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Primary 5 Mathematics Semestral Assessment 2 (End of Year) Paper 2

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Questions

TuitionGoWhere Practice Paper - Mathematics Primary 5

TuitionGoWhere Exam Practice (AI)

Subject: Mathematics
Level: Primary 5
Paper: SA2 (Version 2)
Duration: 1 hour 30 minutes
Total Marks: 80

Name: ________________________
Class: Primary 5 ______
Date: _______________

Instructions to Candidates

Do not open this booklet until you are told to do so.
Follow all instructions carefully.
Answer all questions.
Write your answers in this booklet.
The number of marks is given in brackets [ ] at the end of each question or part question.
Show your working clearly in the space provided.
The use of calculators is not allowed.

Section A: Multiple-Choice Questions (20 marks)

Questions 1 to 10 carry 2 marks each. For each question, four options are given. Choose the correct answer and write its number (1, 2, 3 or 4) in the brackets provided.

1. In the number 4 826 391, what does the digit 8 stand for? [2]

(1) 80 000
(2) 800 000
(3) 8 000 000
(4) 80 000 000
( )

2. Round off 3 748 265 to the nearest ten thousand. [2]

(1) 3 740 000
(2) 3 750 000
(3) 3 700 000
(4) 3 800 000
( )

3. Which of the following is equal to 5 000 000 + 300 000 + 40 000 + 6 000 + 200 + 90 + 7? [2]

(1) 5 346 297
(2) 5 346 279
(3) 5 346 927
(4) 5 346 792
( )

4. Find the value of 72 × (45 + 15) ÷ 9. [2]

(1) 480
(2) 540
(3) 432
(4) 360
( )

5. A factory produced 8 450 toys in January. In February, it produced 3 times as many toys as in January. How many toys were produced in February? [2]

(1) 25 350
(2) 24 350
(3) 25 450
(4) 24 450
( )

6. What is the missing number in the box? [2]

$6 000 000 + \square + 40 000 + 3 000 + 200 + 50 + 8 = 6 743 258$ (1) 700 000
(2) 70 000
(3) 7 000
(4) 700
( )

7. Which of the following numbers when rounded to the nearest hundred gives 2 450 000? [2]

(1) 2 449 450
(2) 2 449 549
(3) 2 450 049
(4) 2 450 549
( )

8. Find the value of 8 000 000 − 2 345 678. [2]

(1) 5 654 322
(2) 5 654 321
(3) 5 654 422
(4) 5 654 421
( )

9. A number when divided by 8 gives a quotient of 125 000 and a remainder of 5. What is the number? [2]

(1) 1 000 005
(2) 1 000 000
(3) 1 000 050
(4) 1 000 500
( )

10. The sum of two numbers is 1 200 000. The difference between the two numbers is 300 000. What is the larger number? [2]

(1) 450 000
(2) 750 000
(3) 900 000
(4) 1 050 000
( )

Section B: Short Answer Questions (30 marks)

Questions 11 to 20 carry 2 marks each. Show your working clearly and write your answers in the spaces provided. For questions which require units, give your answers in the units stated.

11. Write 7 045 608 in words. [2]

12. Arrange the following numbers from the smallest to the greatest. [2]

$4 826 391,\quad 4 862 391,\quad 4 286 391,\quad 4 628 391$

Ans: _________________________________________________________________

13. Find the value of $5 600 000 \div 800$ . [2]

Ans: _______________________

14. A number is 4 500 000 when rounded to the nearest hundred thousand. What is the greatest possible value of this number? [2]

Ans: _______________________

15. Complete the number pattern. [2]

$2 500 000,\quad 2 450 000,\quad 2 400 000,\quad \square,\quad 2 300 000$

Ans: _______________________

16. Find the value of $48 \times 25 \times 4$ . [2]

Ans: _______________________

17. There are 3 456 789 people in City A. City B has 1 234 567 fewer people than City A. How many people are there in City B? [2]

Ans: _______________________

18. A box contains 2 500 packets of biscuits. Each packet has 12 biscuits. How many biscuits are there in the box? [2]

Ans: _______________________

19. Find the value of $6 000 000 - 48 \times 5000$ . [2]

Ans: _______________________

20. The product of two numbers is 720 000. One of the numbers is 800. What is the other number? [2]

Ans: _______________________

Section C: Structured / Long Answer Questions (30 marks)

Questions 21 to 25 carry 3 to 6 marks each. Show your working clearly and write your answers in the spaces provided.

21. A library has 4 567 890 books. [3]

(a) Round off the number of books to the nearest ten thousand.
(b) The library buys another 123 456 books. How many books does the library have now?
(c) If the books are packed into boxes of 500 books each, how many boxes are needed to pack all the books after the new purchase?

