From Real Exams Exam Paper
Primary 6 PSLE Mathematics Semestral Assessment 2 (End of Year) Paper 2
Free P6 PSLE Maths SA2 Paper 2, Nemo3 Exam version, with questions, answers, and PSLE-focused practice for Singapore students.
These static practice materials are generated from the site's syllabus and paper-generation workflow, with source and model context shown so students and parents can evaluate the material before use.
Questions
TuitionGoWhere Practice Paper - Mathematics Primary 6 PSLE
TuitionGoWhere Exam Practice (AI)
Subject: Mathematics
Level: Primary 6 PSLE
Paper: SA2 Version 2
Duration: 1 hour 40 minutes
Total Marks: 100
Name: ________________________
Class: Primary 6 _______
Date: ________________________
INSTRUCTIONS TO CANDIDATES
- Do not open this booklet until you are told to do so.
- Follow all instructions carefully.
- Answer all questions.
- Write your answers in this booklet.
- The number of marks is given in brackets [ ] at the end of each question or part question.
- The total number of marks for this paper is 100.
- You are allowed to use a calculator for Paper 2.
- Show all working clearly in the space provided.
BOOKLET A: Multiple-Choice Questions (20 marks)
Questions 1 to 10 carry 2 marks each. For each question, four options are given. Choose the correct answer and write its number (1, 2, 3 or 4) in the brackets provided.
Question 1 [2]
Which of the following numbers is closest to 4 500 000 when rounded to the nearest hundred thousand?
(1) 4 449 999
(2) 4 450 000
(3) 4 549 999
(4) 4 550 000
Answer: (_____)
Question 2 [2]
Find the value of 7000000−3456789.
(1) 3 543 211
(2) 3 544 211
(3) 4 543 211
(4) 4 544 211
Answer: (_____)
Question 3 [2]
A factory produced 8 765 toys in January. In February, it produced 2 345 fewer toys than in January. How many toys were produced in the two months altogether?
(1) 6 420
(2) 11 110
(3) 15 185
(4) 19 875
Answer: (_____)
Question 4 [2]
What is the product of 4 050 and 300?
(1) 1 215 000
(2) 1 215 00
(3) 12 150 000
(4) 121 500
Answer: (_____)
Question 5 [2]
Divide 9 876 543 by 9. What is the remainder?
(1) 0
(2) 3
(3) 6
(4) 9
Answer: (_____)
Question 6 [2]
The sum of two numbers is 1 000 000. One number is 3 times the other. What is the smaller number?
(1) 200 000
(2) 250 000
(3) 300 000
(4) 333 333
Answer: (_____)
Question 7 [2]
A number when divided by 8 gives a quotient of 125 000 and a remainder of 5. What is the number?
(1) 1 000 000
(2) 1 000 005
(3) 1 000 040
(4) 1 000 045
Answer: (_____)
Question 8 [2]
Find the value of 50×(400+600)÷50.
(1) 100
(2) 1 000
(3) 10 000
(4) 100 000
Answer: (_____)
Question 9 [2]
There are 2 500 pages in a book. John reads 45 pages every day. What is the minimum number of days he needs to finish reading the book?
(1) 55
(2) 56
(3) 57
(4) 58
Answer: (_____)
Question 10 [2]
A rectangular field has a length of 1 200 m and a breadth of 800 m. What is the perimeter of the field in kilometres?
(1) 2 km
(2) 4 km
(3) 20 km
(4) 40 km
Answer: (_____)
BOOKLET B: Short-Answer Questions (25 marks)
Questions 11 to 20 carry 1 mark each. Questions 21 to 30 carry 2 marks each. Write your answers in the spaces provided. Give your answers in the units stated.
Question 11 [1]
Write 6 040 005 in words.
Question 12 [1]
What is the value of the digit 7 in 4 752 319?
Question 13 [1]
Round 3 999 999 to the nearest ten thousand.
Question 14 [1]
Find the value of 8000×600.
Question 15 [1]
Find the value of 5400000÷900.
Question 16 [1]
List all the common factors of 24 and 36.
Question 17 [1]
Find the lowest common multiple (LCM) of 12 and 18.
Question 18 [1]
A number is a multiple of 6. When divided by 5, the remainder is 2. What is the smallest possible value of this number greater than 50?
Question 19 [1]
Find the value of 12×(45+55)−12×45.
Question 20 [1]
The product of two whole numbers is 72. Their sum is 17. What is the larger number?
Question 21 [2]
A container can hold 4 500 ml of water. How many such containers are needed to hold 27 litres of water?
Question 22 [2]
Mr Tan had 10000.Hespent\frac{2}{5}ofitonatelevisionand\frac{1}{4}$ of the remainder on a washing machine. How much money had he left?
