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Primary 5 Mathematics Money Quiz

Free P5 Maths Money quiz, AI version, with questions, answers, and syllabus-aligned practice for Singapore students.

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Primary 5 Mathematics AI Generated Generated by DeepSeek V4 Flash Sample 01 Updated 2026-08-17

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Answer Key: Primary 5 Mathematics Quiz - Money

Total Marks: 50


Section A: Multiple Choice Questions (Questions 1 to 5)

2 marks each. 1 mark for correct answer only.

1. Answer: B) $2.90

  • Cost of pen = 0.85+0.85 + 1.20 = $2.05
  • Total cost = 0.85+0.85 + 2.05 = $2.90
  • Teaching Note: "More than" means addition. First find the cost of the pen, then add both costs.
  • Common Mistake: Students may forget to add the pencil's cost after finding the pen's cost.

2. Answer: C) $13.90

  • Cost of apples = 3 × 2.50=2.50 = 7.50
  • Cost of oranges = 2 × 3.20=3.20 = 6.40
  • Total cost = 7.50+7.50 + 6.40 = $13.90
  • Teaching Note: Multiply quantity by unit price for each item, then add the totals.
  • Common Mistake: Adding the unit prices first (3+2=5, 2.50+2.50+3.20=5.70,5×5.70, 5×5.70=$28.50) is incorrect.

3. Answer: C) $36

  • Discount amount = 20% of 45=45 = \frac{20}{100} \times 45 = 0.2 \times 45 = $9$
  • Sale price = 4545 - 9 = $36
  • Teaching Note: "Discount" means a reduction. Find the discount amount first, then subtract from the original price.
  • Alternative Method: Sale price = 80% of 45=0.8×45 = 0.8 × 45 = $36.

4. Answer: B) $15

  • Money spent on book = \frac{2}{5} \times \50 = $20$
  • Remainder after book = 5050 - 20 = $30
  • Money spent on meal = \frac{1}{2} \times \30 = $15$
  • Money left = 3030 - 15 = $15
  • Teaching Note: "Remainder" means what is left. Work step by step: find what was spent, then what is left, then what is spent from the remainder.
  • Common Mistake: Students may take 12\frac{1}{2} of the original $50 instead of the remainder.

5. Answer: B) $13.60

  • Cost of 1 pen = 8.50÷5=8.50 ÷ 5 = 1.70
  • Cost of 8 pens = 8 × 1.70=1.70 = 13.60
  • Teaching Note: Find the unit cost first (cost per pen), then multiply by the new quantity.
  • Alternative Method (Ratio): 5 pens : 8.50=8pens:8.50 = 8 pens : x. x=x = \frac{8}{5} \times 8.50 = $13.60$.

Section B: Short Answer Questions (Questions 6 to 15)

3 marks each. 1 mark for correct method, 1 mark for correct working, 1 mark for correct final answer.

6. Answer: $40.25

  • Cost of belt = 24.5024.50 - 8.75 = $15.75
  • Total cost = 24.50+24.50 + 15.75 = $40.25
  • Teaching Note: "Less than" means subtraction. Find the belt's cost first, then add.
  • Marking Scheme: 1m for belt cost ($15.75), 1m for correct addition, 1m for final answer.

7. Answer: $40.30

  • Cost of chicken = 4 × 6.80=6.80 = 27.20
  • Cost of fish = 3 × 9.50=9.50 = 28.50
  • Total cost = 27.20+27.20 + 28.50 = $55.70
  • Change = 100100 - 55.70 = $40.30
  • Teaching Note: "Change" is what you get back when you pay more than the total cost. Subtract total cost from the amount paid.
  • Marking Scheme: 1m for total cost (55.70),1mforsubtractionfrom55.70), 1m for subtraction from 100, 1m for final answer.