Answer: (a) _______________________
(b) _______________________
(c) _______________________

22. Mr Tan had $50 000. He spent$ \frac{2}{5} $of his money on a television set and$ \frac{1}{4}$ of the remainder on a refrigerator. [4]

(a) How much did he spend on the television set?
(b) How much did he spend on the refrigerator?
(c) How much money had he left?

Answer: (a) _______________________
(b) _______________________
(c) _______________________

23. A factory produces 1 250 toys each day. It operates 6 days a week. [4]

(a) How many toys does it produce in one week?
(b) How many toys does it produce in 4 weeks?
(c) If the toys are packed into cartons of 25 toys each, how many cartons are needed for the toys produced in 4 weeks?
(d) If each carton is sold for $120, how much money is collected from selling all the cartons?

Answer: (a) _______________________
(b) _______________________
(c) _______________________
(d) _______________________

24. The sum of three numbers A, B and C is 1 200 000. [5]

A is twice of B.
B is 3 times of C.
Find the value of A.

Answer: _______________________

25. A school has 2 450 students. [5]

$\frac{3}{7}$ of the students are boys.
$\frac{2}{5}$ of the girls wear spectacles.
$\frac{1}{3}$ of the boys wear spectacles.
How many students in the school wear spectacles?

Answer: _______________________

End of Paper

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Answers

TuitionGoWhere Practice Paper - Mathematics Primary 5 (SA2 Version 2) - Answer Key

Total Marks: 80

Section A: Multiple-Choice Questions (20 marks)

1. Answer: (2) 800 000 [2]

Working:
The number is 4 826 391.
Place values from left: 4 (millions), 8 (hundred thousands), 2 (ten thousands), 6 (thousands), 3 (hundreds), 9 (tens), 1 (ones).
Digit 8 is in the hundred thousands place → 8 × 100 000 = 800 000.

Key concept: In a 7-digit number, the second digit from the left is the hundred thousands place.

2. Answer: (2) 3 750 000 [2]

Working:
Number: 3 748 265
Ten thousands digit = 4
Next digit (thousands) = 8 ≥ 5, so round up the ten thousands digit from 4 to 5.
Digits after ten thousands become zeros.
→ 3 750 000

Key concept: When rounding to the nearest ten thousand, look at the thousands digit. If ≥ 5, round up.

3. Answer: (1) 5 346 297 [2]

Working:
Add by place value:
5 000 000

300 000 = 5 300 000
40 000 = 5 340 000
6 000 = 5 346 000
200 = 5 346 200
90 = 5 346 290
7 = 5 346 297

Key concept: Expanded form shows the value of each digit. Add from largest to smallest place value.

4. Answer: (1) 480 [2]

Working:
Order of operations (BODMAS): Brackets first, then Division/Multiplication (left to right).
45 + 15 = 60
72 × 60 = 4320
4320 ÷ 9 = 480

Alternative: 72 ÷ 9 = 8, then 8 × 60 = 480 (easier mental calculation).

Key concept: Brackets first. Multiplication and division have equal priority — work left to right.

5. Answer: (1) 25 350 [2]

Working:
January: 8 450 toys
February: 3 × 8 450 = 25 350 toys
Calculation: 8 000 × 3 = 24 000; 450 × 3 = 1 350; Total = 25 350

Key concept: "3 times as many" means multiply by 3.

6. Answer: (1) 700 000 [2]

Working:
Sum of known parts: 6 000 000 + 40 000 + 3 000 + 200 + 50 + 8 = 6 043 258
Target: 6 743 258
Missing = 6 743 258 − 6 043 258 = 700 000

Key concept: Find the missing addend by subtracting the sum of known parts from the total.

7. Answer: (3) 2 450 049 [2]

Working:
Rounding to nearest hundred: look at tens digit.
(1) 2 449 450 → tens digit 5, hundreds digit 4 → rounds to 2 449 500 ✗
(2) 2 449 549 → tens digit 4, hundreds digit 5 → rounds to 2 449 500 ✗
(3) 2 450 049 → tens digit 4, hundreds digit 0 → rounds to 2 450 000 ✓
(4) 2 450 549 → tens digit 4, hundreds digit 5 → rounds to 2 450 500 ✗

Key concept: To round to nearest hundred, check the tens digit. If tens < 5, round down (hundreds digit stays); if tens ≥ 5, round up.

8. Answer: (1) 5 654 322 [2]

Working:
8 000 000 − 2 345 678
= 5 654 322
Check: 5 654 322 + 2 345 678 = 8 000 000 ✓

Key concept: Subtraction with regrouping across zeros. Verify by adding back.

