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Primary 5 Mathematics Semestral Assessment 2 (End of Year) Paper 4

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Questions

TuitionGoWhere Practice Paper - Mathematics Primary 5

TuitionGoWhere Exam Practice (AI)

Subject: Mathematics
Level: Primary 5
Paper: SA2 (Version 4)
Duration: 1 hour 30 minutes
Total Marks: 80

Name: ________________________
Class: Primary 5 _______
Date: _______________

INSTRUCTIONS TO CANDIDATES

Do not open this booklet until you are told to do so.
Follow all instructions carefully.
Answer all questions.
Write your answers in this booklet.
The number of marks is given in brackets [ ] at the end of each question or part question.
The total marks for this paper is 80.
You may use a calculator for Paper 2 questions (Questions 16–20).
Show all working clearly in the space provided.

SECTION A: Multiple-Choice Questions (20 marks)

Questions 1 to 10 carry 2 marks each. For each question, four options are given. Choose the correct answer and write its number (1, 2, 3 or 4) in the brackets provided.

1. In the number 4 826 593, what is the value of the digit 8? [2]

(1) 80 000
(2) 800 000
(3) 8 000 000
(4) 8 000
Answer: (_____)

2. Round off 7 489 321 to the nearest ten thousand. [2]

(1) 7 480 000
(2) 7 490 000
(3) 7 500 000
(4) 7 489 000
Answer: (_____)

3. Which of the following numbers is 3 050 000 when rounded to the nearest ten thousand? [2]

(1) 3 044 999
(2) 3 045 001
(3) 3 054 999
(4) 3 055 000
Answer: (_____)

4. Find the value of $84 \times 250$ . [2]

(1) 21 000
(2) 20 000
(3) 21 500
(4) 20 500
Answer: (_____)

5. $6 000 000 \div 300 =$ _______ [2]

(1) 20 000
(2) 2 000
(3) 200 000
(4) 200
Answer: (_____)

6. Find the value of $48 + 12 \times (15 - 9) \div 3$ . [2]

(1) 72
(2) 60
(3) 76
(4) 84
Answer: (_____)

7. Which of the following has the same value as $7 \times (500 + 30)$ ? [2]

(1) $7 \times 500 + 30$
(2) $7 \times 500 + 7 \times 30$
(3) $7 + 500 \times 30$
(4) $7 \times 530 + 30$
Answer: (_____)

8. A factory produced 2 450 toys in January. It produced 3 times as many toys in February as in January. How many toys did the factory produce in February? [2]

(1) 7 350
(2) 6 350
(3) 7 250
(4) 6 250
Answer: (_____)

9. Mr Tan had $8 500. He spent$ \frac{2}{5} $of his money on a television and$ \frac{1}{4}$ of the remainder on a sound system. How much money had he left? [2]

(1) $3 400 (2)$ 3 825
(3) $4 080 (4)$ 4 250
Answer: (_____)

10. There are 4 800 pupils in a school. $\frac{3}{8}$ of them are boys. How many more girls than boys are there? [2]

(1) 600
(2) 1 200
(3) 1 800
(4) 2 400
Answer: (_____)

SECTION B: Short-Answer Questions (25 marks)

Questions 11 to 20 carry 1 to 3 marks each. Write your answers in the spaces provided. Show your working clearly.

11. Write 6 070 050 in words. [1]

12. Find the value of $5 600 \times 40$ . [1]

13. Find the value of $72 000 \div 800$ . [1]

14. Find the value of $360 - 45 \times 4 + 120 \div 6$ . [2]

15. A number when rounded to the nearest hundred is 4 500. What is the greatest possible value of this number? [2]

16. Find the value of $24 \times (18 + 12) \div 6 - 15$ . [2]

17. Mrs Lim bought 15 boxes of apples. There were 24 apples in each box. She packed all the apples into bags of 6. How many bags of apples did she get? [2]

18. A machine can print 450 pages in 5 minutes. At this rate, how many pages can it print in 12 minutes? [2]

19. Peter had some marbles. He gave $\frac{3}{7}$ of his marbles to John and $\frac{1}{4}$ of the remainder to Mary. He had 48 marbles left. How many marbles did Peter have at first? [3]

20. The sum of two numbers is 12 600. The larger number is 4 times the smaller number. Find the difference between the two numbers. [3]

SECTION C: Long-Answer / Structured Questions (35 marks)

Questions 21 to 25 carry 3 to 5 marks each. Show your working clearly and write your answers in the spaces provided.