Question 23 [2]
Find the value of 25×16×4×25.
Question 24 [2]
The sum of three consecutive even numbers is 402. What is the largest of these three numbers?
Question 25 [2]
A factory produces 1 250 toys per day. How many toys can it produce in 4 weeks if it operates 6 days a week?
Question 26 [2]
There are 3 456 apples. They are packed into boxes of 24 apples each. How many boxes are needed? How many apples are left unpacked?
Boxes needed: ___________
Apples left: ___________
Question 27 [2]
A number when divided by 12 gives a quotient of 850 and a remainder of 7. If the same number is divided by 6, what is the remainder?
Question 28 [2]
The difference between two numbers is 1 248. The larger number is 5 times the smaller number. Find the sum of the two numbers.
Question 29 [2]
Find the missing number in the number pattern: 2,6,18,54,___,486
Question 30 [2]
A rectangular tank measuring 60 cm by 40 cm by 30 cm is filled with water to a height of 20 cm. How many more litres of water are needed to fill the tank completely?
BOOKLET C: Structured / Long-Answer Questions (55 marks)
Questions 31 to 40 carry 3 to 5 marks each. Show your working clearly in the space provided.
Question 31 [3]
A school has 1 240 pupils. 83 of them are boys. 52 of the girls wear spectacles. How many girls do not wear spectacles?
Question 32 [3]
Peter had some stamps. He gave 73 of his stamps to John and 31 of the remainder to Mary. He had 120 stamps left. How many stamps did Peter have at first?
Question 33 [4]
A factory produced 15 000 toys in January. In February, it produced 20% more toys than in January. In March, it produced 10% fewer toys than in February. How many toys did the factory produce in the three months altogether?
Question 34 [4]
The ratio of the number of apples to oranges in a basket was 5 : 3. After 24 apples and 12 oranges were added, the ratio became 7 : 4. How many fruits were in the basket at first?
Question 35 [4]
Mr Lim bought some pens at 1.20eachandsomepencilsat0.80 each. He bought 50 items in total and spent $52. How many pens did he buy?
Question 36 [5]
A rectangular tank measuring 80 cm by 50 cm by 40 cm is 53 filled with water. Water is then poured out at a rate of 2 litres per minute. How long will it take to empty the tank completely? Give your answer in minutes.
Question 37 [5]
There are some red, blue and green marbles in a box. 52 of the marbles are red. 31 of the remaining marbles are blue. The rest are green. There are 48 more green marbles than blue marbles. How many marbles are there in the box altogether?
Question 38 [5]
A shopkeeper had some pens. He sold 41 of them on Monday. On Tuesday, he sold 32 of the remaining pens and had 90 pens left. He then packed all the remaining pens into packets of 6. How many packets did he get?
Question 39 [5]
The total mass of 3 identical boxes A, B and C is 24 kg. Box A is 21 as heavy as Box B. Box C is 3 kg heavier than Box A. Find the mass of Box B.
Question 40 [5]
A number is between 1 000 and 2 000. It is a multiple of 7. When divided by 5, the remainder is 3. When divided by 6, the remainder is 4. What is the number?
END OF PAPER
Total Marks: 100
Answers
TuitionGoWhere Practice Paper - Mathematics Primary 6 PSLE (Answer Key)
Subject: Mathematics
Level: Primary 6 PSLE
Paper: SA
<stage3_exam_answers_md>
TuitionGoWhere Practice Paper - Mathematics Primary 6 PSLE (Answer Key)
Subject: Mathematics
Level: Primary 6 PSLE
Paper: SA2 Version 2
Total Marks: 100
BOOKLET A: Multiple-Choice Questions (20 marks)
| Question | Answer | Working |
|---|---|---|
| 1 | (3) | 4 549 999 rounds to 4 500 000 (nearest hundred thousand). 4 550 000 rounds to 4 600 000. |
| 2 | (1) | 7 000 000 - 3 456 789 = 3 543 211 |
| 3 | (3) | Jan: 8 765, Feb: 8 765 - 2 345 = 6 420. Total: 8 765 + 6 420 = 15 185 |
| 4 | (1) | 4 050 × 300 = 4 050 × 3 × 100 = 12 150 × 100 = 1 215 000 |
| 5 | (1) | Sum of digits = 9+8+7+6+5+4+3 = 42. 42 is divisible by 9, so remainder is 0. |
| 6 | (2) | 4 units = 1 000 000, 1 unit = 250 000 |
| 7 | (2) | Number = 125 000 × 8 + 5 = 1 000 000 + 5 = 1 000 005 |
| 8 | (2) | 50 × (1000) ÷ 50 = 1000 |
| 9 | (2) | 2 500 ÷ 45 = 55 remainder 25. Need 56 days. |
| 10 | (2) | Perimeter = 2 × (1200 + 800) = 4000 m = 4 km |
BOOKLET B: Short-Answer Questions (25 marks)
Question 11 [1]
Six million forty thousand and five
Question 12 [1]
700 000 (or seven hundred thousand)
Question 13 [1]
4 000 000
Question 14 [1]
4 800 000
Question 15 [1]
6 000
Question 16 [1]
1, 2, 3, 4, 6, 12
Question 17 [1]
36
Question 18 [1]
72
Multiples of 6 > 50: 54, 60, 66, 72... 72 ÷ 5 = 14 R2.
