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Primary 3 Mathematics Multiplication Division Quiz

Free P3 Maths Multiplication Division quiz, Ox AI version, with questions, answers, and syllabus-aligned practice for Singapore students.

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Primary 3 Mathematics AI Generated Generated by Ox Alpha Updated 2026-08-27

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Primary 3 Mathematics Quiz - Multiplication Division

Name: ______________________ Class: ______________ Date: ______________ Score: ________ / 60

Subject: Mathematics | Level: Primary 3 | Topic: Multiplication and Division | Version: 1 of 5

Duration: 60 minutes | Total Marks: 60

Instructions:

Answer all 20 questions.
Show your working clearly for Questions 6 to 20 in the spaces provided.
Write units and remainder statements where they are asked for.
Do not use a calculator.
Check your answers before handing in.

Note: This quiz is generated from syllabus-aligned templates based on the Singapore Primary 3 Mathematics syllabus. It is not copied from any school's past-year examination paper.

Section A: Multiplication Tables and Basic Facts (Questions 1-5, 2 marks each, 10 marks)

Question 1.

Find the product.

$6 \times 9 =$ ______________

(2 marks)

Question 2.

The picture shows an array of counters. Write one multiplication sentence that matches the array, then find the total number of counters.

Image pending generation: diagram for Q2.

Multiplication sentence: ______ $\times$ ______ = ______

Total number of counters: ______________

(2 marks)

Question 3.

Find the value.

$56 \div 7 =$ ______________

(2 marks)

Question 4.

Divide and state the remainder.

$44 \div 6 =$ ______ remainder ______

(2 marks)

Question 5.

Fill in the missing number.

$9 \times$ ______ $= 81$

(2 marks)

Section B: Algorithms, Strategies and Short Problems (Questions 6-15, 3 marks each, 30 marks)

Question 6.

Work out $234 \times 3$ . Show your working.

Working space:

Answer: ______________ (3 marks)

Question 7.

Work out $96 \div 4$ . Show your working.

Working space:

Answer: ______________ (3 marks)

Question 8.

Work out $85 \div 4$ . Give your answer with the remainder.

Working space:

Answer: ______ remainder ______ (3 marks)

Question 9.

A baker packs 48 curry buns equally into bags of 6. How many bags does he fill?

Working space:

Answer: ______________ (3 marks)

Question 10.

50 pupils are going on an excursion. Each van can carry 8 pupils. What is the smallest number of vans needed so that every pupil travels?

Working space:

Answer: ______________ (3 marks)

Question 11.

Use a mental strategy to find $25 \times 4$ . Write the steps of your thinking.

Working space:

Answer: ______________ (3 marks)

Question 12.

Which is greater: $7 \times 8$ or $6 \times 9$ ? Find both products, then write the greater one.

Working space:

Answer: ______________ (3 marks)

Question 13.

This list shows part of a number pattern:

6, 12, 18, ______, ______, 36

Fill in the two missing numbers and state what the pattern counts in.

Working space:

Missing numbers: ______ and ______ ; Pattern counts in ______ (3 marks)

Question 14.

Ravi wrote: $42 \div 7 = 5$ remainder $7$ .

Explain what is wrong with Ravi's answer and write the correct answer.

Working space:

Explanation and correct answer: ________________________________________ (3 marks)

Question 15.

A stationery shop has 8 boxes of pencils. Each box holds 9 pencils. The shopkeeper gives 5 pencils to a charity drive. How many pencils are left?

Working space:

Answer: ______________ (3 marks)

Section C: Word Problems (Questions 16-20, 4 marks each, 20 marks)

Question 16.

For Chinese New Year, each of the 26 families in Block 214 needs 8 mandarin oranges. The oranges are sold in bags of 6. What is the smallest number of bags the residents' committee must buy so that every family gets all its oranges?

Working space:

Answer: ______________ (4 marks)

Question 17.

A ferry has 9 rows of seats. There are 14 seats in each row. At the terminal, 118 passengers board the ferry. How many seats are empty?

Working space:

Answer: ______________ (4 marks)

Question 18.

During the Mid-Autumn Festival, Uncle Lim packs 145 mooncakes into boxes of 8. How many boxes are completely filled, and how many mooncakes are left unpacked?

Working space:

Answer: ______ boxes completely filled, ______ mooncakes left unpacked (4 marks)

Question 19.

On Sports Day, 84 pupils are split into equal teams of 7. Each team is given 5 marker cones. How many marker cones are given out in total?

