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Primary 5 Mathematics Geometry Quiz

Free P5 Maths Geometry quiz, Ox Exam version, with questions, answers, and syllabus-aligned practice for Singapore students.

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Primary 5 Mathematics From Real Exams Generated by Ox Alpha Updated 2026-08-27

Questions

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Answers

Primary 5 Mathematics Quiz - Geometry: Answer Key

Answer 1.

36014895=117360^\circ - 148^\circ - 95^\circ = 117^\circ. Correct option: (2).

Answer 2.

Vertically opposite angles are equal, so angle QTS=68QTS = 68^\circ. Correct option: (2).

Answer 3.

Two angles are equal (4040^\circ each), so two sides are equal: isosceles. Correct option: (2).

Answer 4.

Opposite angles of a rhombus are equal, so the answer is 6565^\circ. Correct option: (2).

Answer 5.

x=180112=68x = 180^\circ - 112^\circ = 68^\circ. Correct option: (3).

Answer 6.

Angles on a straight line add to 180180^\circ: x=1803590=55x = 180^\circ - 35^\circ - 90^\circ = 55^\circ.

Answer 7.

Base angles are equal. Each base angle =(18040)÷2=140÷2=70= (180^\circ - 40^\circ) \div 2 = 140^\circ \div 2 = 70^\circ.

Answer 8.

Adjacent angles of a parallelogram are supplementary and opposite angles are equal: angle Q=180115=65Q = 180^\circ - 115^\circ = 65^\circ; angle R=115R = 115^\circ; angle S=65S = 65^\circ.

Answer 9.

(a) Area =12×12×8=48= \frac{1}{2} \times 12 \times 8 = 48 cm2^2. (b) Height =(2×48)÷16=96÷16=6= (2 \times 48) \div 16 = 96 \div 16 = 6 cm.

Answer 10.

x+2x+3x+30=360x + 2x + 3x + 30 = 360, so 6x=3306x = 330 and x=55x = 55.

Answer 11.

(a) ABDCAB \parallel DC, so angle ADCADC and angle DABDAB are co-interior: ADC=18072=108ADC = 180^\circ - 72^\circ = 108^\circ. (b) Angle ABCABC and angle BCDBCD are co-interior: ABC=180115=65ABC = 180^\circ - 115^\circ = 65^\circ.

Answer 12.

Rectangle: 10×6=6010 \times 6 = 60 cm2^2. Triangle: 12×10×4=20\frac{1}{2} \times 10 \times 4 = 20 cm2^2. Total area =60+20=80= 60 + 20 = 80 cm2^2.

Answer 13.

(a) Volume =25×12×8=2400= 25 \times 12 \times 8 = 2400 cm3^3. (b) 24002400 cm3=2400^3 = 2\,\ell\,400 ml.

Answer 14.

(a) Angle BOD=55BOD = 55^\circ because vertically opposite angles are equal. (b) Angle AOD=18055=125AOD = 180^\circ - 55^\circ = 125^\circ (angles on the straight line ABAB add to 180180^\circ).

Answer 15.

(a) Volume =6×6×6=216= 6 \times 6 \times 6 = 216 cm3^3. (b) Small cube volume =2×2×2=8= 2 \times 2 \times 2 = 8 cm3^3; number =216÷8=27= 216 \div 8 = 27 small cubes.

Answer 16.

(a) x+3x+48=180x + 3x + 48 = 180, so 4x=1324x = 132 and x=33x = 33. (b) Angle D=3×33=99D = 3 \times 33 = 99^\circ; angle E=33E = 33^\circ. (c) By angles: obtuse triangle, since one angle (9999^\circ) is greater than 9090^\circ. By sides: scalene triangle, since all three angles are different, so all three sides are different.

Answer 17.

(a) Adjacent angles of a rhombus are supplementary: DAB=180104=76DAB = 180^\circ - 104^\circ = 76^\circ. (b) AB=ADAB = AD (all sides of a rhombus are equal), so triangle ABDABD is isosceles. Thus angle ADB=ADB = angle ABD=(18076)÷2=52ABD = (180^\circ - 76^\circ) \div 2 = 52^\circ. (c) Angle ABD=52ABD = 52^\circ (equal to angle ADBADB, shown in (b)).

Answer 18.

(a) Capacity =30×20×15=9000= 30 \times 20 \times 15 = 9000 cm3^3. (b) Water volume =30×20×10=6000= 30 \times 20 \times 10 = 6000 cm3=6^3 = 6\,\ell. (c) Water needed =90006000=3000= 9000 - 6000 = 3000 cm3^3.

Answer 19.

(a) Angle BOD=65BOD = 65^\circ (vertically opposite angle AOCAOC). (b) Angle BOC=18065=115BOC = 180^\circ - 65^\circ = 115^\circ (straight line CDCD), so angle EOB=11540=75EOB = 115^\circ - 40^\circ = 75^\circ. (c) No. Angle EOB=7590EOB = 75^\circ \neq 90^\circ (equivalently angle AOE=65+40=10590AOE = 65^\circ + 40^\circ = 105^\circ \neq 90^\circ), so OEOE is not perpendicular to ABAB.

Answer 20.

(a) Volume of water =40×25×18=18000= 40 \times 25 \times 18 = 18\,000 cm3^3. (b) Volume of cube =10×10×10=1000= 10 \times 10 \times 10 = 1000 cm3^3. (c) Total volume =18000+1000=19000= 18\,000 + 1000 = 19\,000 cm3^3; new depth =19000÷(40×25)=19000÷1000=19= 19\,000 \div (40 \times 25) = 19\,000 \div 1000 = 19 cm. (d) No. The new depth of 1919 cm is less than the tank height of 2020 cm, so the water does not overflow.