From Real Exams Exam Paper

Primary 4 Mathematics Semestral Assessment 2 (End of Year) Paper 3

Free Exam-Derived Owl Alpha Primary 4 Mathematics Semestral Assessment 2 (End of Year) Paper 3 practice paper with questions and answers for Singapore students. This page is rendered as a direct URL so the questions and answers can be discovered without pressing in-page buttons.

These static practice materials are generated from the site's syllabus and paper-generation workflow, with source and model context shown so students and parents can evaluate the material before use.

Primary 4 Mathematics From Real Exams Generated by Owl Alpha Updated 2026-06-03

Questions

<!-- TuitionGoWhere generation metadata: stage=3-1; model=openrouter/owl-alpha; model_label=Owl Alpha; generated=2026-06-02; Sources: Stage 2-1 real exam-derived templates and Stage 2-2 exam-enriched syllabus. -->

TuitionGoWhere Practice Paper - Mathematics Primary 4

TuitionGoWhere Exam Practice (AI)

Subject:Mathematics
Level:Primary 4
Paper:SA2 (Version 3 of 5)
Duration:1 h 30 min
Total Marks:60

Name: ________________________ Class: ______________ Date: ______________


Instructions

  1. Answer all questions.
  2. Write your answers in the spaces provided.
  3. Show your working clearly in the space provided for Section C. Marks will be awarded for correct working.
  4. Do not use a calculator.

Section A: Multiple Choice (10 marks)

Choose the correct answer and write its letter in the brackets provided. Each question carries 2 marks.

1. In the number 63,814, what does the digit 3 stand for? ( )

(A) 3 (B) 30 (C) 300 (D) 3 000

2. Round 45 726 to the nearest thousand. ( )

(A) 45 000 (B) 45 700 (C) 46 000 (D) 50 000

3. Which of the following numbers is divisible by both 3 and 4? ( )

(A) 18 (B) 24 (C) 27 (D) 32

4. Find the value of 84÷6+1584 \div 6 + 15. ( )

(A) 14 (B) 29 (C) 99 (D) 129

5. A number when rounded to the nearest hundred is 8 400. Which of the following could be the number? ( )

(A) 8 349 (B) 8 395 (C) 8 449 (D) 8 460

6. Mrs Tan bought 8 packets of cookies. Each packet contained 25 cookies. She gave 45 cookies to her neighbours. How many cookies did she have left? ( )

(A) 155 (B) 200 (C) 245 (D) 445

7. What is the sum of the first two common multiples of 4 and 6? ( )

(A) 12 (B) 24 (C) 36 (D) 48

8. 6×40+6×8=6 \times 40 + 6 \times 8 = ? ( )

(A) 48 (B) 240 (C) 288 (D) 336

9. A factory produces 1 250 bottles of juice each day. How many bottles of juice does the factory produce in 6 days? ( )

(A) 1 256 (B) 6 250 (C) 7 500 (D) 12 500

10. Mr Lim had 9 450 stamps. He packed them equally into 9 albums. How many stamps were in each album? ( )

(A) 15 (B) 105 (C) 1 005 (D) 1 050


Section B: Short Answer (20 marks)

Write your answers in the spaces provided. Each question carries 2 marks.

11. Write forty-two thousand and five in figures.

Ans: ____________

12. Arrange the following numbers from smallest to largest.

38 204 , 38 024 , 32 804

Ans: ____________, ____________, ____________

13. Find the product of 136 and 7.

Ans: ____________

14. Find the quotient and remainder when 5 678 is divided by 8.

Quotient: ____________ Remainder: ____________

15. Find the value of 9264÷892 - 64 \div 8.

Ans: ____________

16. List all the factors of 36.

Ans: ____________

17. What is the first common multiple of 5 and 8 that is greater than 50?

Ans: ____________

18. The digit 7 in 57 293 is replaced by the digit 2 to form a new number. What is the difference between the two numbers?

Ans: ____________

19. Round 29 504 to the nearest hundred.

Ans: ____________

20. A fruiterer had 15 000 apples. He sold 6 780 apples in the morning and 4 390 apples in the afternoon. How many apples were left?

Ans: ____________


Section C: Word Problems (30 marks)

Show your working clearly and write your answers in the spaces provided. Each question carries the number of marks shown in the brackets.

