Primary 5 Mathematics Practice Paper 5

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TuitionGoWhere Practice Paper - Mathematics Primary 5

TuitionGoWhere Practice Paper (AI)

Subject: Mathematics
Level: Primary 5
Paper: Practice Paper 5 (Version 5)
Duration: 1 hour 30 minutes
Total Marks: 100

Name: _________________________
Class: Primary 5 _______
Date: _________________________

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INSTRUCTIONS TO CANDIDATES

1. Do not open this booklet until you are told to do so.
2. Follow all instructions carefully.
3. Answer all questions.
4. Write your answers in this booklet.
5. The number of marks is given in brackets [ ] at the end of each question or part question.
6. The total marks for this paper is 100.
7. You may use a calculator for this paper.
8. Show all working clearly in the space provided.

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SECTION A: Multiple Choice Questions (20 marks)

Questions 1 to 10 carry 2 marks each. Choose the correct answer and write its number (1, 2, 3 or 4) in the brackets provided.

1. In the number 7,382,459, what is the value of the digit 8? [2]

(1) 80
(2) 800
(3) 8,000
(4) 80,000

Answer: (_____)

2. Round off 4,567,892 to the nearest ten thousand. [2]

(1) 4,560,000
(2) 4,570,000
(3) 4,600,000
(4) 5,000,000

Answer: (_____)

3. Which of the following numbers is the smallest? [2]

(1) 3,045,678
(2) 3,054,678
(3) 3,405,678
(4) 3,450,678

Answer: (_____)

4. What is the product of 3,456 and 28? [2]

(1) 96,768
(2) 96,868
(3) 97,768
(4) 97,868

Answer: (_____)

5. Divide 84,672 by 16. [2]

(1) 5,292
(2) 5,392
(3) 5,292
(4) 5,392

Answer: (_____)

6. Evaluate: 48 + 12 × 6 − 36 ÷ 4 [2]

(1) 108
(2) 117
(3) 120
(4) 126

Answer: (_____)

7. Find the value of (72 − 24) ÷ 8 + 5 × 6. [2]

(1) 36
(2) 39
(3) 42
(4) 45

Answer: (_____)

8. A factory produced 12,345 toys in January. It produced 3,456 more toys in February than in January. How many toys did the factory produce in February? [2]

(1) 8,889
(2) 15,801
(3) 15,791
(4) 15,811

Answer: (_____)

9. There are 4,320 apples. They are packed equally into 15 boxes. How many apples are there in each box? [2]

(1) 288
(2) 289
(3) 290
(4) 291

Answer: (_____)

10. Mr Tan had $8,500. He spent$\frac{2}{5}$of his money on a television and$\frac{1}{4}$ of the remainder on a refrigerator. How much money did he have left? [2]

(1) $2,550 (2)$3,060
(3) $3,825 (4)$5,100

Answer: (_____)

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SECTION B: Short Answer Questions (40 marks)

Questions 11 to 20 carry 2 marks each. Show your working clearly and write your answers in the spaces provided. For questions which require units, give your answers in the units stated.

11. Write 6,040,305 in words. [2]

Answer: _________________________________________________________________

12. Find the value of 5,600,000 + 340,000 + 7,000 + 500 + 30 + 4. [2]

Answer: _________________________________________________________________

13. Round off 2,748,593 to the nearest hundred thousand. [2]

Answer: _________________________________________________________________

14. Multiply 4,327 by 35. [2]

Answer: _________________________________________________________________

15. Divide 96,840 by 24. [2]

Answer: _________________________________________________________________

16. Evaluate: 84 ÷ 7 × 6 + 45 − 18 [2]

Answer: _________________________________________________________________

17. Find the value of 120 − (36 + 24) ÷ 5 × 4. [2]

Answer: _________________________________________________________________

18. A library has 12,450 English books and 8,760 Chinese books. How many more English books than Chinese books are there? [2]

Answer: _________________________________________________________________

19. Mrs Lim bought 25 packets of sweets. Each packet contained 36 sweets. She gave 450 sweets to her neighbours. How many sweets did she have left? [2]

Answer: _________________________________________________________________

20. A number when divided by 18 gives a quotient of 345 and a remainder of 7. What is the number? [2]

Answer: _________________________________________________________________

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SECTION C: Long Answer Questions (40 marks)

Questions 21 to 25 carry 8 marks each. Show your working clearly and write your answers in the spaces provided.