9. Answer: (1) 1 000 005 [2]

Working:
Division algorithm: Dividend = Divisor × Quotient + Remainder
Number = 8 × 125 000 + 5 = 1 000 000 + 5 = 1 000 005

Key concept: Dividend = Divisor × Quotient + Remainder. Remainder must be less than divisor (5 < 8 ✓).

10. Answer: (2) 750 000 [2]

Working:
Let larger = L, smaller = S
L + S = 1 200 000
L − S = 300 000
Add: 2L = 1 500 000 → L = 750 000
Check: S = 450 000; Sum = 1 200 000; Difference = 300 000 ✓

Key concept: Sum and difference problems: Larger = (Sum + Difference) ÷ 2.

Section B: Short Answer Questions (30 marks)

11. Answer: Seven million forty-five thousand six hundred and eight [2]

Marking:

Correct words for millions: "Seven million" [1]
Correct words for thousands and below: "forty-five thousand six hundred and eight" [1]
Accept "Seven million, forty-five thousand, six hundred and eight" (commas optional)
Common error: "Seven million four hundred fifty-six thousand eight" (wrong place value for 045)

Key concept: Read in groups of three digits from right: millions, thousands, ones. Zero in ten thousands place → "forty-five thousand" not "four hundred fifty thousand".

12. Answer: 4 286 391, 4 628 391, 4 826 391, 4 862 391 [2]

Working:
All numbers have 4 millions. Compare hundred thousands:
2 (smallest) → 4 286 391
6 → 4 628 391
8 → compare ten thousands: 2 vs 6 → 2 is smaller → 4 826 391, then 4 862 391

Key concept: Compare digits from left to right (highest place value first).

13. Answer: 7 000 [2]

Working:
5 600 000 ÷ 800
= 56 000 ÷ 8 (divide both by 100)
= 7 000
Check: 7 000 × 800 = 5 600 000 ✓

Key concept: Cancel zeros by dividing both numbers by the same power of 10.

14. Answer: 4 549 999 [2]

Working:
Rounded to nearest hundred thousand = 4 500 000
Range: 4 450 000 ≤ number < 4 550 000
Greatest possible = 4 549 999

Key concept: When rounding to nearest hundred thousand, the halfway point is 50 000. Numbers from 4 450 000 to 4 549 999 round to 4 500 000.

15. Answer: 2 350 000 [2]

Working:
Pattern decreases by 50 000 each step:
2 500 000 → 2 450 000 → 2 400 000 → 2 350 000 → 2 300 000

Key concept: Identify the common difference in a number pattern.

16. Answer: 4 800 [2]

Working:
48 × 25 × 4
= 48 × (25 × 4) (group 25 and 4 first)
= 48 × 100
= 4 800

Key concept: Use associative property to make multiplication easier. 25 × 4 = 100 is a known fact.

17. Answer: 2 222 222 [2]

Working:
City A: 3 456 789
City B: 3 456 789 − 1 234 567 = 2 222 222
Check: 2 222 222 + 1 234 567 = 3 456 789 ✓

Key concept: "Fewer than" means subtraction. Align place values carefully.

18. Answer: 30 000 [2]

Working:
2 500 × 12
= 2 500 × 10 + 2 500 × 2
= 25 000 + 5 000
= 30 000

Alternative: 2 500 × 12 = 25 × 100 × 12 = 25 × 1 200 = 30 000

Key concept: Break multiplication into friendly parts (distributive property).

19. Answer: 5 760 000 [2]

Working:
Order of operations: Multiplication before subtraction.
48 × 5 000 = 240 000
6 000 000 − 240 000 = 5 760 000

Key concept: BODMAS — multiplication before subtraction.

20. Answer: 900 [2]

Working:
Product = 720 000
One number = 800
Other number = 720 000 ÷ 800 = 7 200 ÷ 8 = 900
Check: 900 × 800 = 720 000 ✓

Key concept: Division is the inverse of multiplication. Cancel zeros: 720 000 ÷ 800 = 7 200 ÷ 8.

Section C: Structured / Long Answer Questions (30 marks)

21. [3 marks]

(a) 4 570 000 [1]
Working: 4 567 890 → ten thousands digit = 6, thousands digit = 7 ≥ 5 → round up to 4 570 000.

(b) 4 691 346 [1]
Working: 4 567 890 + 123 456 = 4 691 346.

(c) 9 383 [1]
Working: Total books = 4 691 346
Boxes needed = 4 691 346 ÷ 500 = 9 382.692 → 9 383 boxes (need 1 more for remainder)
Check: 9 382 × 500 = 4 691 000; remainder 346 → need 9 383rd box.

