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Primary 3 Mathematics Practice Paper 3

Free P3 Maths Practice Paper 3, Ox AI version, with questions, answers, and syllabus-aligned practice for Singapore students.

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Primary 3 Mathematics AI Generated Generated by Ox Alpha Updated 2026-08-27

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TuitionGoWhere Practice Paper - Mathematics Primary 3

Answer Key with Marking Scheme — Whole Numbers (Version 3 of 5)

Total Marks: 50 | Section A: 16 | Section B: 16 | Section C: 18

Key idea used throughout this paper: In a 4-digit number, the places from right to left are ones, tens, hundreds, thousands. Each place is worth 10 times the place to its right. To compare numbers, compare the thousands digits first, then hundreds, then tens, then ones.


Section A: Multiple Choice

Q1 (2 m) — Answer: (2) 0

Method: Write the places under 7065: 7 = thousands, 0 = hundreds, 6 = tens, 5 = ones. The hundreds digit is 0. Teaching note: A digit can be 0 and still "hold" a place. Zero keeps the other digits in their correct positions. Common mistake: Choosing 6 because "there is nothing in the hundreds place". The question asks which digit sits there, and that digit is 0.

Q2 (2 m) — Answer: (3) 900

Method: In 3928, the digit 9 is in the hundreds place. Value = 9×100=9009 \times 100 = 900. Teaching note: "Digit" is

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TuitionGoWhere Practice Paper - Mathematics Primary 3

Answer Key with Marking Scheme — Whole Numbers (Version 3 of 5)

Total Marks: 50 | Section A: 16 | Section B: 16 | Section C: 18

Key idea used throughout this paper: In a 4-digit number, the places from right to left are ones, tens, hundreds, thousands. Each place is worth 10 times the place to its right. To compare numbers, compare thousands digits first, then hundreds, then tens, then ones.


Section A: Multiple Choice

Q1 (2 m)(2) 0 Method: In 7065, places are 7 = thousands, 0 = hundreds, 6 = tens, 5 = ones. The hundreds digit is 0. Teaching note: A digit can be 0 and still hold its place; zero keeps other digits correctly positioned. Common mistake: Choosing 6 because "nothing seems to be in the hundreds place".

Q2 (2 m)(3) 900 Method: In 3928, digit 9 is in the hundreds place. Value = 9×100=9009 \times 100 = 900. Teaching note: "Digit" names the symbol; "value" is what that digit is worth in its position.

Q3 (2 m)(1) 6421 Method: six thousand = 6000, four hundred = 400, twenty-one = 21. 6000+400+21=64216000 + 400 + 21 = 6421. Common mistake: Option (2) 6241 swaps the hundreds and tens digits when reading "four hundred and twenty-one".

Q4 (2 m)(2) 4752 Method: All numbers have 4 thousands. Compare hundreds: 7 > 5 > 2, so 4752 and 4725 lead. Compare tens: 5 > 2, so 4752 is greatest.

Q5 (2 m)(2) 3610 Method: The pattern increases by 100 each step (3510+100=36103510 + 100 = 3610; check: 3610+100=37103610 + 100 = 3710 ✓).

Q6 (2 m)(1) 4930 Method: The pattern decreases by 100 each step (5030100=49305030 - 100 = 4930; check: 4930100=48304930 - 100 = 4830 ✓).

Q7 (2 m)(3) 7418 Method: An even number ends in 0, 2, 4, 6 or 8. Eliminate 7841 (ends in 1). Among 7814, 7418, 7481... wait, 7481 ends in 1, so only 7814 and 7418 are even. Compare: 7418 < 7814, so 7418 is the smallest even number.

Q8 (2 m)(1) 9831 Method: To make the greatest number, place the largest digit in the largest place: 9, then 8, then 3, then 1 → 9831.


Section B: Short Answer

Q9 (2 m)Five thousand and seventy-three Marking: 1 mark for correct thousands wording, 1 mark for correct rest of number ("and seventy-three").