21. A school has 1,248 students. $\frac{3}{8}$ of the students are boys. The rest are girls. [8]

(a) How many boys are there in the school? [2]

(b) How many girls are there in the school? [2]

(c) If $\frac{2}{3}$ of the girls wear spectacles, how many girls wear spectacles? [2]

(d) What fraction of the total number of students are girls who wear spectacles? Express your answer in the simplest form. [2]

Answer:
(a) _________________________________________________________________
(b) _________________________________________________________________
(c) _________________________________________________________________
(d) _________________________________________________________________

22. Mr Ahmad had some money. He spent $\frac{3}{7}$ of it on a laptop and $\frac{1}{2}$ of the remainder on a printer. He had $480 left. [8]

(a) What fraction of his money did he spend on the printer? [2]

(b) How much money did Mr Ahmad have at first? [3]

(c) How much did the laptop cost? [3]

Answer:
(a) _________________________________________________________________
(b) _________________________________________________________________
(c) _________________________________________________________________

23. A factory produced 45,600 toys in 3 months. In the first month, it produced 12,800 toys. In the second month, it produced 3,400 more toys than in the first month. [8]

(a) How many toys did the factory produce in the second month? [2]

(b) How many toys did the factory produce in the third month? [3]

(c) What is the average number of toys produced per month? [3]

Answer:
(a) _________________________________________________________________
(b) _________________________________________________________________
(c) _________________________________________________________________

24. There are 3,240 marbles in Box A and Box B altogether. After 540 marbles are transferred from Box A to Box B, both boxes have the same number of marbles. [8]

(a) How many marbles are there in Box B after the transfer? [3]

(b) How many marbles were there in Box A at first? [3]

(c) How many more marbles were there in Box A than in Box B at first? [2]

Answer:
(a) _________________________________________________________________
(b) _________________________________________________________________
(c) _________________________________________________________________

25. A rectangular tank measures 60 cm by 40 cm by 30 cm. It is filled with water to a height of 18 cm. [8]

(a) What is the volume of water in the tank? [2]

(b) How many more litres of water are needed to fill the tank completely? [3]

(c) If water flows into the tank at a rate of 2 litres per minute, how long will it take to fill the tank completely from the current water level? Give your answer in minutes. [3]

Answer:
(a) _________________________________________________________________
(b) _________________________________________________________________
(c) _________________________________________________________________

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END OF PAPER

Total Marks: 100

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TuitionGoWhere Practice Paper - Mathematics Primary 5 (Answer Key)

Subject: Mathematics
Level: Primary 5
Paper: Practice Paper 5 (Version 5)
Total Marks: 100

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SECTION A: Multiple Choice Questions (20 marks)

1. Answer: (4) 80,000 [2]

Working:
The digit 8 is in the ten thousands place.
Value = 8 × 10,000 = 80,000

Key concept: Place value up to 10 million. The places from right to left are: ones, tens, hundreds, thousands, ten thousands, hundred thousands, millions.

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2. Answer: (2) 4,570,000 [2]

Working:
To round to the nearest ten thousand, look at the thousands digit (7).
Since 7 ≥ 5, round up the ten thousands digit (6 → 7).
4,567,892 → 4,570,000

Key concept: Rounding rules - if the digit to the right is 5 or more, round up; if less than 5, round down.

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3. Answer: (1) 3,045,678 [2]

Working:
Compare digits from left to right (millions place):
All have 3 millions.
Hundred thousands: 0, 0, 4, 4 → smallest is 0.
Ten thousands: 4, 5 → smallest is 4.
So 3,045,678 is the smallest.

Key concept: Compare numbers by place value starting from the highest place.

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4. Answer: (1) 96,768 [2]

Working:
3,456 × 28
= 3,456 × (20 + 8)
= 3,456 × 20 + 3,456 × 8
= 69,120 + 27,648
= 96,768

Key concept: Multiplication by a 2-digit number using distributive property.

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5. Answer: (1) 5,292 [2]

Working:
84,672 ÷ 16
= 84,672 ÷ 8 ÷ 2
= 10,584 ÷ 2
= 5,292

Alternative: Long division
16 | 84,672
-80
46
-32
147
-144
32
-32
0
Answer: 5,292

Key concept: Division by 2-digit numbers. Can simplify by dividing by factors (16 = 8 × 2).

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6. Answer: (2) 117 [2]

Working:
48 + 12 × 6 − 36 ÷ 4
= 48 + 72 − 9 (Multiplication and division first, left to right)
= 120 − 9 (Addition and subtraction, left to right)
= 111

Wait, let me recalculate:
48 + 12 × 6 − 36 ÷ 4
= 48 + 72 − 9
= 120 − 9
= 111

But 111 is not an option. Let me check the options again: (1) 108, (2) 117, (3) 120, (4) 126

Let me re-evaluate: 12 × 6 = 72, 36 ÷ 4 = 9, 48 + 72 = 120, 120 − 9 = 111.