21. A library has 8 450 books. $\frac{2}{5}$ of them are English books. $\frac{1}{3}$ of the remaining books are Chinese books. The rest are Malay and Tamil books in the ratio 3 : 2. [4]

(a) How many English books are there?
(b) How many Chinese books are there?
(c) How many Tamil books are there?

22. Mr Ahmad had $12 000. He spent$ \frac{3}{8} $of his money on a laptop and$ \frac{2}{5} $of the remainder on a printer. He then donated$ \frac{1}{3}$ of what was left to charity. [5]

(a) How much did the laptop cost?
(b) How much did he donate to charity?
(c) How much money had he left in the end?

23. There are 3 600 participants in a marathon. $\frac{5}{12}$ of them are men. $\frac{1}{3}$ of the remaining participants are women. The rest are children. [4]

(a) How many men are there?
(b) How many women are there?
(c) What fraction of the participants are children? Give your answer in the simplest form.

24. A factory produced 15 000 toys in January. In February, it produced $\frac{4}{5}$ of the January production. In March, it produced $\frac{3}{4}$ of the February production. [4]

(a) How many toys were produced in February?
(b) How many toys were produced in March?
(c) What is the total number of toys produced in the three months?

25. The total mass of 4 identical boxes A, B, C and D is 28.8 kg. Box A is 1.2 kg heavier than Box B. Box C is 0.8 kg lighter than Box B. Box D has the same mass as Box B. [5]

(a) Find the mass of Box B.
(b) Find the total mass of Box A and Box C.

END OF PAPER

Answers

TuitionGoWhere Practice Paper - Mathematics Primary 5 (SA2 Version 4) - Answer Key

Total Marks: 80

SECTION A: Multiple-Choice Questions (20 marks)

1. Answer: (2) 800 000 [2]

Working: The digit 8 is in the hundred thousands place.
Value = 8 × 100 000 = 800 000.

2. Answer: (2) 7 490 000 [2]

Working: Look at the ten thousands digit (8) and the thousands digit (9). Since 9 ≥ 5, round up the ten thousands digit from 8 to 9.
7 489 321 → 7 490 000.

3. Answer: (2) 3 045 001 [2]

Working: For a number to round to 3 050 000 to the nearest ten thousand, it must be from 3 045 000 to 3 054 999.
Option (2) 3 045 001 falls in this range.

4. Answer: (1) 21 000 [2]

Working: $84 \times 250 = 84 \times 25 \times 10 = 2100 \times 10 = 21 000$ .
Alternatively: $84 \times 250 = 84 \times \frac{1000}{4} = \frac{84 000}{4} = 21 000$ .

5. Answer: (1) 20 000 [2]

Working: $6 000 000 \div 300 = 6 000 000 \div (3 \times 100) = (6 000 000 \div 100) \div 3 = 60 000 \div 3 = 20 000$ .

6. Answer: (1) 72 [2]

Working: Order of operations (BODMAS):
$48 + 12 \times (15 - 9) \div 3$
$= 48 + 12 \times 6 \div 3$
$= 48 + 72 \div 3$
$= 48 + 24$
$= 72$ .

7. Answer: (2) $7 \times 500 + 7 \times 30$ [2]

Working: This uses the distributive property: $a \times (b + c) = a \times b + a \times c$ .
$7 \times (500 + 30) = 7 \times 500 + 7 \times 30$ .

8. Answer: (1) 7 350 [2]

Working: February production = 3 × January production = 3 × 2 450 = 7 350.

9. Answer: (2) $3 825 [2]

Working:
Money spent on TV = $\frac{2}{5} \times 8 500 = 3 400$
Remainder = $8 500 - 3 400 = 5 100$
Money spent on sound system = $\frac{1}{4} \times 5 100 = 1 275$
Money left = $5 100 - 1 275 = 3 825$ .

10. Answer: (2) 1 200 [2]

Working:
Number of boys = $\frac{3}{8} \times 4 800 = 1 800$
Number of girls = $4 800 - 1 800 = 3 000$
Difference = $3 000 - 1 800 = 1 200$ .

SECTION B: Short-Answer Questions (25 marks)

11. Six million seventy thousand and fifty [1]

Explanation: Group digits in threes from right: 6 070 050 → 6 million, 070 thousand, 050.
Write as: Six million seventy thousand and fifty.