8. Answer: $102

  • Discount amount = 15% of 120=120 = \frac{15}{100} \times 120 = 0.15 \times 120 = $18$
  • Discounted price = 120120 - 18 = $102
  • Teaching Note: "Discounted price" is the price after the discount is applied.
  • Alternative Method: Discounted price = 85% of 120=0.85×120 = 0.85 × 120 = $102.
  • Marking Scheme: 1m for discount amount ($18), 1m for subtraction, 1m for final answer.

9. Answer: $140

  • Amount saved in February = \frac{3}{4} \times \80 = $60$
  • Total saved = 80+80 + 60 = $140
  • Teaching Note: "Of" in fractions means multiplication. 34\frac{3}{4} of 80means80 means \frac{3}{4} \times 80$.
  • Marking Scheme: 1m for February savings ($60), 1m for addition, 1m for final answer.

10. Answer: $1.55

  • Cost of 1 pen = 18.60÷12=18.60 ÷ 12 = 1.55
  • Teaching Note: To find the cost of one item when given the cost of a pack, divide the total cost by the number of items.
  • Marking Scheme: 1m for correct division setup, 1m for correct calculation, 1m for final answer.

11. Answer: $120

  • Money spent on dress = 35% of 200=0.35×200 = 0.35 × 200 = $70
  • Money spent on shoes = 25% of 200=0.25×200 = 0.25 × 200 = $50
  • Total spent = 70+70 + 50 = $120
  • Teaching Note: "Altogether" means add. Find each amount separately, then add.
  • Alternative Method: Total percentage spent = 35% + 25% = 60%. Total spent = 60% of 200=0.6×200 = 0.6 × 200 = $120.
  • Marking Scheme: 1m for dress cost (70),1mforshoescost(70), 1m for shoes cost (50), 1m for total ($120).

12. Answer: $40

  • Cost price per kg = 120÷50=120 ÷ 50 = 2.40
  • Selling price per kg = $3.20
  • Profit per kg = 3.203.20 - 2.40 = $0.80
  • Total profit = 50 × 0.80=0.80 = 40
  • Teaching Note: Profit = Selling Price - Cost Price. Find the cost per kg first, then the profit per kg, then multiply by the total kg.
  • Alternative Method: Total selling price = 50 × 3.20=3.20 = 160. Profit = 160160 - 120 = $40.
  • Marking Scheme: 1m for cost per kg (2.40),1mforprofitperkg(2.40), 1m for profit per kg (0.80), 1m for total profit ($40).

13. Answer: $72

  • Ratio Ali : Ben = 3 : 5
  • Ben's share = 5 parts = $45
  • 1 part = 45÷5=45 ÷ 5 = 9
  • Ali's share = 3 parts = 3 × 9=9 = 27
  • Total = 27+27 + 45 = $72
  • Teaching Note: In ratio problems, find the value of 1 part first. Then multiply to find other amounts.
  • Marking Scheme: 1m for value of 1 part (9),1mforAlisshare(9), 1m for Ali's share (27), 1m for total ($72).

14. Answer: $25.90

  • Cost of magazine = \frac{2}{5} \times \18.50 = \frac{2 \times 18.50}{5} = \frac{37}{5} = $7.40$
  • Total cost = 18.50+18.50 + 7.40 = $25.90
  • Teaching Note: "Of" means multiply. Find the magazine cost first, then add.
  • Marking Scheme: 1m for magazine cost ($7.40), 1m for addition, 1m for final answer.

15. Answer: $39.20

  • Cost of cloth = 2.5 × 12.80=12.80 = 32.00
  • Cost of ribbon = 3 × 2.40=2.40 = 7.20
  • Total cost = 32.00+32.00 + 7.20 = $39.20
  • Teaching Note: Multiply quantity by unit price for each item. Be careful with decimal multiplication.
  • Marking Scheme: 1m for cloth cost (32.00),1mforribboncost(32.00), 1m for ribbon cost (7.20), 1m for total ($39.20).

Section C: Problem-Solving Questions (Questions 16 to 20)

4 marks each. 1 mark for correct method/working, 1 mark for each correct intermediate step, 1 mark for correct final answer.