21. A library had 24 500 books. The librarians bought 3 680 more books and then donated 1 925 old books to a community centre. How many books did the library have in the end? [3 marks]

Working:

Ans: ____________

22. A machine wraps 235 sweets every minute. How many sweets does the machine wrap in 45 minutes? [3 marks]

Working:

Ans: ____________

23. 4 identical chairs cost $468. How much do 9 such chairs cost? [3 marks]

Working:

Ans: ____________

24. There are 1 890 passengers on a train. At the first station, 456 passengers alighted and 327 passengers boarded the train. At the second station, 589 passengers alighted and 145 boarded the train. How many passengers are on the train now? [4 marks]

Working:

Ans: ____________

25. A farmer collected 9 450 eggs. He packed all the eggs into boxes of 6.

(a) How many boxes did he use? [2 marks]

(b) How many eggs were left over? [1 mark]

Working:

Ans (a): ____________ Ans (b): ____________

26. Ben is thinking of a number. When he divides the number by 7, the quotient is 124 and the remainder is 5. What is the number? [3 marks]

Working:

Ans: ____________

27. A school hall has 28 rows of chairs. There are 36 chairs in each row. 645 chairs are occupied. How many chairs are not occupied? [3 marks]

Working:

Ans: ____________

28. A shop owner bought 15 crates of oranges. Each crate contained 120 oranges. He threw away 84 rotten oranges and packed the remaining oranges equally into bags of 8. How many bags did he pack? [4 marks]

Working:

Ans: ____________

29. The table below shows the number of visitors to a museum over four days.

DayNumber of Visitors
Monday2 450
Tuesday1 875
Wednesday3 120
Thursday2 555

(a) How many visitors were there altogether over the four days? [2 marks]

(b) The museum wants to reach a total of 12 000 visitors for the week. How many more visitors must visit on Friday and Saturday combined? [2 marks]

Working:

Ans (a): ____________ Ans (b): ____________

30. Raju had $5 000. He bought a television for $1 295 and a sound system for $868. He then bought 3 identical tables for $417 each. How much money did Raju have left? [4 marks]

Working:

Ans: ____________

Answers

<!-- TuitionGoWhere generation metadata: stage=3-1; model=openrouter/owl-alpha; model_label=Owl Alpha; generated=2026-06-02; Sources: Stage 2-1 real exam-derived templates and Stage 2-2 exam-enriched syllabus. -->

TuitionGoWhere Practice Paper - Mathematics Primary 4 - Answer Key

SA2 (Version 3 of 5)


Section A: Multiple Choice (10 marks)

QnAnswerMarksWorking / Explanation
1D2In 63 814, the digit 3 is in the thousands place. Value = 3 × 1 000 = 3 000. Common mistake: Confusing "digit" (3) with "value" (3 000).
2C245 726: The digit in the hundreds place is 7. Since 7 ≥ 5, round up. 45 726 ≈ 46 000.
3B218 ÷ 4 = 4 R2 (No). 24 ÷ 3 = 8, 24 ÷ 4 = 6 (Yes). 27 ÷ 4 = 6 R3 (No). 32 ÷ 3 = 10 R2 (No).
4B2Division before addition: 84 ÷ 6 = 14. Then 14 + 15 = 29. Common mistake: Calculating left-to-right (84 ÷ 21 = 4).
5C2Rounding to nearest hundred: 8 349 → 8 300. 8 395 → 8 400. 8 449 → 8 400. 8 460 → 8 500. Both 8 395 and 8 449 round to 8 400. Only C is an option.
6A28 × 25 = 200. 200 – 45 = 155.
7C2Multiples of 4: 4, 8, 12, 16, 20, 24... Multiples of 6: 6, 12, 18, 24... First two common multiples: 12 and 24. Sum = 12 + 24 = 36.
8C2Using distributive law: 6 × 40 + 6 × 8 = 6 × (40 + 8) = 6 × 48 = 288. Or: 240 + 48 = 288.
9C21 250 × 6 = 7 500.
10D29 450 ÷ 9 = 1 050.