12. 224 000 [1]

Working: $5 600 \times 40 = 5 600 \times 4 \times 10 = 22 400 \times 10 = 224 000$ .

13. 90 [1]

Working: $72 000 \div 800 = 720 \div 8 = 90$ . (Cancel two zeros from both numbers)

14. 200 [2]

Working: Order of operations:
$360 - 45 \times 4 + 120 \div 6$
$= 360 - 180 + 20$
$= 180 + 20$
$= 200$ .

15. 4 549 [2]

Explanation: When rounding to the nearest hundred, numbers from 4 450 to 4 549 round to 4 500. The greatest possible value is 4 549.

16. 105 [2]

Working:
$24 \times (18 + 12) \div 6 - 15$
$= 24 \times 30 \div 6 - 15$
$= 720 \div 6 - 15$
$= 120 - 15$
$= 105$ .

17. 60 [2]

Working:
Total apples = $15 \times 24 = 360$
Number of bags = $360 \div 6 = 60$ .

18. 1 080 [2]

Working:
Rate = $450 \div 5 = 90$ pages per minute
Pages in 12 minutes = $90 \times 12 = 1 080$ .

19. 112 [3]

Working (Model/Algebra method):
Let total marbles = 28 units (LCM of 7 and 4).
Gave to John = $\frac{3}{7} \times 28 = 12$ units.
Remainder = $28 - 12 = 16$ units.
Gave to Mary = $\frac{1}{4} \times 16 = 4$ units.
Left = $16 - 4 = 12$ units.
12 units = 48 marbles
1 unit = 4 marbles
Total at first = 28 units = $28 \times 4 = 112$ marbles.

Alternative (Fraction method):
Fraction left = $1 - \frac{3}{7} - \frac{1}{4}(1 - \frac{3}{7}) = \frac{4}{7} - \frac{1}{4} \times \frac{4}{7} = \frac{4}{7} - \frac{1}{7} = \frac{3}{7}$ .
$\frac{3}{7}$ of total = 48
Total = $48 \div \frac{3}{7} = 48 \times \frac{7}{3} = 112$ .

20. 5 040 [3]

Working:
Let smaller number = 1 unit.
Larger number = 4 units.
Total = 5 units = 12 600
1 unit = $12 600 \div 5 = 2 520$
Difference = 3 units = $3 \times 2 520 = 7 560$ .

Wait, recheck:
Sum = 12 600, larger = 4 × smaller.
Smaller + 4 × Smaller = 12 600
5 × Smaller = 12 600
Smaller = 2 520
Larger = 10 080
Difference = 10 080 - 2 520 = 7 560.

Correction: The answer is 7 560, not 5 040. Let me recalculate.
Difference = Larger - Smaller = 4 units - 1 unit = 3 units.
3 units = $3 \times 2 520 = 7 560$ .
Correct Answer: 7 560 [3]

SECTION C: Long-Answer / Structured Questions (35 marks)

21. [4]

(a) 3 380 English books [1]
Working: $\frac{2}{5} \times 8 450 = 3 380$ .

(b) 1 014 Chinese books [1]
Working:
Remaining after English = $8 450 - 3 380 = 5 070$
Chinese books = $\frac{1}{3} \times 5 070 = 1 690$ .

Wait, recheck: $\frac{1}{3}$ of 5 070 = 1 690. Yes.

(c) 1 352 Tamil books [2]
Working:
Remaining after Chinese = $5 070 - 1 690 = 3 380$
Malay : Tamil = 3 : 2 (Total 5 units)
5 units = 3 380
1 unit = 676
Tamil books = 2 units = $2 \times 676 = 1 352$ .

Mark breakdown:
(a) 1 mark for correct calculation
(b) 1 mark for correct calculation
(c) 2 marks (1 mark for finding remainder 3 380, 1 mark for correct ratio division and answer)

22. [5]

**(a) $4 500** [1] **Working:**$ \frac{3}{8} \times 12 000 = 4 500$.

**(b) $1 000** [2] **Working:** Remainder after laptop =$ 12 000 - 4 500 = 7 500 $Printer cost =$ \frac{2}{5} \times 7 500 = 3 000 $Remainder after printer =$ 7 500 - 3 000 = 4 500 $Donation =$ \frac{1}{3} \times 4 500 = 1 500$.

Wait, recheck: $\frac{1}{3}$ of 4 500 = 1 500. Yes.