Hmm, 111 is not in the options. There might be an error in the question or options. Let me check if the expression was meant to be different.

If the expression was 48 + 12 × 6 − 36 ÷ 3 = 48 + 72 − 12 = 108 (option 1)
If the expression was 48 + 12 × 6 − 36 ÷ 2 = 48 + 72 − 18 = 102 (not an option)
If the expression was 48 + 12 × 5 − 36 ÷ 4 = 48 + 60 − 9 = 99 (not an option)

Actually, let me recalculate: 48 + 72 = 120, 120 − 9 = 111. None of the options match.

Correction for the answer key: The correct answer is 111, but it's not in the options. This appears to be an error in the question design. For the purpose of this answer key, I'll note the discrepancy.

Marking note: If this were a real exam, the question would be reviewed. Students who correctly apply BODMAS and get 111 should be awarded the marks.

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7. Answer: (2) 39 [2]

Working:
(72 − 24) ÷ 8 + 5 × 6
= 48 ÷ 8 + 5 × 6 (Brackets first)
= 6 + 30 (Division and multiplication, left to right)
= 36 (Addition)

Wait, 6 + 30 = 36, which is option (1), not (2).

Let me recalculate: 48 ÷ 8 = 6, 5 × 6 = 30, 6 + 30 = 36.

So the answer should be (1) 36, not (2) 39.

Correction: Answer: (1) 36

Key concept: Order of operations (BODMAS) - Brackets, Orders, Division/Multiplication (left to right), Addition/Subtraction (left to right).

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8. Answer: (2) 15,801 [2]

Working:
January: 12,345 toys
February: 12,345 + 3,456 = 15,801 toys

Key concept: Addition of whole numbers up to 10 million in word problems.

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9. Answer: (1) 288 [2]

Working:
4,320 ÷ 15
= 4,320 ÷ 5 ÷ 3
= 864 ÷ 3
= 288

Key concept: Division by 2-digit numbers. Can simplify by dividing by factors (15 = 5 × 3).

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10. Answer: (3) $3,825 [2]

Working:
Total money = $8,500 Spent on TV =$\frac{2}{5} \times 8,500 = 3,400$Remainder =$8,500 − 3,400 = 5,100$Spent on refrigerator =$\frac{1}{4} \times 5,100 = 1,275$Left =$5,100 − 1,275 = 3,825$

Alternative (fraction method):
Fraction spent on TV = $\frac{2}{5}$
Fraction of remainder spent on refrigerator = $\frac{1}{4} \times \frac{3}{5} = \frac{3}{20}$
Total fraction spent = $\frac{2}{5} + \frac{3}{20} = \frac{8}{20} + \frac{3}{20} = \frac{11}{20}$
Fraction left = $1 − \frac{11}{20} = \frac{9}{20}$
Amount left = $\frac{9}{20} \times 8,500 = 3,825$

Key concept: Fraction of a quantity, fraction of remainder, multi-step fraction problems.

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SECTION B: Short Answer Questions (40 marks)

11. Answer: Six million forty thousand three hundred five [2]

Marking:

• Correct words for millions: "Six million" [1]
• Correct words for thousands: "forty thousand" [0.5]
• Correct words for hundreds/tens/ones: "three hundred five" [0.5]
• Accept "Six million and forty thousand three hundred and five"
• Must not write "Six million forty thousand three hundred AND five" (the "and" before the last part is acceptable in British English)

Key concept: Reading and writing numbers up to 10 million in words.

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12. Answer: 5,947,534 [2]

Working:
5,600,000

• 340,000
• 7,000
• 500
• 30
• 4
  = 5,947,534

Key concept: Place value addition / expanded form to standard form.

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13. Answer: 2,700,000 [2]

Working:
To round to the nearest hundred thousand, look at the ten thousands digit (4).
Since 4 < 5, round down (keep hundred thousands digit as 7).
2,748,593 → 2,700,000

Key concept: Rounding to the nearest hundred thousand.

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14. Answer: 151,445 [2]

Working:
4,327 × 35
= 4,327 × (30 + 5)
= 4,327 × 30 + 4,327 × 5
= 129,810 + 21,635
= 151,445

Alternative (long multiplication):
4,327
× 35

21,635  (4,327 × 5)  

129,810 (4,327 × 30)

151,445

Key concept: Multiplication of 4-digit by 2-digit numbers.

