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Primary 4 Mathematics Data Analysis Quiz

Free P4 Maths Data Analysis quiz, LongCat AI version, with questions, answers, and syllabus-aligned practice for Singapore students.

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Primary 4 Mathematics AI Generated Generated by LongCat 2.0 LLM Updated 2026-08-17

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Answers

Primary 4 Mathematics Quiz - Data Analysis

Answer Key


Section A: Tables and Data Interpretation

Question 1 (1 mark)

  • Answer: 21
  • Working: Aisha's fiction books = 12, Ben's fiction books = 9. Total = 12 + 9 = 21
  • Marking note: Award 1 mark for the correct answer. No working required for 1-mark questions.

Question 2 (1 mark)

  • Answer: Ben
  • Working: Comics column: Aisha = 15, Ben = 18, Chloe = 10, David = 12, Elena = 14. The highest value is 18 (Ben).
  • Marking note: Award 1 mark for "Ben" only.

Question 3 (1 mark)

  • Answer: 7
  • Working: David's non-fiction = 13, Chloe's non-fiction = 6. Difference = 13 − 6 = 7
  • Marking note: Award 1 mark for the correct answer.

Question 4 (2 marks)

  • Answer: 31
  • Working: Poetry column: Aisha = 5, Ben = 2, Chloe = 10, David = 8, Elena = 6. Total = 5 + 2 + 10 + 8 + 6 = 31
  • Marking note: Award 2 marks for correct answer with or without working. Award 1 mark if the student adds correctly but makes one arithmetic error (e.g., writes 30 or 32).

Question 5 (2 marks)

  • Answer: Yes, the statement is correct. Elena read 10 fiction books and 6 poetry books. 10 − 6 = 4.
  • Working: From the table: Elena's fiction = 10, Elena's poetry = 6. Difference = 10 − 6 = 4. Since the difference is 4, the statement is verified.
  • Marking note: Award 2 marks for correct verification with working. Award 1 mark for correct numbers extracted from the table but incomplete or missing subtraction.

Question 6 (2 marks)

  • Answer: 10.4 (or 10 if rounding to nearest whole number, but accept 10.4)
  • Working: Fiction books: Aisha = 12, Ben = 9, Chloe = 14, David = 7, Elena = 10. Sum = 12 + 9 + 14 + 7 + 10 = 52. Average = 52 ÷ 5 = 10.4
  • Marking note: Award 2 marks for correct answer. Award 1 mark for correct sum (52) but incorrect or missing division. Accept 10.4 or 10½.

Question 7 (3 marks)

(a) (1 mark)

  • Answer: 40
  • Working: 16 + 9 + 11 + 4 = 40
  • Marking note: Award 1 mark for correct total.

(b) (2 marks)

  • Answer: 40
  • Working: Original total for 5 students = 40 × 5 = 200. Farhan's total = 40. New total = 200 + 40 = 240. Number of students = 6. New average = 240 ÷ 6 = 40
  • Marking note: Award 2 marks for correct answer with working. Award 1 mark for correct method with arithmetic error, or for finding the new total (240) but not completing the division.

Question 8 (2 marks)

  • Answer: 9 units
  • Working: Ben read 18 comics. Scale: 1 unit = 2 books. Height = 18 ÷ 2 = 9 units
  • Marking note: Award 2 marks for correct answer. Award 1 mark for correct division setup (18 ÷ 2) with wrong final answer.

Section B: Line Graphs

Question 9 (1 mark)

  • Answer: 28°C
  • Working: From the graph, at 6 a.m. the temperature is at the lowest point, which is 28°C.
  • Marking note: Award 1 mark for 28°C. Accept 28 without unit for 1 mark.

Question 10 (1 mark)

  • Answer: 34°C
  • Working: From the graph, at 12 p.m. the temperature reaches the highest point, which is 34°C.
  • Marking note: Award 1 mark for 34°C. Accept 34 without unit for 1 mark.

Question 11 (1 mark)

  • Answer: 8 a.m. to 9 a.m. (or 9 a.m. to 10 a.m.)
  • Working: The steepest part of the graph (greatest increase) appears between 8 a.m. and 9 a.m. where the temperature rises from approximately 30°C to 32°C (a 2°C increase in one hour). Accept any one-hour interval where the increase is greatest based on the graph.
  • Marking note: Award 1 mark for identifying the correct time interval. Accept "8 a.m. to 9 a.m." or "9 a.m. to 10 a.m." based on graph reading.

Question 12 (2 marks)

  • Answer: 6°C
  • Working: Highest temperature = 34°C (at 12 p.m.). Lowest temperature = 28°C (at 6 a.m.). Difference = 34 − 28 = 6°C
  • Marking note: Award 2 marks for correct answer. Award 1 mark for identifying both highest and lowest values correctly but making a subtraction error.

Question 13 (1 mark)

  • Answer: 9 a.m. (or 11 a.m.)
  • Working: From the graph, the temperature line passes through 31°C at approximately 9 a.m. (on the way up) and again at approximately 11 a.m. (on the way down). Accept either answer.
  • Marking note: Award 1 mark for either 9 a.m. or 11 a.m.

