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Primary 3 Mathematics Multiplication Division Quiz

Free P3 Maths Multiplication Division quiz, Ox Exam version, with questions, answers, and syllabus-aligned practice for Singapore students.

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Primary 3 Mathematics From Real Exams Generated by Ox Alpha Updated 2026-08-27

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Primary 3 Mathematics Quiz - Multiplication Division — Answer Key

Total Marks: 55


Section A: Multiple Choice (Questions 1 to 5)

Answer 1.

Answer: B. 56 (2 marks)

  • Multiplication means equal groups: 7×87 \times 8 means 7 groups of 8.
  • Method: recall the table of 8: 8×7=568 \times 7 = 56. Check by doubling: 7×4=287 \times 4 = 28, and 28+28=5628 + 28 = 56.
  • Common mistake: choosing 63, which is 7×97 \times 9. Always match the second factor carefully.

Answer 2.

Answer: B. 6 (2 marks)

  • Division asks: how many equal groups? 54÷954 \div 9 asks "9 times what makes 54?"
  • Method: recall 9×6=549 \times 6 = 54, so 54÷9=654 \div 9 = 6.
  • Common mistake: choosing 7 or 8 from near-by table facts; check by multiplying back: 9×6=549 \times 6 = 54 ✓.

Answer 3.

Answer: A. 2 (2 marks)

  • A remainder is what is left over after making as many equal groups as possible.
  • Method: find the largest multiple of 6 that is not more than 44: 6×7=426 \times 7 = 42. Then 4442=244 - 42 = 2.
  • So 44÷6=744 \div 6 = 7 remainder 2. The remainder is 2.
  • Common mistake: choosing C (7) — that is the quotient, not the remainder. Read the question for the word "remainder".

Answer 4.

Answer: C. 48 (2 marks)

  • An array shows equal rows, so we multiply: 6 rows of 8 counters.
  • Method: 6×8=486 \times 8 = 48.
  • Common mistake: choosing A (14) by adding 6+86 + 8. Rows of objects are counted by multiplying, not adding.

Answer 5.

Answer: D. 72 (2 marks)

  • "9 packets of 8 stickers each" means 9 equal groups of 8, so multiply.
  • Method: 9×8=729 \times 8 = 72.
  • Common mistake: choosing A (17) by adding 9+89 + 8. Equal groups always point to multiplication.

Section B: Short Answer (Questions 6 to 10)

Answer 6.

Answer: 9 (2 marks)

  • The missing number is a factor: something times 6 makes 54.
  • Method: use the inverse operation, division: 54÷6=954 \div 6 = 9.
  • Check: 9×6=549 \times 6 = 54 ✓.
  • Marking: 1 mark for method (54÷654 \div 6), 1 mark for answer 9.

Answer 7.

Answer: 702 (2 marks)

  • "Product" means the answer to a multiplication.
  • Column method with regrouping:
    • Ones: 4×3=124 \times 3 = 12 → write 2, carry 1 to the tens.
    • Tens: 3×3=93 \times 3 = 9, plus 1 carried = 10 → write 0, carry 1 to the hundreds.
    • Hundreds: 2×3=62 \times 3 = 6, plus 1 carried = 7.
  • So 234×3=702234 \times 3 = 702.
  • Check by place value: 200×3=600200 \times 3 = 600, 30×3=9030 \times 3 = 90, 4×3=124 \times 3 = 12; 600+90+12=702600 + 90 + 12 = 702 ✓.
  • Marking: 1 mark for correct method/regrouping, 1 mark for answer 702.

Answer 8.

Answer: 24 (2 marks)

  • Division can be done by splitting: 96=80+1696 = 80 + 16.
  • Method: 80÷4=2080 \div 4 = 20 and 16÷4=416 \div 4 = 4, so 96÷4=20+4=2496 \div 4 = 20 + 4 = 24.
  • Long-division check: 9÷4=29 \div 4 = 2 remainder 1; bring down the 6 to make 16; 16÷4=416 \div 4 = 4 → 24.
  • Check: 4×24=964 \times 24 = 96 ✓.
  • Marking: 1 mark for method, 1 mark for answer 24.

Answer 9.

