Primary 4 Mathematics Semestral Assessment 2 (End of Year) Paper 5

Primary 4 Mathematics Quiz - Whole Numbers - Answer Key (Version 5 of 5)

TuitionGoWhere Exam Practice (AI)

Subject: Mathematics | Level: Primary 4 | Paper: SA2 Practice Quiz - Whole Numbers | Total Marks: 50

Marking guidance: Award method marks (M) for correct steps even if the final answer is wrong. Award answer marks (A) only for fully correct values with correct units where required.

Section A: Multiple Choice (Questions 1-5)

Question 1 (2 marks)

Answer: D) 6,000

Teaching notes: In 86,405, name each position from the right: 5 ones, 0 tens, 4 hundreds, 6 thousands, 8 ten thousands. The digit 6 sits

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Primary 4 Mathematics Quiz - Whole Numbers - Answer Key (Version 5 of 5)

TuitionGoWhere Exam Practice (AI)

Subject: Mathematics | Level: Primary 4 | Paper: SA2 Practice Quiz - Whole Numbers | Total Marks: 50

Marking guidance: Award method marks (M) for correct steps even if the final answer is wrong. Award answer marks (A) only for fully correct values, with correct units where required.

Section A: Multiple Choice (Questions 1-5)

Question 1 (2 marks)

Answer: D) 6,000 Teaching note: In 86,405, read place values from the right: 5 ones, 0 tens, 4 hundreds, 6 thousands, 8 ten thousands. The digit 6 sits in the thousands place, so it stands for 6,000.

Question 2 (2 marks)

Answer: D) 49,900 Teaching note: Compare the thousands digits first. Both B and D have 49 thousands; then compare hundreds: 900 < 998, so 49,900 is the smallest.

Question 3 (2 marks)

Answer: D) 27,500 Teaching note: To round to the nearest hundred, look at the tens digit (8). Since 8 ≥ 5, round up: 27,483 ≈ 27,500.

Question 4 (2 marks)

Answer: C) 6 Teaching note: 54 ÷ 6 = 9 exactly, so 6 is a factor of 54. The others leave remainders (54 ÷ 4 = 13 r 2; 54 ÷ 5 = 10 r 4; 54 ÷ 7 = 7 r 5).

Question 5 (2 marks)

Answer: C) 79 Teaching note: The rule is ×2 then +1: 4→9→19→39→79. Check: 39 × 2 + 1 = 79.

Section B: Short Answer (Questions 6-10)

Question 6 (2 marks)

Answer: 68,040 Teaching note: Sixty-eight thousand = 68,000; add forty in the tens place: 68,040. Common error: writing 68,004 or 68,400.

Question 7 (2 marks)

Answer: 72,501, 72,105, 71,999, 71,099 Teaching note: Compare thousands first (72 > 71), then compare within each group using hundreds/tens/ones.

Question 8 (2 marks)

Answer: Any number from 33,500 to 34,499 (e.g., 34,200) Teaching note: Accept any whole number in this range. Numbers below 33,500 round down to 33,000; numbers from 34,500 round up to 35,000.

Question 9 (2 marks)

Answer: 1, 2, 5, 10 Teaching note: Factors of 20: 1, 2, 4, 5, 10, 20. Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30. The common ones are 1, 2, 5 and 10. Deduct if 1 is omitted.

Question 10 (2 marks)

Quotient: 651 Remainder: 6 Teaching note: 651 × 8 = 5,208; 5,214 − 5,208 = 6. Check that the remainder is smaller than the divisor (6 < 8).

Section C: Calculations and Patterns (Questions 11-15)

Question 11 (3 marks)

Working: 4,075 × 6 = (4,000 × 6) + (75 × 6) = 24,000 + 450 Answer: 24,450 Marks: M1 for setting out, M1 for partial products, A1 for 24,450.

Question 12 (3 marks)

Working: 245 × 38 = 245 × 30 + 245 × 8 = 7,350 + 1,960 Answer: 9,310 Marks: M1 for splitting into 30 and 8, M1 for both partial products, A1 for 9,310.

Question 13 (3 marks)

Working: Each number decreases by 4,500: 81,000 − 76,500 = 4,500; 76,500 − 72,000 = 4,500; 72,000 − 67,500 = 4,500. Continue: 67,500 − 4,500 = 63,000; 63,000 − 4,500 = 58,500. Answer: 63,000 and 58,500 Marks: M1 for identifying the rule (−4,500), M1 for applying it once correctly, A1 for both numbers.

Question 14 (3 marks)

Working: 29,468 ≈ 29,000 (hundreds digit 4 < 5, round down). 41,207 ≈ 41,000 (hundreds digit 2 < 5, round down). 29,000 + 41,000 = 70,000. Answer: 29,468 + 41,207 ≈ 70,000 Marks: M1 for both rounded values, M1 for adding them, A1 for the number sentence with ≈.

Question 15 (3 marks)

(a) Working: Place the largest digit first, then descending: 9, 8, 5, 2, 0. (a) Answer: 98,520 (b) Working: First digit cannot be 0, so start with the smallest non-zero digit (2), then place remaining digits ascending: 0, 5, 8, 9. (b) Answer: 20,589 Marks: A1 each part, plus M1 for showing correct ordering reasoning.

Section D: Word Problems (Questions 16-20)

Question 16 (3 marks)

Working: Total books received = 3,875 + 2,460 = 6,335 books Books not yet shelved = 6,335 − 1,190 = 5,145 books Answer statement: 5,145 books were not yet placed on the shelves. Marks: M1 for addition, M1 for subtraction, A1 for 5,145 with units and statement.

Question 17 (3 marks)

Working: Tins needed = 245 × 36 = 245 × 30 + 245 × 6 = 7,350 + 1,470 Answer statement: 8,820 tins of biscuits are needed to fill 36 cartons completely. Marks: M1 for choosing multiplication, M1 for correct computation, A1 for 8,820 tins with units and statement.

Question 18 (3 marks)

Working: 6,350 ÷ 7 = 907 remainder 1 Check: 907 × 7 = 6,349; 6,350 − 6,349 = 1 Answer statement: There are 907 stickers in each album, with 1 sticker left over. Marks: M1 for division set-up, M1 for quotient and remainder, A1 for both values with units and statement.

Question 19 (3 marks)

Working: The number must be a multiple of both 6 and 8, so find the least common multiple. Multiples of 6: 6, 12, 18, 24, ... Multiples of 8: 8, 16, 24, ... LCM = 24 Answer statement: The least number of beads Mei Ling can have is 24 beads. Marks: M1 for listing multiples or using LCM idea, M1 for identifying 24, A1 for 24 beads with units and statement.

Question 20 (3 marks)

Working: Seats in one hall = 26 × 32 = 832 seats Seats in 4 halls = 832 × 4 = 3,328 seats Empty seats = 3,328 − 2,850 = 478 seats Answer statement: 478 seats were empty on Friday night. Marks: M1 for finding total seats, M1 for subtracting tickets sold, A1 for 478 seats with units and statement.

END OF ANSWER KEY

Reminder for markers: For Section D, withhold the final A mark if units are missing or the answer statement is absent, even when the numerical value is correct.