.
5 001 ÷ 9 = 555 r 6 ✗
5 008 ÷ 9 = 556 r 4 ✗
5 015 ÷ 9 = 557 r 2 ✗
5 022 ÷ 9 = 558 r 0 ✗
5 029 ÷ 9 = 558 r 7 ✗
5 036 ÷ 9 = 559 r 5 ✓

Answer: 5 036 [4 marks]

Verification:
5 036 ÷ 7 = 719 remainder 3 ✓
5 036 ÷ 9 = 559 remainder 5 ✓

Mark breakdown:

  • Correct understanding of both conditions: 1 mark
  • Systematic method to find numbers satisfying first condition: 1 mark
  • Checking second condition correctly: 1 mark
  • Correct final answer: 1 mark

25. [5 marks]

Given: Total pupils = 1 240
Boys = 3/8 of total
Girls = 1 − 3/8 = 5/8 of total
Girls wearing spectacles = 2/5 of girls

(a) Number of girls:
Girls = 5/8 × 1 240
= 5 × 155
= 775 girls [1 mark]

(b) Girls wearing spectacles:
Girls with spectacles = 2/5 × 775
= 2 × 155
= 310 girls [2 marks]

(c) Fraction of total pupils who are girls wearing spectacles:
Fraction = 310 / 1 240
= 31 / 124 (divide by 10)
= 1 / 4 (divide by 31) [2 marks]

Alternative for (c):
Fraction = (5/8) × (2/5) = 10/40 = 1/4

Mark breakdown:

  • (a) Correct fraction of girls and calculation: 1 mark
  • (b) Correct fraction of girls with spectacles and calculation: 2 marks (1 for method, 1 for answer)
  • (c) Correct fraction and simplification to simplest form: 2 marks (1 for correct fraction, 1 for simplest form)

TOTAL MARKS: 80