Answers: 9 remainder 2 (2 marks)

  • Find the largest multiple of 7 not more than 65: 7×9=637 \times 9 = 63.
  • Subtract: 6563=265 - 63 = 2, so the remainder is 2.
  • So 65÷7=965 \div 7 = 9 remainder 2.
  • Common mistake: writing 10 remainder −5. The quotient must be the largest whole number of groups, so the remainder must be smaller than 7.
  • Marking: 1 mark for quotient 9, 1 mark for remainder 2.

Answer 10.

Answer: 12 (2 marks)

  • "What number multiplied by 8 gives 96?" is a missing-factor problem.
  • Method: use the inverse operation: 96÷8=1296 \div 8 = 12.
  • Working: 8×10=808 \times 10 = 80; 9680=1696 - 80 = 16; 16÷8=216 \div 8 = 2; so 10+2=1210 + 2 = 12.
  • Check: 8×12=968 \times 12 = 96 ✓.
  • Marking: 1 mark for method (96÷896 \div 8), 1 mark for answer 12.

Section C: Short Problems (Questions 11 to 15)

Answer 11.

(a) One matching multiplication sentence: 4×7=284 \times 7 = 28 (or 7×4=287 \times 4 = 28). (1 mark)

(b) Answer: 28 mangoes (2 marks)

  • The picture shows 4 equal groups of 7, so multiply: 4×7=284 \times 7 = 28.
  • Repeated addition check: 7+7+7+7=287 + 7 + 7 + 7 = 28 ✓.
  • Marking for (b): 1 mark for correct working (4×74 \times 7), 1 mark for answer 28 with the word "mangoes".
  • Expected visual support: 4 baskets, each with exactly 7 mangoes, captions "7 mangoes" visible.

Answer 12.

Answer: 870 (3 marks)

  • Column method with regrouping:
    • Ones: 5×6=305 \times 6 = 30 → write 0, carry 3.
    • Tens: 4×6=244 \times 6 = 24, plus 3 carried = 27 → write 7, carry 2.
    • Hundreds: 1×6=61 \times 6 = 6, plus 2 carried = 8.
  • So 145×6=870145 \times 6 = 870.
  • Place-value check: 100×6=600100 \times 6 = 600; 40×6=24040 \times 6 = 240; 5×6=305 \times 6 = 30

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Primary 3 Mathematics Quiz - Multiplication Division — Answer Key

Total Marks: 55


Section A: Multiple Choice (Questions 1 to 5)

Answer 1.

Answer: B. 56 (2 marks)

  • Multiplication means equal groups: 7×87 \times 8 means 7 groups of 8.
  • Method: recall the table of 8: 8×7=568 \times 7 = 56. Check by doubling: 7×4=287 \times 4 = 28, and 28+28=5628 + 28 = 56.
  • Common mistake: choosing 63, which is 7×97 \times 9. Always match the second factor carefully.

Answer 2.

Answer: B. 6 (2 marks)

  • Division asks: how many equal groups? 54÷954 \div 9 asks "9 times what makes 54?"
  • Method: recall 9×6=549 \times 6 = 54, so 54÷9=654 \div 9 = 6.
  • Common mistake: choosing 7 or 8 from near-by table facts; check by multiplying back: 9×6=549 \times 6 = 54 ✓.

Answer 3.

Answer: A. 2 (2 marks)

  • A remainder is what is left over after making as many equal groups as possible.
  • Method: find the largest multiple of 6 that is not more than 44: 6×7=426 \times 7 = 42. Then 4442=244 - 42 = 2.
  • So 44÷6=744 \div 6 = 7 remainder 2. The remainder is 2.
  • Common mistake: choosing C (7) — that is the quotient, not the remainder. Read the question for the word "remainder".

Answer 4.

Answer: C. 48 (2 marks)

  • An array shows equal rows, so we multiply: 6 rows of 8 counters.
  • Method: 6×8=486 \times 8 = 48.
  • Common mistake: choosing A (14) by adding 6+86 + 8. Rows of objects are counted by multiplying, not adding.

Answer 5.

Answer: D. 72 (2 marks)

  • "9 packets of 8 stickers each" means 9 equal groups of 8, so multiply.
  • Method: 9×8=729 \times 8 = 72.
  • Common mistake: choosing A (17) by adding 9+89 + 8. Equal groups always point to multiplication.