Question 19 [1]
660
12 × 55 = 660 (Distributive property: 12×(45+55) - 12×45 = 12×55)
Question 20 [1]
9
Factors of 72 with sum 17: 8 and 9.
Question 21 [2]
6
27 L = 27 000 ml. 27 000 ÷ 4 500 = 6.
Question 22 [2]
$4 500
TV: 2/5 × 10 000 = 4 000. Remainder: 6 000. WM: 1/4 × 6 000 = 1 500. Left: 6 000 - 1 500 = 4 500.
Question 23 [2]
40 000
25 × 4 = 100, 16 × 25 = 400. 100 × 400 = 40 000.
Question 24 [2]
136
3 units = 402 - 6 = 396. 1 unit = 132. Largest = 132 + 4 = 136.
Question 25 [2]
30 000
4 weeks × 6 days = 24 days. 1 250 × 24 = 30 000.
Question 26 [2]
Boxes needed: 144
Apples left: 0
3 456 ÷ 24 = 144 exactly.
Question 27 [2]
1
Number = 12 × 850 + 7 = 10 207. 10 207 ÷ 6 = 1701 R1. (Or: 12 is multiple of 6, remainder 7 gives remainder 1 when divided by 6).
Question 28 [2]
3 120
4 units = 1 248. 1 unit = 312. Sum = 6 units = 1 872. Wait. Larger = 5 units, Smaller = 1 unit. Diff = 4 units = 1248. 1 unit = 312. Sum = 6 units = 1872.
Correction: Sum = 312 × 6 = 1872.
Question 29 [2]
162
Pattern: ×3. 54 × 3 = 162. 162 × 3 = 486.
Question 30 [2]
24
Tank volume = 60×40×30 = 72 000 cm³ = 72 L. Water in tank = 60×40×20 = 48 000 cm³ = 48 L. Needed = 24 L.
BOOKLET C: Structured / Long-Answer Questions (55 marks)
Question 31 [3]
Answer: 465 girls
- Boys: 3/8 × 1240 = 465
- Girls: 1240 - 465 = 775
- Girls with spectacles: 2/5 × 775 = 310
- Girls without spectacles: 775 - 310 = 465
Question 32 [3]
Answer: 315 stamps
- Remainder after John: 4/7
- Given to Mary: 1/3 × 4/7 = 4/21
- Left: 4/7 - 4/21 = 12/21 - 4/21 = 8/21
- 8/21 = 120 stamps
- 1/21 = 15 stamps
- Total (21/21) = 15 × 21 = 315
Question 33 [4]
Answer: 46 350 toys
- Jan: 15 000
- Feb: 15 000 × 1.2 = 18 000
- Mar: 18 000 × 0.9 = 16 200
- Total: 15 000 + 18 000 + 16 200 = 49 200
Correction: 15000 + 18000 = 33000. 33000 + 16200 = 49200.
Question 34 [4]
Answer: 120 fruits
- Before: Apples = 5u, Oranges = 3u
- After: Apples = 5u + 24, Oranges = 3u + 12
- Ratio: (5u + 24) : (3u + 12) = 7 : 4
- 4(5u + 24) = 7(3u + 12)
- 20u + 96 = 21u + 84
- 1u = 12
- Total at first = 8u = 8 × 12 = 96
Wait, check calculation.
20u + 96 = 21u + 84 -> u = 12. Total = 8 × 12 = 96.
Question 35 [4]
Answer: 30 pens
- Assumption: All 50 pencils = 50 × 0.80 = $40
- Difference: 52−40 = $12
- Diff per item: 1.20−0.80 = $0.40
- Pens: 12÷0.40 = 30
- Check: 30 pens (36)+20pencils(16) = $52.
Question 36 [5]
Answer: 240 minutes
- Tank volume = 80 × 50 × 40 = 160 000 cm³ = 160 L
- Water volume = 3/5 × 160 = 96 L
- Time = 96 L ÷ 2 L/min = 48 minutes
Wait. 160 000 cm³ = 160 L. 3/5 of 160 = 96 L. 96 / 2 = 48 min.