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15. Answer: 4,035 [2]

Working:
96,840 ÷ 24
= 96,840 ÷ 8 ÷ 3
= 12,105 ÷ 3
= 4,035

Alternative (long division):
24 | 96,840
-96
08
-0
84
-72
120
-120
0
Answer: 4,035

Key concept: Division by 2-digit numbers using factor method or long division.

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16. Answer: 99 [2]

Working:
84 ÷ 7 × 6 + 45 − 18
= 12 × 6 + 45 − 18 (Division first)
= 72 + 45 − 18 (Multiplication)
= 117 − 18 (Addition)
= 99 (Subtraction)

Key concept: Order of operations (BODMAS) without brackets.

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17. Answer: 72 [2]

Working:
120 − (36 + 24) ÷ 5 × 4
= 120 − 60 ÷ 5 × 4 (Brackets first)
= 120 − 12 × 4 (Division)
= 120 − 48 (Multiplication)
= 72 (Subtraction)

Key concept: Order of operations with brackets.

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18. Answer: 3,690 [2]

Working:
12,450 − 8,760 = 3,690

Key concept: Subtraction of whole numbers in comparison word problems.

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19. Answer: 450 [2]

Working:
Total sweets = 25 × 36 = 900
Sweets left = 900 − 450 = 450

Key concept: Multi-step word problem involving multiplication and subtraction.

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20. Answer: 6,217 [2]

Working:
Number = Divisor × Quotient + Remainder
= 18 × 345 + 7
= 6,210 + 7
= 6,217

Key concept: Relationship between dividend, divisor, quotient, and remainder: Dividend = Divisor × Quotient + Remainder.

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SECTION C: Long Answer Questions (40 marks)

21. [8 marks]

(a) Number of boys = $\frac{3}{8} \times 1,248 = 468$ [2]

Working:
$\frac{3}{8} \times 1,248 = 3 \times 156 = 468$

Marking:

• Correct method (fraction × total) [1]
• Correct answer 468 [1]

(b) Number of girls = 1,248 − 468 = 780 [2]

Working:
Total − Boys = Girls
1,248 − 468 = 780

Alternative: $\frac{5}{8} \times 1,248 = 780$

Marking:

• Correct method [1]
• Correct answer 780 [1]

(c) Girls wearing spectacles = $\frac{2}{3} \times 780 = 520$ [2]

Working:
$\frac{2}{3} \times 780 = 2 \times 260 = 520$

Marking:

• Correct method (fraction × number of girls) [1]
• Correct answer 520 [1]

(d) Fraction = $\frac{520}{1,248} = \frac{5}{12}$ [2]

Working:
$\frac{520}{1,248} = \frac{520 \div 104}{1,248 \div 104} = \frac{5}{12}$

Alternative simplification:
$\frac{520}{1,248} = \frac{260}{624} = \frac{130}{312} = \frac{65}{156} = \frac{5}{12}$

Marking:

• Correct fraction formed (520/1248) [1]
• Correct simplification to 5/12 [1]

Key concepts: Fraction of a quantity, subtraction to find complement, fraction of a fraction, simplifying fractions.

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22. [8 marks]

(a) Fraction spent on printer = $\frac{1}{2} \times \frac{4}{7} = \frac{2}{7}$ [2]

Working:
Fraction spent on laptop = $\frac{3}{7}$
Remainder = $1 − \frac{3}{7} = \frac{4}{7}$
Fraction spent on printer = $\frac{1}{2} \times \frac{4}{7} = \frac{2}{7}$

Marking:

• Correct remainder fraction (4/7) [1]
• Correct multiplication and answer (2/7) [1]

(b) Let total money = $x$ [3]

Working:
Fraction left = $1 − \frac{3}{7} − \frac{2}{7} = \frac{2}{7}$
$\frac{2}{7} \times x = 480$
$x = 480 \div \frac{2}{7} = 480 \times \frac{7}{2} = 240 \times 7 = 1,680$

Check:
Laptop: $\frac{3}{7} \times 1,680 = 720$
Remainder: $1,680 − 720 = 960$
Printer: $\frac{1}{2} \times 960 = 480$
Left: $960 − 480 = 480$ ✓

Marking:

• Correct fraction left (2/7) [1]
• Correct equation setup [1]
• Correct answer $1,680 [1]

(c) Laptop cost = $\frac{3}{7} \times 1,680 = 720$ [3]

Working:
$\frac{3}{7} \times 1,680 = 3 \times 240 = 720$

Marking:

• Correct method (fraction × total) [1]
• Correct calculation [1]
• Correct answer $720 [1]

Key concepts: Fraction of remainder, working backwards from remainder, fraction addition/subtraction.

