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Primary 6 PSLE Mathematics Semestral Assessment 2 (End of Year) Paper 1

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Questions

TuitionGoWhere Practice Paper - Mathematics Primary 6 PSLE

TuitionGoWhere Secondary School (AI)


Subject:	Mathematics
Level:	Primary 6 (PSLE)
Paper:	SA2 Practice Paper — Version 1 of 5
Duration:	1 hour 30 minutes (90 minutes)
Total Marks:	50
Name:	_______________________________
Class:	_______________________________
Date:	_______________________________

Instructions

Write your name, class, and date in the spaces provided above.
Answer all questions in the spaces provided.
Show your working clearly — marks are awarded for correct steps even if the final answer is wrong.
Do not use a calculator.
The number of marks available for each question is shown in brackets, e.g. (2).
You are advised to spend no more than 90 minutes on this paper.

Section A: Short Answer Questions [20 marks]

Answer each question in the space provided. Each question carries 2 marks.

1. Write the following number in numerals.

Five million, two hundred and three thousand, six hundred and forty-eight.

..................................................................................................................

(2 marks)

2. What is the value of the digit 7 in the number 3,728,456?

..................................................................................................................

(2 marks)

3. Round 4,678,352 to the nearest hundred thousand.

..................................................................................................................

(2 marks)

4. Find the highest common factor (HCF) of 36 and 54.

..................................................................................................................

(2 marks)

5. List all the prime numbers between 40 and 60.

..................................................................................................................

(2 marks)

6. Find the lowest common multiple (LCM) of 8 and 14.

..................................................................................................................

(2 marks)

7. Express 84 as a product of its prime factors. Give your answer in index notation.

..................................................................................................................

(2 marks)

8. Find the value of:

(a) 15 × 240 = ______________

(b) 3,600 ÷ 12 = ______________

..................................................................................................................

(2 marks)

9. The table below shows the population of four towns.

Town	Population
A	2,345,678
B	2,435,678
C	2,345,768
D	2,354,678

Arrange the populations from least to greatest.

..................................................................................................................

(2 marks)

10. A factory produces 12,500 toys per day. How many toys will it produce in the month of March?

..................................................................................................................

(2 marks)

Section B: Structured Questions [20 marks]

Show your working clearly. Each question carries 4 marks.

11. A school library has 24,816 books. The school buys another 15,438 books and then donates 9,275 old books to a community centre.

(a) How many books does the library have after the new books are added?

(b) How many books remain after the donation?

..................................................................................................................

(4 marks)

12. The product of two numbers is 2,016. One of the numbers is 48. What is the other number?

..................................................................................................................

(4 marks)

13. Find the smallest number that is exactly divisible by 6, 9, and 15.

..................................................................................................................

(4 marks)

14. A fruit seller packed 480 oranges into bags of 8 each. He then repacked them into bags of 12 each.

(a) How many bags of 8 did he have at first?

(b) How many bags of 12 can he make with the same oranges?

..................................................................................................................

(4 marks)

15. Three bells ring at intervals of 6 minutes, 8 minutes, and 12 minutes respectively. If they ring together at 8:00 a.m., at what time will they next ring together?

..................................................................................................................

(4 marks)

Section C: Problem Sums [10 marks]

Show your working clearly. Each question carries 5 marks.

16. Mr Tan had a sum of money. He spent ₹3,250 on groceries and ₹1,780 on transport. He then gave half of the remaining money to his wife. After that, he donated ₹950 to charity and found that he had ₹2,400 left. How much money did Mr Tan have at first?

..................................................................................................................

(5 marks)

17. The total mass of Box A and Box B is 8,400 g. Box A is 1,250 g heavier than Box B.

(a) What is the mass of Box B?

(b) What is the mass of Box A?

..................................................................................................................

(5 marks)

18. A concert hall has 1,250 seats. On Friday, 785 seats were filled. On Saturday, 920 seats were filled. How many seats were not filled over the two days combined?

..................................................................................................................

(5 marks)

19. The number N is a 7-digit number. It has the following properties:

The digit in the millions place is 5.
The digit in the hundred thousands place is 3.
The digit in the tens place is 8.
All other digits are 0.

(a) Write down the number N.

(b) Round N to the nearest million.

..................................................................................................................

(5 marks)

20. A farmer has 3 fields. Field A produces 2,350 kg of rice. Field B produces 1,875 kg more than Field A. Field C produces twice as much as Field B.

(a) How much rice does Field B produce?

(b) How much rice does Field C produce?

(c) What is the total rice produced from all three fields?

..................................................................................................................