Section B: Short Answer (20 marks)

QnAnswerMarksWorking / Explanation
1142 0052Forty-two thousand = 42 000. Five = 5. Combine: 42 005.
1232 804, 38 024, 38 2042Compare ten-thousands (3), then thousands (2 vs 8). 32 804 is smallest. Then compare hundreds: 0 vs 2. 38 024 < 38 204.
139522136 × 7 = 952.
14Quotient: 709, Remainder: 625 678 ÷ 8: 8 × 709 = 5 672. 5 678 – 5 672 = 6.
15842Division before subtraction: 64 ÷ 8 = 8. Then 92 – 8 = 84. Common mistake: Left-to-right (92 – 64 = 28, 28 ÷ 8 = 3.5).
161, 2, 3, 4, 6, 9, 12, 18, 362Find pairs: 1×36, 2×18, 3×12, 4×9, 6×6. List in order.
17802Multiples of 5: 5, 10, 15... 50, 55, 60, 65, 70, 75, 80... Multiples of 8: 8, 16, 24... 40, 48, 56, 64, 72, 80... First common multiple > 50 is 80.
1850 0002Original: 57 293. New: 52 293. Difference = 57 293 – 52 293 = 5 000. Or: The digit 7 is in the ten thousands place (70 000). Replaced by 2 (20 000). Difference = 70 000 – 20 000 = 50 000.
1929 500229 504: The digit in the tens place is 0. Since 0 < 5, round down. 29 504 ≈ 29 500.
203 830215 000 – 6 780 = 8 220. 8 220 – 4 390 = 3 830.

Section C: Word Problems (30 marks)

21. [3 marks]

  • Books after buying: 24 500 + 3 680 = 28 180
  • Books after donating: 28 180 – 1 925 = 26 255
  • Answer: 26 255
  • M1 for correct addition, M1 for correct subtraction, A1 for final answer.

22. [3 marks]

  • 235 × 45
  • 235 × 40 = 9 400
  • 235 × 5 = 1 175
  • 9 400 + 1 175 = 10 575
  • Answer: 10 575
  • M2 for correct multiplication, A1 for final answer.

23. [3 marks]

  • Cost of 1 chair: $468 ÷ 4 = $117
  • Cost of 9 chairs: $117 × 9 = $1 053
  • Answer: $1 053
  • M1 for finding unit cost, M1 for multiplying by 9, A1 for final answer.

24. [4 marks]

  • After first station: 1 890 – 456 + 327 = 1 761
  • After second station: 1 761 – 589 + 145 = 1 317
  • Answer: 1 317
  • M1 for first alight/board, M1 for first station total, M1 for second alight/board, A1 for final answer. Alternative: Net change = –456 + 327 – 589 + 145 = –573. 1 890 – 573 = 1 317.

25. [3 marks]

  • (a) 9 450 ÷ 6 = 1 575. Answer (a): 1 575 boxes [2 marks: M1 for division, A1 for answer]
  • (b) 1 575 × 6 = 9 450. Remainder = 0. Answer (b): 0 eggs [1 mark]
  • Common mistake: Students may expect a non-zero remainder. Check: 9 450 is divisible by 6.

26. [3 marks]

  • Number = (Quotient × Divisor) + Remainder
  • Number = (124 × 7) + 5
  • 124 × 7 = 868
  • 868 + 5 = 873
  • Answer: 873
  • M1 for correct formula, M1 for multiplication, A1 for final answer. Common mistake: Forgetting to add the remainder.

27. [3 marks]

  • Total chairs: 28 × 36 = 1 008
  • Unoccupied chairs: 1 008 – 645 = 363
  • Answer: 363
  • M1 for finding total chairs, M1 for subtraction, A1 for final answer.

28. [4 marks]

  • Total oranges bought: 15 × 120 = 1 800
  • Good oranges: 1 800 – 84 = 1 716
  • Number of bags: 1 716 ÷ 8 = 214
  • Answer: 214 bags
  • M1 for total oranges, M1 for subtracting rotten oranges, M1 for dividing by 8, A1 for final answer.

29. [4 marks]

  • (a) Total visitors: 2 450 + 1 875 + 3 120 + 2 555 = 10 000 [2 marks: M1 for adding all four values, A1 for total]
    • Answer (a): 10 000
  • (b) Visitors still needed: 12 000 – 10 000 = 2 000 [2 marks: M1 for subtraction, A1 for answer]
    • Answer (b): 2 000

30. [4 marks]

  • Total spent on TV and sound system: $1 295 + $868 = $2 163
  • Total spent on 3 tables: $417 × 3 = $1 251
  • Total spent altogether: $2 163 + $1 251 = $3 414
  • Money left: $5 000 – $3 414 = $1 586
  • Answer: $1 586
  • M1 for adding TV and sound system, M1 for cost of 3 tables, M1 for finding total spent, A1 for final answer. Alternative: Subtract sequentially from 5 000.