Marking notes:

(a) 1 mark for correct rounding.
(b) 1 mark for correct addition.
(c) 1 mark for correct division and rounding up (not truncating).
Common error in (c): giving 9 382 (forgetting the remainder needs a box).

22. [4 marks]

**(a) $20 000** [1] **Working:**$ \frac{2}{5} \times 50 000 = 20 000$

**(b) $7 500** [1] **Working:** Remainder after TV = 50 000 − 20 000 = 30 000 Refrigerator =$ \frac{1}{4} \times 30 000 = 7 500$

**(c) $22 500** [2] **Working:** Total spent = 20 000 + 7 500 = 27 500 Left = 50 000 − 27 500 = 22 500 **Alternative:** Fraction left =$ 1 - \frac{2}{5} - \frac{1}{4}(1 - \frac{2}{5}) = 1 - \frac{2}{5} - \frac{1}{4} \times \frac{3}{5} = 1 - \frac{2}{5} - \frac{3}{20} = \frac{20 - 8 - 3}{20} = \frac{9}{20}\frac{9}{20} \times 50 000 = 22 500$

Marking notes:

(a) 1 mark.
(b) 1 mark (must use remainder, not original amount).
(c) 2 marks (1 for method, 1 for answer). Accept follow-through from (a) and (b).
Common error: Calculating refrigerator as $\frac{1}{4} \times 50 000 = 12 500$ (using original instead of remainder).

23. [4 marks]

(a) 7 500 [1]
Working: 1 250 × 6 = 7 500 toys per week.

(b) 30 000 [1]
Working: 7 500 × 4 = 30 000 toys in 4 weeks.

(c) 1 200 [1]
Working: 30 000 ÷ 25 = 1 200 cartons.

**(d) $144 000** [1] **Working:** 1 200 ×$ 120 = $144 000.

Marking notes:

Each part 1 mark. Follow-through allowed (e.g., if (b) wrong but (c) correctly uses (b)'s answer).
Common error: In (d), multiplying 30 000 × 120 instead of 1 200 × 120.

24. [5 marks]

Answer: 720 000 [5]

Working (Algebraic method):
Let C = $x$
B = 3 $x$
A = 2 × B = 2 × 3 $x$ = 6 $x$
Sum: A + B + C = 6 $x$ + 3 $x$ + $x$ = 10 $x$ = 1 200 000
$x$ = 120 000
A = 6 $x$ = 6 × 120 000 = 720 000

Working (Unit/Bar model method):
C = 1 unit
B = 3 units
A = 6 units
Total = 10 units = 1 200 000
1 unit = 120 000
A = 6 units = 720 000

Check: A = 720 000, B = 360 000, C = 120 000. Sum = 1 200 000 ✓. A = 2×B ✓. B = 3×C ✓.

Marking notes:

2 marks for correct setup (ratio/units: A:B:C = 6:3:1 or equivalent).
2 marks for finding 1 unit = 120 000.
1 mark for final answer A = 720 000.
Accept any clear method (algebra, units, bar model).

25. [5 marks]

Answer: 882 [5]

Working:
Total students = 2 450
Boys = $\frac{3}{7} \times 2 450 = 1 050$
Girls = 2 450 − 1 050 = 1 400

Boys with spectacles = $\frac{1}{3} \times 1 050 = 350$
Girls with spectacles = $\frac{2}{5} \times 1 400 = 560$

Total with spectacles = 350 + 560 = 910

Wait, let me recalculate:
$\frac{3}{7} \times 2450 = 1050$ boys ✓
Girls = 2450 - 1050 = 1400 ✓
Boys with specs = $\frac{1}{3} \times 1050 = 350$ ✓
Girls with specs = $\frac{2}{5} \times 1400 = 560$ ✓
Total = 350 + 560 = 910

Correction: The answer is 910, not 882. Let me verify the question numbers again.

Actually, 2450 × 3/7 = 1050 boys. 2450 - 1050 = 1400 girls.
1/3 of 1050 = 350 boys with specs.
2/5 of 1400 = 560 girls with specs.
Total = 910.

Marking notes:

1 mark for finding number of boys (1 050).
1 mark for finding number of girls (1 400).
1 mark for boys with spectacles (350).
1 mark for girls with spectacles (560).
1 mark for total (910).
Follow-through allowed at each step.
Common error: Finding fraction of total instead of fraction of boys/girls separately.
Common error: Using wrong denominator (e.g., $\frac{2}{5}$ of total students).

End of Answer Key