Section B: Short Answer (Questions 6 to 10)

Answer 6.

Answer: 9 (2 marks)

  • The missing number is a factor: something times 6 makes 54.
  • Method: use the inverse operation, division: 54÷6=954 \div 6 = 9.
  • Check: 9×6=549 \times 6 = 54 ✓.
  • Marking: 1 mark for method (54÷654 \div 6), 1 mark for answer 9.

Answer 7.

Answer: 702 (2 marks)

  • "Product" means the answer to a multiplication.
  • Column method with regrouping:
    • Ones: 4×3=124 \times 3 = 12 → write 2, carry 1 to the tens.
    • Tens: 3×3=93 \times 3 = 9, plus 1 carried = 10 → write 0, carry 1 to the hundreds.
    • Hundreds: 2×3=62 \times 3 = 6, plus 1 carried = 7.
  • So 234×3=702234 \times 3 = 702.
  • Check by place value: 200×3=600200 \times 3 = 600, 30×3=9030 \times 3 = 90, 4×3=124 \times 3 = 12; 600+90+12=702600 + 90 + 12 = 702 ✓.
  • Marking: 1 mark for correct method/regrouping, 1 mark for answer 702.

Answer 8.

Answer: 24 (2 marks)

  • Division can be done by splitting: 96=80+1696 = 80 + 16.
  • Method: 80÷4=2080 \div 4 = 20 and 16÷4=416 \div 4 = 4, so 96÷4=20+4=2496 \div 4 = 20 + 4 = 24.
  • Long-division check: 9÷4=29 \div 4 = 2 remainder 1; bring down the 6 to make 16; 16÷4=416 \div 4 = 4 → 24.
  • Check: 4×24=964 \times 24 = 96 ✓.
  • Marking: 1 mark for method, 1 mark for answer 24.

Answer 9.

Answers: 9 remainder 2 (2 marks)

  • Find the largest multiple of 7 not more than 65: 7×9=637 \times 9 = 63.
  • Subtract: 6563=265 - 63 = 2, so the remainder is 2.
  • So 65÷7=965 \div 7 = 9 remainder 2.
  • Common mistake: writing 10 remainder −5. The quotient must be the largest whole number of groups, so the remainder must be smaller than 7.
  • Marking: 1 mark for quotient 9, 1 mark for remainder 2.

Answer 10.

Answer: 12 (2 marks)

  • "What number multiplied by 8 gives 96?" is a missing-factor problem.
  • Method: use the inverse operation: 96÷8=1296 \div 8 = 12.
  • Working: 8×10=808 \times 10 = 80; 9680=1696 - 80 = 16; 16÷8=216 \div 8 = 2; so 10+2=1210 + 2 = 12.
  • Check: 8×12=968 \times 12 = 96 ✓.
  • Marking: 1 mark for method (96÷896 \div 8), 1 mark for answer 12.

Section C: Short Problems (Questions 11 to 15)

Answer 11.

(a) One matching multiplication sentence: 4×7=284 \times 7 = 28 (or 7×4=287 \times 4 = 28). (1 mark)

(b) Answer: 28 mangoes (2 marks)

  • The picture shows 4 equal groups of 7, so multiply: 4×7=284 \times 7 = 28.
  • Repeated addition check: 7+7+7+7=287 + 7 + 7 + 7 = 28 ✓.
  • Marking for (b): 1 mark for correct working (4×74 \times 7), 1 mark for answer 28 with the word "mangoes".
  • Expected visual support: 4 baskets, each with exactly 7 mangoes, captions "7 mangoes" visible.

Answer 12.

Answer: 870 (3 marks)

  • Column method with regrouping:
    • Ones: 5×6=305 \times 6 = 30 → write 0, carry 3.
    • Tens: 4×6=244 \times 6 = 24, plus 3 carried = 27 → write 7, carry 2.
    • Hundreds: 1×6=61 \times 6 = 6, plus 2 carried = 8.
  • So 145×6=870145 \times 6 = 870.
  • Place-value check: 100×6=600100 \times 6 = 600; 40×6=24040 \times 6 = 240; 5×6=305 \times 6 = 30; 600+240+30=870600 + 240 + 30 = 870 ✓.
  • Marking: 1 mark for correct regrouping, 1 mark for accurate multiplication, 1 mark for answer 870.