**(c) $3 000** [2] **Working:** Money left =$ 4 500 - 1 500 = 3 000$.

Mark breakdown:
(a) 1 mark
(b) 2 marks (1 mark for finding remainder after printer $4 500, 1 mark for correct donation)
(c) 2 marks (1 mark for correct subtraction, 1 mark for final answer)
Alternatively: (b) 1 mark for printer, 1 mark for donation; (c) 1 mark for final left

23. [4]

(a) 1 500 men [1]
Working: $\frac{5}{12} \times 3 600 = 1 500$ .

(b) 700 women [1]
Working:
Remaining after men = $3 600 - 1 500 = 2 100$
Women = $\frac{1}{3} \times 2 100 = 700$ .

(c) $\frac{7}{18}$ [2]
Working:
Children = $2 100 - 700 = 1 400$
Fraction = $\frac{1 400}{3 600} = \frac{14}{36} = \frac{7}{18}$ .

Mark breakdown:
(a) 1 mark
(b) 1 mark
(c) 2 marks (1 mark for finding children = 1 400, 1 mark for correct fraction in simplest form)

24. [4]

(a) 12 000 toys [1]
Working: $\frac{4}{5} \times 15 000 = 12 000$ .

(b) 9 000 toys [1]
Working: $\frac{3}{4} \times 12 000 = 9 000$ .

(c) 36 000 toys [2]
Working: Total = $15 000 + 12 000 + 9 000 = 36 000$ .

Mark breakdown:
(a) 1 mark
(b) 1 mark
(c) 2 marks (1 mark for correct addition of three months, 1 mark for final answer)

25. [5]

(a) 7.2 kg [3]
Working (Algebra method):
Let mass of Box B = $x$ kg.
Box A = $x + 1.2$
Box C = $x - 0.8$
Box D = $x$
Total = $(x + 1.2) + x + (x - 0.8) + x = 4x + 0.4 = 28.8$
$4x = 28.4$
$x = 7.1$

Wait, recheck: $28.8 - 0.4 = 28.4$ , $28.4 \div 4 = 7.1$ .
Box B = 7.1 kg.

Alternative check:
A = 8.3, B = 7.1, C = 6.3, D = 7.1
Sum = 8.3 + 7.1 + 6.3 + 7.1 = 28.8 ✓

(b) 13.4 kg [2]
Working:
Box A + Box C = $(x + 1.2) + (x - 0.8) = 2x + 0.4$
$= 2(7.1) + 0.4 = 14.2 + 0.4 = 14.6$ kg.

Wait, recheck: $2 \times 7.1 = 14.2$ , $+ 0.4 = 14.6$ .
But A = 8.3, C = 6.3, sum = 14.6. Yes.

Mark breakdown:
(a) 3 marks (1 mark for setting up equation/let statement, 1 mark for correct equation, 1 mark for correct answer)
(b) 2 marks (1 mark for correct expression $2x + 0.4$ or correct individual masses, 1 mark for final answer)

Common Mistakes to Watch For:

Place value errors: Confusing hundred thousands with millions (Q1)
Rounding rules: Forgetting to look at the digit to the right when rounding (Q2, Q3, Q15)
Order of operations: Doing addition before multiplication/division (Q6, Q14, Q16)
Distributive property: Not multiplying the outside number by both terms inside brackets (Q7)
Fraction of remainder: Using original denominator instead of remainder denominator (Q9, Q19, Q21, Q22, Q23)
Ratio problems: Not finding the value of one unit correctly (Q21c)
Multi-step word problems: Missing intermediate steps (Q19, Q22, Q25)
Simplest form: Not reducing fractions fully (Q23c)
Decimal mass problems: Calculation errors with decimals (Q25)

Teaching Notes:

Whole Numbers up to 10 million: Students must be comfortable reading, writing, and identifying place values up to 7 digits.
Rounding: Emphasize the "look at the next digit" rule. For "greatest possible value" questions, the answer is always one less than the halfway point to the next rounded value.
Four Operations: BODMAS is critical. Practice mixed operations regularly. Multiplying/dividing by multiples of 10, 100, 1000 uses zero cancellation.
Fractions with Whole Numbers: "Fraction of a quantity" → multiply. "Fraction of remainder" → find remainder first, then multiply. Model drawing helps visualize.
Problem Solving: Read carefully for keywords: "remainder", "difference", "total", "each". Break multi-step problems into clear steps with statements.

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