(5 marks)

— End of Paper —

Answers

TuitionGoWhere Practice Paper - Mathematics Primary 6 SA2 — Answer Key

Paper: Version 1 of 5 | Total Marks: 50

Section A: Short Answer Questions [20 marks]

1. Write in numerals: Five million, two hundred and three thousand, six hundred and forty-eight.

Answer: 5,203,648

Working:

Five million = 5,000,000
Two hundred and three thousand = 203,000
Six hundred and forty-eight = 648
Total = 5,000,000 + 203,000 + 648 = 5,203,648

(2 marks)

2. What is the value of the digit 7 in 3,728,456?

Answer: 700,000 (seven hundred thousand)

Working:

The digit 7 is in the hundred thousands place.
Value = 7 × 100,000 = 700,000

(2 marks)

3. Round 4,678,352 to the nearest hundred thousand.

Answer: 4,700,000

Working:

The hundred thousands digit is 6 (in 4,678,352).
The digit to the right (ten thousands place) is 7, which is ≥ 5.
Round up: 4,600,000 → 4,700,000

(2 marks)

4. Find the HCF of 36 and 54.

Answer: 18

Working:

Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36
Factors of 54: 1, 2, 3, 6, 9, 18, 27, 54
Common factors: 1, 2, 3, 6, 9, 18
Highest common factor = 18

Alternative method (prime factorisation):

36 = 2² × 3²
54 = 2 × 3³
HCF = 2¹ × 3² = 2 × 9 = 18

(2 marks)

5. List all prime numbers between 40 and 60.

Answer: 41, 43, 47, 53, 59

Working:

Check each number between 40 and 60 for factors other than 1 and itself.
41 ✓, 42 ✗, 43 ✓, 44 ✗, 45 ✗, 46 ✗, 47 ✓, 48 ✗, 49 = 7×7 ✗, 50 ✗, 51 = 3×17 ✗, 52 ✗, 53 ✓, 54 ✗, 55 = 5×11 ✗, 56 ✗, 57 = 3×19 ✗, 58 ✗, 59 ✓

(2 marks)

6. Find the LCM of 8 and 14.

Answer: 56

Working:

Multiples of 8: 8, 16, 24, 32, 40, 48, 56, 64…
Multiples of 14: 14, 28, 42, 56, 70…
LCM = 56

Alternative method:

8 = 2³; 14 = 2 × 7
LCM = 2³ × 7 = 8 × 7 = 56

(2 marks)

7. Express 84 as a product of its prime factors in index notation.

Answer: 2² × 3 × 7

Working:

84 ÷ 2 = 42
42 ÷ 2 = 21
21 ÷ 3 = 7
7 ÷ 7 = 1

84 = 2 × 2 × 3 × 7 = 2² × 3 × 7

(2 marks)

(a) 15 × 240 = 3,600

(b) 3,600 ÷ 12 = 300

Working:

(a) 15 × 240 = 15 × 24 × 10 = 360 × 10 = 3,600
(b) 3,600 ÷ 12 = 300 (since 12 × 300 = 3,600)

(2 marks)

9. Arrange from least to greatest.

Answer: A (2,345,678), C (2,345,768), D (2,354,678), B (2,435,678)

Working:

All start with 2 million.
Compare hundred thousands: A and C have 3, D has 3, B has 4 → B is largest.
Compare A vs C: both 2,345,xxx → A has 678, C has 768 → A < C.
Compare C vs D: C = 2,345,768; D = 2,354,678 → ten thousands: 4 vs 5 → C < D.
Order: A < C < D < B

(2 marks)

10. Toys produced in March.

Answer: 387,500 toys

Working:

March has 31 days.
12,500 × 31 = 12,500 × 30 + 12,500 = 375,000 + 12,500 = 387,500

(2 marks)

Section B: Structured Questions [20 marks]

11.

(a) Books after new books added:

Answer: 40,254 books

Working:

24,816 + 15,438 = 40,254

(b) Books remaining after donation:

Answer: 30,979 books

Working:

40,254 − 9,275 = 30,979

(4 marks: 2 marks for each part)

12. Product of two numbers is 2,016. One number is 48. Find the other.

Answer: 42

Working:

Other number = 2,016 ÷ 48
2,016 ÷ 48 = 42
Check: 48 × 42 = 48 × 40 + 48 × 2 = 1,920 + 96 = 2,016 ✓

(4 marks)

13. Smallest number divisible by 6, 9, and 15.

Answer: 90

Working:

Find LCM of 6, 9, and 15.
6 = 2 × 3
9 = 3²
15 = 3 × 5
LCM = 2 × 3² × 5 = 2 × 9 × 5 = 90

(4 marks)

14.

(a) Bags of 8 at first:

Answer: 60 bags

Working:

480 ÷ 8 = 60

(b) Bags of 12:

Answer: 40 bags

Working:

480 ÷ 12 = 40

(4 marks: 2 marks for each part)

15. Three bells ring at intervals of 6, 8, and 12 minutes. They ring together at 8:00 a.m. When next together?

Answer: 8:24 a.m.