Answer 13.

Answers: 8 complete groups; 6 pupils not in a complete group (3 marks)

  • Divide: 70÷8=870 \div 8 = 8 remainder 6, because 8×8=648 \times 8 = 64 and 7064=670 - 64 = 6.
  • So there are 8 complete groups of 8, and 6 pupils are not in a complete group.
  • Check: 8×8+6=64+6=708 \times 8 + 6 = 64 + 6 = 70 ✓.
  • Marking: 1 mark for method (70÷870 \div 8), 1 mark for 8 complete groups, 1 mark for 6 pupils.

Answer 14.

Answer: 82 pens (3 marks)

  • Step 1 — total pens: 5×24=1205 \times 24 = 120.
  • Step 2 — pens left after selling: 12038=82120 - 38 = 82.
  • Statement: The bookshop has 82 pens left.
  • Marking: 1 mark for 5×24=1205 \times 24 = 120, 1 mark for subtraction, 1 mark for answer 82 with units.

Answer 15.

Answer: 113 (3 marks)

  • Rule: number = quotient × divisor + remainder.
  • Working: 12×9=10812 \times 9 = 108; 108+5=113108 + 5 = 113.
  • Check: 113÷9=12113 \div 9 = 12 remainder 5 ✓.
  • Marking: 1 mark for the rule/method, 1 mark for 12×9=10812 \times 9 = 108, 1 mark for answer 113.

Section D: Word Problems (Questions 16 to 20)

Answer 16.

Answer: 180 marbles (4 marks)

  • Siti's marbles: 4×36=1444 \times 36 = 144.
  • Altogether: 36+144=18036 + 144 = 180.
  • Statement: Ravi and Siti have 180 marbles altogether.
  • Marking: 1 mark for 4×36=1444 \times 36 = 144, 1 mark for adding Ravi's marbles, 1 mark for answer 180, 1 mark for a correct statement.

Answer 17.

Answer: 27 cards (4 marks)

  • Step 1 — cards per child at first: 128÷4=32128 \div 4 = 32.
  • Step 2 — after giving 5 away: 325=2732 - 5 = 27.
  • Statement: Each child has 27 cards in the end.
  • Marking: 1 mark for 128÷4=32128 \div 4 = 32, 1 mark for 32532 - 5, 1 mark for answer 27, 1 mark for a correct statement.

Answer 18.

Answer: 9 trips (4 marks)

  • Divide: 58÷7=858 \div 7 = 8 remainder 2, because 7×8=567 \times 8 = 56 and 5856=258 - 56 = 2.
  • 8 full trips carry 56 boxes, but 2 boxes are still left, so the van needs 1 more trip.
  • Therefore the van must make 8+1=98 + 1 = 9 trips. We round up because every box must be delivered.
  • Statement: The van must make 9 trips.
  • Marking: 1 mark for 58÷758 \div 7, 1 mark for remainder 2, 1 mark for rounding up to 9, 1 mark for explanation/statement.

Answer 19.

(a) Answer: 40 full trays (2 marks)

  • Divide: 245÷6=40245 \div 6 = 40 remainder 5, because 6×40=2406 \times 40 = 240 and 245240=5245 - 240 = 5.
  • Marking: 1 mark for method, 1 mark for 40 full trays.

(b) Answer: 5 eggs (2 marks)

  • The remainder is the unpacked eggs: 245240=5245 - 240 = 5.
  • Marking: 1 mark for using the remainder, 1 mark for answer 5 with units.

Answer 20.

Answer: 42 chairs (4 marks)

  • Step 1 — chairs at first: 8×35=2808 \times 35 = 280.
  • Step 2 — total after adding: 280+56=336280 + 56 = 336.
  • Step 3 — share equally among 8 rows: 336÷8=42336 \div 8 = 42.
  • Statement: There are 42 chairs in each row now.
  • Marking: 1 mark for 8×35=2808 \times 35 = 280, 1 mark for 280+56=336280 + 56 = 336, 1 mark for 336÷8=42336 \div 8 = 42, 1 mark for a correct statement.

End of Answer Key