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Primary 5 Mathematics Fractions Quiz

Free P5 Maths Fractions quiz, Ox AI version, with questions, answers, and syllabus-aligned practice for Singapore students.

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Primary 5 Mathematics AI Generated Generated by Ox Alpha Updated 2026-08-27

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Answers

Primary 5 Mathematics Quiz - Fractions: Answer Key

Answer 1.

(a) 5÷8=585 \div 8 = \frac{5}{8} (the division sign becomes a fraction bar). (b) 1120=55100=0.55\frac{11}{20} = \frac{55}{100} = 0.55 (multiply numerator and denominator by 5 to make hundredths).

Answer 2.

Use a common denominator of 24: 23=1624\frac{2}{3} = \frac{16}{24}, 58=1524\frac{5}{8} = \frac{15}{24}, 34=1824\frac{3}{4} = \frac{18}{24}. Since 1524<1624<1824\frac{15}{24} < \frac{16}{24} < \frac{18}{24}: 58<23<34\frac{5}{8} < \frac{2}{3} < \frac{3}{4}.

Answer 3.

34×89=3×84×9=2436\frac{3}{4} \times \frac{8}{9} = \frac{3 \times 8}{4 \times 9} = \frac{24}{36} Simplify by dividing top and bottom by 12: 2436=23\frac{24}{36} = \frac{2}{3}. (Marking note: 1 mark for correct product, 1 mark for simplest form.)

Answer 4.

Change to improper fractions: 214=942\frac{1}{4} = \frac{9}{4} and 156=1161\frac{5}{6} = \frac{11}{6}. Common denominator 12: 2712+2212=4912=4112\frac{27}{12} + \frac{22}{12} = \frac{49}{12} = 4\frac{1}{12}.

Answer 5.

325=(3×5)+25=1753\frac{2}{5} = \frac{(3 \times 5) + 2}{5} = \frac{17}{5}

Answer 6.

Common denominator 10: 610+710510=810\frac{6}{10} + \frac{7}{10} - \frac{5}{10} = \frac{8}{10} Simplify: 810=45\frac{8}{10} = \frac{4}{5}.

Answer 7.

Change to improper fractions: 123=531\frac{2}{3} = \frac{5}{3} and 225=1252\frac{2}{5} = \frac{12}{5}. 53×125=6015=4\frac{5}{3} \times \frac{12}{5} = \frac{60}{15} = 4

Answer 8.

Change to improper fraction: 312=723\frac{1}{2} = \frac{7}{2}. Dividing by 78\frac{7}{8} means multiplying by its reciprocal 87\frac{8}{7}: 72×87=5614=4\frac{7}{2} \times \frac{8}{7} = \frac{56}{14} = 4.

Answer 9.

"56\frac{5}{6} of 48" means 56×48\frac{5}{6} \times 48. Method: 48÷6=848 \div 6 = 8 (one part), then 8×5=408 \times 5 = 40.

Answer 10.

Work from left to right. Step 1: 213×34=73×34=2112=742\frac{1}{3} \times \frac{3}{4} = \frac{7}{3} \times \frac{3}{4} = \frac{21}{12} = \frac{7}{4}. Step 2: 74÷116=74×67=4228=32=112\frac{7}{4} \div 1\frac{1}{6} = \frac{7}{4} \times \frac{6}{7} = \frac{42}{28} = \frac{3}{2} = 1\frac{1}{2}.

Answer 11.

Flour used = 25\frac{2}{5} of 34\frac{3}{4} kg =25×34=620=310= \frac{2}{5} \times \frac{3}{4} = \frac{6}{20} = \frac{3}{10} kg. (Marking note: 1 mark for recognising "of" as multiply, 1 mark for product, 1 mark for simplification with unit.)

Answer 12.

Ribbon remaining = 558234=458228=238=2785\frac{5}{8} - 2\frac{3}{4} = \frac{45}{8} - \frac{22}{8} = \frac{23}{8} = 2\frac{7}{8} m.

Answer 13.

Water now = 1212+33541412\frac{1}{2} + 3\frac{3}{5} - 4\frac{1}{4}. Using common denominator 20: 25020+72208520=23720=111720\frac{250}{20} + \frac{72}{20} - \frac{85}{20} = \frac{237}{20} = 11\frac{17}{20} ℓ. (New-student tip: change each mixed number to twentieths first, then add and subtract the numerators.)

Answer 14.

Walking: 38×40=15\frac{3}{8} \times 40 = 15 pupils. Bus: 14×40=10\frac{1}{4} \times 40 = 10 pupils. Driven: 401510=1540 - 15 - 10 = 15 pupils.

Answer 15.

Sugar needed = 23×312=23×72=146=73=213\frac{2}{3} \times 3\frac{1}{2} = \frac{2}{3} \times \frac{7}{2} = \frac{14}{6} = \frac{7}{3} = 2\frac{1}{3} cups.