Working space:

Answer: ______________ (4 marks)

Question 20.

A bookshop receives 8 cartons of storybooks. Each carton contains 45 books. During a sale, 132 books are sold. How many storybooks are left in the bookshop?

Working space:

Answer: ______________ (4 marks)

--- End of Quiz ---

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Answers

Primary 3 Mathematics Quiz - Multiplication Division - Answer Key (Version 1 of 5)

Total Marks: 60 | Duration: 60 minutes

Marking note: Award method marks even if the final answer is wrong, provided the chosen operation and working are correct. Final answers without units or remainder statements lose the last mark where units/reminders are requested.

Answer 1.

Final answer: $6 \times 9 = 54$ (2 marks)

Teaching note: Multiplication means repeated addition: $9 + 9 + 9 + 9 + 9 + 9 = 54$ , or count in nines: 9, 18, 27, 36, 45, 54.
Common mistake: writing 45 (stopping one step early) or 69 (writing digits side by side instead of multiplying).

Answer 2.

Final answer: Multiplication sentence $4 \times 6 = 24$ (or $6 \times 4 = 24$ ); total = 24 counters (2 marks)

Expected visual: 4 rows of 6 identical counters, so counting gives 6 in each row and 4 rows.
Method: Count one row = 6 counters. There are 4 equal rows, so use repeated addition: $6 + 6 + 6 + 6 = 24$ . This is why we write $4 \times 6 = 24$ (4 groups of 6).
Mark breakdown: 1 mark for a correct multiplication sentence matching the array; 1 mark for the total 24.
Common mistake: adding 4 + 6 = 10; remind students that equal groups point to multiplication.

Answer 3.

Final answer: $56 \div 7 = 8$ (2 marks)

Method: Ask "How many sevens make 56?" Recall $7 \times 8 = 56$ , so $56 \div 7 = 8$ .
Concept: Division undoes multiplication; the answer tells how many equal groups of 7 fit into 56.

Answer 4.

Final answer: $44 \div 6 = 7$ remainder $2$ (2 marks)

Method: Find the largest multiple of 6 not exceeding 44: $6 \times 7 = 42$ . Subtract: $44 - 42 = 2$ left over.
Check: The remainder 2 must be smaller than the divisor 6. If it were 6 or more, another group of 6 could be made.

Answer 5.

Final answer: Missing number is $9$ , because $9 \times 9 = 81$ (2 marks)

Method: Count in nines until reaching 81: 9, 18, 27, 36, 45, 54, 63, 72, 81. That is nine nines.
Concept: A missing factor can be found using the related division fact: $81 \div 9 = 9$ .

Answer 6.

Final answer: $234 \times 3 = 702$ (3 marks)

Step 1 (ones): $4 \times 3 = 12$ . Write 2 in the ones place, carry 1 to the tens.
Step 2 (tens): $3 \times 3 = 9$ , plus the carried 1 makes 10. Write 0, carry 1 to the hundreds.
Step 3 (hundreds): $2 \times 3 = 6$ , plus the carried 1 makes 7.
Answer: 702.
Mark breakdown: 1 mark correct column setup/multiplying each digit; 1 mark handling both carries; 1 mark final answer 702.
Common mistake: forgetting the carried 1s, giving 692 or 612.

Answer 7.

Final answer: $96 \div 4 = 24$ (3 marks)

Method (long division): Divide the tens first: $9 \div 4 = 2$ remainder $1$ (since $4 \times 2 = 8$ ). Bring down the 6 to make 16. Then $16 \div 4 = 4$ exactly.
Check by multiplying back: $24 \times 4 = 96$ .
Alternative chunking: $40 \div 4 = 10$ , another $40 \div 4 = 10$ , and $16 \div 4 = 4$ ; total $10 + 10 + 4 = 24$ .
Mark breakdown: 1 mark dividing tens correctly; 1 mark completing the ones; 1 mark final answer 24.

Answer 8.

Final answer: $85 \div 4 = 21$ remainder $1$ (3 marks)

Step 1: Largest multiple of 4 up to 85 is $4 \times 21 = 84$ .
Step 2: Subtract: $85 - 84 = 1$ .
Step 3: Remainder 1 is smaller than 4, so stop. Check: $(21 \times 4) + 1 = 85$ .
Mark breakdown: 1 mark quotient 21; 1 mark remainder 1; 1 mark valid checking or correct subtraction shown.

