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Primary 6 PSLE Mathematics Semestral Assessment 2 (End of Year) Paper 1

Free P6 PSLE Maths SA2 Paper 1, Ox Exam version, with questions, answers, and PSLE-focused practice for Singapore students.

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Primary 6 PSLE Mathematics From Real Exams Generated by Ox Alpha Updated 2026-08-27

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TuitionGoWhere Practice Paper - Answer Key - Mathematics Primary 6 PSLE

SA2 Practice Paper - Whole Numbers (Version 1 of 5)

Section A

Question 1 (a) 6 402 050 (b) The digit 4 is in the hundred thousands place, so its value is 400 000.

Question 2 (a) Nearest thousand: 7 468 295 → 7 468 000 (b) Nearest ten thousand: 7 468 295 → 7 470 000

Question 3 24+18÷6×57=24+3×57=24+157=24 + 18 \div 6 \times 5 - 7 = 24 + 3 \times 5 - 7 = 24 + 15 - 7 = 32

Question 4 84=2×4284 = 2 \times 42, 126=3×42126 = 3 \times 42. GCF = 42 (Check: 84=22×3×784 = 2^2 \times 3 \times 7, 126=2×32×7126 = 2 \times 3^2 \times 7; common factors 2×3×7=422 \times 3 \times 7 = 42.)

Question 5 LCM of 12 and 18 = 36 minutes. 08:45 + 36 min = 09:21

Section B

Question 6 1275×24=1\,275 \times 24 = 30 600 toys

Question 7 3840÷16=3\,840 \div 16 = 240 stamps per album

Question 8 (1500+96)÷14=1596÷14=(1\,500 + 96) \div 14 = 1\,596 \div 14 = 114

Question 9 245×18=245 \times 18 = $4 410

Question 10 After buying the bicycle, remainder =95×2=190= 95 \times 2 = 190. Money at first =190+128== 190 + 128 = $318

Section C

Question 11 Factors of 60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

Question 12 Pages in one hour: 385×60=23100385 \times 60 = 23\,100. Books: 23100÷120=19223\,100 \div 120 = 192 remainder 60. 192 complete books

Question 13 Two numbers with product 216 and sum 35: 8 and 27 (8×27=2168 \times 27 = 216; 8+27=358 + 27 = 35)

Question 14 LCM of 8, 12, 20 = 120 seconds = 2 minutes. Next ring together: 09:02

Question 15 Greatest: 7 520. Smallest: 2 057. Difference: 75202057=7\,520 - 2\,057 = 5 463

Question 16 45kg=45000g45\,\text{kg} = 45\,000\,\text{g}. 45000÷850=5245\,000 \div 850 = 52 remainder 800. 52 full days, with 800 g remaining.

Question 17 n4(mod9)n \equiv 4 \pmod{9} and n3(mod11)n \equiv 3 \pmod{11}. Testing n=4,13,22,31,40,49,58n = 4, 13, 22, 31, 40, 49, \mathbf{58}: 58÷9=658 \div 9 = 6 r 4; 58÷11=558 \div 11 = 5 r 3. Smallest number of chairs = 58

Question 18 Let Ben = 1 unit. Ali = 2 units, Calvin = 3 units. Total = 6 units = 720, so 1 unit = 120. Ali = 240, Ben = 120, Calvin = 360

Question 19 Buying 30 pens gives 6 free pens: 30+6=3630 + 6 = 36. Cost = 30 \times \3 = **90**

Question 20 Sticks in Figure nn: 3n+13n + 1. (a) Figure 50: 3×50+1=3 \times 50 + 1 = 151 sticks (b) 3n+1=1003n=99n=333n + 1 = 100 \Rightarrow 3n = 99 \Rightarrow n = 33. Figure 33


Total: 70 marks