Answer 16.

Fraction spent: 14+25=520+820=1320\frac{1}{4} + \frac{2}{5} = \frac{5}{20} + \frac{8}{20} = \frac{13}{20}. Fraction left: 11320=7201 - \frac{13}{20} = \frac{7}{20} of his salary, worth 1050.Salary=1050. Salary = 1050 ÷ \frac{7}{20} = 1050 × \frac{20}{7} = 3000.(Check:rent3000. (Check: rent 750 + food 1200=1200 = 1950 spent; 30003000 − 1950 = $1050 left. ✓)

Answer 17.

(i) Number of pieces = 9÷34=9×43=129 \div \frac{3}{4} = 9 \times \frac{4}{3} = 12 pieces. (ii) Each piece gives 2 halves: 12×2=2412 \times 2 = 24 half-pieces.

Answer 18.

Capacity = 225=1252\frac{2}{5} = \frac{12}{5} ℓ. Water in jug = 58×125=6040=32=112\frac{5}{8} \times \frac{12}{5} = \frac{60}{40} = \frac{3}{2} = 1\frac{1}{2} ℓ. Water needed = 12532=24101510=910\frac{12}{5} - \frac{3}{2} = \frac{24}{10} - \frac{15}{10} = \frac{9}{10} ℓ.

Answer 19.

After Monday: remainder = 125=351 - \frac{2}{5} = \frac{3}{5} of the book. Tuesday: read 13\frac{1}{3} of the remainder = 13×35=15\frac{1}{3} \times \frac{3}{5} = \frac{1}{5} of the book. Left: 3515=25\frac{3}{5} - \frac{1}{5} = \frac{2}{5} of the book = 120 pages. Book = 120÷25=120×52=300120 \div \frac{2}{5} = 120 \times \frac{5}{2} = 300 pages.

Answer 20.

After morning: remainder = 137=471 - \frac{3}{7} = \frac{4}{7} of the apples. Afternoon sold: 58×47=2056=514\frac{5}{8} \times \frac{4}{7} = \frac{20}{56} = \frac{5}{14} of the apples. Left: 47514=814514=314\frac{4}{7} - \frac{5}{14} = \frac{8}{14} - \frac{5}{14} = \frac{3}{14} of the apples = 30 apples. At first: $30 \div \frac{3}{14}

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Primary 5 Mathematics Quiz - Fractions: Answer Key

Answer 1.

(a) 5÷8=585 \div 8 = \frac{5}{8} (the division sign becomes a fraction bar). (b) 1120=55100=0.55\frac{11}{20} = \frac{55}{100} = 0.55 (multiply numerator and denominator by 5 to make hundredths).

Answer 2.

Use a common denominator of 24: 23=1624\frac{2}{3} = \frac{16}{24}, 58=1524\frac{5}{8} = \frac{15}{24}, 34=1824\frac{3}{4} = \frac{18}{24}. Since 1524<1624<1824\frac{15}{24} < \frac{16}{24} < \frac{18}{24}: 58<23<34\frac{5}{8} < \frac{2}{3} < \frac{3}{4}.

Answer 3.

34×89=2436\frac{3}{4} \times \frac{8}{9} = \frac{24}{36} Simplify by dividing top and bottom by 12: 2436=23\frac{24}{36} = \frac{2}{3}. (Marking note: 1 mark for correct product, 1 mark for simplest form.)

Answer 4.

Change to improper fractions: 214=942\frac{1}{4} = \frac{9}{4} and 156=1161\frac{5}{6} = \frac{11}{6}. Common denominator 12: 2712+2212=4912=4112\frac{27}{12} + \frac{22}{12} = \frac{49}{12} = 4\frac{1}{12}.

Answer 5.

325=(3×5)+25=1753\frac{2}{5} = \frac{(3 \times 5) + 2}{5} = \frac{17}{5}

Answer 6.

Common denominator 10: 610+710510=810\frac{6}{10} + \frac{7}{10} - \frac{5}{10} = \frac{8}{10} Simplify: 810=45\frac{8}{10} = \frac{4}{5}.

Answer 7.

Change to improper fractions: 123=531\frac{2}{3} = \frac{5}{3} and 225=1252\frac{2}{5} = \frac{12}{5}. 53×125=6015=4\frac{5}{3} \times \frac{12}{5} = \frac{60}{15} = 4

Answer 8.

Change to improper fraction: 312=723\frac{1}{2} = \frac{7}{2}. Dividing by 78\frac{7}{8} means multiplying by its reciprocal 87\frac{8}{7}: 72×87=5614=4\frac{7}{2} \times \frac{8}{7} = \frac{56}{14} = 4.

Answer 9.