Q10 (2 m)3906 Method: three thousand = 3000, nine hundred = 900, six = 6. 3000+900+6=39063000 + 900 + 6 = 3906. Teaching note: The tens place holds 0, so we write 06 in the last two places.

Q11 (2 m)6000 Method: In 6842, digit 6 is in the thousands place. Value = 6×1000=60006 \times 1000 = 6000.

Q12 (2 m)2909, 2919, 2990, 2999 Method: All have 2 thousands and 9 hundreds. Compare tens: 0 < 1 < 9. For the two numbers with 9 tens, compare ones: 0 < 9. Marking: 2 marks fully correct; deduct 1 mark if only one pair is swapped.

Q13 (2 m)6600 and 6000 Method: The pattern decreases by 300 each step (7200300=69007200 - 300 = 6900; 6900300=66006900 - 300 = 6600; 6600300=63006600 - 300 = 6300 ✓; 6300300=60006300 - 300 = 6000). Marking: 1 mark per missing number.

Q14 (2 m) (a) 6308 < 63806308\ \mathbf{<}\ 6380 — same thousands and hundreds digits; compare tens: 0 < 8. (b) 9999 < 100009999\ \mathbf{<}\ 10\,000 — any 4-digit number is smaller than the smallest 5-digit number. Marking: 1 mark per correct sign.

Q15 (2 m)2057 Method: A 4-digit number cannot start with 0, so choose the smallest non-zero digit (2) for the thousands place. Then place the remaining digits in increasing order: 0, 5, 7 → 2057. Common mistake: Writing 0257, which is not a 4-digit number.

Q16 (2 m) (a) 8450 — read each board under its heading: 8 thousands, 4 hundreds, 5 tens, 0 ones. (b) 400 — digit 4 is in the hundreds place; value = 4×100=4004 \times 100 = 400. Marking: 1 mark per part.


Section C: Word Problems

Q17 (4 m) (a) 2653, 2365, 2356 [2 m] Method: All have 2 thousands. Compare hundreds: 6 > 3. For 2365 vs 2356, compare tens: 6 > 5. (b) 288 books [2 m] Working: 26532365=2882653 - 2365 = 288 Best-selling booth: Booth B (2653); second best: Booth A (2365). Marking: 1 mark for correct method/subtraction set up, 1 mark for correct answer with units.

Q18 (4 m) Day 2: 1500250=12501500 - 250 = 1250 Day 3: 1250250=10001250 - 250 = 1000 Day 4: 1000250=7501000 - 250 = 750

(a) 750 people [2 m] (b) 4500 people [2 m] Working: 1500+1250+1000+750=45001500 + 1250 + 1000 + 750 = 4500 Marking: Award method marks for correct day-by-day working even if the final total is wrong.

Q19 (5 m) (a) 7640 [2 m] Method: Place largest digits in largest places: 7, 6, 4, 0. It is even because it ends in 0. (b) 4067 [2 m] Method: Must end in an odd digit, so 7 goes in the ones place. Use the smallest non-zero digit (4) in the thousands place, then 0, then 6 → 4067. (c) [1 m] If 0 were placed in the thousands place, the number would begin with 0 and would no longer be a 4-digit number (e.g., 0467 is really just 467, a 3-digit number). Marking: Accept any clear explanation mentioning that leading zero makes it not a 4-digit number.

Q20 (5 m) (a) Class 3C [1 m] Method: Compare thousands digits: 2 > 1, so 2008 is the largest. (b) 109 caps [2 m] Working: 20081899=1092008 - 1899 = 109 (c) No, the total does not reach the target. [2 m] Working: 1980+1899=38791980 + 1899 = 3879 3879+2008=58873879 + 2008 = 5887 5887+105=59925887 + 105 = 5992 Since 5992<60005992 < 6000, the school falls short of the target by 60005992=86000 - 5992 = 8 caps. Marking: 1 mark for correct total with working shown, 1 mark for correct conclusion ("No") with comparison against 6000.


— End of Answer Key —

Marks check: Section A = 16 marks, Section B = 16 marks, Section C = 18 marks. Total = 50 marks.