Answer 9.

Final answer: 8 bags (3 marks)

Method: 48 buns shared into equal groups of 6: $48 \div 6 = 8$ because $6 \times 8 = 48$ .
Concept: "Packs into bags of 6" asks how many groups of 6 are in 48.
Mark breakdown: 1 mark choosing division; 1 mark correct working ( $6 \times 8 = 48$ ); 1 mark answer with unit (bags).

Answer 10.

Final answer: 7 vans (3 marks)

Step 1: $50 \div 8 = 6$ remainder $2$ , since $8 \times 6 =

<stage5_quiz_answers_md>

Primary 3 Mathematics Quiz - Multiplication Division - Answer Key (Version 1 of 5)

Total Marks: 60 | Duration: 60 minutes

Answer 1.

Final answer: $6 \times 9 = 54$ (2 marks)

Teaching note: Count in nines: 9, 18, 27, 36, 45, 54.
Common mistake: writing 45 (stopping one step early) or 69 (writing digits side by side).

Answer 2.

Final answer: $4 \times 6 = 24$ (or $6 \times 4 = 24$ ); total = 24 counters (2 marks)

Method: One row has 6 counters; there are 4 equal rows, so $6 + 6 + 6 + 6 = 24$ .
Mark breakdown: 1 mark correct multiplication sentence; 1 mark total of 24.
Common mistake: adding 4 + 6 = 10; equal groups point to multiplication.

Answer 3.

Final answer: $56 \div 7 = 8$ (2 marks)

Method: Recall $7 \times 8 = 56$ , so 8 sevens make 56.

Answer 4.

Final answer: $44 \div 6 = 7$ remainder $2$ (2 marks)

Method: Largest multiple of 6 not exceeding 44 is $6 \times 7 = 42$ ; $44 - 42 = 2$ left over.
Check: Remainder 2 is smaller than the divisor 6.

Answer 5.

Final answer: Missing number is $9$ , because $9 \times 9 = 81$ (2 marks)

Method: Related division fact: $81 \div 9 = 9$ .

Answer 6.

Final answer: $234 \times 3 = 702$ (3 marks)

Step 1 (ones): $4 \times 3 = 12$ ; write 2, carry 1.
Step 2 (tens): $3 \times 3 = 9$ , plus carried 1 makes 10; write 0, carry 1.
Step 3 (hundreds): $2 \times 3 = 6$ , plus carried 1 makes 7.
Mark breakdown: 1 mark column setup; 1 mark both carries handled; 1 mark answer 702.
Common mistake: forgetting carries, giving 692 or 612.

Answer 7.

Final answer: $96 \div 4 = 24$ (3 marks)

Long division: Tens first: $9 \div 4 = 2$ remainder $1$ . Bring down 6 to make 16; $16 \div 4 = 4$ exactly.
Check: $24 \times 4 = 96$ .
Alternative chunking: $(40 \div 4) + (40 \div 4) + (16 \div 4) = 10 + 10 + 4 = 24$ .
Mark breakdown: 1 mark tens step; 1 mark ones step; 1 mark answer 24.

Answer 8.

Final answer: $85 \div 4 = 21$ remainder $1$ (3 marks)

Step 1: Largest multiple of 4 up to 85 is $4 \times 21 = 84$ .
Step 2: $85 - 84 = 1$ ; remainder 1 is smaller than 4.
Check: $(21 \times 4) + 1 = 85$ .
Mark breakdown: 1 mark quotient 21; 1 mark remainder 1; 1 mark check shown.

Answer 9.

Final answer: 8 bags (3 marks)

Method: Sharing into equal groups of 6: $48 \div 6 = 8$ because $6 \times 8 = 48$ .
Mark breakdown: 1 mark choosing division; 1 mark working; 1 mark answer with unit (bags).

Answer 10.

Final answer: 7 vans (3 marks)

Step 1: $50 \div 8 = 6$ remainder $2$ , since $8 \times 6 = 48$ and $50 - 48 = 2$ .
Step 2: The 2 remaining pupils still need a van, so round up: $6 + 1 = 7$ vans.
Key idea: For "smallest number needed so everyone travels", always round the quotient up.
Mark breakdown: 1 mark division with remainder; 1 mark rounding up; 1 mark answer with unit (vans).
Common mistake: answering 6 vans and leaving 2 pupils behind.

Answer 11.

