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Primary 4 Mathematics Semestral Assessment 2 (End of Year) Paper 3
Free P4 Maths SA2 Paper 3, LongCat Exam version, with questions, answers, and syllabus-aligned practice for Singapore students.
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TuitionGoWhere Practice Paper - Mathematics Primary 4 - Answer Key
SA2 (Version 3 of 5)
Section A: Multiple Choice (10 marks)
| Qn | Answer | Marks | Working / Explanation |
|---|---|---|---|
| 1 | D | 2 | In 63 814, the digit 3 is in the thousands place. Value = 3 × 1 000 = 3 000. Common mistake: Confusing "digit" (3) with "value" (3 000). |
| 2 | C | 2 | 45 726: The digit in the hundreds place is 7. Since 7 ≥ 5, round up. 45 726 ≈ 46 000. |
| 3 | B | 2 | 18 ÷ 4 = 4 R2 (No). 24 ÷ 3 = 8, 24 ÷ 4 = 6 (Yes). 27 ÷ 4 = 6 R3 (No). 32 ÷ 3 = 10 R2 (No). |
| 4 | B | 2 | Division before addition: 84 ÷ 6 = 14. Then 14 + 15 = 29. Common mistake: Calculating left-to-right (84 ÷ 21 = 4). |
| 5 | C | 2 | Rounding to nearest hundred: 8 349 → 8 300. 8 395 → 8 400. 8 449 → 8 400. 8 460 → 8 500. Both 8 395 and 8 449 round to 8 400. Only C is an option. |
| 6 | A | 2 | 8 × 25 = 200. 200 – 45 = 155. |
| 7 | C | 2 | Multiples of 4: 4, 8, 12, 16, 20, 24... Multiples of 6: 6, 12, 18, 24... First two common multiples: 12 and 24. Sum = 12 + 24 = 36. |
| 8 | C | 2 | Using distributive law: 6 × 40 + 6 × 8 = 6 × (40 + 8) = 6 × 48 = 288. Or: 240 + 48 = 288. |
| 9 | C | 2 | 1 250 × 6 = 7 500. |
| 10 | D | 2 | 9 450 ÷ 9 = 1 050. |
Section B: Short Answer (20 marks)
| Qn | Answer | Marks | Working / Explanation |
|---|---|---|---|
| 11 | 42 005 | 2 | Forty-two thousand = 42 000. Five = 5. Combine: 42 005. |
| 12 | 32 804, 38 024, 38 204 | 2 | Compare ten-thousands (3), then thousands (2 vs 8). 32 804 is smallest. Then compare hundreds: 0 vs 2. 38 024 < 38 204. |
| 13 | 952 | 2 | 136 × 7 = 952. |
| 14 | Quotient: 709, Remainder: 6 | 2 | 5 678 ÷ 8: 8 × 709 = 5 672. 5 678 – 5 672 = 6. |
| 15 | 84 | 2 | Division before subtraction: 64 ÷ 8 = 8. Then 92 – 8 = 84. Common mistake: Left-to-right (92 – 64 = 28, 28 ÷ 8 = 3.5). |
| 16 | 1, 2, 3, 4, 6, 9, 12, 18, 36 | 2 | Find pairs: 1×36, 2×18, 3×12, 4×9, 6×6. List in order. |
| 17 | 80 | 2 | Multiples of 5: 5, 10, 15... 50, 55, 60, 65, 70, 75, 80... Multiples of 8: 8, 16, 24... 40, 48, 56, 64, 72, 80... First common multiple > 50 is 80. |
| 18 | 50 000 | 2 | Original: 57 293. New: 52 293. Difference = 57 293 – 52 293 = 5 000. Or: The digit 7 is in the ten thousands place (70 000). Replaced by 2 (20 000). Difference = 70 000 – 20 000 = 50 000. |
| 19 | 29 500 | 2 | 29 504: The digit in the tens place is 0. Since 0 < 5, round down. 29 504 ≈ 29 500. |
| 20 | 3 830 | 2 | 15 000 – 6 780 = 8 220. 8 220 – 4 390 = 3 830. |
Section C: Word Problems (30 marks)
21. [3 marks]
- Books after buying: 24 500 + 3 680 = 28 180
- Books after donating: 28 180 – 1 925 = 26 255
- Answer: 26 255
- M1 for correct addition, M1 for correct subtraction, A1 for final answer.
22. [3 marks]
- 235 × 45
- 235 × 40 = 9 400
- 235 × 5 = 1 175
- 9 400 + 1 175 = 10 575
- Answer: 10 575
- M2 for correct multiplication, A1 for final answer.
23. [3 marks]
- Cost of 1 chair: $468 ÷ 4 = $117
- Cost of 9 chairs: $117 × 9 = $1 053
- Answer: $1 053
- M1 for finding unit cost, M1 for multiplying by 9, A1 for final answer.
24. [4 marks]
- After first station: 1 890 – 456 + 327 = 1 761
- After second station: 1 761 – 589 + 145 = 1 317
- Answer: 1 317
- M1 for first alight/board, M1 for first station total, M1 for second alight/board, A1 for final answer. Alternative: Net change = –456 + 327 – 589 + 145 = –573. 1 890 – 573 = 1 317.
25. [3 marks]
- (a) 9 450 ÷ 6 = 1 575. Answer (a): 1 575 boxes [2 marks: M1 for division, A1 for answer]
- (b) 1 575 × 6 = 9 450. Remainder = 0. Answer (b): 0 eggs [1 mark]
- Common mistake: Students may expect a non-zero remainder. Check: 9 450 is divisible by 6.
26. [3 marks]
- Number = (Quotient × Divisor) + Remainder
- Number = (124 × 7) + 5
- 124 × 7 = 868
- 868 + 5 = 873
- Answer: 873
- M1 for correct formula, M1 for multiplication, A1 for final answer. Common mistake: Forgetting to add the remainder.
27. [3 marks]
- Total chairs: 28 × 36 = 1 008
- Unoccupied chairs: 1 008 – 645 = 363
- Answer: 363
- M1 for finding total chairs, M1 for subtraction, A1 for final answer.
28. [4 marks]
- Total oranges bought: 15 × 120 = 1 800
- Good oranges: 1 800 – 84 = 1 716
- Number of bags: 1 716 ÷ 8 = 214
- Answer: 214 bags
- M1 for total oranges, M1 for subtracting rotten oranges, M1 for dividing by 8, A1 for final answer.
29. [4 marks]
- (a) Total visitors: 2 450 + 1 875 + 3 120 + 2 555 = 10 000 [2 marks: M1 for adding all four values, A1 for total]
- Answer (a): 10 000
- (b) Visitors still needed: 12 000 – 10 000 = 2 000 [2 marks: M1 for subtraction, A1 for answer]
- Answer (b): 2 000
30. [4 marks]
- Total spent on TV and sound system: $1 295 + $868 = $2 163
- Total spent on 3 tables: $417 × 3 = $1 251
- Total spent altogether: $2 163 + $1 251 = $3 414
- Money left: $5 000 – $3 414 = $1 586
- Answer: $1 586
- M1 for adding TV and sound system, M1 for cost of 3 tables, M1 for finding total spent, A1 for final answer. Alternative: Subtract sequentially from 5 000.