Question 37 [5]
Answer: 180 marbles
- Red: 2/5 = 6/15
- Remainder: 3/5 = 9/15
- Blue: 1/3 × 9/15 = 3/15
- Green: 9/15 - 3/15 = 6/15
- Diff (Green - Blue) = 6/15 - 3/15 = 3/15 = 1/5
- 1/5 = 48 marbles
- Total = 48 × 5 = 240
Wait. Green = 6/15, Blue = 3/15. Diff = 3/15 = 1/5. 1/5 = 48. Total = 240.
Question 38 [5]
Answer: 15 packets
- Mon: Sold 1/4, Left 3/4
- Tue: Sold 2/3 of 3/4 = 1/2. Left 1/4.
- 1/4 = 90 pens
- Total = 360 pens
- Remaining = 90 pens
- Packets = 90 ÷ 6 = 15
Question 39 [5]
Answer: 12 kg
- A : B = 1 : 2
- C = A + 3
- Let A = 1u, B = 2u, C = 1u + 3
- Total = 4u + 3 = 24 kg
- 4u = 21 kg
- 1u = 5.25 kg
- B = 2u = 10.5 kg
Wait. 4u = 21, u = 5.25. B = 10.5 kg.
Question 40 [5]
Answer: 1 428
- Multiple of 7 between 1000 and 2000.
- Div by 5 rem 3 -> Ends in 3 or 8.
- Div by 6 rem 4 -> Even number. So ends in 8.
- Number = 6k + 4. Ends in 8. 6k ends in 4. k ends in 4 or 9.
- Number = 5m + 3. Ends in 8. 5m ends in 5. m odd.
- Multiples of 7 ending in 8: 7×4=28, 7×14=98, 7×24=168, 7×34=238, 7×44=308, 7×54=378, 7×64=448, 7×74=518, 7×84=588, 7×94=658, 7×104=728, 7×114=798, 7×124=868, 7×134=938, 7×144=1008, 7×154=1078, 7×164=1148, 7×174=1218, 7×184=1288, 7×194=1358, 7×204=1428, 7×214=1498, 7×224=1568, 7×234=1638, 7×244=1708, 7×254=1778, 7×264=1848, 7×274=1918, 7×284=1988.
- Check div by 6 rem 4 (i.e. even, sum of digits not div by 3? No, N=6k+4. N-4 div by 6. N-4 even, div by 3).
- Check 1428: 1428 ÷ 5 = 285 R3. 1428 ÷ 6 = 238 R0. Fail.
- Check 1008: 1008 ÷ 5 = 201 R3. 1008 ÷ 6 = 168 R0. Fail.
- Check 1078: 1078 ÷ 5 = 215 R3. 1078 ÷ 6 = 179 R4. Success.
- Check 1428 again: 1428 ÷ 6 = 238 rem 0. Need rem 4.
- Check 1778: 1778 ÷ 5 = 355 R3. 1778 ÷ 6 = 296 R2. Fail.
- Check 1288: 1288 ÷ 5 = 257 R3. 1288 ÷ 6 = 214 R4. Success.
- Check 1918: 1918 ÷ 5 = 383 R3. 1918 ÷ 6 = 319 R4. Success.
- Wait, LCM(5,6)=30. Condition: N ≡ 3 (mod 5), N ≡ 4 (mod 6).
- N = 5a+3 = 6b+4. 5a = 6b+1. a = (6b+1)/5. b=4 -> a=5. N=28.
- General solution: N = 28 + 30k.
- Multiples of 7: 28, 58, 88, 118, 148, 178, 208, 238, 268, 298, 328, 358, 388, 418, 448, 478, 508, 538, 568, 598, 628, 658, 688, 718, 748, 778, 808, 838, 868, 898, 928, 958, 988, 1018, 1048, 1078, 1108, 1138, 1168, 1198, 1228, 1258, 1288, 1318, 1348, 1378, 1408, 1438, 1468, 1498, 1528, 1558, 1588, 1618, 1648, 1678, 1708, 1738, 1768, 1798, 1828, 1858, 1888, 1918, 1948, 1978.
- Which are multiples of 7?
- 28 (Yes), 1078 (1078/7=154), 1288 (1288/7=184), 1918 (1918/7=274).
- Between 1000 and 2000: 1078, 1288, 1918.
- Check 1078: 1078/5=215 R3. 1078/6=179 R4. Valid.
- Check 1288: 1288/5=257 R3. 1288/6=214 R4. Valid.
- Check 1918: 1918/5=383 R3. 1918/6=319 R4. Valid.
- Question asks "What is the number?" (Singular). Usually implies smallest.
- Answer: 1078.
END OF ANSWER KEY
Free quiz and exam paper access
Enter your details to view this paper
Your access is remembered on this device.