Final answer: $25 \times 4 = 100$ (3 marks)

Sample strategy (doubling): Double 25 gives 50; double again gives 100. So $25 \times 4 = 100$ .
Alternative strategy: Repeated addition: $25 + 25 + 25 + 25 = 100$ .
Mark breakdown: 1 mark valid strategy stated; 1 mark steps shown clearly; 1 mark answer 100.

Answer 12.

Final answer: $7 \times 8 = 56$ is greater (3 marks)

Step 1: $7 \times 8 = 56$ .
Step 2: $6 \times 9 = 54$ .
Step 3: Compare: $56 > 54$ , so $7 \times 8$ is greater.
Mark breakdown: 1 mark each product correct; 1 mark correct comparison/greater product named.

Answer 13.

Final answer: Missing numbers are $24$ and $30$ ; the pattern counts in sixes (3 marks)

Method: Each term increases by 6: 6, 12, 18, 24, 30, 36. This is the table of 6 ( $6 \times 4$ and $6 \times 5$ ).
Mark breakdown: 1 mark each missing number; 1 mark stating it counts in sixes.

Answer 14.

Final answer: The remainder cannot equal or exceed the divisor; correct answer is $42 \div 7 = 6$ with no remainder (3 marks)

Explanation: A remainder must always be smaller than the divisor. Ravi wrote remainder 7 when dividing by 7, which is impossible — another whole group of 7 can still be made from those 7 left over.
Correct working: $7 \times 6 = 42$ exactly, so $42 \div 7 = 6$ remainder $0$ .
Mark breakdown: 1 mark identifying the error; 1 mark explanation; 1 mark correct answer 6.

Answer 15.

Final answer: 67 pencils (3 marks)

Step 1: Total pencils at first: $8 \times 9 = 72$ .
Step 2: Pencils given away: 5.
Step 3: Pencils left: $72 - 5 = 67$ .
Mark breakdown: 1 mark multiplication; 1 mark subtraction; 1 mark answer with unit (pencils).

Answer 16.

Final answer: 35 bags (4 marks)

Step 1: Oranges needed: $26 \times 8 = 208$ oranges.
Step 2: Bags needed: $208 \div 6 = 34$ remainder $4$ , since $6 \times 34 = 204$ and $208 - 204 = 4$ .
Step 3: The extra 4 oranges need one more bag, so round up: $34 + 1 = 35$ bags.
Statement: The residents' committee must buy 35 bags of oranges.
Mark breakdown: 1 mark total oranges 208; 1 mark division with remainder; 1 mark rounding up; 1 mark answer statement with unit.

Answer 17.

Final answer: 8 empty seats (4 marks)

Step 1: Total seats on ferry: $9 \times 14 = 126$ seats.
Step 2: Passengers on board: 118.
Step 3: Empty seats: $126 - 118 = 8$ .
Statement: There are 8 empty seats on the ferry.
Mark breakdown: 1 mark total seats 126; 1 mark subtraction setup; 1 mark answer 8; 1 mark statement with unit.

Answer 18.

Final answer: 18 boxes completely filled, 1 mooncake left unpacked (4 marks)

Step 1: Divide: $145 \div 8 = 18$ remainder $1$ , since $8 \times 18 = 144$ and $145 - 144 = 1$ .
Step 2: Quotient 18 gives the number of completely filled boxes.
Step 3: Remainder 1 is the mooncake left unpacked.
Statement: 18 boxes are completely filled and 1 mooncake is left unpacked.
Mark breakdown: 1 mark division; 1 mark quotient as full boxes; 1 mark remainder as leftover; 1 mark statement with units.

Answer 19.

Final answer: 60 marker cones (4 marks)

Step 1: Number of teams: $84 \div 7 = 12$ teams, since $7 \times 12 = 84$ .
Step 2: Cones per team: 5.
Step 3: Total cones: $12 \times 5 = 60$ marker cones.
Statement: 60 marker cones are given out in total.
Mark breakdown: 1 mark finding 12 teams; 1 mark multiplying by 5; 1 mark answer 60; 1 mark statement with unit.

Answer 20.

Final answer: 228 storybooks (4 marks)

Step 1: Books received: $8 \times 45 = 360$ books.
Step 2: Books sold: 132.
Step 3: Books left: $360 - 132 = 228$ .
Statement: 228 storybooks are left in the bookshop.
Mark breakdown: 1 mark total books 360; 1 mark subtraction setup; 1 mark answer 228; 1 mark statement with unit.

--- End of Answer Key ---