16. Answer: $540

  • Sale price after 25% discount = 75% of 800=0.75×800 = 0.75 × 800 = $600
  • Additional 10% off sale price = 10% of 600=0.1×600 = 0.1 × 600 = $60
  • Final price = 600600 - 60 = $540
  • Teaching Note: Apply discounts one at a time. The second discount is applied to the already discounted price, not the original price.
  • Common Mistake: Adding the discounts (25% + 10% = 35%) and applying 35% off 800gives800 gives 520, which is incorrect.
  • Marking Scheme: 1m for sale price (600),1mforadditionaldiscount(600), 1m for additional discount (60), 1m for final price ($540), 1m for correct working.

17. Answer: $48

  • Let the original amount be xx.
  • Money spent on book = 14x\frac{1}{4}x
  • Remainder after book = x14x=34xx - \frac{1}{4}x = \frac{3}{4}x
  • Money spent on pen = 23×34x=12x\frac{2}{3} \times \frac{3}{4}x = \frac{1}{2}x
  • Money left = \frac{3}{4}x - \frac{1}{2}x = \frac{1}{4}x = \12$
  • Therefore, x = 12 \times 4 = \48$
  • Teaching Note: Work backwards from the end. The 12leftis12 left is \frac{1}{4}$ of the original amount. Alternatively, use model drawing to visualise the fractions.
  • Marking Scheme: 1m for correct fraction of remainder, 1m for finding fraction left (14\frac{1}{4}), 1m for correct equation, 1m for final answer.

18. Answer: $96

  • Total cost price = 200 × 0.60=0.60 = 120
  • Number sold at $1.20 = 80% of 200 = 0.8 × 200 = 160 oranges
  • Number sold at $0.80 = 200 - 160 = 40 oranges
  • Total selling price = (160 × 1.20)+(40×1.20) + (40 × 0.80) = 192+192 + 32 = $224
  • Profit = 224224 - 120 = $104
  • Teaching Note: Profit = Total Selling Price - Total Cost Price. Calculate each part carefully.
  • Marking Scheme: 1m for cost price (120),1mfornumberoforangesateachprice(160and40),1mfortotalsellingprice(120), 1m for number of oranges at each price (160 and 40), 1m for total selling price (224), 1m for profit ($104).

19. Answer: $12

  • Ratio Lily : Mary = 2 : 7
  • Let Lily have 2 units and Mary have 7 units.
  • After Mary gives 15toLily:Lily=2units+15 to Lily: Lily = 2 units + 15, Mary = 7 units - $15
  • They are equal: 2 units + 15=7units15 = 7 units - 15
  • 2 units + 15+15 + 15 = 7 units
  • 2 units + $30 = 7 units
  • 5 units = $30
  • 1 unit = $6
  • Lily at first = 2 units = 2 × 6=6 = 12
  • Teaching Note: Use the "before and after" method. The difference between Mary and Lily is 5 units. After the transfer, they are equal, meaning Mary gave half the difference to Lily. So 5 units = 30,1unit=30, 1 unit = 6.
  • Marking Scheme: 1m for setting up the equation, 1m for solving for 1 unit (6),1mforLilysamount(6), 1m for Lily's amount (12), 1m for correct working.

20. Answer: Option A gives a lower price. It is $24 lower.

  • Option A: 20% off 2400=802400 = 80% of 2400 = 0.8 × 2400=2400 = 1920
  • Option B: First discount: 10% off 2400=902400 = 90% of 2400 = 0.9 × 2400=2400 = 2160
  • Second discount: 10% off 2160=902160 = 90% of 2160 = 0.9 × 2160=2160 = 1944
  • Difference = 19441944 - 1920 = $24
  • Option A is $24 lower.
  • Teaching Note: Two successive 10% discounts are NOT the same as one 20% discount. The second 10% is applied to a smaller amount, so the total discount is less than 20%.
  • Marking Scheme: 1m for Option A price (1920),1mforOptionBprice(1920), 1m for Option B price (1944), 1m for identifying Option A as lower, 1m for correct difference ($24).

End of Answer Key