Question 14 (2 marks)

  • Answer: Yes, the statement is accurate. The temperature at 6 a.m. was 28°C and it increased to 34°C at 12 p.m. The graph shows a steady upward trend from 6 a.m. to 12 p.m. with no decreases during this period.
  • Working: From the graph: 6 a.m. = 28°C, 7 a.m. = 29°C, 8 a.m. = 30°C, 9 a.m. = 31°C, 10 a.m. = 32°C, 11 a.m. = 33°C, 12 p.m. = 34°C. The temperature increases by approximately 1°C each hour, showing a steady rise.
  • Marking note: Award 2 marks for "Yes" with correct explanation referencing data from the graph. Award 1 mark for "Yes" with incomplete or vague explanation. Award 0 marks for "No" regardless of explanation.

Section C: Pie Charts and Data Reasoning

Question 15 (2 marks)

  • Answer: 15 students
  • Working: Oranges = 25% of 60 students. 25% × 60 = 25/100 × 60 = 15 students
  • Marking note: Award 2 marks for correct answer. Award 1 mark for correct method (25% × 60 or equivalent) with arithmetic error.

Question 16 (2 marks)

  • Answer: 9 students
  • Working: Apples = 30% of 60 = 18 students. Grapes = 15% of 60 = 9 students. Difference = 18 − 9 = 9 students
  • Marking note: Award 2 marks for correct answer. Award 1 mark for finding both values (18 and 9) but not subtracting, or for correct method with one arithmetic error.

Question 17 (2 marks)

  • Answer: 1/5
  • Working: Bananas = 20%. 20% = 20/100 = 1/5 (simplified by dividing numerator and denominator by 20)
  • Marking note: Award 2 marks for 1/5. Award 1 mark for 20/100 (not simplified) or 2/10 (partially simplified). Do not accept 20% as a final answer since the question asks for a fraction.

Question 18 (3 marks)

  • Answer: 15%
  • Working: Original durian = 10% of 60 = 6 students. New durian count = 6 + 5 = 11. New total students = 60 + 5 = 65. Percentage = 11/65 × 100 = 16.92...% ≈ 17% (rounded to nearest whole number)
  • Marking note: Award 3 marks for correct answer (17%) with complete working. Award 2 marks for correct method with minor arithmetic error. Award 1 mark for finding the original number of durian students (6) or the new total (65) but not completing the calculation. Note: 16.92% rounds to 17%, not 15%.

Correction: The answer is 17%, not 15%. The working above is correct: 11 ÷ 65 × 100 = 16.92% ≈ 17%.


Question 19 (4 marks total)

(a) (1 mark)

  • Answer: March
  • Working: Comparing all values: 52,100 is the highest. This is in March.
  • Marking note: Award 1 mark for "March".

(b) (1 mark)

  • Answer: 52,000
  • Working: 52,100 rounded to the nearest thousand: look at the hundreds digit (1). Since 1 < 5, round down. 52,100 ≈ 52,000
  • Marking note: Award 1 mark for 52,000.

(c) (2 marks)

  • Answer: 13,350
  • Working: Highest = 52,100 (March). Lowest = 38,750 (February). Difference = 52,100 − 38,750 = 13,350
  • Marking note: Award 2 marks for correct answer. Award 1 mark for identifying both highest and lowest values correctly but making a subtraction error.

Question 20 (5 marks total)

(a) (3 marks)

  • Answer: Bar graph with correct heights:
    • Reading: 10 students → 10 ÷ 2 = 5 units high
    • Sports: 15 students → 15 ÷ 2 = 7.5 units high
    • Music: 8 students → 8 ÷ 2 = 4 units high
    • Art: 7 students → 7 ÷ 2 = 3.5 units high
  • Marking note: Award 3 marks for all four bars correctly drawn with correct heights. Award 2 marks for three correct bars. Award 1 mark for two correct bars. Deduct 1 mark if the student uses an incorrect scale (e.g., 1 unit = 1 student instead of 1 unit = 2 students).

(b) (2 marks)

  • Answer: 37.5%
  • Working: Total students = 10 + 15 + 8 + 7 = 40. Sports = 15. Percentage = 15/40 × 100 = 37.5%
  • Marking note: Award 2 marks for correct answer. Award 1 mark for correct fraction (15/40) but not converting to percentage, or for correct method with arithmetic error. Accept 37.5% or 38% if student rounds.

Summary of Marks

QuestionMarksTopic Focus
11Reading tables, addition
21Reading tables, comparison
31Reading tables, subtraction
42Reading tables, column total
52Data verification, subtraction
62Average calculation
7(a)1Addition
7(b)2Average with new data, rounding
82Scale interpretation
91Reading line graphs
101Reading line graphs
111Interpreting trends in line graphs
122Finding range from line graph
131Reading intermediate values
142Evaluating statements using graph data
152Percentage of a total
162Percentage comparison
172Converting percentage to fraction
183Percentage change with new data
19(a)1Reading tables, comparison
19(b)1Rounding to nearest thousand
19(c)2Finding range from table data
20(a)3Drawing bar graph with scale
20(b)2Percentage calculation
Total30

This quiz was generated as syllabus-aligned practice content. It is not derived from past-year examination papers.