Working:

Find LCM of 6, 8, and 12.
6 = 2 × 3
8 = 2³
12 = 2² × 3
LCM = 2³ × 3 = 8 × 3 = 24 minutes
8:00 a.m. + 24 minutes = 8:24 a.m.

(4 marks)

Section C: Problem Sums [10 marks]

16. Mr Tan's money problem (backward working).

Answer: ₹15,660

Working (backward method):

After donating ₹950, he had ₹2,400 left.
Before donation: ₹2,400 + ₹950 = ₹3,350
This ₹3,350 is half of what remained before giving to wife.
Before giving to wife: ₹3,350 × 2 = ₹6,700
He spent ₹3,250 + ₹1,780 = ₹5,030 on groceries and transport.
Original amount: ₹6,700 + ₹5,030 = ₹11,730

Correction — re-check:

Let original = X
After groceries and transport: X − 3,250 − 1,780 = X − 5,030
Gave half to wife: remaining = (X − 5,030) ÷ 2
After donating ₹950: (X − 5,030) ÷ 2 − 950 = 2,400
(X − 5,030) ÷ 2 = 2,400 + 950 = 3,350
X − 5,030 = 3,350 × 2 = 6,700
X = 6,700 + 5,030 = ₹11,730

Answer: ₹11,730

(5 marks: 1 mark each for correct backward steps, 1 mark for final answer)

17. Box A + Box B = 8,400 g. Box A is 1,250 g heavier than Box B.

(a) Mass of Box B:

Answer: 3,575 g

(b) Mass of Box A:

Answer: 4,825 g

Working:

If we subtract the difference: 8,400 − 1,250 = 7,150
Box B = 7,150 ÷ 2 = 3,575 g
Box A = 3,575 + 1,250 = 4,825 g
Check: 3,575 + 4,825 = 8,400 ✓

(5 marks: 2 marks for (a), 2 marks for (b), 1 mark for correct method)

18. Concert hall: 1,250 seats. Friday: 785 filled. Saturday: 920 filled. Seats not filled over two days?

Answer: 800 seats

Working:

Total seats available over 2 days = 1,250 × 2 = 2,500 seats
Total filled = 785 + 920 = 1,705 seats
Not filled = 2,500 − 1,705 = 795 seats

Correction:

785 + 920 = 1,705
2,500 − 1,705 = 795

Answer: 795 seats

(5 marks: 1 mark for total seats, 1 mark for total filled, 1 mark for subtraction, 1 mark for final answer, 1 mark for unit)

19. 7-digit number N.

(a) Write down N.

Answer: 5,300,080

Working:

Millions place: 5
Hundred thousands place: 3
Tens place: 8
All other digits: 0
N = 5,300,080

(b) Round N to the nearest million.

Answer: 5,000,000

Working:

5,300,080 → hundred thousands digit is 3 (< 5), so round down.
Rounded = 5,000,000

(5 marks: 3 marks for (a), 2 marks for (b))

20. Three fields.

(a) Field B:

Answer: 4,225 kg

Working:

Field B = 2,350 + 1,875 = 4,225 kg

(b) Field C:

Answer: 8,450 kg

Working:

Field C = 4,225 × 2 = 8,450 kg

(c) Total rice from all three fields:

Answer: 15,025 kg

Working:

Total = 2,350 + 4,225 + 8,450 = 15,025 kg

(5 marks: 1 mark for (a), 1 mark for (b), 2 marks for (c), 1 mark for correct method across all parts)

Mark Summary

Section	Marks
A: Questions 1–10	20
B: Questions 11–15	20
C: Questions 16–20	10
Total	50

Common Mistakes & Marking Notes

Q2: Award full marks for "700,000" or "seven hundred thousand". Do not accept just "7".
Q3: Common error — rounding to nearest ten thousand (4,680,000). This is wrong; the question asks for hundred thousand.
Q4: Accept any valid method (listing factors, prime factorisation, or Euclidean algorithm).
Q7: Award 1 mark for correct prime factorisation even if index notation is not used; award full marks only for index notation form.
Q9: Award 1 mark for correct order, 1 mark for showing comparison reasoning.
Q11: Award 1 mark for each correct part even if the other part is wrong (no carry-over penalty).
Q15: Award 2 marks for finding LCM = 24, 1 mark for adding to 8:00, 1 mark for correct time format.
Q16: This is a backward-working problem. Award marks for each correct backward step even if arithmetic slips occur. Accept model-drawing method as alternative.
Q18: Common error — students may only consider one day. Award marks for showing understanding of two days.
Q20: Award marks independently for each part. If (a) is wrong but (b) correctly uses (a)'s answer, award follow-through marks for (b) and (c).