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23. [8 marks]

(a) Second month = 12,800 + 3,400 = 16,200 toys [2]

Working:
First month: 12,800
Second month: 12,800 + 3,400 = 16,200

Marking:

• Correct addition [1]
• Correct answer 16,200 [1]

(b) Third month = 45,600 − 12,800 − 16,200 = 16,600 toys [3]

Working:
Total = 45,600
First two months = 12,800 + 16,200 = 29,000
Third month = 45,600 − 29,000 = 16,600

Marking:

• Correct sum of first two months [1]
• Correct subtraction from total [1]
• Correct answer 16,600 [1]

(c) Average = 45,600 ÷ 3 = 15,200 toys per month [3]

Working:
Average = Total ÷ Number of months
= 45,600 ÷ 3 = 15,200

Marking:

• Correct formula (total ÷ 3) [1]
• Correct division [1]
• Correct answer 15,200 with units [1]

Key concepts: Multi-step word problem, "more than" comparison, average calculation.

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24. [8 marks]

(a) After transfer, both boxes have the same number. Total = 3,240. [3]

Working:
After transfer: Box A = Box B
Total = 3,240
Each box = 3,240 ÷ 2 = 1,620
Box B after transfer = 1,620

Marking:

• Understanding that after transfer, boxes are equal [1]
• Correct division by 2 [1]
• Correct answer 1,620 [1]

(b) Box A at first = Box A after transfer + 540 = 1,620 + 540 = 2,160 [3]

Working:
540 marbles transferred FROM Box A TO Box B.
So Box A at first = Box A after + 540 = 1,620 + 540 = 2,160

Check: Box B at first = 3,240 − 2,160 = 1,080
After transfer: Box A = 2,160 − 540 = 1,620, Box B = 1,080 + 540 = 1,620 ✓

Marking:

• Correct understanding of transfer direction [1]
• Correct addition of 540 [1]
• Correct answer 2,160 [1]

(c) Difference at first = 2,160 − 1,080 = 1,080 [2]

Working:
Box A at first = 2,160
Box B at first = 3,240 − 2,160 = 1,080
Difference = 2,160 − 1,080 = 1,080

Alternative: Difference = 2 × 540 = 1,080 (since transferring 540 equalises them, the original difference was twice the transfer amount)

Marking:

• Correct Box B at first [1]
• Correct difference [1]

Key concepts: Transfer problems, equalising quantities, working backwards from equal state.

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25. [8 marks]

(a) Volume of water = 60 × 40 × 18 = 43,200 cm³ [2]

Working:
Volume = Length × Breadth × Height of water
= 60 cm × 40 cm × 18 cm
= 43,200 cm³

Marking:

• Correct formula (L × B × H) [1]
• Correct answer 43,200 cm³ [1]

(b) Tank capacity = 60 × 40 × 30 = 72,000 cm³ [3]

Working:
Total volume = 60 × 40 × 30 = 72,000 cm³
Volume needed = 72,000 − 43,200 = 28,800 cm³
Convert to litres: 28,800 cm³ = 28.8 litres (since 1,000 cm³ = 1 litre)

Marking:

• Correct total volume [1]
• Correct volume needed [1]
• Correct conversion to litres (28.8 litres) [1]

(c) Time = 28.8 ÷ 2 = 14.4 minutes [3]

Working:
Water needed = 28.8 litres
Rate = 2 litres/minute
Time = Volume ÷ Rate = 28.8 ÷ 2 = 14.4 minutes

Marking:

• Correct formula (volume ÷ rate) [1]
• Correct division [1]
• Correct answer 14.4 minutes [1]

Key concepts: Volume of cuboid, unit conversion (cm³ to litres), rate problems (time = quantity ÷ rate).

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MARKING SUMMARY

Section	Questions	Marks per Question	Total Marks
A (MCQ)	1-10	2	20
B (Short Answer)	11-20	2	40
C (Long Answer)	21-25	8	40
Total	25		100

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COMMON MISTAKES TO WATCH FOR

1. Place value errors: Confusing ten thousands with hundred thousands, etc.
2. Rounding errors: Rounding to the wrong place value, or rounding down when should round up.
3. Order of operations: Doing addition before multiplication/division, or not following left-to-right for same-precedence operations.
4. Fraction of remainder: Forgetting to calculate the remainder first before taking the fraction.
5. Transfer problems: Adding to the wrong box, or not understanding that the total remains constant.
6. Unit conversion: Forgetting to convert cm³ to litres (÷ 1000), or converting incorrectly.
7. Average calculation: Dividing by the wrong number of items/months.
8. Simplifying fractions: Not simplifying to the simplest form, or incorrect simplification.

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END OF ANSWER KEY