"56\frac{5}{6} of 48" means 56×48\frac{5}{6} \times 48. Method: 48÷6=848 \div 6 = 8 (one part), then 8×5=408 \times 5 = 40.

Answer 10.

Work from left to right. Step 1: 213×34=73×34=2112=742\frac{1}{3} \times \frac{3}{4} = \frac{7}{3} \times \frac{3}{4} = \frac{21}{12} = \frac{7}{4}. Step 2: 74÷116=74×67=4228=32=112\frac{7}{4} \div 1\frac{1}{6} = \frac{7}{4} \times \frac{6}{7} = \frac{42}{28} = \frac{3}{2} = 1\frac{1}{2}.

Answer 11.

Flour used = 25\frac{2}{5} of 34\frac{3}{4} kg =25×34=620=310= \frac{2}{5} \times \frac{3}{4} = \frac{6}{20} = \frac{3}{10} kg. (Marking note: 1 mark for recognising "of" as multiply, 1 mark for product, 1 mark for simplification with unit.)

Answer 12.

Ribbon remaining = 558234=458228=238=2785\frac{5}{8} - 2\frac{3}{4} = \frac{45}{8} - \frac{22}{8} = \frac{23}{8} = 2\frac{7}{8} m.

Answer 13.

Water now = 1212+33541412\frac{1}{2} + 3\frac{3}{5} - 4\frac{1}{4}. Using common denominator 20: 25020+72208520=23720=111720\frac{250}{20} + \frac{72}{20} - \frac{85}{20} = \frac{237}{20} = 11\frac{17}{20} ℓ. (New-student tip: change each mixed number to twentieths first, then add and subtract the numerators.)

Answer 14.

Walking: 38×40=15\frac{3}{8} \times 40 = 15 pupils. Bus: 14×40=10\frac{1}{4} \times 40 = 10 pupils. Driven: 401510=1540 - 15 - 10 = 15 pupils.

Answer 15.

Sugar needed = 23×312=23×72=146=73=213\frac{2}{3} \times 3\frac{1}{2} = \frac{2}{3} \times \frac{7}{2} = \frac{14}{6} = \frac{7}{3} = 2\frac{1}{3} cups.

Answer 16.

Fraction spent: 14+25=520+820=1320\frac{1}{4} + \frac{2}{5} = \frac{5}{20} + \frac{8}{20} = \frac{13}{20}. Fraction left: 11320=7201 - \frac{13}{20} = \frac{7}{20} of his salary, worth 1050.Salary=1050. Salary = 1050 ÷ \frac{7}{20} = 1050 × \frac{20}{7} = 3000.(Check:rent3000. (Check: rent 750 + food 1200=1200 = 1950 spent; 30003000 − 1950 = $1050 left. ✓)

Answer 17.

(i) Number of pieces = 9÷34=9×43=129 \div \frac{3}{4} = 9 \times \frac{4}{3} = 12 pieces. (ii) Each piece gives 2 halves: 12×2=2412 \times 2 = 24 half-pieces.

Answer 18.

Capacity = 225=1252\frac{2}{5} = \frac{12}{5} ℓ. Water in jug = 58×125=6040=32=112\frac{5}{8} \times \frac{12}{5} = \frac{60}{40} = \frac{3}{2} = 1\frac{1}{2} ℓ. Water needed = 12532=24101510=910\frac{12}{5} - \frac{3}{2} = \frac{24}{10} - \frac{15}{10} = \frac{9}{10} ℓ.

Answer 19.

After Monday: remainder = 125=351 - \frac{2}{5} = \frac{3}{5} of the book. Tuesday: read 13\frac{1}{3} of the remainder = 13×35=15\frac{1}{3} \times \frac{3}{5} = \frac{1}{5} of the book. Left: 3515=25\frac{3}{5} - \frac{1}{5} = \frac{2}{5} of the book = 120 pages. Book = 120÷25=120×52=300120 \div \frac{2}{5} = 120 \times \frac{5}{2} = 300 pages.

Answer 20.

After morning: remainder = 137=471 - \frac{3}{7} = \frac{4}{7} of the apples. Afternoon sold: 58×47=2056=514\frac{5}{8} \times \frac{4}{7} = \frac{20}{56} = \frac{5}{14} of the apples. Left: 47514=814514=314\frac{4}{7} - \frac{5}{14} = \frac{8}{14} - \frac{5}{14} = \frac{3}{14} of the apples = 30 apples. At first: 30÷314=30×143=14030 \div \frac{3}{14} = 30 \times \frac{14}{3} = 140 apples. (Check: morning sold 37×140=60\frac{3}{7} × 140 = 60; remaining 80; afternoon sold 58×80=50\frac{5}{8} × 80 = 50; left 8050=3080 − 50 = 30. ✓)

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