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Primary 5 Mathematics Practice Paper 5

Free P5 Maths Practice Paper 5, Ox AI version, with questions, answers, and syllabus-aligned practice for Singapore students.

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Primary 5 Mathematics AI Generated Generated by Ox Alpha Updated 2026-08-27

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TuitionGoWhere Practice Paper - Mathematics Primary 5 — Answer Key (Version 5 of 5)

TuitionGoWhere Practice Paper (AI) | Topic: Whole Numbers | Total Marks: 40

Note: Syllabus-aligned AI-generated answers; not sourced from past-year papers.


Section A (5 marks)

1. 300,000 [1] In 7,305,214 the digit 3 sits in the hundred-thousands place (millions: 7, hundred-thousands: 3, ten-thousands: 0, thousands: 5, hundreds: 2, tens: 1, ones: 4). Its value is 3 × 100,000 = 300,000. Common mistake: writing 3 (the digit) instead of its place value.

2. 9,620,005 [1] Millions group: 9 → "nine million". Thousands group: 620 → "six hundred and twenty thousand". Ones group: 005 → "and five". Combine: 9,620,005.

3. Five million, forty thousand and three hundred [1] Split into groups of three from the right: 5 | 040 | 300. Read each group with its place-name: five million, forty thousand, three hundred. The zero in the ten-thousands place means we skip straight from "million" to "forty thousand".

4. 4,000 thousands [1] 1,000 thousands = 1,000,000, so 4,000,000 ÷ 1,000


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# TuitionGoWhere Practice Paper - Mathematics Primary 5 — Answer Key (Version 5 of 5)

**TuitionGoWhere Practice Paper (AI)** | Topic: Whole Numbers | Total Marks: 40

*Note: Syllabus-aligned AI-generated answers; not sourced from past-year papers.*

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## Section A (5 marks)

**1.** **300,000** [1]
In 7,305,214 the digit 3 sits in the **hundred-thousands** place (millions: 7, hundred-thousands: 3, ten-thousands: 0, thousands: 5, hundreds: 2, tens: 1, ones: 4). Its value is 3 × 100,000 = 300,000.
*Common mistake:* writing 3 (the digit) instead of its place value.

**2.** **9,620,005** [1]
Millions group: 9 → "nine million". Thousands group: 620 → "six hundred and twenty thousand". Ones group: 005 → "and five". Combine: 9,620,005.

**3.** **Five million, forty thousand and three hundred** [1]
Split into groups of three from the right: 5 | 040 | 300. Read each group with its place-name: five million, forty thousand, three hundred. The zero in the ten-thousands place means we skip straight from "million" to "forty thousand".

**4.** **4,000 thousands** [1]
1,000 thousands = 1,000,000, so 4,000,000 ÷ 1,000 = 4,000. There are 4,000 thousands in 4,000,000.

**5.** **2,999,990** [1]
Subtracting across zeros requires borrowing: 3,000,000 − 10 = 2,999,990.
*Common mistake:* writing 2,900,000 or 2,999,000 by misaligning place values.

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## Section B (5 marks)

**6.** **4,580,000** [1]
Rounding to the nearest ten thousand: look at the thousands digit (2). Since 2 < 5, round down: 4,582,917 → 4,580,000.

**7.** **725** [1]
Dividing by 100 moves each digit two places to the right: 72,500 ÷ 100 = 725.

**8.** **North Dome** [1]
Round each capacity to the nearest thousand:
- National Stadium: 55,000 → 55,000
- East Stadium: 48,750 → 49,000
- West Arena: 52,300 → 52,000
- North Dome: 49,980 → **50,000** ✓

Only North Dome rounds to 50,000 (its hundreds digit 9 ≥ 5 rounds it up).

**9.** **162** [1]
Each term is multiplied by 3: 2 × 3 = 6, 6 × 3 = 18, 18 × 3 = 54, so 54 × 3 = **162**.

**10.** **32** [1]
Order of operations: multiply first — 4 × 6 = 24; then add — 8 + 24 = 32.
*Common mistake:* adding first (12 × 6 = 72).

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## Section C (10 marks)

**11.** **43** [2]
Order of operations (÷ and × before − and +):
36 − 12 ÷ 4 + 5 × 2
= 36 − 3 + 10
= 33 + 10
= **43**

**12.**
(a) **126,000** — 42 × 3 = 126, then append four zeros: 420 × 300 = 126,000.
(b) **70** — 56 ÷ 8 = 7; cancel two zeros from both numbers: 56,000 ÷ 800 = 70. [2]

**13.** **3,080,200** [2]
Place the digits: millions = 3, hundred-thousands = 0, ten-thousands = 8, thousands = 0, hundreds = 2, tens = 0, ones = 0 → 3,080,200.

**14.**
(a) **91,000** — 39,847 ≈ 40,000 and 51,209 ≈ 51,000 (nearest thousand); 40,000 + 51,000 = 91,000.
(b) **91,056** — 39,847 + 51,209 = 91,056. The estimate is close to the actual sum. [2]

**15.**
(a) **Rule:** Multiply the previous term by 2, then add 1 (each term = previous term × 2 + 1).
(b) **95** — 47 × 2 + 1 = 94 + 1 = 95. [2]

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## Section D (20 marks)

**16.** **There were 10,570 tins altogether.** [4]
Tins in filled cartons: 245 × 38 = 9,310
Working: 245 × 38 = 245 × 30 + 245 × 8 = 7,350 + 1,960 = 9,310
Total tins: 9,310 + 1,260 = **10,570 tins**

**17.** **Mr Tan had $5,000 at first.** [4]
Total spent: $1,850 + $675 = $2,525
Money at first: $2,525 + $2,475 = **$5,000**

**18.** **The bookshop sold 192 books altogether.** [4]
Model method: storybooks = 3 units, comic books = 1 unit.
Difference: 3 units − 1 unit = 2 units = 96
1 unit = 96 ÷ 2 = 48
Comic books = 48; storybooks = 3 × 48 = 144
Altogether: 48 + 144 = **192 books**

**19.** **Each donor gave $23.** [4]
Money per drive: $4,232 ÷ 8 = $529
Money per donor: $529 ÷ 23 = **$23**
Check: 23 × 23 = 529; 529 × 8 = 4,232 ✓

**20.** **The stall had 5,270 oranges at first.** [4]
Tuesday's sales: 1,250 − 350 = 900
Total sold over three days: 1,250 + 900 + 980 = 3,130
Oranges at first: 3,130 + 2,140 = **5,270 oranges**

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